Deck 8: Estimation of the Mean and Proportion
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Deck 8: Estimation of the Mean and Proportion
1
The z value for a 85% confidence interval for the population mean with
known is:
A)1.96
B)2.33
C)1.44
D)2.58

A)1.96
B)2.33
C)1.44
D)2.58
1.44
2
A random sample of 82 customers,who visited a department store,spent an average of $71 at this store.Suppose the standard deviation of expenditures at this store is
= $19.The 98% confidence interval for the population mean (rounded to two decimal places)is:

Part A: The lower limit is $66.11 Part B: The upper limit is $75.89
3
To decrease the width of a confidence interval,we should always prefer to:
A)lower the confidence level
B)increase the confidence level
C)increase the sample size
D)decrease the sample size
A)lower the confidence level
B)increase the confidence level
C)increase the sample size
D)decrease the sample size
increase the sample size
4
You can decrease the width of a confidence interval by:
A)lowering the confidence level or decreasing the sample size
B)increasing the confidence level or decreasing the sample size
C)lowering the confidence level or increasing the sample size
D)increasing the confidence level or increasing the sample size
A)lowering the confidence level or decreasing the sample size
B)increasing the confidence level or decreasing the sample size
C)lowering the confidence level or increasing the sample size
D)increasing the confidence level or increasing the sample size
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5
We use the t distribution to make a confidence interval for the population mean if the population from which the sample is drawn is (approximately)normally distributed,the population standard deviation is unknown,and the sample size is at least:
A)30
B)100
C)50
D)2
A)30
B)100
C)50
D)2
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6
A sample of size 97 from a population having standard deviation
= 7 produced a mean of 47.The 99% confidence interval for the population mean (rounded to two decimal places)is:

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7
The mean IQ score of a sample of 61 students selected from a high school is 87.Suppose the standard deviation of IQ's at this school is
= 8.4.The 99% confidence interval for the population mean (rounded to two decimal places)is:

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8
The single value of a sample statistic that we assign to the population parameter is a:
A)single estimate
B)unique estimate
C)point estimate
D)singular estimate
A)single estimate
B)unique estimate
C)point estimate
D)singular estimate
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9
The width of a confidence interval depends on the size of the:
A)population mean
B)margin of error
C)sample mean
D)none of these
A)population mean
B)margin of error
C)sample mean
D)none of these
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10
The sample statistic used to estimate a population parameter is a(n):
A)random variable
B)qualitative variable
C)estimator
D)parameter
A)random variable
B)qualitative variable
C)estimator
D)parameter
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11
When making a confidence interval for the population mean using the t procedures,the degrees of freedom for the t distribution are:
A)n
B)n - 2
C)n + 1
D)n - 1
A)n
B)n - 2
C)n + 1
D)n - 1
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12
The z value for a 90% confidence interval for the population mean with
known is:
A)2.05
B)1.645
C)2.17
D)1.60

A)2.05
B)1.645
C)2.17
D)1.60
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13
Estimation is a procedure by which we assign a numerical value or numerical values to the:
A)population parameter based on the information collected from a sample
B)sample statistic based on the information collected from a sample
C)population parameter based on the information collected from a population
D)sample statistic based on the information collected from a population
A)population parameter based on the information collected from a sample
B)sample statistic based on the information collected from a sample
C)population parameter based on the information collected from a population
D)sample statistic based on the information collected from a population
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14
A sample of size 65 from a population having standard deviation
= 55 produced a mean of 234.00.The 95% confidence interval for the population mean (rounded to two decimal places)is:

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15
For most distributions,we can use the normal distribution to make a confidence interval for a population mean provided that the population standard deviation
is known and the sample size is:
A)greater than 30
B)less than 25
C)greater than or equal to 30
D)greater than 100

