Deck 18: Electrochemistry

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Question
What is undergoing oxidation in the redox reaction represented by the following cell notation? Fe(s) ∣ Fe3+(aq) <strong>What is undergoing oxidation in the redox reaction represented by the following cell notation? Fe(s) ∣ Fe<sup>3+</sup>(aq)   Cl<sub>2</sub>(g) ∣ Cl⁻(aq) ∣ Pt(s)</strong> A) Fe(s) B) Fe<sup>3+</sup>(aq) C) Cl<sub>2</sub>(g) D) Cl⁻(aq) E) Pt(s) <div style=padding-top: 35px> Cl2(g) ∣ Cl⁻(aq) ∣ Pt(s)

A) Fe(s)
B) Fe3+(aq)
C) Cl2(g)
D) Cl⁻(aq)
E) Pt(s)
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Question
Which of the following is the strongest reducing agent?

A) Al(s)
B) Zn(s)
C) Mg(s)
D) Al3+(aq)
E) Mg2+(aq)
Question
Describe how water can be made to be a good conductor of electrical current.

A) use pure water
B) heat the water
C) add salt
D) chill the water
E) vaporize the water
Question
Determine the cell notation for the redox reaction given below: Sn(s) + 2Ag⁺(aq) → Sn2+(aq) + 2Ag(s)

A) Ag+(aq) ∣ Ag(s) <strong>Determine the cell notation for the redox reaction given below: Sn(s) + 2Ag⁺(aq) → Sn<sup>2+</sup>(aq) + 2Ag(s)</strong> A) Ag<sup>+</sup>(aq) ∣ Ag(s)   Sn(s) ∣ Sn<sup>2+</sup>(aq) B) Ag(s) ∣ Ag<sup>+</sup>(aq)   Sn<sup>2+</sup>(aq) ∣ Sn(s) C) Sn(s) ∣ Sn<sup>2+</sup>(aq)   Ag<sup>+</sup>(aq) ∣ Ag(s) D) Sn<sup>2+</sup>(aq) ∣ Sn(s)   Ag(s) ∣ Ag<sup>+</sup>(aq) E) Sn(s) ∣ Ag(s)   Sn<sup>2+</sup>(aq) ∣ Ag<sup>+</sup>(aq) <div style=padding-top: 35px> Sn(s) ∣ Sn2+(aq)
B) Ag(s) ∣ Ag+(aq) <strong>Determine the cell notation for the redox reaction given below: Sn(s) + 2Ag⁺(aq) → Sn<sup>2+</sup>(aq) + 2Ag(s)</strong> A) Ag<sup>+</sup>(aq) ∣ Ag(s)   Sn(s) ∣ Sn<sup>2+</sup>(aq) B) Ag(s) ∣ Ag<sup>+</sup>(aq)   Sn<sup>2+</sup>(aq) ∣ Sn(s) C) Sn(s) ∣ Sn<sup>2+</sup>(aq)   Ag<sup>+</sup>(aq) ∣ Ag(s) D) Sn<sup>2+</sup>(aq) ∣ Sn(s)   Ag(s) ∣ Ag<sup>+</sup>(aq) E) Sn(s) ∣ Ag(s)   Sn<sup>2+</sup>(aq) ∣ Ag<sup>+</sup>(aq) <div style=padding-top: 35px> Sn2+(aq) ∣ Sn(s)
C) Sn(s) ∣ Sn2+(aq) <strong>Determine the cell notation for the redox reaction given below: Sn(s) + 2Ag⁺(aq) → Sn<sup>2+</sup>(aq) + 2Ag(s)</strong> A) Ag<sup>+</sup>(aq) ∣ Ag(s)   Sn(s) ∣ Sn<sup>2+</sup>(aq) B) Ag(s) ∣ Ag<sup>+</sup>(aq)   Sn<sup>2+</sup>(aq) ∣ Sn(s) C) Sn(s) ∣ Sn<sup>2+</sup>(aq)   Ag<sup>+</sup>(aq) ∣ Ag(s) D) Sn<sup>2+</sup>(aq) ∣ Sn(s)   Ag(s) ∣ Ag<sup>+</sup>(aq) E) Sn(s) ∣ Ag(s)   Sn<sup>2+</sup>(aq) ∣ Ag<sup>+</sup>(aq) <div style=padding-top: 35px> Ag+(aq) ∣ Ag(s)
D) Sn2+(aq) ∣ Sn(s) <strong>Determine the cell notation for the redox reaction given below: Sn(s) + 2Ag⁺(aq) → Sn<sup>2+</sup>(aq) + 2Ag(s)</strong> A) Ag<sup>+</sup>(aq) ∣ Ag(s)   Sn(s) ∣ Sn<sup>2+</sup>(aq) B) Ag(s) ∣ Ag<sup>+</sup>(aq)   Sn<sup>2+</sup>(aq) ∣ Sn(s) C) Sn(s) ∣ Sn<sup>2+</sup>(aq)   Ag<sup>+</sup>(aq) ∣ Ag(s) D) Sn<sup>2+</sup>(aq) ∣ Sn(s)   Ag(s) ∣ Ag<sup>+</sup>(aq) E) Sn(s) ∣ Ag(s)   Sn<sup>2+</sup>(aq) ∣ Ag<sup>+</sup>(aq) <div style=padding-top: 35px> Ag(s) ∣ Ag+(aq)
E) Sn(s) ∣ Ag(s) <strong>Determine the cell notation for the redox reaction given below: Sn(s) + 2Ag⁺(aq) → Sn<sup>2+</sup>(aq) + 2Ag(s)</strong> A) Ag<sup>+</sup>(aq) ∣ Ag(s)   Sn(s) ∣ Sn<sup>2+</sup>(aq) B) Ag(s) ∣ Ag<sup>+</sup>(aq)   Sn<sup>2+</sup>(aq) ∣ Sn(s) C) Sn(s) ∣ Sn<sup>2+</sup>(aq)   Ag<sup>+</sup>(aq) ∣ Ag(s) D) Sn<sup>2+</sup>(aq) ∣ Sn(s)   Ag(s) ∣ Ag<sup>+</sup>(aq) E) Sn(s) ∣ Ag(s)   Sn<sup>2+</sup>(aq) ∣ Ag<sup>+</sup>(aq) <div style=padding-top: 35px> Sn2+(aq) ∣ Ag+(aq)
Question
Which of the following is the strongest reducing agent?

