What would be the g Al / mole S ratio for the product of a reaction between aluminum and sulfur?

Question

Quizplus · Accepted Answer

The balanced equation for the reaction between aluminum and sulfur is:
2Al + 3S → Al2S3
This means that for every 2 moles of aluminum reacting, 3 moles of sulfur are needed to form 1 mole of Al2S3. The molar mass of aluminum is 26.98 g/mole, and the molar mass of sulfur is 32.06 g/mole. Therefore, the mass ratio of aluminum to sulfur in the product is:
(2 mol Al x 26.98 g/mole) / (1 mol Al2S3) ÷ (3 mol S x 32.06 g/mole) / (1 mol Al2S3)
= 17.99 g Al / mole S.

What Would Be the G Al / Mole S Ratio