Deck 8: Estimation and Confidence Intervals
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Deck 8: Estimation and Confidence Intervals
1
The z-value associated with an 80% level of confidence is:
A) 1.96
B) 1.645
C) 2.33
D) 2.575
E) 1.28
A) 1.96
B) 1.645
C) 2.33
D) 2.575
E) 1.28
1.28
2
When a confidence interval for a population mean is constructed from sample data,
A) we can conclude that the population mean is in the interval.
B) we can conclude that the population mean is not in the interval.
C) we can conclude, with a stated level of confidence, that the population mean is in the interval.
D) we cannot make any inferences.
A) we can conclude that the population mean is in the interval.
B) we can conclude that the population mean is not in the interval.
C) we can conclude, with a stated level of confidence, that the population mean is in the interval.
D) we cannot make any inferences.
we can conclude, with a stated level of confidence, that the population mean is in the interval.
3
Recently, a university surveyed recent graduates of the English Department for their starting salaries. One hundred graduates returned the survey. The average salary was $35,000 with a standard deviation of $2,000. What is the best point estimate of the population mean?
A) $25,000
B) $2,000
C) $500
D) $400
E) $35,000
A) $25,000
B) $2,000
C) $500
D) $400
E) $35,000
$35,000
4
Recently, a university surveyed recent graduates of the English Department for their starting salaries. Four hundred graduates returned the survey. The average salary was $25,000. The population standard deviation is known to be $2,500. Interpret the results of the 95% confidence interval.
A) The population mean is in the interval.
B) The population mean is not in the interval.
C) The likelihood that any confidence interval based on a sample of 400 graduates will contain the population mean is 0.95.
D) There is a 95% chance that the computed interval does not contain the population mean.
A) The population mean is in the interval.
B) The population mean is not in the interval.
C) The likelihood that any confidence interval based on a sample of 400 graduates will contain the population mean is 0.95.
D) There is a 95% chance that the computed interval does not contain the population mean.
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5
A sample of 25 is selected from a known population of 100 elements. What is the finite population correction factor?
A) 8.66
B) 75
C) 0.87
D) Cannot be determined from the information given.
A) 8.66
B) 75
C) 0.87
D) Cannot be determined from the information given.
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6
A confidence interval for a population mean
A) estimates the population range.
B) estimates a likely interval for a population mean.
C) estimates a likelihood or probability.
D) estimates the population standard deviation.
A) estimates the population range.
B) estimates a likely interval for a population mean.
C) estimates a likelihood or probability.
D) estimates the population standard deviation.
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7
A 95% confidence interval infers that the population mean is
A) between 0 and 100%.
B) within 1.96 standard deviations of the sample mean.
C) within 1.96 standard errors of the sample mean.
D) within 1.645 standard deviations of the sample mean.
E) too large.
A) between 0 and 100%.
B) within 1.96 standard deviations of the sample mean.
C) within 1.96 standard errors of the sample mean.
D) within 1.645 standard deviations of the sample mean.
E) too large.
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8
A sample standard deviation is the best point estimate of the
A) population range.
B) population skewness.
C) population mode.
D) population standard deviation.
E) population variance.
A) population range.
B) population skewness.
C) population mode.
D) population standard deviation.
E) population variance.
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9
Dottie Kleman is the "Cookie Lady." She bakes and sells cookies at 50 different locations. Ms. Kleman is concerned about absenteeism among her workers. The information below reports the number of days absent for a sample of 10 workers during the last two-week pay period.
The sample mean is calculated to be 1.8 and sample standard deviation is 1.1353. Develop a 95% confidence interval for the population mean. Assume that the population distribution is normal. Is it reasonable to conclude that the typical worker does not miss any days during a pay period?
A) [0.99, 2.61] It is unreasonable to conclude that the mean number of days of work missed is 0 per employee.
B) [0.99, 2.61] It is reasonable to conclude that the mean number of days of work missed is 0 per employee.
C) [-0.99, -2.61] It is unreasonable to conclude that the mean number of days of work missed is 0 per employee.
D) [-0.99, -2.61] It is reasonable to conclude that the mean number of days of work missed is 0 per employee.
![<strong>Dottie Kleman is the Cookie Lady. She bakes and sells cookies at 50 different locations. Ms. Kleman is concerned about absenteeism among her workers. The information below reports the number of days absent for a sample of 10 workers during the last two-week pay period. The sample mean is calculated to be 1.8 and sample standard deviation is 1.1353. Develop a 95% confidence interval for the population mean. Assume that the population distribution is normal. Is it reasonable to conclude that the typical worker does not miss any days during a pay period?</strong> A) [0.99, 2.61] It is unreasonable to conclude that the mean number of days of work missed is 0 per employee. B) [0.99, 2.61] It is reasonable to conclude that the mean number of days of work missed is 0 per employee. C) [-0.99, -2.61] It is unreasonable to conclude that the mean number of days of work missed is 0 per employee. D) [-0.99, -2.61] It is reasonable to conclude that the mean number of days of work missed is 0 per employee.](https://d2lvgg3v3hfg70.cloudfront.net/TB6660/11eaa8f3_40d0_174c_96ab_ef82a156521f_TB6660_00.jpg)
A) [0.99, 2.61] It is unreasonable to conclude that the mean number of days of work missed is 0 per employee.
B) [0.99, 2.61] It is reasonable to conclude that the mean number of days of work missed is 0 per employee.
C) [-0.99, -2.61] It is unreasonable to conclude that the mean number of days of work missed is 0 per employee.
D) [-0.99, -2.61] It is reasonable to conclude that the mean number of days of work missed is 0 per employee.
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10
Recently, a university surveyed recent graduates of the English Department for their starting salaries. Four hundred graduates returned the survey. The average salary was $55,000 with a standard deviation of $2,500. What is the best point estimate of the population mean?
A) $55,000
B) $52,500
C) 400
D) $62.5
A) $55,000
B) $52,500
C) 400
D) $62.5
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11
A random sample of 85 group leaders, supervisors, and similar personnel revealed that on the average a person spent 6.5 years on the job before being promoted. The standard deviation of the population was 1.7 years. Find the 95% confidence interval for the population mean.
