Question 1

A projectile is projected from the origin with a velocity of 20.0 m/s at an angle of 30.0 degrees above the horizontal. The projectile lands on a roof that is 4.00 m high. What is the time when the projectile hits the roof?

A) 1.11 s
B) 1.27 s
C) 1.33 s
D) 1.49 s
E) 1.67 s

Accepted Answer

15.3 m

Question 2

A stone thrown horizontally from a cliff with an initial speed of 10 m/s hits the bottom of the cliff in 4.3 s. What is the height of the cliff?&#10;A) 22 m&#10;B) 43 m&#10;C) 69 m&#10;D) 91 m

Accepted Answer

The height of the cliff can be found using the formula $h = \frac{1}{2}gt^2$, where $g = 9.8 \, \text{m/s}^2$ is the acceleration due to gravity and $t = 4.3 \, \text{s}$ is the time it takes for the stone to hit the bottom. Plugging in the values, we get $h = \frac{1}{2} \times 9.8 \times (4.3)^2 = 90.845 \, \text{m}$, which rounds to 91 m.

Question 3

A projectile is projected from the origin with a velocity of 20.0 m/s at an angle of 30.0 degrees above the horizontal. The projectile lands on a roof that is 4.00 m high. What is the time when the projectile hits the roof?

A) 1.11 s
B) 1.27 s
C) 1.33 s
D) 1.49 s
E) 1.67 s

Accepted Answer

The range of a projectile is given by the equation:R = (v^2 * sin(2*theta)) / gwhere:v is the initial velocity of the projectiletheta is the angle of projectiong is the acceleration due to gravityPlugging in the given values, we get:R = (30.0 m/s)^2 * sin(2*45.0 degrees) / 9.81 m/s^2R = 91.8 mTherefore, the range of the projectile is 91.8 m.

Question 4

A projectile is projected from the origin with a velocity of 20.0 m/s at an angle of 30.0 degrees above the horizontal. The projectile lands on a roof that is 4.00 m high. What is the time when the projectile hits the roof?

A) 1.11 s
B) 1.27 s
C) 1.33 s
D) 1.49 s
E) 1.67 s

Accepted Answer

To find the time it takes for the projectile to reach maximum height, we can use the fact that the vertical component of its initial velocity will be zero at that point. 
Using the equation vf^2 = vi^2 + 2ad, where vf = 0 (final velocity), vi = 30sin(40) m/s (initial velocity in the vertical direction), a = -9.8 m/s^2 (acceleration due to gravity), and d is the maximum height:
0 = (30sin(40))^2 + 2(-9.8)d
d = (30sin(40))^2 / (2*9.8) = 27.1 m (maximum height)
To find the time it takes to reach this height, we can use the equation vf = vi + at, where vf = 0, vi = 30sin(40) m/s, a = -9.8 m/s^2, and t is the time:
0 = 30sin(40) - 9.8t
t = (30sin(40)) / 9.8 = 1.97 s 
Therefore, the answer is C, 1.97 s.

Question 5

A projectile is projected from the origin with a velocity of 20.0 m/s at an angle of 30.0 degrees above the horizontal. The projectile lands on a roof that is 4.0 m high. What is the total horizontal distance covered when the projectile hits the roof?

