If the nucleus of an atom has a radius of about 5 fm and a mass of about 2 $\times$ 10^-²¹ g,what is its approximate density? (Volume of a sphere = 4$\pi$r³/3)

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Quizplus · Accepted Answer

The density of a sphere is given by the formula:$$density = \frac{mass}{volume}$$The volume of a sphere is given by the formula:$$volume = \frac{4}{3}\pi r^3$$where r is the radius of the sphere.In this problem, the radius of the nucleus is given as 5 fm, and the mass of the nucleus is given as 2 F1F1F1S1F1F1F10 10F1F1F1S1^F1F1F10²¹ g.Substituting these values into the formulas above, we get:$$density = \frac{2 F1F1F1S1F1F1F10 10F1F1F1S1^F1F1F10²¹ g}{\frac{4}{3}\pi (5 fm)^3}$$$$density = 4 F1F1F1S1F1F1F10 10F1F1F1S1^F1F1F10¹⁵ g/cm^3$$Therefore, the approximate density of the nucleus is 4 F1F1F1S1F1F1F10 10F1F1F1S1^F1F1F10¹⁵ g/cm^3.

If the Nucleus of an Atom Has a Radius of About