A spring stretches 1 foot beyond its natural position under a force of 100 points. How much work in foot-pounds is done in stretching it 3 feet beyond its natural position?
A)600
B)30
C)1500
D)450
E)100
F)900
G)150
H)300

Question

Quizplus · Accepted Answer

The work done on a spring is calculated using Hooke's Law, W = (1/2)kx^2. Given that a force of 100 pounds stretches the spring 1 foot, the spring constant k is 100. To stretch it 3 feet, the work done is (1/2)(100)(3^2) = 450 foot-pounds.

A Spring Stretches 1 Foot Beyond Its Natural Position Under