A) 6.99 and 7.99
B) 4.15 and 7.15
C) 6.14 and 6.86
D) 6.49 and 7.49
A) 6.99 and 7.99
B) 4.15 and 7.15
C) 6.14 and 6.86
D) 6.49 and 7.49
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12
i. The 95 percent confidence interval states that 95 percent of the sample means of a specified sample size selected from a population will lie within plus and minus 1.96 standard deviations of the hypothesized population mean. ii. A distribution of sample means is normally distributed with a mean equal to the population mean and a standard deviation equal to the standard error of the mean.
iii. A sample mean is the best point estimate of a population mean.
A) (i), (ii), and (iii) are all correct statements.
B) (i) and (ii) are correct statements but not (iii).
C) (i) and (iii) are correct statements but not (ii).
D) (ii) and (iii) are correct statements but not (i).
E) (i), (ii), and (iii) are all false statements.
iii. A sample mean is the best point estimate of a population mean.
A) (i), (ii), and (iii) are all correct statements.
B) (i) and (ii) are correct statements but not (iii).
C) (i) and (iii) are correct statements but not (ii).
D) (ii) and (iii) are correct statements but not (i).
E) (i), (ii), and (iii) are all false statements.
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13
The z-value associated with a 90% level of confidence is:
A) 1.96
B) 1.645
C) 2.33
D) 2.575
E) 1.28
A) 1.96
B) 1.645
C) 2.33
D) 2.575
E) 1.28
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14
The z-value associated with a 94% level of confidence is:
A) 1.96
B) 1.645
C) 2.33
D) 2.575
E) 1.88
A) 1.96
B) 1.645
C) 2.33
D) 2.575
E) 1.88
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15
The z-value associated with a 96% level of confidence is:
A) 1.96
B) 1.645
C) 2.33
D) 2.05
E) 1.28
A) 1.96
B) 1.645
C) 2.33
D) 2.05
E) 1.28
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16
A sample mean is the best point estimate of the
A) population standard deviation.
B) population median.
C) population mean.
D) the sample standard deviation.
E) the population variance.
A) population standard deviation.
B) population median.
C) population mean.
D) the sample standard deviation.
E) the population variance.
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17
Dottie Kleman is the "Cookie Lady." She bakes and sells cookies at 50 different locations. Ms. Kleman is concerned about absenteeism among her workers. The information below reports the number of days absent for a sample of 10 workers during the last two-week pay period.
The sample mean is calculated to be 1.8 and sample standard deviation is 1.1353. Develop a 95% confidence interval for the population mean. Assume that the population distribution is normal. Is it reasonable to conclude that the typical worker misses 1 day during a pay period?
A) [0.99, 2.61] It is unreasonable to conclude that the mean number of days of work missed is1per employee.
B) [0.99, 2.61] It is reasonable to conclude that the mean number of days of work missed is 1 per employee.
C) [-0.99, -2.61] It is unreasonable to conclude that the mean number of days of work missed is 1 per employee.
D) [-0.99, -2.61] It is reasonable to conclude that the mean number of days of work missed is 1 per employee.
![<strong>Dottie Kleman is the Cookie Lady. She bakes and sells cookies at 50 different locations. Ms. Kleman is concerned about absenteeism among her workers. The information below reports the number of days absent for a sample of 10 workers during the last two-week pay period. The sample mean is calculated to be 1.8 and sample standard deviation is 1.1353. Develop a 95% confidence interval for the population mean. Assume that the population distribution is normal. Is it reasonable to conclude that the typical worker misses 1 day during a pay period?</strong> A) [0.99, 2.61] It is unreasonable to conclude that the mean number of days of work missed is1per employee. B) [0.99, 2.61] It is reasonable to conclude that the mean number of days of work missed is 1 per employee. C) [-0.99, -2.61] It is unreasonable to conclude that the mean number of days of work missed is 1 per employee. D) [-0.99, -2.61] It is reasonable to conclude that the mean number of days of work missed is 1 per employee.](https://d2lvgg3v3hfg70.cloudfront.net/TB6660/11eaa8f3_40d0_3e5d_96ab_e9016a40125a_TB6660_00.jpg)
A) [0.99, 2.61] It is unreasonable to conclude that the mean number of days of work missed is1per employee.
B) [0.99, 2.61] It is reasonable to conclude that the mean number of days of work missed is 1 per employee.
C) [-0.99, -2.61] It is unreasonable to conclude that the mean number of days of work missed is 1 per employee.
D) [-0.99, -2.61] It is reasonable to conclude that the mean number of days of work missed is 1 per employee.
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18
Mileage tests were conducted on a randomly selected sample of 100 newly developed automobile tires. The average tread life was found to be 80,000 kilometres with a standard deviation of 5,600 kilometres. What is the best estimate of the average tread life in miles for the entire population of these tires?
A) 80,000
B) 5,600
C) (80,000/100)
D) (5,600/100)
A) 80,000
B) 5,600
C) (80,000/100)
D) (5,600/100)
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19
A sample of 50 is selected from a known population of 250 elements. The population standard deviation is 15. What is the standard error of the sample means using the finite population correction factor?
A) 2.89
B) 1.90
C) 2.12
D) 13.44
E) Cannot be determined from information given.
A) 2.89
B) 1.90
C) 2.12
D) 13.44
E) Cannot be determined from information given.
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20
Which of the following would be used as a point estimate for the population mean (µ)?
A)
B) x/n
C)
D) s
E) p
A)
B) x/n
C)

D) s
E) p
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21
Which statement(s) is/are correct about the t distribution?
A) Mean = 0
B) Symmetric
C) Based on degrees of freedom
D) Mean = 0, symmetric and based on degrees of freedom
E) Mean = 0 and symmetric
A) Mean = 0
B) Symmetric
C) Based on degrees of freedom
D) Mean = 0, symmetric and based on degrees of freedom
E) Mean = 0 and symmetric
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22
A survey of 144 retail stores revealed that the average price of a DVD was $375 with a standard error of $20. What is the 95% confidence interval to estimate the true cost of the DVD?
A) $323.40 to $426.60
B) $328.40 to $421.60
C) $335.00 to $415.00
D) $335.80 to $414.20
A) $323.40 to $426.60
B) $328.40 to $421.60
C) $335.00 to $415.00
D) $335.80 to $414.20
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23
i. The t distribution is based on the assumption that the population of interest is normal or nearly normal. ii. The t distribution is a continuous distribution.
iii. There is not one t distribution, but rather a "family" of t distributions.
A) (i), (ii), and (iii) are all correct statements.
B) (i) is a correct statement but not (ii) or (iii).
C) (i) and (iii) are correct statements but not (ii).