A) Na(s)
B) Li+(aq)
C) Ca(s)
D) Ca2+(aq)
E) Li(s)
Question
Which of the following is the strongest reducing agent?

A) Sn2+(aq)
B) Cr3+(aq)
C) Sn4+(aq)
D) Cr(s)
E) Sn(s)
Question
Which of the following is TRUE about standard electrode potentials?

A) E°cell is negative for spontaneous reactions.
B) Electrons will flow from a more positive electrode to a more negative electrode.
C) The electrode potential of the standard hydrogen electrode is exactly zero.
D) E°cell is the sum between standard reduction potentials of the anode and the cathode.
E) The electrode in any half-cell with a greater tendency to undergo reduction is negatively charged relative to the standard hydrogen electrode and therefore has E° < 0.
Question
How many electrons are transferred in the following reaction? (The reaction is unbalanced.) I2(s) + Fe(s) → Fe3+(aq) + I⁻(aq)

A) 1
B) 2
C) 6
D) 3
E) 4
Question
What is the oxidizing agent in the redox reaction represented by the following cell notation? Ni(s) ∣ Ni2+(aq) <strong>What is the oxidizing agent in the redox reaction represented by the following cell notation? Ni(s) ∣ Ni<sup>2+</sup>(aq)   Ag<sup>+</sup>(aq) ∣ Ag(s)</strong> A) Ni(s) B) Ni<sup>2+</sup>(aq) C) Ag<sup>+</sup>(aq) D) Ag(s) E) Pt(s) <div style=padding-top: 35px> Ag+(aq) ∣ Ag(s)

A) Ni(s)
B) Ni2+(aq)
C) Ag+(aq)
D) Ag(s)
E) Pt(s)
Question
Determine the redox reaction represented by the following cell notation: Mg(s) ∣ Mg2+(aq) <strong>Determine the redox reaction represented by the following cell notation: Mg(s) ∣ Mg<sup>2+</sup>(aq)   Cu<sup>2+</sup>(aq) ∣ Cu(s)</strong> A) Cu(s) + Mg<sup>2+</sup>(aq) → Mg(s) + Cu<sup>2+</sup>(aq) B) Mg(s) + Cu<sup>2+</sup>(aq) → Cu(s) + Mg<sup>2+</sup>(aq) C) 2Mg(s) + Cu<sup>2+</sup>(aq) → Cu(s) + 2Mg<sup>2+</sup>(aq) D) 2Cu(s) + Mg<sup>2+</sup>(aq) → Mg(s) + 2Cu<sup>2+</sup>(aq) E) 3Mg(s) + 2Cu<sup>2+</sup>(aq) → 2Cu(s) + 3Mg<sup>2+</sup>(aq) <div style=padding-top: 35px> Cu2+(aq) ∣ Cu(s)

A) Cu(s) + Mg2+(aq) → Mg(s) + Cu2+(aq)
B) Mg(s) + Cu2+(aq) → Cu(s) + Mg2+(aq)
C) 2Mg(s) + Cu2+(aq) → Cu(s) + 2Mg2+(aq)
D) 2Cu(s) + Mg2+(aq) → Mg(s) + 2Cu2+(aq)
E) 3Mg(s) + 2Cu2+(aq) → 2Cu(s) + 3Mg2+(aq)
Question
Which of the following is the weakest oxidizing agent?

A) Sn2+(aq)
B) Cr3+(aq)
C) Sn4+(aq)
D) Cr(s)
E) Sn(s)
Question
What is undergoing reduction in the redox reaction represented by the following cell notation? Fe(s) ∣ Fe3+(aq) <strong>What is undergoing reduction in the redox reaction represented by the following cell notation? Fe(s) ∣ Fe<sup>3+</sup>(aq)   Cl<sub>2</sub>(g) ∣ Cl⁻(aq) ∣ Pt(s)</strong> A) Fe(s) B) Fe<sup>3+</sup>(aq) C) Cl<sub>2</sub>(g) D) Cl⁻(aq) E) Pt(s) <div style=padding-top: 35px> Cl2(g) ∣ Cl⁻(aq) ∣ Pt(s)