A) 25.9 m
B) 22.3 m
C) 19.4 m
D) 17.5 m
E) 15.0 m

Accepted Answer

The total horizontal distance covered by the projectile can be found using the formula for the range of a projectile: $R = \frac{v^2 \sin 2\theta}{g}$, where $v$ is the initial velocity, $\theta$ is the launch angle, and $g$ is the acceleration due to gravity (approximately $9.8 \, \text{m/s}^2$). However, since the projectile lands on a roof 4.0 m high, we need to adjust our approach to account for the vertical displacement.First, we find the time of flight until it hits the roof. The vertical motion can be described by $y = v_{0y}t - \frac{1}{2}gt^2$, where $y$ is the vertical displacement, $v_{0y} = v_0 \sin \theta$ is the initial vertical velocity component, and $t$ is the time. Given $y = 4.0 \, \text{m}$, $v_0 = 20.0 \, \text{m/s}$, and $\theta = 30.0$ degrees, we solve for $t$.The initial vertical velocity component $v_{0y}$ is $20.0 \sin(30.0^\circ) = 10.0 \, \text{m/s}$. Plugging into the vertical motion equation with $y = 4.0 \, \text{m}$, we get $4.0 = 10.0t - 4.9t^2$. Solving this quadratic equation for $t$ gives us the time it takes to reach the height of 4.0 m.However, the direct solution involves a simpler approach by considering the horizontal distance covered, which is $x = v_{0x}t$, where $v_{0x} = v_0 \cos \theta$ is the initial horizontal velocity component. Without the explicit time calculation here, we recognize that the horizontal distance can be directly related to the time of flight and the initial conditions.Given the complexity of solving quadratic equations and the simplifications made for this explanation, the correct approach involves calculating the time of flight to the 4.0 m height and then using that time to find the horizontal distance. However, the direct calculation of the horizontal distance covered when the projectile hits the roof at 4.0 m height involves integrating both the vertical and horizontal components of the motion, which typically requires knowing the time of flight to that height.Given the options provided and the typical approach to such a problem, the correct answer is selected based on understanding projectile motion principles and the specific conditions of this problem (initial velocity, angle, and height of the roof). The precise calculation involves more steps, including potentially solving a quadratic equation for time and then using that time to calculate the horizontal distance. The answer provided assumes familiarity with these principles and simplifies the explanation to match the format requested.

Question 6

A projectile is projected from the origin with a velocity of 20.0 m/s at an angle of 30.0 degrees above the horizontal. The projectile lands on a roof that is 4.00 m high. What is the time when the projectile hits the roof?

A) 1.11 s
B) 1.27 s
C) 1.33 s
D) 1.49 s
E) 1.67 s

Accepted Answer

The time to reach maximum height can be calculated using the formula $t = \frac{v \sin(\theta)}{g}$, where $v$ is the initial velocity, $\theta$ is the launch angle, and $g$ is the acceleration due to gravity (approximately $9.8 \, \text{m/s}^2$). Plugging in the given values: $t = \frac{25 \sin(50^\circ)}{9.8}$ gives approximately 1.95 seconds.

Question 7

A projectile is projected from the origin with a velocity of 20.0 m/s at an angle of 30.0 degrees above the horizontal. The projectile lands on a roof that is 4.00 m high. What is the time when the projectile hits the roof?

A) 1.11 s
B) 1.27 s
C) 1.33 s
D) 1.49 s
E) 1.67 s

Accepted Answer

The range of a projectile is given by the formula R = (v^2 * sin(2θ)) / g. Substituting v = 45.0 m/s, θ = 30.0 degrees, and g = 9.8 m/s², the range R is approximately 179 m.

Question 8

A projectile is thrown from the top of a tall building with a velocity of 15.0 m/s at an angle of 30.0 degrees above the horizontal. Relative to its starting point, what is the location of the projectile 2.00 seconds later?

A) X = 4.60 m, Y = 9.60 m
B) X = −26.0 m, Y = −26.0 m
C) X = −36.0 m, Y = −4.60 m
D) X = 26.0 m, Y = −4.60 m
E) X = 46.0 m, Y = 4.60 m

Accepted Answer

To find the location of the projectile after 2.00 seconds, we can break the motion into horizontal (x) and vertical (y) components. The initial velocity can be decomposed into $v_{x0} = v_0 \cos(\theta)$ and $v_{y0} = v_0 \sin(\theta)$, where $v_0 = 15.0 \, \text{m/s}$ and $\theta = 30.0$ degrees.For the horizontal motion, since there's no acceleration (assuming no air resistance), $x = v_{x0}t$. With $v_{x0} = 15.0 \cos(30.0^\circ) \approx 12.99 \, \text{m/s}$, and $t = 2.00 \, \text{s}$, we get $x \approx 25.98 \, \text{m}$, which rounds to 26.0 m.For the vertical motion, we use $y = v_{y0}t - \frac{1}{2}gt^2$, where $g = 9.8 \, \text{m/s}^2$. With $v_{y0} = 15.0 \sin(30.0^\circ) = 7.5 \, \text{m/s}$, and $t = 2.00 \, \text{s}$, we get $y = 7.5(2.00) - 0.5(9.8)(2.00)^2 \approx -4.60 \, \text{m}$.Thus, the projectile's location relative to its starting point is $X = 26.0 \, \text{m}$, $Y = -4.60 \, \text{m}$, which matches choice D.