D) (ii) and (iii) are correct statements but not (i).
E) (i), (ii), and (iii) are all false statements.
iii. There is not one t distribution, but rather a "family" of t distributions.
A) (i), (ii), and (iii) are all correct statements.
B) (i) is a correct statement but not (ii) or (iii).
C) (i) and (iii) are correct statements but not (ii).
D) (ii) and (iii) are correct statements but not (i).
E) (i), (ii), and (iii) are all false statements.
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24
A survey of 25 grocery stores revealed that the average price of a 4-litre bag of milk was $2.98 with a standard error of $0.10. What is the 98% confidence interval to estimate the true cost of a 4-litre bag of milk?
A) $2.75 to $3.21
B) $2.85 to $3.11
C) $2.94 to $3.02
D) $2.95 to $3.01
E) $2.77 to $3.19
A) $2.75 to $3.21
B) $2.85 to $3.11
C) $2.94 to $3.02
D) $2.95 to $3.01
E) $2.77 to $3.19
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25
Dr. Patton is a professor of English. Recently she counted the number of misspelled works in a group of student essays. She noted the distribution of misspelled words per essay followed the normal distribution with a standard deviation of 2.44 words per essay. For her Tuesday class of 50 students, the mean number of misspelled words per essay was 6.05. Construct a 90% confidence interval for the mean number of misspelled words in the population of student essays.
A) 5.374 to 6.726
B) 5.161 to 6.939
C) 5.102 to 6.998
D) 5.482 to 6.618
E) 5.445 to 6.3655
A) 5.374 to 6.726
B) 5.161 to 6.939
C) 5.102 to 6.998
D) 5.482 to 6.618
E) 5.445 to 6.3655
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26
i. The test statistic t has n-1 degrees of freedom. ii. All t distributions have the same mean of zero and a standard deviation of 1.
iii. The t distribution is more spread out and flatter at the center than is the standard normal distribution. However, as the sample size increases, the t distribution curve approaches the standard normal distribution.
A) (i), (ii), and (iii) are all correct statements.
B) (iii) is a correct statement but not (i) or (ii).
C) (i) and (iii) are correct statements but not (ii).
D) (ii) and (iii) are correct statements but not (i).
E) (i), (ii), and (iii) are all false statements.
iii. The t distribution is more spread out and flatter at the center than is the standard normal distribution. However, as the sample size increases, the t distribution curve approaches the standard normal distribution.
A) (i), (ii), and (iii) are all correct statements.
B) (iii) is a correct statement but not (i) or (ii).
C) (i) and (iii) are correct statements but not (ii).
D) (ii) and (iii) are correct statements but not (i).
E) (i), (ii), and (iii) are all false statements.
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27
i. The t distribution is based on the assumption that the population of interest is normal or nearly normal. ii. The t distribution is a discrete distribution.
iii. There is not one t distribution, but rather a "family" of t distributions.
A) (i), (ii), and (iii) are all correct statements.
B) (i) is a correct statement but not (ii) or (iii).
C) (i) and (iii) are correct statements but not (ii).
D) (ii) and (iii) are correct statements but not (i).
E) (i), (ii), and (iii) are all false statements.
iii. There is not one t distribution, but rather a "family" of t distributions.
A) (i), (ii), and (iii) are all correct statements.
B) (i) is a correct statement but not (ii) or (iii).
C) (i) and (iii) are correct statements but not (ii).
D) (ii) and (iii) are correct statements but not (i).
E) (i), (ii), and (iii) are all false statements.
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28
A survey of 144 retail stores revealed that the average price of a DVD was $375 with a standard error of $20. If 90% and 95% confidence intervals were developed to estimate the true cost of the DVD, what similarities would they have?
A) Point estimates
B) Z-values would be the same
C) Standard errors
D) Both point estimates and standard errors would be the same
E) Both standard errors Z-values would be the same
A) Point estimates
B) Z-values would be the same
C) Standard errors
D) Both point estimates and standard errors would be the same
E) Both standard errors Z-values would be the same
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29
A survey of 25 grocery stores revealed that the average price of a 4-litre bag of milk was $2.98 with a standard error of $0.10. If 90% and 95% confidence intervals were developed to estimate the true cost of a 4-litre bag of milk, what similarities would they have?
A) Point estimates
B) t-statistics
C) Standard errors
D) Both the same point estimate and the same standard error
E) Both the same t-statistic and point estimate
A) Point estimates
B) t-statistics
C) Standard errors
D) Both the same point estimate and the same standard error
E) Both the same t-statistic and point estimate
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30
i. The test statistic for a problem involving an unknown population standard deviation is the Student's t distribution. ii. The t distribution approaches the Z distribution as the sample size increases.
iii. As the sample size increases, the computed value of t decreases.
A) (i), (ii), and (iii) are all correct statements.
B) (iii) is a correct statement but not (i) or (ii).
C) (i) and (iii) are correct statements but not (ii).
D) (ii) and (iii) are correct statements but not (i).
E) (i), (ii), and (iii) are all false statements.
iii. As the sample size increases, the computed value of t decreases.
A) (i), (ii), and (iii) are all correct statements.
B) (iii) is a correct statement but not (i) or (ii).
C) (i) and (iii) are correct statements but not (ii).
D) (ii) and (iii) are correct statements but not (i).
E) (i), (ii), and (iii) are all false statements.
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31
i. The Student t distribution has a greater spread than does the z distribution. As a result, the critical values of t for a given level of significance are larger in magnitude than the corresponding z critical values. ii. The test statistic t has n-1 degrees of freedom.
iii. William S. Gosset, a brewmaster, developed the t test for the Guinness Brewery in Ireland, who published it in 1908 using the pen name "Student."
A) (i), (ii), and (iii) are all correct statements.
B) (iii) is a correct statement but not (i) or (ii).
C) (i) and,(iii) are correct statements but not (ii).
D) (ii) and (iii) are correct statements but not (i).
E) (i), (ii), and (iii) are all false statements.
iii. William S. Gosset, a brewmaster, developed the t test for the Guinness Brewery in Ireland, who published it in 1908 using the pen name "Student."
A) (i), (ii), and (iii) are all correct statements.
B) (iii) is a correct statement but not (i) or (ii).
C) (i) and,(iii) are correct statements but not (ii).
D) (ii) and (iii) are correct statements but not (i).
E) (i), (ii), and (iii) are all false statements.