A) Fe(s)
B) Fe3+(aq)
C) Cl2(g)
D) Cl⁻(aq)
E) Pt(s)
Question
What is the reducing agent in the redox reaction represented by the following cell notation? Ni(s) ∣ Ni2+(aq) <strong>What is the reducing agent in the redox reaction represented by the following cell notation? Ni(s) ∣ Ni<sup>2+</sup>(aq)   Ag<sup>+</sup>(aq) ∣ Ag(s)</strong> A) Ni(s) B) Ni<sup>2+</sup>(aq) C) Ag<sup>+</sup>(aq) D) Ag(s) E) Pt(s) <div style=padding-top: 35px> Ag+(aq) ∣ Ag(s)

A) Ni(s)
B) Ni2+(aq)
C) Ag+(aq)
D) Ag(s)
E) Pt(s)
Question
What is undergoing oxidation in the redox reaction represented by the following cell notation? Pb(s) ∣ Pb2+(aq) <strong>What is undergoing oxidation in the redox reaction represented by the following cell notation? Pb(s) ∣ Pb<sup>2+</sup>(aq)   H<sup>+</sup>(aq) ∣ H<sub>2</sub>(g) ∣ Pt(s)</strong> A) H<sub>2</sub>(g) B) H<sup>+</sup>(aq) C) Pb<sup>2+</sup>(aq) D) Pb(s) E) Pt(s) <div style=padding-top: 35px> H+(aq) ∣ H2(g) ∣ Pt(s)

A) H2(g)
B) H+(aq)
C) Pb2+(aq)
D) Pb(s)
E) Pt(s)
Question
Determine the cell notation for the redox reaction given below: Pb(s) + 2H⁺(aq) → Pb2+(aq) + H2(g)

A) H+(aq) ∣ H2(g) ∣ Pt(s) <strong>Determine the cell notation for the redox reaction given below: Pb(s) + 2H⁺(aq) → Pb<sup>2+</sup>(aq) + H<sub>2</sub>(g)</strong> A) H<sup>+</sup>(aq) ∣ H<sub>2</sub>(g) ∣ Pt(s)   Pb(s) ∣ Pb<sup>2+</sup>(aq) B) H<sub>2</sub>(g) ∣ H<sup>+</sup>(aq) ∣ Pt(s)   Pb<sup>2+</sup>(aq) ∣ Pb(s) C) Pb<sup>2+</sup>(aq) ∣ Pb(s)   H<sub>2</sub>(g) ∣ H<sup>+</sup>(aq) ∣ Pt(s) D) Pb(s) ∣ Pb<sup>2+</sup>(aq)   H<sup>+</sup>(aq) ∣ H<sub>2</sub>(g) ∣ Pt(s) E) Pb(s) ∣ H<sub>2</sub>(g)   Pb<sup>2+</sup>(aq) ∣ H<sup>+</sup>(aq) ∣ Pt(s) <div style=padding-top: 35px> Pb(s) ∣ Pb2+(aq)
B) H2(g) ∣ H+(aq) ∣ Pt(s) <strong>Determine the cell notation for the redox reaction given below: Pb(s) + 2H⁺(aq) → Pb<sup>2+</sup>(aq) + H<sub>2</sub>(g)</strong> A) H<sup>+</sup>(aq) ∣ H<sub>2</sub>(g) ∣ Pt(s)   Pb(s) ∣ Pb<sup>2+</sup>(aq) B) H<sub>2</sub>(g) ∣ H<sup>+</sup>(aq) ∣ Pt(s)   Pb<sup>2+</sup>(aq) ∣ Pb(s) C) Pb<sup>2+</sup>(aq) ∣ Pb(s)   H<sub>2</sub>(g) ∣ H<sup>+</sup>(aq) ∣ Pt(s) D) Pb(s) ∣ Pb<sup>2+</sup>(aq)   H<sup>+</sup>(aq) ∣ H<sub>2</sub>(g) ∣ Pt(s) E) Pb(s) ∣ H<sub>2</sub>(g)   Pb<sup>2+</sup>(aq) ∣ H<sup>+</sup>(aq) ∣ Pt(s) <div style=padding-top: 35px> Pb2+(aq) ∣ Pb(s)
C) Pb2+(aq) ∣ Pb(s) <strong>Determine the cell notation for the redox reaction given below: Pb(s) + 2H⁺(aq) → Pb<sup>2+</sup>(aq) + H<sub>2</sub>(g)</strong> A) H<sup>+</sup>(aq) ∣ H<sub>2</sub>(g) ∣ Pt(s)   Pb(s) ∣ Pb<sup>2+</sup>(aq) B) H<sub>2</sub>(g) ∣ H<sup>+</sup>(aq) ∣ Pt(s)   Pb<sup>2+</sup>(aq) ∣ Pb(s) C) Pb<sup>2+</sup>(aq) ∣ Pb(s)   H<sub>2</sub>(g) ∣ H<sup>+</sup>(aq) ∣ Pt(s) D) Pb(s) ∣ Pb<sup>2+</sup>(aq)   H<sup>+</sup>(aq) ∣ H<sub>2</sub>(g) ∣ Pt(s) E) Pb(s) ∣ H<sub>2</sub>(g)   Pb<sup>2+</sup>(aq) ∣ H<sup>+</sup>(aq) ∣ Pt(s) <div style=padding-top: 35px> H2(g) ∣ H+(aq) ∣ Pt(s)
D) Pb(s) ∣ Pb2+(aq) <strong>Determine the cell notation for the redox reaction given below: Pb(s) + 2H⁺(aq) → Pb<sup>2+</sup>(aq) + H<sub>2</sub>(g)</strong> A) H<sup>+</sup>(aq) ∣ H<sub>2</sub>(g) ∣ Pt(s)   Pb(s) ∣ Pb<sup>2+</sup>(aq) B) H<sub>2</sub>(g) ∣ H<sup>+</sup>(aq) ∣ Pt(s)   Pb<sup>2+</sup>(aq) ∣ Pb(s) C) Pb<sup>2+</sup>(aq) ∣ Pb(s)   H<sub>2</sub>(g) ∣ H<sup>+</sup>(aq) ∣ Pt(s) D) Pb(s) ∣ Pb<sup>2+</sup>(aq)   H<sup>+</sup>(aq) ∣ H<sub>2</sub>(g) ∣ Pt(s) E) Pb(s) ∣ H<sub>2</sub>(g)   Pb<sup>2+</sup>(aq) ∣ H<sup>+</sup>(aq) ∣ Pt(s) <div style=padding-top: 35px> H+(aq) ∣ H2(g) ∣ Pt(s)
E) Pb(s) ∣ H2(g) <strong>Determine the cell notation for the redox reaction given below: Pb(s) + 2H⁺(aq) → Pb<sup>2+</sup>(aq) + H<sub>2</sub>(g)</strong> A) H<sup>+</sup>(aq) ∣ H<sub>2</sub>(g) ∣ Pt(s)   Pb(s) ∣ Pb<sup>2+</sup>(aq) B) H<sub>2</sub>(g) ∣ H<sup>+</sup>(aq) ∣ Pt(s)   Pb<sup>2+</sup>(aq) ∣ Pb(s) C) Pb<sup>2+</sup>(aq) ∣ Pb(s)   H<sub>2</sub>(g) ∣ H<sup>+</sup>(aq) ∣ Pt(s) D) Pb(s) ∣ Pb<sup>2+</sup>(aq)   H<sup>+</sup>(aq) ∣ H<sub>2</sub>(g) ∣ Pt(s) E) Pb(s) ∣ H<sub>2</sub>(g)   Pb<sup>2+</sup>(aq) ∣ H<sup>+</sup>(aq) ∣ Pt(s) <div style=padding-top: 35px> Pb2+(aq) ∣ H+(aq) ∣ Pt(s)
Question
Determine the cell notation for the redox reaction given below: 3Cl2(g) + 2Fe(s) → 6Cl⁻(aq) + 2Fe3+(aq)