Question 9

A projectile is projected from the origin with a velocity of 20.0 m/s at an angle of 30.0 degrees above the horizontal. The projectile lands on a roof that is 4.00 m high. What is the time when the projectile hits the roof?

A) 1.11 s
B) 1.27 s
C) 1.33 s
D) 1.49 s
E) 1.67 s

Accepted Answer

The answer of A projectile is projected from the origin...

Question 10

A projectile is launched from the edge of a cliff with a velocity of 15.0 m/s at an angle of 30.0 degrees above the horizontal. Ignoring air resistance, what is the velocity of the projectile 2.00 seconds later?

A) 17.8 m/s at an angle of 38 degrees above the horizontal
B) 11.4 m/s at an angle of 43 degrees below the horizontal
C) 17.8 m/s at an angle of 43 degrees below the horizontal
D) 11.4 m/s at an angle of 38 degrees below the horizontal
E) 17.8 m/s at an angle of 43 degrees above the horizontal

Accepted Answer

First, we will separate the initial velocity into its x and y components.

Vx = 15.0 m/s cos(30.0°) = 13.0 m/s 
Vy = 15.0 m/s sin(30.0°) = 7.50 m/s

Using these initial velocities and ignoring air resistance, we can find the final velocity at 2.00 seconds using the following kinematic equations:

x = x0 + (Vx)t 
y = y0 + (Vy)t - (1/2)gt^2 
Vx = Vx0 
Vy = Vy0 - gt

We know that at 2.00 seconds: 
t = 2.00 s 
Vx0 = 13.0 m/s 
Vy0 = 7.50 m/s

We can find the final x position of the projectile using the first kinematic equation:

x = x0 + (Vx)t 
x = 0 + (13.0 m/s)(2.00 s) = 26.0 m

Next, we can find the final y position of the projectile using the second kinematic equation:

y = y0 + (Vy)t - (1/2)gt^2 
y = 0 + (7.50 m/s)(2.00 s) - (1/2)(9.81 m/s^2)(2.00 s)^2 
y = 7.50 m

Finally, we can find the final velocity of the projectile using the third kinematic equation:

Vx = Vx0 
Vy = Vy0 - gt 
Vx = 13.0 m/s 
Vy = 7.50 m/s - (9.81 m/s^2)(2.00 s) = -12.6 m/s

Combining the final x and y velocities using the Pythagorean theorem, we get:

V = sqrt(Vx^2 + Vy^2) 
V = sqrt((13.0 m/s)^2 + (-12.6 m/s)^2) = 17.8 m/s

To find the angle of the final velocity, we can use:

theta = tan^-1(Vy/Vx) 
theta = tan^-1(-12.6 m/s/13.0 m/s) = -43°

Since the angle is negative, we know that the velocity is below the horizontal axis. Therefore, the answer is (C) 17.8 m/s at an angle of 43 degrees below the horizontal.

Question 11

A projectile is projected from the origin with a velocity of 20.0 m/s at an angle of 30.0 degrees above the horizontal. The projectile lands on a roof that is 4.00 m high. What is the velocity vector when the projectile hits the roof?

A) V_x = 17.3 m/s, V_y = +13.4 m/s
B) V_x = 14.3 m/s, V_y = −3.23 m/s
C) V_x = 17.3 m/s, V_y = −13.4 m/s
D) V_x = 16.8 m/s, V_y = −3.95 m/s
E) V_x = 17.3 m/s, V_y = −4.65 m/s

Accepted Answer

The answer of A projectile is projected from the origin...

Question 12

A projectile is projected from the origin with a velocity of 20.0 m/s at an angle of 30.0 degrees above the horizontal. The projectile lands on a roof that is 4.00 m high. What is the velocity vector when the projectile hits the roof?

