Deck 8: Inferences Based on a Single
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Deck 8: Inferences Based on a Single
1
A revenue department is under orders to reduce the time small business owners spend filling out pension form ABC-5500. Previously the average time spent on the form was 6.3 hours. In order to
Test whether the time to fill out the form has been reduced, a sample of 48 small business owners
Who annually complete the form was randomly chosen, and their completion times recorded. The
Mean completion time for ABC-5500 form was 5.7 hours with a standard deviation of 1.8 hours. In
Order to test that the time to complete the form has been reduced, state the appropriate null and
Alternative hypotheses.
Test whether the time to fill out the form has been reduced, a sample of 48 small business owners
Who annually complete the form was randomly chosen, and their completion times recorded. The
Mean completion time for ABC-5500 form was 5.7 hours with a standard deviation of 1.8 hours. In
Order to test that the time to complete the form has been reduced, state the appropriate null and
Alternative hypotheses.

B
2
An insurance company sets up a statistical test with a null hypothesis that the average time for processing a claim is 7 days, and an alternative hypothesis that the average time for processing a
Claim is greater than 7 days. After completing the statistical test, it is concluded that the average
Time exceeds 7 days. However, it is eventually learned that the mean process time is really 7 days.
What type of error occurred in the statistical test?
A)Type II error
B)No error occurred in the statistical sense.
C)Type III error
D)Type I error
Claim is greater than 7 days. After completing the statistical test, it is concluded that the average
Time exceeds 7 days. However, it is eventually learned that the mean process time is really 7 days.
What type of error occurred in the statistical test?
A)Type II error
B)No error occurred in the statistical sense.
C)Type III error
D)Type I error
D
3

To determine if the mean yield for the soybeans differs from 528 bushels per acre,
we test:
we test:

4
The null hypothesis represents the status quo to the party performing the sampling experiment.
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5
How many tissues should a package of tissues contain? Researchers have determined that a person uses an average of 68 tissues during a cold. Suppose a random sample of 2500 people yielded the
Following data on the number of tissues used during a cold: x = 55, s = 23. Identify the null and
Alternative hypothesis for a test to determine if the mean number of tissues used during a cold is
Less than 68.
A)H0: μ = 68 vs. Ha: μ > 68
B)H0: μ = 68 vs. Ha: μ < 68
C)H0: μ > 68 vs. Ha: μ ≤ 68
D)H0: μ = 68 vs. Ha: μ ≠ 68
Following data on the number of tissues used during a cold: x = 55, s = 23. Identify the null and
Alternative hypothesis for a test to determine if the mean number of tissues used during a cold is
Less than 68.
A)H0: μ = 68 vs. Ha: μ > 68
B)H0: μ = 68 vs. Ha: μ < 68
C)H0: μ > 68 vs. Ha: μ ≤ 68
D)H0: μ = 68 vs. Ha: μ ≠ 68
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8
The State Association of Retired Teachers has recently taken flak from some of its members regarding the poor choice of the associationʹs name. The associationʹs by-laws require that more
Than 60 percent of the association must approve a name change. Rather than convene a meeting, it
Is first desired to use a sample to determine if meeting is necessary. Suppose the association
Decided to conduct a test of hypothesis using the following null and alternative hypotheses:
Define a Type I Error in the context of this problem.
A)They conclude that exactly 60% of the association wants a name change when that is, in fact, true.
B)They conclude that more than 60% of the association wants a name change when, in fact, that is not true.
C)They conclude that more than 60% of the association wants a name change when that is, in fact, true.
D)They conclude that exactly 60% of the association wants a name change when, in fact, that is not true.
Than 60 percent of the association must approve a name change. Rather than convene a meeting, it
Is first desired to use a sample to determine if meeting is necessary. Suppose the association
Decided to conduct a test of hypothesis using the following null and alternative hypotheses:

