College Physics 10th Edition by Raymond Serway,Chris Vuille

تمرين 5

The lens-maker's equation for a lens with index n 1 immersed in a medium with index n 2 takes the form
A thin diverging glass (index = 1.50) lens with R 1 = 3.00 m and R 2 = 6.00 m is surrounded by air. An arrow is placed 10.0 m to the left of the lens. (a) Determine the position of the image. Repeat part (a) with the arrow and lens immersed in (b) water (index = 1.33) (c) a medium with an index of refraction of 2.00. (d) How can a lens that is diverging in air be changed into a converging lens