A projectile traveling with momentum 2 kg m/s in one direction undergoes an impulse in the opposite direction. The force of the impulse is described as 6000(sin500t) kg m/s² and it is exerted over a time range . What is the object's momentum (in the direction of the impulse) after the impulse? A) 10 kg m/s B) -22 kg m/s C) -21 kg m/s D) 20 kg m/s

Question

Quizplus · Accepted Answer

We can use the impulse-momentum theorem, which states that the change in momentum of an object is equal to the impulse exerted on it.

Initial momentum = 2 kg m/s in one direction

Final momentum = ?
Let's first find the impulse:

Impulse = force x time

= (6000 sin 500t) kg m/s^2 x 0.011 s

= 66 sin 500t kg m/s

Now we can use the impulse-momentum theorem:

Final momentum - Initial momentum = Impulse

Final momentum - 2 kg m/s = 66 sin 500t kg m/s

Final momentum = 66 sin 500t + 2

Note that we are only interested in the momentum in the direction of the impulse, which is opposite to the initial direction of motion. The momentum will be negative when the projectile is moving in the opposite direction.

To find the final momentum at the moment the impulse is applied (t = 0):

Final momentum = 66 sin 0 + 2 = 2 kg m/s

So initially the object is moving with momentum 2 kg m/s to the right, and immediately after the impulse it is moving with momentum -22 kg m/s to the left.

Therefore, the answer is B.

A Projectile Traveling with Momentum 2 Kg M/s in One