A) Cl2(g) ∣ Cl⁻(aq) ∣ Pt(s) <strong>Determine the cell notation for the redox reaction given below: 3Cl<sub>2</sub>(g) + 2Fe(s) → 6Cl⁻(aq) + 2Fe<sup>3+</sup>(aq)</strong> A) Cl<sub>2</sub>(g) ∣ Cl⁻(aq) ∣ Pt(s)   Fe(s) ∣ Fe<sup>3+</sup>(aq) B) Cl⁻(aq) ∣ Cl<sub>2</sub>(g) ∣ Pt(s)   Fe<sup>3+</sup>(aq)<sup> </sup>∣<sup> </sup>Fe(s) C) Fe<sup>3+</sup>(aq) ∣ Fe(s)   Cl⁻(aq) ∣ Cl<sub>2</sub>(g) ∣ Pt(s) D) Fe(s) ∣ Cl<sub>2</sub>(g)   Fe<sup>3+</sup>(aq) ∣ Cl⁻(aq) ∣ Pt(s) E) Fe(s) ∣ Fe<sup>3+</sup>(aq)   Cl<sub>2</sub>(g) ∣ Cl⁻(aq) ∣ Pt(s) <div style=padding-top: 35px> Fe(s) ∣ Fe3+(aq)
B) Cl⁻(aq) ∣ Cl2(g) ∣ Pt(s) <strong>Determine the cell notation for the redox reaction given below: 3Cl<sub>2</sub>(g) + 2Fe(s) → 6Cl⁻(aq) + 2Fe<sup>3+</sup>(aq)</strong> A) Cl<sub>2</sub>(g) ∣ Cl⁻(aq) ∣ Pt(s)   Fe(s) ∣ Fe<sup>3+</sup>(aq) B) Cl⁻(aq) ∣ Cl<sub>2</sub>(g) ∣ Pt(s)   Fe<sup>3+</sup>(aq)<sup> </sup>∣<sup> </sup>Fe(s) C) Fe<sup>3+</sup>(aq) ∣ Fe(s)   Cl⁻(aq) ∣ Cl<sub>2</sub>(g) ∣ Pt(s) D) Fe(s) ∣ Cl<sub>2</sub>(g)   Fe<sup>3+</sup>(aq) ∣ Cl⁻(aq) ∣ Pt(s) E) Fe(s) ∣ Fe<sup>3+</sup>(aq)   Cl<sub>2</sub>(g) ∣ Cl⁻(aq) ∣ Pt(s) <div style=padding-top: 35px> Fe3+(aq) Fe(s)
C) Fe3+(aq) ∣ Fe(s) <strong>Determine the cell notation for the redox reaction given below: 3Cl<sub>2</sub>(g) + 2Fe(s) → 6Cl⁻(aq) + 2Fe<sup>3+</sup>(aq)</strong> A) Cl<sub>2</sub>(g) ∣ Cl⁻(aq) ∣ Pt(s)   Fe(s) ∣ Fe<sup>3+</sup>(aq) B) Cl⁻(aq) ∣ Cl<sub>2</sub>(g) ∣ Pt(s)   Fe<sup>3+</sup>(aq)<sup> </sup>∣<sup> </sup>Fe(s) C) Fe<sup>3+</sup>(aq) ∣ Fe(s)   Cl⁻(aq) ∣ Cl<sub>2</sub>(g) ∣ Pt(s) D) Fe(s) ∣ Cl<sub>2</sub>(g)   Fe<sup>3+</sup>(aq) ∣ Cl⁻(aq) ∣ Pt(s) E) Fe(s) ∣ Fe<sup>3+</sup>(aq)   Cl<sub>2</sub>(g) ∣ Cl⁻(aq) ∣ Pt(s) <div style=padding-top: 35px> Cl⁻(aq) ∣ Cl2(g) ∣ Pt(s)
D) Fe(s) ∣ Cl2(g) <strong>Determine the cell notation for the redox reaction given below: 3Cl<sub>2</sub>(g) + 2Fe(s) → 6Cl⁻(aq) + 2Fe<sup>3+</sup>(aq)</strong> A) Cl<sub>2</sub>(g) ∣ Cl⁻(aq) ∣ Pt(s)   Fe(s) ∣ Fe<sup>3+</sup>(aq) B) Cl⁻(aq) ∣ Cl<sub>2</sub>(g) ∣ Pt(s)   Fe<sup>3+</sup>(aq)<sup> </sup>∣<sup> </sup>Fe(s) C) Fe<sup>3+</sup>(aq) ∣ Fe(s)   Cl⁻(aq) ∣ Cl<sub>2</sub>(g) ∣ Pt(s) D) Fe(s) ∣ Cl<sub>2</sub>(g)   Fe<sup>3+</sup>(aq) ∣ Cl⁻(aq) ∣ Pt(s) E) Fe(s) ∣ Fe<sup>3+</sup>(aq)   Cl<sub>2</sub>(g) ∣ Cl⁻(aq) ∣ Pt(s) <div style=padding-top: 35px> Fe3+(aq) ∣ Cl⁻(aq) ∣ Pt(s)
E) Fe(s) ∣ Fe3+(aq) <strong>Determine the cell notation for the redox reaction given below: 3Cl<sub>2</sub>(g) + 2Fe(s) → 6Cl⁻(aq) + 2Fe<sup>3+</sup>(aq)</strong> A) Cl<sub>2</sub>(g) ∣ Cl⁻(aq) ∣ Pt(s)   Fe(s) ∣ Fe<sup>3+</sup>(aq) B) Cl⁻(aq) ∣ Cl<sub>2</sub>(g) ∣ Pt(s)   Fe<sup>3+</sup>(aq)<sup> </sup>∣<sup> </sup>Fe(s) C) Fe<sup>3+</sup>(aq) ∣ Fe(s)   Cl⁻(aq) ∣ Cl<sub>2</sub>(g) ∣ Pt(s) D) Fe(s) ∣ Cl<sub>2</sub>(g)   Fe<sup>3+</sup>(aq) ∣ Cl⁻(aq) ∣ Pt(s) E) Fe(s) ∣ Fe<sup>3+</sup>(aq)   Cl<sub>2</sub>(g) ∣ Cl⁻(aq) ∣ Pt(s) <div style=padding-top: 35px> Cl2(g) ∣ Cl⁻(aq) ∣ Pt(s)
Question
How many electrons are transferred in the following reaction? (The reaction is unbalanced.) Fe2+(aq) + K(s) → Fe(s) + K+(aq)

