A sample of n = 9 scores is selected from a normal population with a mean of µ = 80 and a standard deviation of σ = 12.The probability that the sample mean will be greater than M = 86 is equal to the probability of obtaining a z-score greater than z = 1.50

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Quizplus · Accepted Answer

This statement is true because if we standardize the sample mean using the formula z = (M - µ) / (σ / sqrt(n)), we get z = (86 - 80) / (12 / sqrt(9)) = 1.50. Therefore, the probability of obtaining a sample mean greater than 86 is equal to the probability of obtaining a z-score greater than 1.50, which can be found using a z-table or calculator.

A Sample of N = 9 Scores Is Selected from a Normal