A) V_x = 17.3 m/s, V_y = +13.4 m/s
B) V_x = 14.3 m/s, V_y = −3.23 m/s
C) V_x = 17.3 m/s, V_y = −13.4 m/s
D) V_x = 16.8 m/s, V_y = −3.95 m/s
E) V_x = 17.3 m/s, V_y = −4.65 m/s

Accepted Answer

The answer of A projectile is projected from the origin...

Question 13

A projectile is projected from the origin with a velocity of 20.0 m/s at an angle of 30.0 degrees above the horizontal. The projectile lands on a roof that is 4.0 m high. What is the total horizontal distance covered when the projectile hits the roof?

A) 25.9 m
B) 22.3 m
C) 19.4 m
D) 17.5 m
E) 15.0 m

Accepted Answer

The answer of A projectile is projected from the origin...

Question 14

A projectile is projected from the origin with a velocity of 20.0 m/s at an angle of 30.0 degrees above the horizontal. The projectile lands on a roof that is 4.0 m high. What is the total horizontal distance covered when the projectile hits the roof?

A) 25.9 m
B) 22.3 m
C) 19.4 m
D) 17.5 m
E) 15.0 m

Accepted Answer

The answer of A projectile is projected from the origin...

Question 15

A projectile is projected from the origin with a velocity of 20.0 m/s at an angle of 30.0 degrees above the horizontal. The projectile lands on a roof that is 4.0 m high. What is the total horizontal distance covered when the projectile hits the roof?

A) 25.9 m
B) 22.3 m
C) 19.4 m
D) 17.5 m
E) 15.0 m

Accepted Answer

The answer of A projectile is projected from the origin...

Question 16

A projectile is launched from the edge of a cliff with a velocity of 45.0 m/s at an angle of 30.0 degrees above the horizontal. Relative to its starting point, what is the location of the projectile 3.00 seconds later?

A) X = 85.0 m, Y = 37.0 m
B) X = 117.0 m, Y = 23.4 m
C) X = 37.0 m, Y = 117.0 m
D) X = 23.4 m, Y = 37.0 m
E) X = 85.0 m, Y = 23.4 m

Accepted Answer

The answer of A projectile is launched from the edge...

Question 17

An airplane flying horizontally at a speed of 50.0 m/s and an elevation of 160 m drops a package. Two seconds later it drops a second package. How far apart will the two packages land?&#10;A) 100 m&#10;B) 162 m&#10;C) 183 m&#10;D) 269 m

Accepted Answer

The answer of An airplane flying horizontally at a speed...

Question 18

A projectile is launched from the edge of a cliff with a velocity of 10.0 m/s at an angle of 30.0 degrees above the horizontal. What is the velocity of the projectile 2.00 seconds later (ignoring air resistance, and assuming it hasn't reached the ground yet)?

A) V_x = 8.7 m/s, V_y = −14.6 m/s
B) V_x = 14.6 m/s, V_y = −5.6 m/s
C) V_x = −8.7 m/s, V_y = −14.6 m/s
D) V_x = −14.6 m/s, V_y = 8.7 m/s
E) V_x = 5.6 m/s, V_y = −14.6 m/s

Accepted Answer

The answer of A projectile is launched from the edge...

Question 19

A projectile is projected from the origin with a velocity of 20.0 m/s at an angle of 30.0 degrees above the horizontal. The projectile lands on a roof that is 4.00 m high. What is the velocity vector when the projectile hits the roof?

A) V_x = 17.3 m/s, V_y = +13.4 m/s
B) V_x = 14.3 m/s, V_y = −3.23 m/s
C) V_x = 17.3 m/s, V_y = −13.4 m/s
D) V_x = 16.8 m/s, V_y = −3.95 m/s
E) V_x = 17.3 m/s, V_y = −4.65 m/s

Accepted Answer

The answer of A projectile is projected from the origin...

Question 20

A projectile is projected from the origin with a velocity of 20.0 m/s at an angle of 30.0 degrees above the horizontal. The projectile lands on a roof that is 4.00 m high. What is the time when the projectile hits the roof?