A)greater than 30
B)less than 25
C)greater than or equal to 30
D)greater than 100
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16
The values assigned to a population parameter based on the value(s)of a sample statistic are:
A)the probabilities
B)the probability distribution
C)a sampling distribution
D)estimate(s)
A)the probabilities
B)the probability distribution
C)a sampling distribution
D)estimate(s)
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17
The margin of error for the population mean,assuming
is known,is:
A)z multiplied by the population standard deviation
B)z multiplied by t
C)z multiplied by the standard deviation of the sample mean
D)z multiplied by the sample mean

A)z multiplied by the population standard deviation
B)z multiplied by t
C)z multiplied by the standard deviation of the sample mean
D)z multiplied by the sample mean
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18
The mean federal income tax paid last year by a random sample of 45 persons selected from a city was $4,242.Suppose the standard deviation of tax paid in this city is
= $991.The 95% confidence interval for the population mean (rounded to two decimal places)is:

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19
Which of the following conditions is required to use the t distribution to make a confidence interval for the population mean?
A)The population from which the sample is drawn is (approximately)normally distributed.
B)The sample size is at least 30.
C)The population from which the sample is drawn has a t distribution.
D)The population standard deviation is known.
A)The population from which the sample is drawn is (approximately)normally distributed.
B)The sample size is at least 30.
C)The population from which the sample is drawn has a t distribution.
D)The population standard deviation is known.
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20
The confidence level of an interval estimate is denoted by:
A)
B)
C)
D)
A)

B)

C)

D)

