Find an equation of the plane containing the lines $\frac { x } { 2 } = \frac { y - 2 } { 3 } = \frac { z + 1 } { 1 }$ and $\frac { x + 1 } { 4 } = \frac { y } { 6 } = \frac { z - 3 } { 2 }$

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The Answer of Find an equation of the plane containing the lines $\frac { x } { 2 } = \frac { y - 2 } { 3 } = \frac { z + 1 } { 1 }$ and $\frac { x + 1 } { 4 } = \frac { y } { 6 } = \frac { z - 3 } { 2 }$

Find an Equation of the Plane Containing the Lines x2=y−23=z+11\frac { x } { 2 } = \frac { y - 2 } { 3 } = \frac { z + 1 } { 1 }2x​=3y−2​=1z+1​

Find an Equation of the Plane Containing the Lines $\frac { x } { 2 } = \frac { y - 2 } { 3 } = \frac { z + 1 } { 1 }$