A) 1
B) 2
C) 3
D) 4
E) 6
Question
What is the oxidizing agent in the redox reaction represented by the following cell notation? Sn(s) ∣ Sn2+(aq) <strong>What is the oxidizing agent in the redox reaction represented by the following cell notation? Sn(s) ∣ Sn<sup>2+</sup>(aq)   Ag<sup>+</sup>(aq) ∣ Ag(s)</strong> A) Sn(s) B) Ag<sup>+</sup>(aq) C) Sn<sup>2+</sup>(aq) D) Ag(s) E) Pt(s) <div style=padding-top: 35px> Ag+(aq) ∣ Ag(s)

A) Sn(s)
B) Ag+(aq)
C) Sn2+(aq)
D) Ag(s)
E) Pt(s)
Question
What is the reducing agent in the redox reaction represented by the following cell notation? Sn(s) ∣ Sn2+(aq) <strong>What is the reducing agent in the redox reaction represented by the following cell notation? Sn(s) ∣ Sn<sup>2+</sup>(aq)   Ag<sup>+</sup>(aq) ∣ Ag(s)</strong> A) Sn(s) B) Ag<sup>+</sup>(aq) C) Sn<sup>2+</sup>(aq) D) Ag(s) E) Pt(s) <div style=padding-top: 35px> Ag+(aq) ∣ Ag(s)

