Consider the following equilibrium: 2NOCl(g) 2NO(g)+ Cl 2 (g)with K = 1.6 $\times$ 10 - 5 .In an experiment,1.00 mole of pure NOCl and 1.00 mole of pure Cl 2 are placed in a 1.00-L container.
-If x moles of NOCl react,what is the equilibrium concentration of NO?

Question

Consider the following equilibrium: 2NOCl(g)  2NO(g)+ Cl 2 (g)with K = 1.6 $\times$ 10 - 5 .In an experiment,1.00 mole of pure NOCl and 1.00 mole of pure Cl 2 are placed in a 1.00-L container.
-If x moles of NOCl react,what is the equilibrium concentration of NO?

Quizplus · Accepted Answer

The reaction for the decomposition of NOCl is 2NOCl(g) ⇌ 2NO(g) + Cl2(g). For every mole of NOCl that reacts, one mole of NO is produced. Therefore, if x moles of NOCl react, x moles of NO will be produced, making the correct answer x.

Consider the Following Equilibrium: 2NOCl(g) 2NO(g)+ Cl2(g)with K = ×\times×

Consider the Following Equilibrium: 2NOCl(g) 2NO(g)+ Cl₂(g)with K = $\times$