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book Human Heredity 11th Edition by Michael Cummings cover

Human Heredity 11th Edition by Michael Cummings

Edition 11ISBN: 978-1305251052
book Human Heredity 11th Edition by Michael Cummings cover

Human Heredity 11th Edition by Michael Cummings

Edition 11ISBN: 978-1305251052
Exercise 2
Hypothetical metabolic disease in which protein E is not produced. Lack of protein E causes intellectual disability in humans. Protein E's function is not known, but it is found in all cells of the body. Skin cells from eight individuals who cannot produce protein E were taken and grown in culture. The defect in each of the individuals is the result of a single recessive mutation. Each individual is homozygous for her or his mutation. The cells from one individual were grown with the cells from another individual in all possible combinations of the two. After a few weeks of growth, the mixed cultures were assayed for the presence of protein E. The results are given in the following table. A plus sign means that the two cell types produced protein E when grown together (but not separately); a minus sign means that the two cell types still could not produce protein E. Hypothetical metabolic disease in which protein E is not produced. Lack of protein E causes intellectual disability in humans. Protein E's function is not known, but it is found in all cells of the body. Skin cells from eight individuals who cannot produce protein E were taken and grown in culture. The defect in each of the individuals is the result of a single recessive mutation. Each individual is homozygous for her or his mutation. The cells from one individual were grown with the cells from another individual in all possible combinations of the two. After a few weeks of growth, the mixed cultures were assayed for the presence of protein E. The results are given in the following table. A plus sign means that the two cell types produced protein E when grown together (but not separately); a minus sign means that the two cell types still could not produce protein E.   A) If an individual who is homozygous for the mutation found in individual 2 and heterozygous for the mutation found in individual 4 marries an individual who is homozygous for the mutation found in individual 4 and heterozygous for the mutation found in individual 2, what will be the phenotype of their children? B) List the intermediate that would build up in each of the types of children who could not produce protein E.
A) If an individual who is homozygous for the mutation found in individual 2 and heterozygous for the mutation found in individual 4 marries an individual who is homozygous for the mutation found in individual 4 and heterozygous for the mutation found in individual 2, what will be the phenotype of their children?
B) List the intermediate that would build up in each of the types of children who could not produce protein E.
Explanation
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Individual 1 and 6
It was found that th...

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Human Heredity 11th Edition by Michael Cummings
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