If the solubility of copper(II) sulfate is 4.9 × 10^-3 M, the solubility product is ________.

Question

Quizplus · Accepted Answer

The solubility product (Ksp) for copper(II) sulfate is the product of the molar concentrations of the copper(II) and sulfate ions in a saturated solution. The solubility of copper(II) sulfate is 4.9 × 10^-3 M, so the molar concentration of copper(II) ions in a saturated solution is also 4.9 × 10^-3 M. The molar concentration of sulfate ions in a saturated solution is twice the molar concentration of copper(II) ions, or 9.8 × 10^-3 M. Therefore, the Ksp for copper(II) sulfate is:Ksp = [Cu2+][SO42-]2 = (4.9 × 10-3 M)(9.8 × 10-3 M)2 = 2.4 × 10-5

If the Solubility of Copper(II) Sulfate Is 4