A) Sn(s)
B) Ag+(aq)
C) Sn2+(aq)
D) Ag(s)
E) Pt(s)
Question
What is undergoing reduction in the redox reaction represented by the following cell notation? Pb(s) ∣ Pb2+(aq) <strong>What is undergoing reduction in the redox reaction represented by the following cell notation? Pb(s) ∣ Pb<sup>2+</sup>(aq)   H<sup>+</sup>(aq) ∣ H<sub>2</sub>(g) ∣ Pt(s)</strong> A) H<sub>2</sub>(g) B) H<sup>+</sup>(aq) C) Pb<sup>2+</sup>(aq) D) Pb(s) E) Pt(s) <div style=padding-top: 35px> H+(aq) ∣ H2(g) ∣ Pt(s)

A) H2(g)
B) H+(aq)
C) Pb2+(aq)
D) Pb(s)
E) Pt(s)
Question
Which of the following is the weakest oxidizing agent?

A) Cl2(g)
B) Au+3(aq)
C) F2(g)
D) O2(g)
E) Br2(l)
Question
Which of the following is the weakest oxidizing agent?

A) H2O2(aq)
B) Fe3+(aq)
C) ClO2(g)
D) I2(s)
E) Fe(s)
Question
Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring in an electrochemical cell at 25 °C. (The equation is balanced.) 2K(s) + I2(s) → 2K⁺(aq) + 2I⁻(aq)
K+(aq) + e⁻ → K (s) E° = -2.93 V
I2(s) + 2 e⁻ → 2 I⁻(aq) E° = +0.54 V

A) +6.40 V
B) +1.85 V
C) -5.32 V
D) +3.47 V
E) +5.32 V
Question
Which of the following is the strongest oxidizing agent?

A) Cl2(g)
B) Au+3(aq)
C) F2(g)
D) O2(g)
E) Fe(s)
Question
Which of the following is the weakest reducing agent?

A) Br2(l)
B) Au3+(aq)
C) Ag(s)
D) Br⁻(aq)
E) Au(s)
Question
Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring in an electrochemical cell at 25 °C. (The equation is balanced.) 3Cl2(g) + 2Fe(s) → 6Cl⁻(aq) + 2Fe3+(aq)
Cl2(g) + 2 e⁻ → 2Cl⁻(aq) E° = +1.36 V
Fe3+(aq) + 3 e⁻ → Fe(s) E° = -0.04 V

A) +4.16 V
B) -1.40 V
C) -1.32 V
D) +1.32 V
E) +1.40 V
Question
Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring in an electrochemical cell at 25 °C. (The equation is balanced.) 2 Ag+(aq) + Pb(s) → 2Ag(s) + Pb2+(aq)
Ag+(aq) + e- → Ag(s) E°= 0.80 V
Pb2+(aq) + 2 e- → Pb(s) E°= -0.13 V

A) +0.93 V
B) +1.85 V
C) -5.32 V
D) +5.47 V
E) +0.67 V
Question
Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring in an electrochemical cell at 25°C. (The equation is balanced.) Br2(l) + 2Cl-(aq) → 2Br-(aq) + Cl2 (g)
Br2(l) + 2 e → 2Br-(aq) E°= 1.09 V
2Cl- (aq) → Cl2(g) + 2 e - E°= -1.36 V

A) +0.93 V
B) +2.24 V
C) +2.45 V
D) +5.47 V
E) +0.67 V
Question
Which of the following reactions would be the most spontaneous at 298 K?

A) A + 2 B → C; E°cell = +0.98 V
B) A + B → 2 C; E°cell = -0.030 V
C) A + B → 3 C; E°cell = +0.15 V
D) A + B → C; E°cell = +1.22 V
E) A + B → C; E°cell = -1.22 V
Question
Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring in an electrochemical cell at 2 5°C. (The equation is balanced.) Pb(s) + Br2(l) → Pb2+(aq) + 2 Br⁻(aq)
Pb2+(aq) + 2 e⁻ → Pb(s) E° = -0.13 V
Br2(l) + 2 e⁻ → 2 Br⁻(aq) E° = +1.07 V

A) +1.20 V
B) +0.94 V
C) -0.94 V
D) -1.20 V
E) -0.60 V
Question
Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring in an electrochemical cell at 25°C. (The equation is balanced.) Pb2+(aq) + Mg(s) → Pb(s) + Mg2+(aq)
Mg2+(aq) +2 e- →Mg(s) E°= -2.37 V
Pb2+(aq) + 2e- → Pb(s) E°= -0.13 V

A) +0.93 V
B) +2.24 V
C) -5.32 V
D) +5.47 V
E) +0.67 V
Question
Which of the following is the strongest oxidizing agent?

A) H2O2(aq)
B) Fe3+(aq)
C) ClO2(g)
D) I2(s)
E) Fe(s)
Question
Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring in an electrochemical cell at 25 °C. (The equation is balanced.) Sn(s) + 2Ag⁺(aq) → Sn2+(aq) + 2Ag(s)
Sn2+(aq) + 2 e⁻ → Sn(s) E° = -0.14 V
Ag⁺(aq) + e⁻ → Ag(s) E° = +0.80 V

A) +1.74 V
B) +0.94 V
C) +1.08 V
D) -1.08 V
E) -1.74 V
Question
Determine which of the following pairs of reactants will result in a spontaneous reaction at 25 °C.

