Deck 5: Probability and Probability Distributions

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Given that events A and B are independent and that P(A)= 0.8 and P(B/A)= 0.4,then P(A and B)= 0.32.
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Question
Two or more events are said to be exhaustive if one of them must occur.
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If P(A and B)= 1,then A and B must be collectively exhaustive.
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If P(A and B)= 0,then A and B must be collectively exhaustive.
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Two events are said to be independent when knowledge of one event is of no value when assessing the probability of the other.
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The relative frequency of an event is the number of times the event occurs out of the total number of times the random experiment is run.
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Suppose that after graduation,you will either buy a new car (event A)or take a trip to Europe (event B).In this case,events A and B are mutually exclusive.
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Two or more events are said to be exhaustive if at most one of them can occur.
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Conditional probability is the probability that an event will occur,with no other events taken into consideration.
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You think you have a 90% chance of passing your statistics class.This is an example of subjective probability.
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Probability is a number between 0 and 1,inclusive,which measures the likelihood that some event will occur.
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Two or more events are said to be mutually exclusive if at most one of them can occur.
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If A and B are independent events with P(A)= 0.40 and P(B)= 0.50,then P(A/B)is 0.50.
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Two events A and B are said to mutually be exclusive if P(A and B)= 0.
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The law of large numbers states that subjective probabilities can be estimated based on the long run relative frequencies of events.
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If A and B are two independent events with P(A)= 0.20 and P(B)= 0.60,then P(A and B)= 0.80.
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Suppose A and B are mutually exclusive events where P(A)= 0.3 and P(B)= 0.4.Then,P(A and B)= 0.12.
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The multiplication rule for two events A and B is: P(A and B)= P(A|B)P(A).
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If events A and B have nonzero probabilities,then they can be both independent and mutually exclusive.
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Suppose A and B are two events where P(A)= 0.5,P(B)= 0.4,and P(A and B)= 0.2,then P(B/A)= 0.5.
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A random variable X is standardized when each value of X has the mean of X subtracted from it,and the difference is divided by the standard deviation of X.
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If the random variable X is normally distributed with mean If the random variable X is normally distributed with mean   and standard deviation   ,then the random variable Z defined by   is also normally distributed with mean 0 and standard deviation 1.<div style=padding-top: 35px> and standard deviation If the random variable X is normally distributed with mean   and standard deviation   ,then the random variable Z defined by   is also normally distributed with mean 0 and standard deviation 1.<div style=padding-top: 35px> ,then the random variable Z defined by If the random variable X is normally distributed with mean   and standard deviation   ,then the random variable Z defined by   is also normally distributed with mean 0 and standard deviation 1.<div style=padding-top: 35px> is also normally distributed with mean 0 and standard deviation 1.
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Using the standard normal distribution,the Z-score representing the 5th percentile is 1.645.
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The mean and standard deviation of a normally distributed random variable that has been "standardized" are zero and one,respectively.
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​A probability tree is a graphical representation of how events occur through time,which is useful for calculating probabilities.
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Subjective probability is the probability that a given event will occur,given that another event has already occurred.
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Football teams toss a coin to see who will get their choice of kicking or receiving to begin a game.The probability that given team will win the toss three games in a row is 0.125.
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Two events A and B are said to be independent if P(A and B)= P(A)+ P(B).
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Suppose A and B are mutually exclusive events where P(A)= 0.2 and P(B)= 0.5,then P(A or B)= 0.70.
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When we wish to determine the probability that at least one of several events will occur,we would use the addition rule.
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The number of car insurance policy holders is an example of a discrete random variable.
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Using the standard normal distribution,the Z- score representing the 99th percentile is 2.326.
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The number of people entering a shopping mall on a given day is an example of a discrete random variable.
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The time students spend in a computer lab during one day is an example of a continuous random variable.
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When two events are independent,they are also mutually exclusive.
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The number of cars produced by GM during a given quarter is a continuous random variable.
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The total area under the normal distribution curve is equal to one.
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The temperature of the room in which you are writing this test is a continuous random variable.
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The probability that event A will not occur is denoted as The probability that event A will not occur is denoted as   .<div style=padding-top: 35px> .
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A random variable is a function that associates a numerical value with each possible outcome of a random phenomenon.
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The variance of a binomial distribution is given by the formula The variance of a binomial distribution is given by the formula   ,where n is the number of trials,and p is the probability of success in any trial.<div style=padding-top: 35px> ,where n is the number of trials,and p is the probability of success in any trial.
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The Poisson random variable is a discrete random variable with infinitely many possible values.
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The number of loan defaults per month at a bank is Poisson distributed.
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Using the standard normal curve,the Z- score representing the 75th percentile is 0.674.
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An exponential distribution with parameter An exponential distribution with parameter   = 0.2 has mean and standard deviation both equal to 5.<div style=padding-top: 35px> = 0.2 has mean and standard deviation both equal to 5.
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The Poisson distribution is characterized by a single parameter The Poisson distribution is characterized by a single parameter   ,which must be positive.<div style=padding-top: 35px> ,which must be positive.
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A binomial distribution with n number of trials,and probability of success p can be approximated well by a normal distribution with mean np and variance A binomial distribution with n number of trials,and probability of success p can be approximated well by a normal distribution with mean np and variance   if np > 5 and n(1-p)> 5.<div style=padding-top: 35px> if np > 5 and n(1-p)> 5.
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The binomial distribution is a discrete distribution that deals with a sequence of identical trials,each of which have only two possible outcomes.
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The variance of a binomial distribution for which n = 50 and p = 0.20 is 8.0.
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Using the standard normal curve,the Z- score representing the 10th percentile is 1.28.
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A Poisson distribution is appropriate to determine the probability of a given number of defective items in a shipment.
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Much of the study of probabilistic inventory models,queuing models,and reliability models relies heavily on the Poisson and exponential distributions.
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The binomial random variable represents the number of successes that occur in a specific period of time.
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A random variable X is normally distributed with a mean of 175 and a standard deviation of 50.Given that X = 150,its corresponding Z- score is -0.50.
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The Poisson probability distribution is one of the most commonly used continuous probability distributions.
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For a given probability of success p that is not too close to 0 or 1,the binomial distribution takes on more of a symmetric bell shape as the number of trials n increases.
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The density function specifies the probability distribution of a continuous random variable.​
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The binomial distribution deals with consecutive trials,each of which has two possible outcomes.
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The Poisson distribution is applied to events for which the probability of occurrence over a given span of time,space,or distance is very small.
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The binomial distribution is a continuous distribution.
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A function that associates a numerical value with each possible outcome of an uncertain event is called a _____ variable.