A)They conclude that exactly 60% of the association wants a name change when that is, in fact, true.
B)They conclude that more than 60% of the association wants a name change when, in fact, that is not true.
C)They conclude that more than 60% of the association wants a name change when that is, in fact, true.
D)They conclude that exactly 60% of the association wants a name change when, in fact, that is not true.
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9
A method currently used by doctors to screen women for possible breast cancer fails to
detect cancer in 20% of women who actually have the disease. A new method has been
developed that researchers hope will be able to detect cancer more accurately. A random
sample of 90 women known to have breast cancer were screened using the new method.
Of these, the new method failed to detect cancer in eight. Specify the null and alternative
hypotheses that the researchers wish to test.
detect cancer in 20% of women who actually have the disease. A new method has been
developed that researchers hope will be able to detect cancer more accurately. A random
sample of 90 women known to have breast cancer were screened using the new method.
Of these, the new method failed to detect cancer in eight. Specify the null and alternative
hypotheses that the researchers wish to test.
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12
A __________ is a numerical quantity computed from the data of a sample and is used in reaching a decision on whether or not to reject the null hypothesis.
A)significance level
B)critical value
C)parameter
D)test statistic
A)significance level
B)critical value
C)parameter
D)test statistic
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19
A local eat-in pizza restaurant wants to investigate the possibility of starting to deliver pizzas. The owner of the store has determined that home delivery will be successful only if the average time
Spent on a delivery does not exceed 38 minutes. The owner has randomly selected 27 customers
And delivered pizzas to their homes. What hypotheses should the owner test to demonstrate that
The pizza delivery will not be successful?
Spent on a delivery does not exceed 38 minutes. The owner has randomly selected 27 customers
And delivered pizzas to their homes. What hypotheses should the owner test to demonstrate that
The pizza delivery will not be successful?

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20
The alternative hypothesis is accepted as true unless there is overwhelming evidence that it is false.
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21
Solve the problem.


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23
In a test of hypothesis, the sampling distribution of the test statistic is calculated under the
assumption that the alternative hypothesis is true.
assumption that the alternative hypothesis is true.
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24
For the given rejection region, sketch the sampling distribution for z and indicate the location of the rejection region.
z < -1.96
z < -1.96
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25
For the given rejection region, sketch the sampling distribution for z and indicate the location of the rejection region.
z < -2.33 or z > 2.33
z < -2.33 or z > 2.33
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27
Solve the problem.
A rejection region is established in each tail of the sampling distribution for a two-tailed test.
A rejection region is established in each tail of the sampling distribution for a two-tailed test.
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29
For the given rejection region, sketch the sampling distribution for z and indicate the location of the rejection region.
z < -1.28
z < -1.28
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30
Solve the problem.
Consider the following printout.
Consider the following printout.

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32
Solve the problem.


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33
A Type I error occurs when we accept a false null hypothesis.
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34
For the given rejection region, sketch the sampling distribution for z and indicate the location of the rejection region.
z > 2.575
z > 2.575
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36
For the given rejection region, sketch the sampling distribution for z and indicate the location of the rejection region.
z < -1.96 or z > 1.96
z < -1.96 or z > 1.96
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37
The rejection region refers to the values of the test statistic for which we will reject the alternative
hypothesis.
hypothesis.
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38
The State Association of Retired Teachers has recently taken flak from some of its members regarding the poor choice of the associationʹs name. The associationʹs by-laws require that more
Than 60 percent of the association must approve a name change. Rather than convene a meeting, it
Is first desired to use a sample to determine if meeting is necessary. Suppose the association
Decided to conduct a test of hypothesis using the following null and alternative hypotheses:
Define a Type II Error in the context of this problem.
A)They conclude that exactly 60% of the association wants a name change when, in fact, that is not true.
B)They conclude that more than 60% of the association wants a name change when that is, in fact, true.
C)They conclude that more than 60% of the association wants a name change when, in fact, that is not true.
D)They conclude that exactly 60% of the association wants a name change when that is, in fact, true.
Than 60 percent of the association must approve a name change. Rather than convene a meeting, it
Is first desired to use a sample to determine if meeting is necessary. Suppose the association
Decided to conduct a test of hypothesis using the following null and alternative hypotheses:

A)They conclude that exactly 60% of the association wants a name change when, in fact, that is not true.
B)They conclude that more than 60% of the association wants a name change when that is, in fact, true.
C)They conclude that more than 60% of the association wants a name change when, in fact, that is not true.
D)They conclude that exactly 60% of the association wants a name change when that is, in fact, true.
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40
Solve the problem.


