The following equation describes the oxidation of ethanol to acetic acid by potassium permanganate:
3C2H5OH + 4KMnO4 → 3HC2H3O2 + 4MnO2 + 4KOH + H2O
5) 0 g of ethanol and an excess of aqueous KMnO4 are reacted, and 5.9 g HC2H3O2 results. What is the percent yield?
A) 5.9 g HC2H3O2 is impossible because it represents more than a 100% yield.
B) 91%
C) 100%
D) 67%
E) 30.%
Correct Answer:
Verified
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