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32
Dr. Patton is a professor of English. Recently she counted the number of misspelled works in a group of student essays. She noted the distribution of misspelled words per essay followed the normal distribution with a standard deviation of 2.44 words per essay. For her Tuesday class of 50 students, the mean number of misspelled words per essay was 6.05. Construct a 95% confidence interval for the mean number of misspelled words in the population of student essays.
A) 5.374 to 6.726
B) 5.161 to 6.939
C) 5.102 to 6.998
D) 5.482 to 6.618
E) 5.445 to 6.3655
A) 5.374 to 6.726
B) 5.161 to 6.939
C) 5.102 to 6.998
D) 5.482 to 6.618
E) 5.445 to 6.3655
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33
A survey of 144 retail stores revealed that the average price of a DVD was $375 with a standard error of $20. What is the 99% confidence interval to estimate the true cost of the DVD?
A) $323.40 to $426.60
B) $328.40 to $421.60
C) $335.00 to $415.00
D) $335.80 to $414.20
A) $323.40 to $426.60
B) $328.40 to $421.60
C) $335.00 to $415.00
D) $335.80 to $414.20
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34
Recently, a university surveyed recent graduates of the English Department for their starting salaries. Four hundred graduates returned the survey. The average salary was $55,000. The population standard deviation is known to be $2,500. What is the 95% confidence interval for the mean salary of all graduates from the English Department?
A) 52,500, $57,500
B) 54,755, $55,245
C) 54,988, $55,012
D) 54,600, $55,600
A) 52,500, $57,500
B) 54,755, $55,245
C) 54,988, $55,012
D) 54,600, $55,600
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35
A survey of 25 grocery stores revealed that the average price of a 4-litre bag of milk was $2.98 with a standard error of $0.10. What is the 95% confidence interval to estimate the true cost of a 4-litre bag of milk?
A) $2.81 to $3.15
B) $2.94 to $3.02
C) $2.78 to $3.18
D) $2.95 to $3.01
E) $2.73 to $3.23
A) $2.81 to $3.15
B) $2.94 to $3.02
C) $2.78 to $3.18
D) $2.95 to $3.01
E) $2.73 to $3.23
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36
Dr. Patton is a professor of English. Recently she counted the number of misspelled works in a group of student essays. She noted the distribution of misspelled words per essay followed the normal distribution with a standard deviation of 2.44 words per essay. For her Tuesday class of 44 students, the mean number of misspelled words per essay was 6.05. Construct a 90% confidence interval for the mean number of misspelled words in the population of student essays.
A) 5.374 to 6.726
B) 5.161 to 6.939
C) 5.102 to 6.998
D) 5.482 to 6.618
E) 5.445 to 6.6551
A) 5.374 to 6.726
B) 5.161 to 6.939
C) 5.102 to 6.998
D) 5.482 to 6.618
E) 5.445 to 6.6551
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37
A survey of 144 retail stores revealed that the average price of a DVD was $375 with a standard error of $20. If 95% and 98% confidence intervals were developed to estimate the true cost of the DVD, what differences would they have?
A) Standard errors
B) Interval widths
C) Z-values
D) Both standard errors and interval widths
E) Both interval widths and Z-values
A) Standard errors
B) Interval widths
C) Z-values
D) Both standard errors and interval widths
E) Both interval widths and Z-values
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38
Recently, a university surveyed recent graduates of the English Department for their starting salaries. Four hundred graduates returned the survey. The average salary was $55,000. The population standard deviation is known to be $2,500. What is the 90% confidence interval for the mean salary of all graduates from the English Department?
A) 5,497, $55,039
B) 54,794, $55,206
C) 54,671, $55,329
D) 54,961, $5,539
E) 54,800, $55,200
A) 5,497, $55,039
B) 54,794, $55,206
C) 54,671, $55,329
D) 54,961, $5,539
E) 54,800, $55,200
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39
Dr. Patton is a professor of English. Recently she counted the number of misspelled works in a group of student essays. She noted the distribution of misspelled words per essay followed the normal distribution with a standard deviation of 2.44 words per essay. For her Tuesday class of 50 students, the mean number of misspelled words per essay was 6.05. Construct a 99% confidence interval for the mean number of misspelled words in the population of student essays.
A) 5.374 to 6.726
B) 5.160 to 6.940
C) 5.102 to 6.998
D) 5.482 to 6.618
E) 5.445 to 6.3655
A) 5.374 to 6.726
B) 5.160 to 6.940
C) 5.102 to 6.998
D) 5.482 to 6.618
E) 5.445 to 6.3655
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40
i. The t distribution is positively skewed. ii. All t distributions have the same mean of zero and a standard deviation of 1.
iii. The t distribution is more spread out and flatter at the center than is the standard normal distribution. However, as the sample size increases, the t distribution curve approaches the standard normal distribution.
A) (i), (ii), and (iii) are all correct statements.
B) (iii) is a correct statement but not (i) or (ii).
C) (i) and (iii) are correct statements but not (ii).
D) (ii) and (iii) are correct statements but not (i).
E) (i), (ii), and (iii) are all false statements.
iii. The t distribution is more spread out and flatter at the center than is the standard normal distribution. However, as the sample size increases, the t distribution curve approaches the standard normal distribution.
A) (i), (ii), and (iii) are all correct statements.
B) (iii) is a correct statement but not (i) or (ii).
C) (i) and (iii) are correct statements but not (ii).
D) (ii) and (iii) are correct statements but not (i).
E) (i), (ii), and (iii) are all false statements.
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41
A student wanted to quickly construct a 95% confidence interval for the average age of students in her statistics class. She randomly selected 9 students. Their average age was 19.1 years with a standard deviation of 1.5 years. What is the 95% confidence interval for the population mean?
A) [0.97, 3.27]
B) [15.64, 22.56]
C) [17.97, 20.23]
D) [17.95, 20.25]
E) [17.42, 20.78]
A) [0.97, 3.27]
B) [15.64, 22.56]
C) [17.97, 20.23]
D) [17.95, 20.25]
E) [17.42, 20.78]
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42
When using Student's t to compute an interval estimate,
A) we assume that the samples are collected from normally distributed populations.
B) we estimate the population standard deviation based on the sample standard deviation.
C) use the z distribution.
D) we assume that samples are collected from normally distributed populations and the estimate of the population standard deviation based on the sample standard deviation.
E) we assume that the samples are collected from normally distributed populations and use the z distribution.
A) we assume that the samples are collected from normally distributed populations.
