After reviewing past history, you have assembled the following table showing the frequency of certain levels of sales over the past 40 months. If the smallest random number used to represent sales of 200 units is 0.45, what will be the largest number used to represent sales of 200 units?
$$\begin{array} { | c | r | l | }
\hline \text { Sales (units) } & \text { Frequency } & \text { Corregonding Randam Numbers } \
\hline 100 & 12 & \
\hline 150 & 6 & \
\hline 200 & 8 & 0.45 \leq x

Question

After reviewing past history, you have assembled the following table showing the frequency of certain levels of sales over the past 40 months. If the smallest random number used to represent sales of 200 units is 0.45, what will be the largest number used to represent sales of 200 units?
$$\begin{array} { | c | r | l | } 
\hline \text { Sales (units) } & \text { Frequency } & \text { Corregonding Randam Numbers } \
\hline 100 & 12 & \
\hline 150 & 6 & \
\hline 200 & 8 & 0.45 \leq x < ? ? \
\hline 250 & 4 & \
\hline 300 & 10 & \
\hline
\end{array}$$
A) 0.1000
B) 0.3000
C) 0.5000
D) 0.6500
E) 0.9000

Quizplus · Accepted Answer

To find the largest random number used to represent sales of 200 units, we first calculate the cumulative probability for each sales level. The cumulative probability is the sum of the frequencies of all sales levels up to and including the current level, divided by the total number of observations (40 months).- For 100 units: Frequency = 12, Cumulative probability = 12/40 = 0.30- For 150 units: Frequency = 6, Cumulative probability = (12+6)/40 = 18/40 = 0.45- For 200 units: Frequency = 8, Cumulative probability = (12+6+8)/40 = 26/40 = 0.65Since the smallest random number for sales of 200 units is 0.45, the largest number used to represent sales of 200 units will be the cumulative probability of sales up to 200 units, which is 0.65. This means that the range of random numbers representing sales of 200 units is 0.45 to just under 0.65.

After Reviewing Past History, You Have Assembled the Following Table