Balance the equation C₈H₁₈( )+ ___ O₂(g)$\rightarrow$ ___ CO₂(g)+ ___ H₂O( ).What is the coefficient for O₂(g)?

Question

Quizplus · Accepted Answer

Counting the number of atoms for each element on both sides of the equation, we can see that there are: - 11 carbon atoms (C) - 29 hydrogen atoms (H) - 19 sulfur atoms (S) - Some oxygen atoms (O) on the left side, and a variable number on the right side To balance sulfur, we start with balancing the sulfate ion (SO4) in the left-hand side. There are two sulfate ions on the left, which means there are also two calcium ions (Ca) and two hydroxide ions (OH). To balance these, we need two calcium hydroxide molecules: 2Ca(OH)2 + ___ CS2(g) + ___ SO2(g) + ___ O2(g) → ___ CaSO4(s) + ___ CO2(g) + ___ H2O(g) Now, counting the oxygen atoms, we have: - 4 oxygen atoms from the calcium hydroxide - x oxygen atoms from the oxygen molecule on the right-hand side - y oxygen atoms from the carbon dioxide molecule on the right-hand side - z oxygen atoms from the water molecule on the right-hand side So the total number of oxygen atoms is 4 + x + y + z. To balance this, we can see that we need 4 oxygen molecules on the right-hand side. Therefore, the complete balanced equation is: 2Ca(OH)2 + CS2(g) + 2SO2(g) + 4O2(g) → 2CaSO4(s) + CO2(g) + 2H2O(g) Now we can see that the coefficient for O2 is 4, which means there are 4*2=8 oxygen atoms in total. Since we don't have any other oxygen-containing molecules in the reactants or products, the coefficient for O2 on the left-hand side must be 10 (to get a total of 10 oxygen atoms). Therefore, the coefficient for O₂(g) on the left-hand side is 25 to balance the 25 oxygen atoms produced from 10 oxygen molecules.

Balance the Equation C8H18( )+ ___ O2(g) →\rightarrow→ ___ CO2(g)+ ___ H2O( )

Balance the Equation C₈H₁₈( )+ _ O₂(g) $\rightarrow$ _ CO₂(g)+ ___ H₂O( )