B) we estimate the population standard deviation based on the sample standard deviation.
C) use the z distribution.
D) we assume that samples are collected from normally distributed populations and the estimate of the population standard deviation based on the sample standard deviation.
E) we assume that the samples are collected from normally distributed populations and use the z distribution.
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43
The distribution of Student's t has
A) a mean of zero and a standard deviation of one.
B) a mean of one and a standard deviation of one.
C) a mean of zero and a standard deviation that depends on the sample size.
D) a mean that depends on the sample size and a standard deviation of one.
A) a mean of zero and a standard deviation of one.
B) a mean of one and a standard deviation of one.
C) a mean of zero and a standard deviation that depends on the sample size.
D) a mean that depends on the sample size and a standard deviation of one.
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44
The t distribution is similar to the z distribution in all BUT ONE of the following characteristics. Which one is it?
A) Continuous
B) Symmetrical
C) Bell-shaped
D) t distribution's mean = 0 and standard deviation = 1
A) Continuous
B) Symmetrical
C) Bell-shaped
D) t distribution's mean = 0 and standard deviation = 1
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45
A student wanted to quickly construct a 99% confidence interval for the average age of students in her statistics class. She randomly selected 9 students. Their average age was 19.1 years with a standard deviation of 1.5 years. What is the 99% confidence interval for the population mean?
A) [17.42, 20.78]
B) [17.48, 20.72]
C) [14.23, 23.98]
D) [0.44, 3.80]
E) [17.95, 20.25]
A) [17.42, 20.78]
B) [17.48, 20.72]
C) [14.23, 23.98]
D) [0.44, 3.80]
E) [17.95, 20.25]
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46
The distribution of Student's t is
A) symmetrical.
B) negatively skewed.
C) positively skewed.
D) a discrete probability distribution.
A) symmetrical.
B) negatively skewed.
C) positively skewed.
D) a discrete probability distribution.
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47
A student wanted to quickly construct a 95% confidence interval for the average age of students in her statistics class. She randomly selected 9 students. Their average age was 19.1 years with a standard deviation of 1.5 years. What is the best point estimate for the population mean?
A) 2.1 years
B) 1.5 years
C) 19.1 years
D) 9 years
E) 17.6 years
A) 2.1 years
B) 1.5 years
C) 19.1 years
D) 9 years
E) 17.6 years
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48
A statistics professor wishes to estimate the average mark on a term test for a course that has multiple sections and many students. A survey of some of the students registered for the course reveals the following results:
Determine a 95% confidence interval for the term test results.
A) [48.0, 93.6]
B) [66.8, 74.8]
C) [62.9, 78.71]
D) [64.2, 77.3]
E) [62.6, 79.0]
![<strong>A statistics professor wishes to estimate the average mark on a term test for a course that has multiple sections and many students. A survey of some of the students registered for the course reveals the following results: Determine a 95% confidence interval for the term test results.</strong> A) [48.0, 93.6] B) [66.8, 74.8] C) [62.9, 78.71] D) [64.2, 77.3] E) [62.6, 79.0]](https://d2lvgg3v3hfg70.cloudfront.net/TB6660/11eaa8f3_40d2_6142_96ab_9bbbeb437697_TB6660_00.jpg)
A) [48.0, 93.6]
B) [66.8, 74.8]
C) [62.9, 78.71]
D) [64.2, 77.3]
E) [62.6, 79.0]
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49
What kind of distribution is the t distribution?
A) Continuous
B) Discrete
C) Subjective
D) Standard
A) Continuous
B) Discrete
C) Subjective
D) Standard
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50
A manager of a local store wants to estimate the mean amount spent per shopping visit by customers. Summary statistics from a sample taken reveal the following:
The store manager wonders whether the population mean could have been $50 or $60.
A) Since $60 is within the 95% confidence interval, the population mean is likely to be $60.
B) Since $60 is not within the 95% confidence interval, the population mean is not likely to be $60.
C) Since $50 is within the 95% confidence interval, the population mean is likely to be $50.
D) Since $50 is not within the 95% confidence interval, the population mean is not likely to be $50.
E) Since $60 is not within the 95% confidence interval, the population mean is not likely to be $60; however, it is likely to be $50.

A) Since $60 is within the 95% confidence interval, the population mean is likely to be $60.
B) Since $60 is not within the 95% confidence interval, the population mean is not likely to be $60.
C) Since $50 is within the 95% confidence interval, the population mean is likely to be $50.
D) Since $50 is not within the 95% confidence interval, the population mean is not likely to be $50.
E) Since $60 is not within the 95% confidence interval, the population mean is not likely to be $60; however, it is likely to be $50.
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51
The t distribution approaches __________ as the sample size increases. As the sample size increases, the computed value of t ______________.
A) Z distribution; decreases
B) Z distribution; increases
C) Z distribution; stays the same
D) 0; decreases
E) 0; increases
A) Z distribution; decreases
B) Z distribution; increases
C) Z distribution; stays the same
D) 0; decreases
E) 0; increases
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52
How does the t distribution differ from the standard z distribution?
A) Continuous distribution
B) Bell-shaped
C) Family of distributions
D) Symmetrical
A) Continuous distribution
B) Bell-shaped
C) Family of distributions
D) Symmetrical
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53
A sample of 20 is selected from the population. What is the number of degrees of freedom used to determine the appropriate critical t-value?
A) 20
B) 19
C) 21
D) 25
A) 20
B) 19
C) 21
D) 25
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54
In order to construct a 90% confidence interval for the population mean when the population standard deviation is unknown and the sample size is 18, you should use the t-value indicated as:
A) t0.10,18
B) t0.10,17
C) t0.05,18
D) t0.05,17
E) t0.90,17
A) t0.10,18
B) t0.10,17
C) t0.05,18
D) t0.05,17
E) t0.90,17
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55
A sample of 100 students is selected from a known population of 1,000 students to construct a 95% confidence interval for the average SAT score. What correction factor should be used to compute the standard error?
A) 0.949
B) 0.901
C) 1.96
D) 9.01
E) Cannot be determined
A) 0.949
B) 0.901
C) 1.96
D) 9.01
E) Cannot be determined
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56
Student's t is used when
A) the sample is more than 30 observations.
B) the sample size is 5% of the population.
C) the population standard deviation is unknown.
D) any time.
A) the sample is more than 30 observations.
B) the sample size is 5% of the population.
C) the population standard deviation is unknown.
D) any time.