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21
A researcher wants to make a 99% confidence interval for a population proportion.The most conservative estimate of the sample size that would limit the margin of error to be within 0.033 of the population proportion is:
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22
A sample of 20 elements produced a mean of 91.4 and a standard deviation of 11.16.Assuming that the population has a normal distribution,the 90% confidence interval for the population mean is:
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23
A random sample of 765 persons showed that 13.5% do not have any health insurance.Based on this sample,the 95% confidence interval for the proportion of all persons who do not have any health insurance,rounded to four decimal places,is:
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24
A researcher wants to make a 99% confidence interval for a population mean.She wants the margin of error to be within 4.6 of the population mean.The population standard deviation is 18.22.The sample size that will yield a margin of error within 4.6 of the population mean is:
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25
A researcher wants to make a 95% confidence interval for a population mean.She wants the margin of error to be within 1.9 of the population mean.The population standard deviation is 11.07.The sample size that will yield a margin of error within 1.9 of the population mean is:
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26
A random sample of 983 families selected from a large city showed that 17.5% of them make $100,000 or more per year.Based on this sample,the 99% confidence interval for the proportion of all families living in this city who make $100,000 or more per year,rounded to four decimal places,is:
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27
A researcher wants to make a 99% confidence interval for a population proportion.A preliminary sample produced the sample proportion of 0.680.The sample size that would limit the margin of error to be within 0.024 of the population proportion is:
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28
A random sample of 188 produced a sample proportion of 0.40.The 98% confidence interval for the population proportion,rounded to four decimal places,is:
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29
The value of t for 19 degrees of freedom and a 90% confidence interval is:
A)1.729
B)-1.729
C)2.539
D)-2.539
A)1.729
B)-1.729
C)2.539
D)-2.539
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30
A random sample of 12 life insurance policy holders showed that the mean value of their life insurance policies is $210,000 with a standard deviation of $44,600.Assuming that the values of life insurance policies for all such policy holders are approximately normally distributed,the 99% confidence interval for the mean value of all life insurance policies,rounded to two decimal places,is:
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31
The value of t for 19 degrees of freedom and a 98% confidence interval is:
A)2.861
B)2.539
C)-2.539
D)1.328
A)2.861
B)2.539
C)-2.539
D)1.328
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32
A random sample of 1,100 adults showed that 32% of them are smokers.Based on this sample,the 90% confidence interval for the proportion of all adults who are smokers,rounded to four decimal places,is:
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33
A random sample of 450 produced a sample proportion of 0.71.The 95% confidence interval for the population proportion,rounded to four decimal places,is:
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34
A sample of 25 elements produced a mean of 123.4 and a standard deviation of 18.32.Assuming that the population has a normal distribution,the 90% confidence interval for the population mean,rounded to two decimal places,is:
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35
A company wants to estimate,at a 95% confidence level,the proportion of all families who own its product.A preliminary sample showed that 30.0% of the families in this sample own this company's product.The sample size that would limit the margin of error to be within 0.045 of the population proportion is:
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36
In a random sample of 562 items produced by a machine,the quality control staff found 6.6% to be defective.Based on this sample,the 95% confidence interval for the proportion of defective items in all items produced by this machine,rounded to four decimal places,is:
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37
A random sample of 23 tourists who visited Hawaii this summer spent an average of $1,456.0 on this trip with a standard deviation of $263.00.Assuming that the money spent by all tourists who visit Hawaii has an approximate normal distribution,the 95% confidence interval for the average amount of money spent by all tourists who visit Hawaii,rounded to two decimal places,is:
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38
A researcher wants to estimate the mean age of all Business Week readers at a 99% confidence level.She wants the margin of error to be within 3.1 years of the population mean.The standard deviation of ages of all Business Week readers is 10.04 years.The sample size that will yield a margin of error within 3.1 of the population mean is:
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39
A random sample of 8 houses selected from a city showed that the mean size of these houses is 1,881.0 square feet with a standard deviation of 328.00 square feet.Assuming that the sizes of all houses in this city have an approximate normal distribution,the 90% confidence interval for the mean size of all houses in this city,rounded to two decimal places,is:
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40
A company wants to estimate the mean net weight of all 32-ounce packages of its Yummy Taste cookies at a 95% confidence level.The margin of error is to be within 0.025 ounces of the population mean.The population standard deviation is 0.096 ounces.The sample size that will yield a margin of error within 0.025 ounces of the population mean is:
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41
A company wants to estimate,at a 95% confidence level,the proportion of all families who own its product.The most conservative estimate of the sample size that would limit the margin of error to be within 0.046 of the population proportion is:
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42
Each employee of a large company is encouraged to contribute,through payroll deduction,to an international charity.Annual contributions per employee follow (approximately)a normal distribution.You take a random sample of 25 employees and find that the sample mean annual contribution per employee is $501 with a standard deviation of $17.00.What are the boundaries for a 99% confidence interval for the population mean,rounded to two decimal places?
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43
True or False.The statement: "The 90% confidence interval for the mean is (29.83 ,50.1)." can be interpreted to mean that the probability that the mean lies in the range (29.83 ,50.1)is 90%.
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44
The Eks Survey Company employs 2000 people to conduct telephone surveys.Because many people don't like to answer such surveys,many "hang-ups" (whereby the person hangs up without completing the survey)occur.The owner of Eks wants to determine the mean number of "hang-ups" per employee on a particular day,using 95% confidence.He samples 50 employees,and finds that the mean number of "hang-ups" on that day was 41.0.Suppose that the standard deviation of the number of "hang-ups" for all employees is 21.8 What is the value of the margin of error? (round to four decimal places)
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45
Which of the following is not part of the procedure for estimating the value of a population parameter?
A)Selecting a sample
B)Collecting the required information from the members of the sample
C)Calculating the value of the sample statistic
D)Calculating the exact value of the corresponding population parameter
A)Selecting a sample
B)Collecting the required information from the members of the sample
C)Calculating the value of the sample statistic
D)Calculating the exact value of the corresponding population parameter
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46
The Labor Bureau wants to estimate,at a 90% confidence level,the proportion of all households that receive welfare.The most conservative estimate of the sample size that would limit the margin of error to be within 0.030 of the population proportion is:
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47
In a random sample of 53 items produced by a machine,the quality control staff found 5 of them to be defective.Calculate the point estimate of the population proportion of defective items.Round to 4 decimal places.
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48
Which of the following is not an acceptable condition for using the t distribution to make a confidence interval for
?
A)The population from which the sample is drawn is right-skewed
B)The population from which the sample is drawn is normal
C)The population standard deviation is unknown
D)The population distribution has a mean of zero