A) Pb2+(aq) + Cu(s); if E°(Pb2+/Pb) = -0.13V and E°(Cu2+/Cu) = +0.16V
B) Ag+(aq) + Br⁻(aq); if E°(Ag+/Ag) = 0.80V and E°(Br2/Br-) = +1.09V
C) Li+(aq) + Al(s); if E°(Li+/Li) = -3.04V and E°(Al3+/Al) = -1.66V
D) Fe3+(aq) + Ni(s); if E°(Fe3+/Fe) = -0.04V and E°(Ni2+/Ni) = -0.23V
E) Cd2+(aq) + I-(aq); if E°(Cd2+/Cd) = -0.40V and E°(I2/I-) = + 0.54V
Question
Which of the following is the strongest oxidizing agent?

A) MnO2(s)
B) Cl⁻(aq)
C) Cu⁺(aq)
D) SO42-(aq)
E) MnO4⁻(aq)
Question
Which of the following statements is true for the cell diagram below? Zn(s) ∣ Zn2+(aq) <strong>Which of the following statements is true for the cell diagram below? Zn(s) ∣ Zn<sup>2+</sup>(aq)   Cu<sup>2+</sup>(aq) ∣ Cu(s)</strong> A) Zn is oxidized, Cu is reduced; the single vertical lines represent phase boundaries while the two vertical lines represent a salt bridge. B) Zn<sup>2+</sup>is oxidized, Cu is reduced; the single vertical lines represent phase boundaries while the two vertical lines represent a salt bridge. C) Zn is oxidized, Cu<sup>2+</sup> is reduced; the single vertical lines represent phase boundaries while the two vertical lines represent a salt bridge. D) Zn is oxidized, Cu<sup>2+</sup> is reduced; the single vertical lines represent salt bridges while the two vertical lines represent a phase boundary. E) Zn is reduced, Cu<sup>2+</sup> is oxidized; the single vertical lines represent phase boundaries while the two vertical lines represent a salt bridge. <div style=padding-top: 35px> Cu2+(aq) ∣ Cu(s)

A) Zn is oxidized, Cu is reduced; the single vertical lines represent phase boundaries while the two vertical lines represent a salt bridge.
B) Zn2+is oxidized, Cu is reduced; the single vertical lines represent phase boundaries while the two vertical lines represent a salt bridge.
C) Zn is oxidized, Cu2+ is reduced; the single vertical lines represent phase boundaries while the two vertical lines represent a salt bridge.
D) Zn is oxidized, Cu2+ is reduced; the single vertical lines represent salt bridges while the two vertical lines represent a phase boundary.
E) Zn is reduced, Cu2+ is oxidized; the single vertical lines represent phase boundaries while the two vertical lines represent a salt bridge.
Question
Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring in an electrochemical cell at 25 °C. (The equation is balanced.) Mg(s) + Cu2+(aq) → Cu(s) + Mg2+(aq)
Mg2+(aq) + 2 e⁻ → Mg(s) E° = -2.38 V
Cu2+(aq) + 2 e⁻ → Cu(s) E° = +0.34 V

A) +2.04 V
B) -2.04 V
C) +2.72 V
D) -1.36 V
E) +1.36 V
Question
Which of the following is the weakest reducing agent?

A) Cl2(g)
B) Au+3 (aq)
C) F2(g)
D) O2(g)
E) Fe(s)
Question
Which of the following is the strongest oxidizing agent?

A) Al(s)
B) Zn2+(aq)
C) Mg(s)
D) Al3+(aq)
E) Mg2+(aq)
Question
Which of the following is the strongest oxidizing agent?

A) Br2(l)
B) Au3+(aq)
C) Ag(s)
D) Br⁻(aq)
E) Au(s)
Question
Use the provided reduction potentials to calculate the equilibrium constant (K) for the following balanced redox reaction at 25 °C: 2Al(s) + 3Mg2+(aq) → 2Al3+(aq) + 3Mg(s)
E°(Al3+/Al) = -1.66 V and E°(Mg2+/Mg) = -2.37 V

A) 1.1 × 1072
B) 8.9 × 10-70
C) 9.7 × 10-73
D) 1.0 × 1024
E) 4.6 × 1031
Question
Use the provided reduction potentials to calculate ΔrG° for the following redox reaction: 2Al(s) + 3Mg2+(aq) → 2Al3+(aq) + 3Mg(s)
E°(Al3+/Al) = -1.66 V and E°(Mg2+/Mg) = -2.37 V