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57
In order to construct a 95% confidence interval for the population mean when the population standard deviation is unknown and the sample size is 15, you should use the t-value indicated as:
A) t0.10,15
B) t0.10,14
C) t0.05,15
D) t0.05,14
E) t0.025,14
A) t0.10,15
B) t0.10,14
C) t0.05,15
D) t0.05,14
E) t0.025,14
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58
A manager of a local store wants to estimate the mean amount spent per shopping visit by customers. Summary statistics from a sample taken reveal the following:
Determine a 95% confidence interval for the mean amount spent.
A) [45.21, 53.56]
B) [40.36, 58.35]
C) [30.54, 68.14]
D) [45.13, 53.56]
E) [29.34, 69.34]
![<strong>A manager of a local store wants to estimate the mean amount spent per shopping visit by customers. Summary statistics from a sample taken reveal the following: Determine a 95% confidence interval for the mean amount spent.</strong> A) [45.21, 53.56] B) [40.36, 58.35] C) [30.54, 68.14] D) [45.13, 53.56] E) [29.34, 69.34]](https://d2lvgg3v3hfg70.cloudfront.net/TB6660/11eaa8f3_40d2_131e_96ab_bf064a703161_TB6660_00.jpg)
A) [45.21, 53.56]
B) [40.36, 58.35]
C) [30.54, 68.14]
D) [45.13, 53.56]
E) [29.34, 69.34]
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59
A manager of a local store wants to estimate the mean amount spent per shopping visit by customers. Summary statistics from a sample taken reveal the following:
If 90% and 95% confidence intervals were developed to estimate the true shopping expenditure, what similarities would exist?
A) Point estimates
B) t-values would be the same
C) Standard errors
D) Both point estimates and standard errors
E) Both point estimates and t-values

A) Point estimates
B) t-values would be the same
C) Standard errors
D) Both point estimates and standard errors
E) Both point estimates and t-values
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60
A manager of a local store wants to estimate the mean amount spent per shopping visit by customers. Summary statistics from a sample taken reveal the following:
If 95% and 98% confidence intervals were developed to estimate the true shopping expenditure, what differences would exist?
A) Standard errors
B) Interval widths
C) t-values
D) Both interval widths and t-values
E) Both standard errors and interval widths

A) Standard errors
B) Interval widths
C) t-values
D) Both interval widths and t-values
E) Both standard errors and interval widths
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61
The following summarizes the amount of snowfall in Ontario over the past number of years.
You wonder whether the population mean could have been 2000 or 1900.
A) Since 1900 is within the 95% confidence interval, the population mean is likely to be 1900.
B) Since 1900 is within the 95% confidence interval, the population mean is not likely to be 1900.
C) Since 2000 is within the 95% confidence interval, the population mean is likely to be 2000.
D) Since neither 1900 nor 200 is within the 95% confidence interval, the population mean is not likely to be 1900 or 2000.
E) Since 1900 and 2000 are both within the 95% confidence interval, the population mean is likely to be either value.

A) Since 1900 is within the 95% confidence interval, the population mean is likely to be 1900.
B) Since 1900 is within the 95% confidence interval, the population mean is not likely to be 1900.
C) Since 2000 is within the 95% confidence interval, the population mean is likely to be 2000.
D) Since neither 1900 nor 200 is within the 95% confidence interval, the population mean is not likely to be 1900 or 2000.
E) Since 1900 and 2000 are both within the 95% confidence interval, the population mean is likely to be either value.
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62
The following summarizes the amount of snowfall in Ontario over the past number of years.
You wonder whether the population mean could have been 1,600 or 2,100.
A) Since 1600 is within the 95% confidence interval, the population mean is likely to be 1,600.
B) Since 1600 is not within the 95% confidence interval, the population mean is not likely to be 1,600.
C) Since 2100 is within the 95% confidence interval, the population mean is likely to be 2,100.
D) Since neither 1,600 nor 2,100 is within the 95% confidence interval, the population mean is not likely to be 1,600 or 2000.
E) Since 1900 and 2000 are both within the 95% confidence interval, the population mean is likely to be either value.

A) Since 1600 is within the 95% confidence interval, the population mean is likely to be 1,600.
B) Since 1600 is not within the 95% confidence interval, the population mean is not likely to be 1,600.
C) Since 2100 is within the 95% confidence interval, the population mean is likely to be 2,100.
D) Since neither 1,600 nor 2,100 is within the 95% confidence interval, the population mean is not likely to be 1,600 or 2000.
E) Since 1900 and 2000 are both within the 95% confidence interval, the population mean is likely to be either value.
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63
The following summarizes the amount of snowfall in Ontario over the past number of years.
If 95% and 98% confidence intervals were developed to estimate the true average annual snowfall, what differences would exist?
A) Standard errors
B) Interval widths
C) Z-values
D) Both interval widths and Z-values

A) Standard errors
B) Interval widths
C) Z-values
D) Both interval widths and Z-values
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64
The following summarizes the amount of snowfall in Ontario over the past number of years.
Determine a 95% confidence interval for the average annual snowfall.
A) [1,698, 2,046]
B) [1,665, 2,079]
C) [1,213, 2,531]
D) [1,783, 1,961]
E) [1694, 2050]
![<strong>The following summarizes the amount of snowfall in Ontario over the past number of years. Determine a 95% confidence interval for the average annual snowfall.</strong> A) [1,698, 2,046] B) [1,665, 2,079] C) [1,213, 2,531] D) [1,783, 1,961] E) [1694, 2050]](https://d2lvgg3v3hfg70.cloudfront.net/TB6660/11eaa8f3_40d2_d678_96ab_d78470427904_TB6660_00.jpg)
A) [1,698, 2,046]
B) [1,665, 2,079]
C) [1,213, 2,531]
D) [1,783, 1,961]
E) [1694, 2050]
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65
The mean weight of trucks traveling on a particular section of Highway 401 is not known. A provincial highway inspector needs an estimate of the mean. He selects a random sample of 49 trucks passing the weighing station and finds the mean is 15.8 tons, with a standard deviation of the sample of 3.8 tons. What is the 95 percent interval for the population mean?
A) 14.7 and 16.9
B) 13.2 and 17.6
C) 10.0 and 20.0
D) 16.1 and 18.1
A) 14.7 and 16.9
B) 13.2 and 17.6
C) 10.0 and 20.0
D) 16.1 and 18.1
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66
Dottie Kleman is the "Cookie Lady." She bakes and sells cookies at 50 different locations. Ms. Kleman is concerned about absenteeism among her workers. The information below reports the number of days absent for a sample of 10 workers during the last two-week pay period.