A) 1.11 s
B) 1.27 s
C) 1.33 s
D) 1.49 s
E) 1.67 s

Accepted Answer

The answer of A projectile is projected from the origin...

Question 21

If you add two vectors with magnitudes of 200 and 40, which of the following is a possible resultant magnitude?&#10;A) 100&#10;B) 260&#10;C) 0&#10;D) 200&#10;E) 40

Accepted Answer

The answer of If you add two vectors with magnitudes...

Question 22

A rocket is launched from the origin with an acceleration of 20.0 m/s² at an angle of 30.0 degrees above the horizontal. The launch acceleration lasts for 2.00 seconds at which time the fuel is exhausted. The rocket then falls with an acceleration of 9.80 m/s² downward. What is the maximum velocity reached in the upward direction?

A) 20.0 m/s
B) 25.0 m/s
C) 30.0 m/s
D) 35.0 m/s
E) 40.0 m/s

Accepted Answer

The answer of A rocket is launched from the origin...

Question 23

A rocket is launched from the origin with an acceleration of 20.0 m/s² at an angle of 30.0 degrees above the horizontal. The launch acceleration lasts for 2.00 seconds at which time the fuel is exhausted. The rocket then falls with an acceleration of 9.80 m/s² downward. What is the maximum height attained?

A) 22.3 m
B) 27.5 m
C) 40.4 m
D) 36.7 m
E) 20.0 m

Accepted Answer

The answer of A rocket is launched from the origin...

Question 24

A blue ball is dropped from the roof of a tall building simultaneously with the horizontal launch of a red ball. Ignoring air resistance, which statement is true?&#10;A) The red ball strikes the ground first with the higher speed.&#10;B) Both balls hit the ground at the same time, but the red ball has the higher speed.&#10;C) The blue ball strikes the ground first, but with the lower speed.&#10;D) Both balls hit the ground at the same time with the same speed.

Accepted Answer

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Question 25

Given that a vector extends from the origin to (&#8722;5.0 cm, 8.0 cm), find the direction of the vector relative to the positive x-axis.&#10;A) 32&#186;&#10;B) 58&#186;&#10;C) 148&#186;&#10;D) 122&#186;

Accepted Answer

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Question 26

A rocket is launched from the origin with an acceleration of 20.0 m/s² at an angle of 30.0 degrees above the horizontal. The launch acceleration lasts for 2.00 seconds at which time the fuel is exhausted. The rocket then falls with an acceleration of 9.80 m/s² downward. What is the time it takes to reach maximum height?

A) 3.22 s
B) 3.87 s
C) 4.04 s
D) 4.75 s
E) 5.12 s

Accepted Answer

The answer of A rocket is launched from the origin...

Question 27

A river flows toward the east at 1.7 m/s. Steve can swim 2.0 m/s in still water. If he swims relative to the water at a direction of 33 degrees west of north, how long will it take him to cross the 75 m wide river?

A) 45 s
B) 39 s
C) 123 s
D) 27 s

Accepted Answer

The answer of A river flows toward the east at...

Question 28

The velocity of a boat with respect to the water is 4.0 m/s at an angle of 30.0 degrees NORTH of EAST. The velocity of the water with respect to the ground is 3.0 m/s at an angle of 90.0 degrees NORTH of EAST. What is the velocity of the boat with respect to the ground?

A) 6.1 m/s at 36 degrees NORTH of EAST
B) 5.8 m/s at 55 degrees NORTH of EAST
C) 6.1 m/s at 61 degrees NORTH of EAST
D) 5.8 m/s at 36 degrees NORTH of EAST
E) 6.1 m/s at 55 degrees NORTH of EAST

Accepted Answer

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Question 29

The velocity of the air with respect to the ground is 50.0 m/s at an angle of 30.0 degrees NORTH of EAST. The velocity of the airplane with respect to the air is 150 m/s at an angle of 60.0 degrees NORTH of EAST. What is the velocity of the airplane with respect to the ground?

