Calculate the energy released in joules when one mole of polonium-214 decays according to the following equation. Particle Mass (amu)
Pb-210
209) 98284
Po-214
213) 99519
He-4
4) 00260
(1 kg = 6.022 × 10²⁶ amu;
N_A = 6.022 × 10²³ mol^-1;
C = 2.99792458 × 10⁸ m/s)

Question

Calculate the energy released in joules when one mole of polonium-214 decays according to the following equation.

Particle Mass (amu)
Pb-210
209) 98284
Po-214
213) 99519
He-4
4) 00260
(1 kg = 6.022 × 10²⁶ amu;
N_A = 6.022 × 10²³ mol^-1;
C = 2.99792458 × 10⁸ m/s)

Quizplus · Accepted Answer

Polonium-214 decays through alpha particle emission to form lead-210. The mass difference between the initial and final state is 9 amu. Using the equation E=mc^2 and converting the mass difference to kg/mol, we can calculate the energy released:
E=(9 amu/1 mol)(1 kg/6.022x10^23 amu)(2.99792458x10^8 m/s)^2 = 8.76x10^11 J/mol = 8.76x10^11 J/mol (rounded to two significant figures). Therefore, the best choice is C, which matches this value.

Calculate the Energy Released in Joules When One Mole of Polonium-214