A)The population from which the sample is drawn is right-skewed
B)The population from which the sample is drawn is normal
C)The population standard deviation is unknown
D)The population distribution has a mean of zero
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49
The correct formula for the limits of a confidence interval is:
A)
B)
C)
D)
A)

B)

C)

D)

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50
A random sample of 354 persons showed that 306 do not have health insurance.Calculate the point estimate of the population proportion of persons who do not have health insurance.Round to 4 decimal places.
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51
A scientist is estimating the mean lifetime of a newly-discovered insect.From a sample of 88 insects,she finds a sample mean of 49.2 days.Suppose that the population standard deviation of all lifetimes is 2.500 days.What are the boundaries for a 90% confidence interval for the mean lifetime of the insect,rounded to two decimal places?
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52
Determine the sample size n that is required for estimating the population mean.The population standard deviation
and the desired margin of error are specified.
94% margin of error 3
A)8,836
B)8,836
C)8,835
D)8,837


A)8,836
B)8,836
C)8,835
D)8,837
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53
The Labor Bureau wants to estimate,at a 90% confidence level,the proportion of all households that receive welfare.A preliminary sample showed that 18.5% of households in this sample receive welfare.The sample size that would limit the margin of error to be within 0.036 of the population proportion is:
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54
An advisor to the mayor of a large city wants to estimate,within 2.450 minutes,the mean travel time to work for all employees who work within the city limits.He knows that the standard deviation of all travel times is 11.35 minutes.He also wants to achieve a 95% confidence interval.He will poll a random sample of city employees.How many employees should he poll?
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55
You are estimating the mean waiting time in line at a particular fast-food restaurant.You ask 30 customers,at varying times of the day,how long they waited in line before placing their order.You then take the average of these values and use this average to estimate the mean waiting time for all customers.The average of the 30 values is an example of a(n):
A)Chebyshev estimate
B)point estimate
C)interval estimate
D)confidence estimate
A)Chebyshev estimate
B)point estimate
C)interval estimate
D)confidence estimate
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56
An employee of the College Board analyzed the mathematics section of the SAT for 97 students and finds
= 30.2 and s = 13.0.She reports that a 97% confidence interval for the mean number of correct answers is (27.336,33.064).Does the interval (27.336,33.064)cover the true mean?
Which of the following alternatives is the best answer for the above question?
A)Yes,(27.336,33.064)covers the true mean.
B)No,(27.336,33.064)does not cover the true mean.
C)We will never know whether (27.336,33.064)covers the true mean.
D)The true mean will never be in (27.336,33.064).

Which of the following alternatives is the best answer for the above question?
A)Yes,(27.336,33.064)covers the true mean.
B)No,(27.336,33.064)does not cover the true mean.
C)We will never know whether (27.336,33.064)covers the true mean.
D)The true mean will never be in (27.336,33.064).
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57
A t distribution has a standard deviation of
.If the standard deviation is equal to 1.1055,what is the value of the t critical value for a 90% confidence interval?

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58
We are using the mean of a sample as a point estimate for the mean of a normal distribution with a standard deviation of 5.The margin of error,with 95% confidence,for this estimate is 0.860.What is the sample size?
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59
In a 1997 poll of 261 male,married,upper-level managers conducted by Joy Schneer and Frieda Reitman for Fortune magazine,31% of the men stated that their wives worked either full-time or part-time (Fortune,March 17,1997).What are the boundaries for a 99% confidence interval for p,the proportion of all male,married,upper-level managers whose wives work?
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60
Out of a sample of 639 gasoline purchases at a self-service gas station,544 were made with a credit or debit card.Obtain the predeterminated margin of error.Round your answer to three decimal places.
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