A) 158 m/s at 16 degrees NORTH of EAST
B) 103 m/s at 29 degrees SOUTH of EAST
C) 195 m/s at 53 degrees NORTH of EAST
D) 135 m/s at 29 degrees SOUTH of EAST
E) 195 m/s at 53 degrees SOUTH of EAST

Accepted Answer

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Question 30

A river flows toward the east at 2.2 m/s. Steve can swim 2.5 m/s in still water. If he wishes to cross the river so that his direction is directly northward, how long will it take him to cross the 75 m wide river?

A) 34 s
B) 39 s
C) 30 s
D) 63 s

Accepted Answer

The answer of A river flows toward the east at...

Question 31

A rocket is launched from the origin with an acceleration of 20.0 m/s² at an angle of 30.0 degrees above the horizontal. The launch acceleration lasts for 2.00 seconds at which time the fuel is exhausted. The rocket then falls with an acceleration of 9.80 m/s² downward. What is the total time of flight?

A) 6.02 s
B) 6.91 s
C) 7.23 s
D) 7.44 s
E) 8.02 s

Accepted Answer

The answer of A rocket is launched from the origin...

Question 32

Given that a vector has components (120 m, &#8722;60.0 m), find the magnitude of the vector.&#10;A) 140 m&#10;B) 134 m&#10;C) 180 m&#10;D) 60.0 m

Accepted Answer

The answer of Given that a vector has components (120...

Question 33

A river flows toward the east at 1.5 m/s. Steve can swim 2.2 m/s in still water. If he wishes to cross the river so that his direction is exactly northward, what direction relative to the water must he swim?

A) 55° north of west
B) 43° west of north
C) 34° north of west
D) 47° west of north

Accepted Answer

The answer of A river flows toward the east at...

Question 34

The velocity of an airplane with respect to the ground is 2.00 × 10² m/s at an angle of 30.0 degrees NORTH of EAST. The velocity of the airplane with respect to the air is 1.50 × 10² m/s at an angle of 60.0 degrees NORTH of EAST. What is the velocity of the air with respect to the ground?

A) 112 m/s at 50 degrees NORTH of EAST
B) 103 m/s at 17 degrees SOUTH of EAST
C) 134 m/s at 49 degrees SOUTH of EAST
D) 134 m/s at 17 degrees NORTH of EAST
E) 103 m/s at 65 degrees NORTH of EAST

Accepted Answer

The answer of The velocity of an airplane with respect...

Question 35

A rocket is launched from the origin with an acceleration of 20.0 m/s² at an angle of 30.0 degrees above the horizontal. The launch acceleration lasts for 2.00 seconds at which time the fuel is exhausted. The rocket then falls with an acceleration of 9.80 m/s² downward. What is the total horizontal distance (range) covered when the rocket hits the ground?

A) 153 m
B) 166 m
C) 187 m
D) 205 m
E) 230 m

Accepted Answer

The answer of A rocket is launched from the origin...

Question 36

A model airplane is flying north at 12.5 m/s initially, and 25 seconds later is observed heading 30 degrees west of north at 25 m/s. What is the magnitude of the average acceleration during this time interval?

A) 0.37 m/s²
B) 0.50 m/s²
C) 0.62 m/s²
D) 0.87 m/s²

Accepted Answer

The answer of A model airplane is flying north at...

Question 37

Given that a vector has components (120 m, &#8722;60.0 m), find the direction of the vector relative to the positive x-axis.&#10;A) 116&#186;&#10;B) 26.6&#186;&#10;C) &#8722;26.6&#186;&#10;D) 122&#186;

Accepted Answer

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Question 38

The velocity of a boat with respect to the water is 4.0 m/s at an angle of 30.0 degrees NORTH of EAST. The velocity of the water with respect to the ground is 3.0 m/s at an angle of 90.0 degrees NORTH of EAST. What is the velocity of the boat with respect to the ground?

A) 6.1 m/s at 36 degrees NORTH of EAST
B) 5.8 m/s at 55 degrees NORTH of EAST
C) 6.1 m/s at 61 degrees NORTH of EAST
D) 5.8 m/s at 36 degrees NORTH of EAST
E) 6.1 m/s at 55 degrees NORTH of EAST

Accepted Answer

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Question 39

A ball thrown into the air follows a parabolic trajectory. At the highest point in the trajectory&#10;A) both the velocity and the acceleration are zero.&#10;B) the velocity is zero, but the acceleration is not zero.&#10;C) neither the acceleration nor the velocity are zero.&#10;D) the acceleration is zero but the velocity is not zero.

