Suppose that the mileage (in thousands of miles) which car owners can obtain from a certain kind of tire has the probability density $p ( x ) = \left\{ \begin{array} { l l }
\frac { 1 } { 100 } \cdot e ^ { - \frac { x } { 100 } } & \text { if } x \geq 0 \
0 & \text { if } x

Question

Suppose that the mileage (in thousands of miles) which car owners can obtain from a certain kind of tire has the probability density $p ( x ) = \left\{ \begin{array} { l l } 
\frac { 1 } { 100 } \cdot e ^ { - \frac { x } { 100 } } & \text { if } x \geq 0 \
0 & \text { if } x < 0
\end{array} \right.$ Find the probability that a tire chosen at random will last
(a) at most 10,000 miles.(b) between 15,000 and 25,000 miles.(c) at least 30,000 miles.

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The Answer of Suppose that the mileage (in thousands of miles) which car owners can obtain from a certain kind of tire has the probability density $p ( x ) = \left\{ \begin{array} { l l } 
\frac { 1 } { 100 } \cdot e ^ { - \frac { x } { 100 } } & \text { if } x \geq 0 \
0 & \text { if } x < 0
\end{array} \right.$ Find the probability that a tire chosen at random will last
(a) at most 10,000 miles.(b) between 15,000 and 25,000 miles.(c) at least 30,000 miles.

Suppose That the Mileage (In Thousands of Miles) Which Car