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41

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44
A bottling company produces bottles that hold 12 ounces of liquid. Periodically, the company gets complaints that their bottles are not holding enough liquid. To test this claim, the bottling
Company randomly samples 64 bottles and finds the average amount of liquid held by the bottles
Is 11.9155 ounces with a standard deviation of 0.40 ounce. Suppose the p-value of this test is
0.0455. State the proper conclusion.
Company randomly samples 64 bottles and finds the average amount of liquid held by the bottles
Is 11.9155 ounces with a standard deviation of 0.40 ounce. Suppose the p-value of this test is
0.0455. State the proper conclusion.

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48
Consider the following printout. 

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49
A consumer product magazine recently ran a story concerning the increasing prices of digital cameras. The story stated that digital camera prices dipped a couple of years ago, but now are
Beginning to increase in price because of added features. According to the story, the average price
Of all digital cameras a couple of years ago was $215.00. A random sample of cameras was recently
Taken and entered into a spreadsheet. It was desired to test to determine if that average price of all
Digital cameras is now more than $215.00. The information was entered into a spreadsheet and the
Following printout was obtained:
Beginning to increase in price because of added features. According to the story, the average price
Of all digital cameras a couple of years ago was $215.00. A random sample of cameras was recently
Taken and entered into a spreadsheet. It was desired to test to determine if that average price of all
Digital cameras is now more than $215.00. The information was entered into a spreadsheet and the
Following printout was obtained:

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50

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51
The smaller the p-value in a test of hypothesis, the more significant the results are.
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52
A large university is interested in learning about the average time it takes students to drive to campus. The university sampled 238 students and asked each to provide the amount of time they
Spent traveling to campus. This variable, travel time, was then used conduct a test of hypothesis.
The goal was to determine if the average travel time of all the universityʹs students differed from
20 minutes. Suppose the large-sample test statistic was calculated to be z = 2.14. Find the p-value
For this test of hypothesis.
A)p = 0.4838
B)p = 0.9838
C)p = 0.0324
D)p = 0.0162
Spent traveling to campus. This variable, travel time, was then used conduct a test of hypothesis.
The goal was to determine if the average travel time of all the universityʹs students differed from
20 minutes. Suppose the large-sample test statistic was calculated to be z = 2.14. Find the p-value
For this test of hypothesis.
A)p = 0.4838
B)p = 0.9838
C)p = 0.0324
D)p = 0.0162
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54
A large university is interested in learning about the average time it takes students to drive to campus. The university sampled 238 students and asked each to provide the amount of time they
Spent traveling to campus. This variable, travel time, was then used to create a confidence interval
And to conduct a test of hypothesis, both of which are shown in the printout below.
Spent traveling to campus. This variable, travel time, was then used to create a confidence interval
And to conduct a test of hypothesis, both of which are shown in the printout below.

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Based on the information in the screen below, what would you conclude in the test of 

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60
Solve the problem.
The rejection region for a two-tailed test with α = .05 is -1.96 < z < 1.96.
The rejection region for a two-tailed test with α = .05 is -1.96 < z < 1.96.
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61
Consider the following printout. 