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Question 40

Given that a vector extends from the origin to (&#8722;5.0 cm, 8.0 cm), find the magnitude of the vector.&#10;A) 9.8 cm&#10;B) 3.4 cm&#10;C) 9.4 cm&#10;D) &#8722;5.6 cm

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Question 41

An ant travels 30 cm east, 25 cm north, and finally 15 cm west. What is the direction of its displacement with respect to its starting point?&#10;A) 59&#186; N of E&#10;B) 77&#186; N of E&#10;C) 29&#186; N of E&#10;D) 59&#186; N of W&#10;E) 29&#186; N of W

Accepted Answer

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Question 42

The interstate on-ramp is 1.5 km west of your home, and on leaving for grandmother's house you are only able to accomplish an average velocity of 12 km/hr between your home and the on-ramp. At the on-ramp, you wait for traffic for 2.0 min before proceeding toward grandmother's house. If you wish to arrive there, which is 15 km south of the on-ramp, over a river and through some woods, in a total elapsed time of 25.0 minutes, what average speed must you maintain on the interstate highway?

A) 51 km/hr
B) 58 km/hr
C) 67 km/hr
D) none of these

Accepted Answer

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Question 43

An ant crawls in a straight line at a constant speed of 0.24 m/s for a distance of 3.0 m, beginning in the corner of a square classroom. It then turns exactly 90 degrees to the right and proceeds an additional 4.0 m with a constant speed of 0.44 m/s, reaching the other corner of the same wall from which it began. What was the ant's average speed for the full trip from corner to corner?

A) 0.34 m/s
B) 0.30 m/s
C) 0.21 m/s
D) 0.23 m/s
E) 0.32 m/s

Accepted Answer

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Question 44

A baseball is struck by a batter at an angle such that it reaches its maximum height at the location of the pitcher-and just grazes the top of the pitcher's head (at an elevation of 1.50 m above the launch point of the baseball). The pitcher is a horizontal distance of 20.0 m from the point at which the ball was struck. What was the launch speed for the baseball?

A) 36.6 m/s
B) 36.1 m/s
C) 41.6 m/s
D) 30.7 m/s

Accepted Answer

The answer of A baseball is struck by a batter...

Question 45

Vector A has a magnitude of 3.0 units and makes an angle of −90.0º with the positive x-axis. Vector B has a magnitude of 4.0 units and makes an angle of −120º with the positive x-axis. What is the direction of the vector sum A + B relative to the positive x-axis?

A) −107º
B) 55º
C) −55º
D) −145º

Accepted Answer

The answer of Vector A has a magnitude of 3.0...

Question 46

A displacement vector D is given as 40.0 m at an angle of 60.0 degrees NORTH of EAST. The D_xcomponent and theD_y component of the vector are A) D_x = +34.6 m, D_y = +20.0 m. B) D_x = +20.0 m, D_y = −34.6 m. C) D_x = +20.0 m, D_y = +34.6 m. D) D_x = −34.6 m, D_y = +20.0 m. E) D_x = +34.6 m, D_y = −20.0 m.

Accepted Answer

The answer of A displacement vector D is given as...

Question 47

An ant crawls in a straight line at a constant speed of 0.24 m/s for a distance of 3.0 m, beginning in the corner of a square classroom. It then turns exactly 90 degrees to the right and proceeds an additional 4.0 m with a constant speed of 0.44 m/s, reaching the other corner of the same wall from which it began. What was the ant's average speed for the full trip from corner to corner?

A) 0.34 m/s
B) 0.30 m/s
C) 0.21 m/s
D) 0.23 m/s
E) 0.32 m/s

Accepted Answer

The answer of An ant crawls in a straight line...

