
Contemporary Engineering Economics 6th Edition by Chan Park
النسخة 6الرقم المعياري الدولي: 978-0134105598
Contemporary Engineering Economics 6th Edition by Chan Park
النسخة 6الرقم المعياري الدولي: 978-0134105598 تمرين 14
The following equation describes the conversion of a cash flow into an equivalent equal payment series with N = 10:
A = [800 + 20( A / G, 6%, 7)]
× ( P / A ,6%, 7)( A / P ,6%, 10)
+ [300( F / A ,6%,3) 500]( A / F ,6%, 10)
Reconstruct the original cash flow diagram.
A = [800 + 20( A / G, 6%, 7)]
× ( P / A ,6%, 7)( A / P ,6%, 10)
+ [300( F / A ,6%,3) 500]( A / F ,6%, 10)
Reconstruct the original cash flow diagram.
التوضيح
A formula for the conversion of a cash f...
Contemporary Engineering Economics 6th Edition by Chan Park
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