An inspector correctly identifies defective products 90% of the time. For the next 10 products, the probability that he makes fewer than two incorrect inspections is 0.736.

Question

Quizplus · Accepted Answer

We can use the binomial distribution formula to solve this problem. Let X be the number of incorrect inspections out of 10. We want to find P(X < 2) = P(X = 0) + P(X = 1).

The probability of an incorrect inspection is 1 - 0.9 = 0.1. The probability of a correct inspection is 0.9.

P(X = 0) = 0.9^10 = 0.3487
P(X = 1) = 10C1 * 0.9^9 * 0.1 = 0.3874

Therefore, P(X < 2) = P(X = 0) + P(X = 1) = 0.3487 + 0.3874 = 0.7361, which matches the given probability. Therefore, the answer is A) True.

An Inspector Correctly Identifies Defective Products 90% of the Time