Lead(II) nitrate reacts with sodium chloride in aqueous solution to form a precipitate. What is the net ionic equation for this reaction? A) Na⁺(aq) + Cl^2-(aq) → Na₂Cl(s) B) Na⁺(aq) + NO₃^-(aq) → NaNO₃(s) C) Pb²⁺(aq) + 2NO₃^-(aq) → Pb(NO₃)₂(s) D) Na⁺(aq) + Cl^-(aq) → NaCl(s) E) Pb²⁺(aq) + 2Cl^-(aq) → PbCl₂(s)

Question

Quizplus · Accepted Answer

The correct net ionic equation is Pb2+(aq) + 2Cl-(aq) → PbCl2(s). This equation shows that lead(II) ions and chloride ions react to form a precipitate of lead(II) chloride. The other answer choices include incorrect or unnecessary ions and do not properly represent the reaction that takes place.

Lead(II) Nitrate Reacts with Sodium Chloride in Aqueous Solution to Form