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63
A large university is interested in learning about the average time it takes students to drive to campus. The university sampled 238 students and asked each to provide the amount of time they
Spent traveling to campus. This variable, travel time, was then used conduct a test of hypothesis.
The goal was to determine if the average travel time of all the universityʹs students differed from
20 minutes. Suppose the sample mean and sample standard deviation were calculated to be 23.2
And 20.26 minutes, respectively. Calculate the value of the test statistic to be used in the test.
A)z = 2.437
B)z = 0.173
C)z = 2.551
D)z = 37.59
Spent traveling to campus. This variable, travel time, was then used conduct a test of hypothesis.
The goal was to determine if the average travel time of all the universityʹs students differed from
20 minutes. Suppose the sample mean and sample standard deviation were calculated to be 23.2
And 20.26 minutes, respectively. Calculate the value of the test statistic to be used in the test.
A)z = 2.437
B)z = 0.173
C)z = 2.551
D)z = 37.59
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69
A local eat-in pizza restaurant wants to investigate the possibility of starting to deliver pizzas. The owner of the store has determined that home delivery will be successful only if the average time
Spent on a delivery does not exceed 27 minutes. The owner has randomly selected 17 customers
And delivered pizzas to their homes in order to test whether the mean delivery time actually
Exceeds 27 minutes. What assumption is necessary for this test to be valid?
A)The population variance must equal the population mean.
B)The sample mean delivery time must equal the population mean delivery time.
C)None. The Central Limit Theorem makes any assumptions unnecessary.
D)The population of delivery times must have a normal distribution.
Spent on a delivery does not exceed 27 minutes. The owner has randomly selected 17 customers
And delivered pizzas to their homes in order to test whether the mean delivery time actually
Exceeds 27 minutes. What assumption is necessary for this test to be valid?
A)The population variance must equal the population mean.
B)The sample mean delivery time must equal the population mean delivery time.
C)None. The Central Limit Theorem makes any assumptions unnecessary.
D)The population of delivery times must have a normal distribution.
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71
The scores on a standardized test are reported by the testing agency to have a mean of 75.
Based on his personal observations, a school guidance counselor believes the mean score is
much higher. He collects the following scores from a sample of 50 randomly chosen
students who took the test.
Based on his personal observations, a school guidance counselor believes the mean score is
much higher. He collects the following scores from a sample of 50 randomly chosen
students who took the test.

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73
A consumer product magazine recently ran a story concerning the increasing prices of digital cameras. The story stated that digital camera prices dipped a couple of years ago, but now are
Beginning to increase in price because of added features. According to the story, the average price
Of all digital cameras a couple of years ago was $215.00. A random sample of n = 200 cameras was
Recently taken and entered into a spreadsheet. It was desired to test to determine if that average
Price of all digital cameras is now more than $215.00. Find the large-sample rejection region
Appropriate for this test if we are using

Beginning to increase in price because of added features. According to the story, the average price
Of all digital cameras a couple of years ago was $215.00. A random sample of n = 200 cameras was
Recently taken and entered into a spreadsheet. It was desired to test to determine if that average
Price of all digital cameras is now more than $215.00. Find the large-sample rejection region
Appropriate for this test if we are using


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74
The scores on a standardized test are reported by the testing agency to have a mean of 70.
Based on his personal observations, a school guidance counselor believes the mean score is
much higher. He collects the following scores from a sample of 50 randomly chosen
students who took the test.
Based on his personal observations, a school guidance counselor believes the mean score is
much higher. He collects the following scores from a sample of 50 randomly chosen
students who took the test.

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75
A supermarket sells rotisserie chicken at a fixed price per chicken rather than by the
weight of the chicken. The store advertises that the average weight of their chickens is 4.6
pounds. A random sample of 30 of the storeʹs chickens yielded the weights (in pounds)
shown below.
weight of the chicken. The store advertises that the average weight of their chickens is 4.6
pounds. A random sample of 30 of the storeʹs chickens yielded the weights (in pounds)
shown below.

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80
A supermarket sells rotisserie chicken at a fixed price per chicken rather than by the
weight of the chicken. The store advertises that the average weight of their chickens is 4.6
pounds. A random sample of 30 of the storeʹs chickens yielded the weights (in pounds)
shown below.
weight of the chicken. The store advertises that the average weight of their chickens is 4.6
pounds. A random sample of 30 of the storeʹs chickens yielded the weights (in pounds)
shown below.

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