A)conditional
B)random
C)population
D)sample
Question
The probabilities shown in a table with two rows, <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> and <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> and two columns, <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> and <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> ,are as follows: P( <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> and <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> )= 0.10,P( <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> and <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> )= 0.30,P( <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> and <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> )= 0.05,and P( <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> and <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> )= 0.55.Then P( <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> | <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> )is

A)0.33.
B)0.35.
C)0.65.
D)0.67.
Question
Probabilities that can be estimated from long-run relative frequencies of events are called _____ probabilities.

A)objective
B)subjective
C)complementary
D)joint
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The probability of an event and the probability of its complement always sum to

A)1.
B)0.
C)any value between 0 and 1.
D)any positive value.
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If A and B are mutually exclusive events with P(A)= 0.70,then P(B)

A)can be any value between 0 and 1.
B)can be any value between 0 and 0.70.
C)cannot be larger than 0.30.
D)can be any value between 0.30 and 0.70.
Question
Which of the following statements is true?

A)Probabilities must be negative.
B)Probabilities must be greater than 1.
C)The sum of all probabilities for a random variable must be equal to 1.
D)The sum of all probabilities for a random variable must be equal to 0.
Question
If two events are independent,what is the probability that they both occur?

A)0
B)0.50
C)1.00
D)This cannot be determined from the information given.
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A discrete probability distribution

A)is a set of possible values and a corresponding set of probabilities that sum to 1.
B)is a modeling tool that can be used to incorporate uncertainty into models.
C)can be estimated from long-run proportions.
D)is the distribution of a single random variable.
Question
If events A and B are mutually exclusive,then the probability of both events occurring simultaneously is equal to

A)0.0.
B)0.5.
C)1.0.
D)any value between 0.5 and 1.0.
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There are two types of random variables,they are

A)discrete and continuous.
B)exhaustive and mutually exclusive.
C)complementary and cumulative.
D)real and unreal.
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If P(A)= P(A|B),then events A and B are said to be