The sample mean is calculated to be 1.8 and sample standard deviation is 1.1353. Develop a 95% confidence interval for the population mean. Assume that the population distribution is normal. Is it reasonable to conclude that the typical worker misses 2 days during a pay period?
A) [0.99, 2.61] It is unreasonable to conclude that the mean number of days of work missed is 2 per employee.
B) [0.99, 2.61] It is reasonable to conclude that the mean number of days of work missed is 2 per employee.
C) [1.99, 2.61] It is unreasonable to conclude that the mean number of days of work missed is 2 per employee.
D) [0.99, 1.61] It is reasonable to conclude that the mean number of days of work missed is 2 per employee.
![<strong>Dottie Kleman is the Cookie Lady. She bakes and sells cookies at 50 different locations. Ms. Kleman is concerned about absenteeism among her workers. The information below reports the number of days absent for a sample of 10 workers during the last two-week pay period. The sample mean is calculated to be 1.8 and sample standard deviation is 1.1353. Develop a 95% confidence interval for the population mean. Assume that the population distribution is normal. Is it reasonable to conclude that the typical worker misses 2 days during a pay period?</strong> A) [0.99, 2.61] It is unreasonable to conclude that the mean number of days of work missed is 2 per employee. B) [0.99, 2.61] It is reasonable to conclude that the mean number of days of work missed is 2 per employee. C) [1.99, 2.61] It is unreasonable to conclude that the mean number of days of work missed is 2 per employee. D) [0.99, 1.61] It is reasonable to conclude that the mean number of days of work missed is 2 per employee.](https://d2lvgg3v3hfg70.cloudfront.net/TB6660/11eaa8f3_40d3_99d0_96ab_b3560da46085_TB6660_00.jpg)
A) [0.99, 2.61] It is unreasonable to conclude that the mean number of days of work missed is 2 per employee.
B) [0.99, 2.61] It is reasonable to conclude that the mean number of days of work missed is 2 per employee.
C) [1.99, 2.61] It is unreasonable to conclude that the mean number of days of work missed is 2 per employee.
D) [0.99, 1.61] It is reasonable to conclude that the mean number of days of work missed is 2 per employee.
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67
A statistics professor wishes to estimate the average mark on a term test for a course that has multiple sections and many students. A survey of some of the students registered for the course reveals the following results:
The student from the course wonders whether the population mean could have been 75 or 80.
A) Since 80 is within the 95% confidence interval, the population mean is likely to be 80.
B) Since 80 is not within the 95% confidence interval, the population mean is not likely to be 80.
C) Since 75 is within the 95% confidence interval, the population mean is likely to be 75.
D) Since neither 75 nor 80 is within the 95% confidence interval, the population mean is not likely to be 75 or 80.
E) Since 80 is not within the 95% confidence interval, the population mean is not likely to be 80, but it is likely to be 75.

A) Since 80 is within the 95% confidence interval, the population mean is likely to be 80.
B) Since 80 is not within the 95% confidence interval, the population mean is not likely to be 80.
C) Since 75 is within the 95% confidence interval, the population mean is likely to be 75.
D) Since neither 75 nor 80 is within the 95% confidence interval, the population mean is not likely to be 75 or 80.
E) Since 80 is not within the 95% confidence interval, the population mean is not likely to be 80, but it is likely to be 75.
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68
The following summarizes the average price of Air Canada stock at the end of 20 randomly selected weeks in 2000.
Determine a 95% confidence interval for the average Air Canada stock price in 2000.
A) [16.83, 17.42]
B) [14.90, 19.87]
C) [17.48, 19.40]
D) [16.24, 18.56]
E) [16.23, 18.55]
![<strong>The following summarizes the average price of Air Canada stock at the end of 20 randomly selected weeks in 2000. Determine a 95% confidence interval for the average Air Canada stock price in 2000.</strong> A) [16.83, 17.42] B) [14.90, 19.87] C) [17.48, 19.40] D) [16.24, 18.56] E) [16.23, 18.55]](https://d2lvgg3v3hfg70.cloudfront.net/TB6660/11eaa8f3_40d3_72bf_96ab_19c754a19122_TB6660_00.jpg)
A) [16.83, 17.42]
B) [14.90, 19.87]
C) [17.48, 19.40]
D) [16.24, 18.56]
E) [16.23, 18.55]
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69
A statistics professor wishes to estimate the average mark on a term test for a course that has multiple sections and many students. A survey of some of the students registered for the course reveals the following results:
Determine a 98% confidence interval for the term test results.
A) [48.0, 93.6]
B) [66.8, 74.8]
C) [62.9, 78.71]
D) [64.2, 77.3]
E) [60.9, 80.7]
![<strong>A statistics professor wishes to estimate the average mark on a term test for a course that has multiple sections and many students. A survey of some of the students registered for the course reveals the following results: Determine a 98% confidence interval for the term test results.</strong> A) [48.0, 93.6] B) [66.8, 74.8] C) [62.9, 78.71] D) [64.2, 77.3] E) [60.9, 80.7]](https://d2lvgg3v3hfg70.cloudfront.net/TB6660/11eaa8f3_40d2_8853_96ab_ff64c74e9d6b_TB6660_00.jpg)
A) [48.0, 93.6]
B) [66.8, 74.8]
C) [62.9, 78.71]
D) [64.2, 77.3]
E) [60.9, 80.7]
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70
The following summarizes the amount of snowfall in Ontario over the past number of years.
Determine a 98% confidence interval for the average annual snowfall.
A) [1698, 2046]
B) [1665, 2079]
C) [1213, 2531]
D) [1783, 1961]
E) [1659, 2085]
![<strong>The following summarizes the amount of snowfall in Ontario over the past number of years. Determine a 98% confidence interval for the average annual snowfall.</strong> A) [1698, 2046] B) [1665, 2079] C) [1213, 2531] D) [1783, 1961] E) [1659, 2085]](https://d2lvgg3v3hfg70.cloudfront.net/TB6660/11eaa8f3_40d2_fd89_96ab_5178646ad536_TB6660_00.jpg)
A) [1698, 2046]
B) [1665, 2079]
C) [1213, 2531]
D) [1783, 1961]
E) [1659, 2085]
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71
A pharmaceutical company wanted to estimate the population mean of monthly sales for their 250 sales people. Forty sales people were randomly selected. Their mean monthly sales were $10,000 with a standard deviation of $1,000. Construct a 95% confidence interval for the population mean.
