The volume of a 15.0 g sample of N₂ gas at a pressure of 2.7 atm is 6.24 L. What is the temperature of the sample?

Question

Quizplus · Accepted Answer

We can use the ideal gas law to solve for the temperature: PV = nRT where P = 2.7 atm, V = 6.24 L, n = 15.0 g / (atomic weight of N₂) = 15.0 g / (14.01 g/mol) = 1.07 mol, and R is the gas constant. R = 0.08206 L atm/mol K Substituting in these values and solving for T, we get: T = PV / nR T = (2.7 atm) x (6.24 L) / (1.07 mol x 0.08206 L atm/mol K) T = 110 K Converting to Celsius, we subtract 273.15: T = -163.15°C Therefore, the answer is choice D: 110°F.

The Volume of a 15 ∘\circ∘ C B)190 ∘\circ∘ C C)3 ∘\circ∘ C D)110

The Volume of a 15 $\circ$ C
B)190^$\circ$C
C)3 $\circ$ C
D)110