A)mutually exclusive.
B)independent.
C)dependent.
D)complementary.
Question
The probabilities shown in a table with two rows, <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> and <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> and two columns, <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> and <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> ,are as follows: P( <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> and <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> )= 0.10,P( <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> and <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> )= 0.30,P( <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> and <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> )= 0.05,and P( <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> and <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> )= 0.55.Then P( <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> | <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. <div style=padding-top: 35px> ),calculated up to two decimals,is

A)0.33.
B)0.35.
C)0.65.
D)0.67.
Question
If P(A)= 0.25 and P(B)= 0.65,then P(A and B)is

A)0.25.
B)0.40.
C)0.90.
D)This cannot be determined from the information given.
Question
If two events are collectively exhaustive,what is the probability that both occur at the same time?

A)0.00
B)0.50
C)1.00
D)This cannot be determined from the information given.
Question
The formal way to revise probabilities based on new information is to use _____ probabilities.

A)complementary
B)conditional
C)unilateral
D)common sense
Question
Probabilities that cannot be estimated from long-run relative frequencies of events are called

A)objective probabilities.
B)subjective probabilities.
C)complementary probabilities.
D)joint probabilities.
Question
If two events are mutually exclusive,what is the probability that both occur at the same time?

A)0.0
B)0.5
C)1.0
D)This can be any probability between 0 and 1.
Question
The law of large numbers is relevant to the estimation of _____ probabilities.

A)objective
B)subjective
C)both objective and subjective
D)neither objective nor subjective
Question
If A and B are any two events with P(A)= 0.8 and P(B|A)= 0.4,then the joint probability of A and B is:

A)0.80
B)0.40
C)0.32
D)1.20
Question
Which of the following best describes the concept of probability?

