What is the expression for the partial pressure of "A" for the following reaction under ideal conditions? A(g) B(g)

Question

What is the expression for the partial pressure of "A" for the following reaction under ideal conditions? A(g)  B(g)

Quizplus · Accepted Answer

The expression for the partial pressure of A can be obtained using the ideal gas law and the mole fraction of A. Since the reaction is written in terms of gases, we can assume ideal gas behavior. The mole fraction of A is given by n(A)/(n(A)+n(B)). From the balanced equation, n(A) = n(B)/11. Substituting this into the mole fraction expression gives n(B)/(12*n(B)) = 1/12. Therefore, the mole fraction of A is 1/12. Using the ideal gas law, we can write PA = (n(A)/V) RT = (n(B)/(12V)) RT. Since n(B)/(12V) is the mole fraction of B, which is given by S(B), the expression simplifies to PA = (S(B)V) RT/S(A+B). Finally, since S(A+B) = 1-S(B), the expression becomes PA = (S(B)V) RT/(1-S(B)), which is the same as choice (B).

What Is the Expression for the Partial Pressure of "A