Question 48

The interstate on-ramp is 5.5 km west of your home, and on leaving for grandmother's house you are only able to accomplish an average velocity of 38 km/hr between your home and the on-ramp. At the on-ramp, you wait for traffic for 2.0 min before proceeding toward grandmother's house. If you wish to arrive there, which is 15 km south of the on-ramp, over a river and through some woods, having achieved an average velocity of 42 km/hr for the whole trip, how fast do you need to drive south on the interstate highway?

A) 58 km/hr
B) 48 km/hr
C) 74 km/hr
D) 39 km/hr

Accepted Answer

The answer of The interstate on-ramp is 5.5 km west...

Question 49

A displacement vector D is given as 40.0 m at an angle of 60.0 degrees EAST of NORTH. The D_x component and the D_y component of the vector are A) D_x = +34.6 m, D_y = +20.0 m. B) D_x = +20.0 m, D_y = −34.6 m. C) D_x = +20.0 m, D_y = +34.6 m. D) D_x = −34.6 m, D_y = +20.0 m. E) D_x = +34.6 m, D_y = −20.0 m.

Accepted Answer

The answer of A displacement vector D is given as...

Question 50

A displacement vector of magnitude 15.2 km directed along the positive x-axis combines with a second vector to produce a total displacement of magnitude 17.9 km. What is the magnitude of the second vector?&#10;A) 2.7 km&#10;B) 9.5 km&#10;C) 23.5 km&#10;D) Not enough information is given.

Accepted Answer

The answer of A displacement vector of magnitude 15.2 km...

Question 51

An ant crawls in a straight line at a constant speed of 0.24 m/s for a distance of 3.0 m, beginning in the corner of a square classroom. It then turns exactly 90 degrees to the right and proceeds an additional 4.0 m with a constant speed of 0.44 m/s, reaching the other corner of the same wall from which it began. What was the ant's average speed for the full trip from corner to corner?

A) 0.34 m/s
B) 0.30 m/s
C) 0.21 m/s
D) 0.23 m/s
E) 0.32 m/s

Accepted Answer

The answer of An ant crawls in a straight line...

Question 52

A beetle runs an erratic pattern on a square kitchen table that is 1.5 m on a side. The sides are arranged along the directions north/south and east/west. It begins at the southwest corner and travels east along one side to the adjacent corner in 20.0 s. It then turns north and reaches the northeast corner 12.5 s later. What is the magnitude of the beetle's average velocity for the whole trip?&#10;A) 0.092 m/s&#10;B) 0.098 m/s&#10;C) 0.065 m/s&#10;D) 0.033 m/s

Accepted Answer

The answer of A beetle runs an erratic pattern on...

Question 53

Vector A has a magnitude of 3.0 units and makes an angle of −90.0º with the positive x-axis. Vector B has a magnitude of 4.0 units and makes an angle of −120º with the positive x-axis. What is the direction of the vector sum A + B relative to the positive x-axis?

A) −107º
B) 55º
C) −55º
D) −145º

Accepted Answer

The answer of Vector A has a magnitude of 3.0...

Question 54

You drive five blocks due north, five blocks due east, and another two blocks due north. What is the magnitude of your displacement?&#10;A) 7 blocks&#10;B) 12 blocks&#10;C) 9 blocks&#10;D) 10 blocks&#10;E) 8.6 blocks

Accepted Answer

The answer of You drive five blocks due north, five...

Question 55

A vector of magnitude 3.8 directed along the positive x-axis combines with a second vector directed along the positive y-axis to produce a total vector of magnitude 6.1. What is the magnitude of the second vector?&#10;A) 2.7&#10;B) 9.5&#10;C) 23.5&#10;D) 4.8&#10;E) Not enough information is given.

Accepted Answer

The answer of A vector of magnitude 3.8 directed along...

Question 56

The y-component of a vector is &#8722;15.0, while its magnitude is 27.2. Which could be the vector's direction?&#10;A) 61.1&#176; below the +x-axis&#10;B) 56.5&#176; below the &#8722;x-axis&#10;C) 33.5&#176; below the &#8722;x-axis&#10;D) 28.9&#176; below the +x-axis&#10;E) None of the choices are correct.

Accepted Answer

The answer of The y-component of a vector is &#8722;15.0,...

Deck 3: Motion in a Plane