A)It is a measure of the likelihood that a particular event will occur.
B)It is a measure of the likelihood that a particular event will occur,given that another event has already occurred.
C)It is a measure of the likelihood of the simultaneous occurrence of two or more events.
D)None of these choices describe the concept of probability.
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Deck 5: Probability and Probability Distributions
1
Given that events A and B are independent and that P(A)= 0.8 and P(B/A)= 0.4,then P(A and B)= 0.32.
True
2
Two or more events are said to be exhaustive if one of them must occur.
True
3
If P(A and B)= 1,then A and B must be collectively exhaustive.
True
4
If P(A and B)= 0,then A and B must be collectively exhaustive.
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5
Two events are said to be independent when knowledge of one event is of no value when assessing the probability of the other.
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6
The relative frequency of an event is the number of times the event occurs out of the total number of times the random experiment is run.
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7
Suppose that after graduation,you will either buy a new car (event A)or take a trip to Europe (event B).In this case,events A and B are mutually exclusive.
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8
Two or more events are said to be exhaustive if at most one of them can occur.
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9
Conditional probability is the probability that an event will occur,with no other events taken into consideration.
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10
You think you have a 90% chance of passing your statistics class.This is an example of subjective probability.
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11
Probability is a number between 0 and 1,inclusive,which measures the likelihood that some event will occur.
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12
Two or more events are said to be mutually exclusive if at most one of them can occur.
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13
If A and B are independent events with P(A)= 0.40 and P(B)= 0.50,then P(A/B)is 0.50.
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14
Two events A and B are said to mutually be exclusive if P(A and B)= 0.
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15
The law of large numbers states that subjective probabilities can be estimated based on the long run relative frequencies of events.
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16
If A and B are two independent events with P(A)= 0.20 and P(B)= 0.60,then P(A and B)= 0.80.
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17
Suppose A and B are mutually exclusive events where P(A)= 0.3 and P(B)= 0.4.Then,P(A and B)= 0.12.
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18
The multiplication rule for two events A and B is: P(A and B)= P(A|B)P(A).
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19
If events A and B have nonzero probabilities,then they can be both independent and mutually exclusive.
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20
Suppose A and B are two events where P(A)= 0.5,P(B)= 0.4,and P(A and B)= 0.2,then P(B/A)= 0.5.
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21
A random variable X is standardized when each value of X has the mean of X subtracted from it,and the difference is divided by the standard deviation of X.
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22
If the random variable X is normally distributed with mean If the random variable X is normally distributed with mean   and standard deviation   ,then the random variable Z defined by   is also normally distributed with mean 0 and standard deviation 1. and standard deviation If the random variable X is normally distributed with mean   and standard deviation   ,then the random variable Z defined by   is also normally distributed with mean 0 and standard deviation 1. ,then the random variable Z defined by If the random variable X is normally distributed with mean   and standard deviation   ,then the random variable Z defined by   is also normally distributed with mean 0 and standard deviation 1. is also normally distributed with mean 0 and standard deviation 1.
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23
Using the standard normal distribution,the Z-score representing the 5th percentile is 1.645.
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24
The mean and standard deviation of a normally distributed random variable that has been "standardized" are zero and one,respectively.
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25
​A probability tree is a graphical representation of how events occur through time,which is useful for calculating probabilities.
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26
Subjective probability is the probability that a given event will occur,given that another event has already occurred.
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27
Football teams toss a coin to see who will get their choice of kicking or receiving to begin a game.The probability that given team will win the toss three games in a row is 0.125.
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28
Two events A and B are said to be independent if P(A and B)= P(A)+ P(B).
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29
Suppose A and B are mutually exclusive events where P(A)= 0.2 and P(B)= 0.5,then P(A or B)= 0.70.
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30
When we wish to determine the probability that at least one of several events will occur,we would use the addition rule.
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31
The number of car insurance policy holders is an example of a discrete random variable.
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32
Using the standard normal distribution,the Z- score representing the 99th percentile is 2.326.
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33
The number of people entering a shopping mall on a given day is an example of a discrete random variable.
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34
The time students spend in a computer lab during one day is an example of a continuous random variable.
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35
When two events are independent,they are also mutually exclusive.
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36
The number of cars produced by GM during a given quarter is a continuous random variable.
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37
The total area under the normal distribution curve is equal to one.
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38
The temperature of the room in which you are writing this test is a continuous random variable.
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39
The probability that event A will not occur is denoted as The probability that event A will not occur is denoted as   . .
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40
A random variable is a function that associates a numerical value with each possible outcome of a random phenomenon.
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41
The variance of a binomial distribution is given by the formula The variance of a binomial distribution is given by the formula   ,where n is the number of trials,and p is the probability of success in any trial. ,where n is the number of trials,and p is the probability of success in any trial.
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42
The Poisson random variable is a discrete random variable with infinitely many possible values.
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43
The number of loan defaults per month at a bank is Poisson distributed.
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44
Using the standard normal curve,the Z- score representing the 75th percentile is 0.674.
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45
An exponential distribution with parameter An exponential distribution with parameter   = 0.2 has mean and standard deviation both equal to 5. = 0.2 has mean and standard deviation both equal to 5.
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46
The Poisson distribution is characterized by a single parameter The Poisson distribution is characterized by a single parameter   ,which must be positive. ,which must be positive.
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47
A binomial distribution with n number of trials,and probability of success p can be approximated well by a normal distribution with mean np and variance A binomial distribution with n number of trials,and probability of success p can be approximated well by a normal distribution with mean np and variance   if np > 5 and n(1-p)> 5. if np > 5 and n(1-p)> 5.
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48
The binomial distribution is a discrete distribution that deals with a sequence of identical trials,each of which have only two possible outcomes.
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49
The variance of a binomial distribution for which n = 50 and p = 0.20 is 8.0.
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50
Using the standard normal curve,the Z- score representing the 10th percentile is 1.28.
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51
A Poisson distribution is appropriate to determine the probability of a given number of defective items in a shipment.
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52
Much of the study of probabilistic inventory models,queuing models,and reliability models relies heavily on the Poisson and exponential distributions.
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53
The binomial random variable represents the number of successes that occur in a specific period of time.
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54
A random variable X is normally distributed with a mean of 175 and a standard deviation of 50.Given that X = 150,its corresponding Z- score is -0.50.
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55
The Poisson probability distribution is one of the most commonly used continuous probability distributions.
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56
For a given probability of success p that is not too close to 0 or 1,the binomial distribution takes on more of a symmetric bell shape as the number of trials n increases.
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57
The density function specifies the probability distribution of a continuous random variable.​
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58
The binomial distribution deals with consecutive trials,each of which has two possible outcomes.
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59
The Poisson distribution is applied to events for which the probability of occurrence over a given span of time,space,or distance is very small.
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60
The binomial distribution is a continuous distribution.
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61
A function that associates a numerical value with each possible outcome of an uncertain event is called a _____ variable.