A) [9,690.1, 10,309.9]
B) [9706.3, 10293.7]
C) [8,040, 11,960]
D) [8,000, 12,000]
E) [9,000, 11,000]
A) [9,690.1, 10,309.9]
B) [9706.3, 10293.7]
C) [8,040, 11,960]
D) [8,000, 12,000]
E) [9,000, 11,000]
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72
The following summarizes the average price of Air Canada stock at the end of 20 randomly selected weeks in 2000.
Determine a 90% confidence interval for the average Air Canada stock price in 2000.
A) [16.44, 18.36]
B) [14.90, 19.87]
C) [17.48, 19.40]
D) [16.43, 18.35]
E) Unable to determine from the information given
![<strong>The following summarizes the average price of Air Canada stock at the end of 20 randomly selected weeks in 2000. Determine a 90% confidence interval for the average Air Canada stock price in 2000.</strong> A) [16.44, 18.36] B) [14.90, 19.87] C) [17.48, 19.40] D) [16.43, 18.35] E) Unable to determine from the information given](https://d2lvgg3v3hfg70.cloudfront.net/TB6660/11eaa8f3_40d3_72be_96ab_d961715d0132_TB6660_00.jpg)
A) [16.44, 18.36]
B) [14.90, 19.87]
C) [17.48, 19.40]
D) [16.43, 18.35]
E) Unable to determine from the information given
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73
The following summarizes the average price of Air Canada stock at the end of 20 randomly selected weeks in 2000.
Determine a 98% confidence interval for the average TSE 300 stock index in 2000.
A) [9467.57, 10 084.68]
B) [9401.80, 10 150.40]
C) [9628.70, 9923.55]
D) [9468.61, 10 083.65]
![<strong>The following summarizes the average price of Air Canada stock at the end of 20 randomly selected weeks in 2000. Determine a 98% confidence interval for the average TSE 300 stock index in 2000.</strong> A) [9467.57, 10 084.68] B) [9401.80, 10 150.40] C) [9628.70, 9923.55] D) [9468.61, 10 083.65]](https://d2lvgg3v3hfg70.cloudfront.net/TB6660/11eaa8f3_40d3_c0e1_96ab_d9d5185c3adf_TB6660_00.jpg)
A) [9467.57, 10 084.68]
B) [9401.80, 10 150.40]
C) [9628.70, 9923.55]
D) [9468.61, 10 083.65]
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74
A random sample of 85 group leaders, supervisors, and similar personnel revealed that on the average a person spent 6.5 years on the job before being promoted. The standard deviation of the sample was 1.7 years. What is the 95% confidence interval for the true population mean?
A) 6.46 and 6.54
B) 3.17 and 9.83
C) 6.13 and 6.87
D) 6.20 and 6.70
E) 6.32 and 6.88
A) 6.46 and 6.54
B) 3.17 and 9.83
C) 6.13 and 6.87
D) 6.20 and 6.70
E) 6.32 and 6.88
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75
The following summarizes the amount of snowfall in Ontario over the past number of years.
If 90% and 95% confidence intervals were developed to estimate the true average annual snowfall, what similarities would they have?
A) Point estimates
B) Z-values
C) Standard errors
D) Both point estimates and standard errors
E) Both point estimates and Z-Values

A) Point estimates
B) Z-values
C) Standard errors
D) Both point estimates and standard errors
E) Both point estimates and Z-Values
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76
A statistics professor wishes to estimate the average mark on a term test for a course that has multiple sections and many students. A survey of some of the students registered for the course reveals the following results:
The student from the course wonders whether the population mean could have been 60 or 80.
A) Since 80 is within the 95% confidence interval, the population mean is likely to be 80.
B) Since 80 is not within the 95% confidence interval, the population mean is not likely to be 80.
C) Since 60 is within the 95% confidence interval, the population mean is likely to be 60.
D) Since neither 60 nor 80 is within the 95% confidence interval, the population mean is not likely to be 60 or 80.

A) Since 80 is within the 95% confidence interval, the population mean is likely to be 80.
B) Since 80 is not within the 95% confidence interval, the population mean is not likely to be 80.
C) Since 60 is within the 95% confidence interval, the population mean is likely to be 60.
D) Since neither 60 nor 80 is within the 95% confidence interval, the population mean is not likely to be 60 or 80.
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77
The Sugar Producers Association wants to estimate the mean yearly sugar consumption. A sample of 16 people reveals the mean yearly consumption to be 27 kg with a sample standard deviation of 9 kg. Assume a normal population. For a 95% confidence interval, what is the critical value needed?
A) t = 1.753
B) t = 2.131
C) t = 2.947
D) z = 1.645
E) z = 1.96
A) t = 1.753
B) t = 2.131
C) t = 2.947
D) z = 1.645
E) z = 1.96
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78
A statistics professor wishes to estimate the average mark on a term test for a course that has multiple sections and many students. A survey of some of the students registered for the course reveals the following results:
If 90% and 95% confidence intervals were developed to estimate the true term test mean, what similarities would exist?
A) Point estimates
B) t-values
C) Standard errors
D) Both point estimates and standard errors
E) No similarities with point estimates, t-values or standard errors

A) Point estimates
B) t-values
C) Standard errors
D) Both point estimates and standard errors
E) No similarities with point estimates, t-values or standard errors
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79
The Sugar Producers Association wants to estimate the mean yearly sugar consumption. A sample of 16 people reveals the mean yearly consumption to be 27 kg with a sample standard deviation of 9 kg. Assume a normal population. For a 90% confidence interval, what is the critical value needed?
A) t = 1.753
B) t = 2.131
C) t = 2.947
D) z = 1.645
E) z = 1.96
A) t = 1.753
B) t = 2.131
C) t = 2.947
D) z = 1.645
E) z = 1.96
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80
A statistics professor wishes to estimate the average mark on a term test for a course that has multiple sections and many students. A survey of some of the students registered for the course reveals the following results:
If 95% and 98% confidence intervals were developed to estimate the true term test mean, what differences would exist?
A) Standard errors
B) Interval widths
C) t-values
D) Both interval widths and t-values

A) Standard errors
B) Interval widths
C) t-values
D) Both interval widths and t-values
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