A)conditional
B)random
C)population
D)sample
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62
The probabilities shown in a table with two rows, <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. and <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. and two columns, <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. and <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. ,are as follows: P( <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. and <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. )= 0.10,P( <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. and <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. )= 0.30,P( <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. and <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. )= 0.05,and P( <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. and <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. )= 0.55.Then P( <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. | <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   )is</strong> A)0.33. B)0.35. C)0.65. D)0.67. )is

A)0.33.
B)0.35.
C)0.65.
D)0.67.
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63
Probabilities that can be estimated from long-run relative frequencies of events are called _____ probabilities.

A)objective
B)subjective
C)complementary
D)joint
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64
The probability of an event and the probability of its complement always sum to

A)1.
B)0.
C)any value between 0 and 1.
D)any positive value.
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65
If A and B are mutually exclusive events with P(A)= 0.70,then P(B)

A)can be any value between 0 and 1.
B)can be any value between 0 and 0.70.
C)cannot be larger than 0.30.
D)can be any value between 0.30 and 0.70.
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66
Which of the following statements is true?

A)Probabilities must be negative.
B)Probabilities must be greater than 1.
C)The sum of all probabilities for a random variable must be equal to 1.
D)The sum of all probabilities for a random variable must be equal to 0.
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67
If two events are independent,what is the probability that they both occur?

A)0
B)0.50
C)1.00
D)This cannot be determined from the information given.
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68
A discrete probability distribution

A)is a set of possible values and a corresponding set of probabilities that sum to 1.
B)is a modeling tool that can be used to incorporate uncertainty into models.
C)can be estimated from long-run proportions.
D)is the distribution of a single random variable.
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69
If events A and B are mutually exclusive,then the probability of both events occurring simultaneously is equal to

A)0.0.
B)0.5.
C)1.0.
D)any value between 0.5 and 1.0.
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70
There are two types of random variables,they are

A)discrete and continuous.
B)exhaustive and mutually exclusive.
C)complementary and cumulative.
D)real and unreal.
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71
If P(A)= P(A|B),then events A and B are said to be

A)mutually exclusive.
B)independent.
C)dependent.
D)complementary.
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72
The probabilities shown in a table with two rows, <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. and <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. and two columns, <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. and <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. ,are as follows: P( <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. and <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. )= 0.10,P( <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. and <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. )= 0.30,P( <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. and <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. )= 0.05,and P( <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. and <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. )= 0.55.Then P( <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. | <strong>The probabilities shown in a table with two rows,   and   and two columns,   and   ,are as follows: P(   and   )= 0.10,P(   and   )= 0.30,P(   and   )= 0.05,and P(   and   )= 0.55.Then P(   |   ),calculated up to two decimals,is</strong> A)0.33. B)0.35. C)0.65. D)0.67. ),calculated up to two decimals,is

A)0.33.
B)0.35.
C)0.65.
D)0.67.
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73
If P(A)= 0.25 and P(B)= 0.65,then P(A and B)is

A)0.25.
B)0.40.
C)0.90.
D)This cannot be determined from the information given.
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74
If two events are collectively exhaustive,what is the probability that both occur at the same time?

A)0.00
B)0.50
C)1.00
D)This cannot be determined from the information given.
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75
The formal way to revise probabilities based on new information is to use _____ probabilities.

A)complementary
B)conditional
C)unilateral
D)common sense
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76
Probabilities that cannot be estimated from long-run relative frequencies of events are called

A)objective probabilities.
B)subjective probabilities.
C)complementary probabilities.
D)joint probabilities.
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77
If two events are mutually exclusive,what is the probability that both occur at the same time?

A)0.0
B)0.5
C)1.0
D)This can be any probability between 0 and 1.
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78
The law of large numbers is relevant to the estimation of _____ probabilities.

A)objective
B)subjective
C)both objective and subjective
D)neither objective nor subjective
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79
If A and B are any two events with P(A)= 0.8 and P(B|A)= 0.4,then the joint probability of A and B is:

A)0.80
B)0.40
C)0.32
D)1.20
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80
Which of the following best describes the concept of probability?

A)It is a measure of the likelihood that a particular event will occur.
B)It is a measure of the likelihood that a particular event will occur,given that another event has already occurred.
C)It is a measure of the likelihood of the simultaneous occurrence of two or more events.
D)None of these choices describe the concept of probability.
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