A) +4.1 × 102 kJ mol-1
B) +1.4 × 102 kJ mol-1
C) -2.3 × 102 kJ mol-1
D) -7.8 × 102 kJ mol-1
E) +6.8 × 102 kJ mol-1
Question
Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.945 M and [   ] = 1.37 M Zn(s) +   (aq) →   (aq) + Cr(s) E°(Zn<sup>2+</sup>/Zn) = -0.76 V and E°(Cr<sup>3</sup><sup>+</sup>/Cr) = -0.73 V</strong> A) +0.03 V B) -0.03 V C) -1.18 V D) +1.18 V E) +0.49 V <div style=padding-top: 35px> ] = 0.945 M and [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.945 M and [   ] = 1.37 M Zn(s) +   (aq) →   (aq) + Cr(s) E°(Zn<sup>2+</sup>/Zn) = -0.76 V and E°(Cr<sup>3</sup><sup>+</sup>/Cr) = -0.73 V</strong> A) +0.03 V B) -0.03 V C) -1.18 V D) +1.18 V E) +0.49 V <div style=padding-top: 35px> ] = 1.37 M Zn(s) + <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.945 M and [   ] = 1.37 M Zn(s) +   (aq) →   (aq) + Cr(s) E°(Zn<sup>2+</sup>/Zn) = -0.76 V and E°(Cr<sup>3</sup><sup>+</sup>/Cr) = -0.73 V</strong> A) +0.03 V B) -0.03 V C) -1.18 V D) +1.18 V E) +0.49 V <div style=padding-top: 35px> (aq) → <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.945 M and [   ] = 1.37 M Zn(s) +   (aq) →   (aq) + Cr(s) E°(Zn<sup>2+</sup>/Zn) = -0.76 V and E°(Cr<sup>3</sup><sup>+</sup>/Cr) = -0.73 V</strong> A) +0.03 V B) -0.03 V C) -1.18 V D) +1.18 V E) +0.49 V <div style=padding-top: 35px> (aq) + Cr(s)
E°(Zn2+/Zn) = -0.76 V and E°(Cr3+/Cr) = -0.73 V

A) +0.03 V
B) -0.03 V
C) -1.18 V
D) +1.18 V
E) +0.49 V
Question
Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.914 M and [   ] = 0.0230 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +2.32 V B) +2.30 V C) -2.32 V D) -2.30 V E) +1.23 V <div style=padding-top: 35px> ] = 0.914 M and [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.914 M and [   ] = 0.0230 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +2.32 V B) +2.30 V C) -2.32 V D) -2.30 V E) +1.23 V <div style=padding-top: 35px> ] = 0.0230 M Mg(s) + <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.914 M and [   ] = 0.0230 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +2.32 V B) +2.30 V C) -2.32 V D) -2.30 V E) +1.23 V <div style=padding-top: 35px> (aq) → <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.914 M and [   ] = 0.0230 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +2.32 V B) +2.30 V C) -2.32 V D) -2.30 V E) +1.23 V <div style=padding-top: 35px> (aq) + Fe(s)
E°(Mg2+/Mg) = -2.37 V and E°(Fe3+/Fe) = -0.036 V

A) +2.32 V
B) +2.30 V
C) -2.32 V
D) -2.30 V
E) +1.23 V
Question
Which of the following metals will dissolve in HCl?

A) Au; E°(Au3+/Au) = +1.50V
B) Ag; E°(Ag+/Ag) = +0.80V
C) Cu; E°(Cu2+/Cu) = +0.34V
D) Al; E°(Al3+/Al) = -1.66V
E) Pt; E°(Pt2+/Pt) = +1.19V
Question
Determine which of the following pairs of reactants will result in a spontaneous reaction at 25 °C.

A) Sn4+(aq) + Mg(s); if E°(Sn4+/Sn2+) = +0.15V and E°(Mg2+/Mg) = -2.37V
B) Cr3+(aq) + Ni(s); if E°(Cr3+/Cr) = -0.73V and E°(Ni2+/Ni) = -0.23V
C) Zn(s) + Na+(aq); if E°(Zn2+/Zn) = -0.76V and E°(Na+/Na) = -2.71V
D) Fe(s) + Ba2+(aq); if E°(Fe3+/Fe) = -0.04V and E°(Ba2+/Ba) = -2.90V
E) Ni2+(aq) + NO(g); if E°(Ni2+/Ni) = -0.23V and E°(NO3-/NO) = +0.96V
Question
If the standard reduction potential of Zn is -0.76 V, which of the following statements about a cell whose half-cells are Zn2+/Zn and SHE is correct?

A) SHE will be the cell's cathode, Zn(s) will be the cell's anode, and the measured cell potential will be 0.76 V.
B) SHE will be the cell's anode, Zn(s) will be the cell's cathode, and the measured cell potential will be 0.76 V.
C) SHE will be the cell's cathode, Zn(s) will be the cell's anode, and the measured cell potential will be -0.76 V.
D) SHE will be the cell's cathode, Zn2+(aq) will be the cell's anode, and the measured cell potential will be 0.76 V.
E) H+(aq) will be the cell's cathode, Zn2+(aq) will be the cell's anode, and the measured cell potential will be 0.76 V.
Question
Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 2.00 M and [   ] = 0.00300 M Zn(s) +   (aq) →   (aq) + Cr(s) E°(Zn<sup>2+</sup>/Zn) = -0.76 V and E°(Cr<sup>3+</sup>/Cr) = -0.73 V</strong> A) +0.06 V B) -0.19 V C) +1.30 V D) +0.02 V E) +0.11 V <div style=padding-top: 35px> ] = 2.00 M and [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 2.00 M and [   ] = 0.00300 M Zn(s) +   (aq) →   (aq) + Cr(s) E°(Zn<sup>2+</sup>/Zn) = -0.76 V and E°(Cr<sup>3+</sup>/Cr) = -0.73 V</strong> A) +0.06 V B) -0.19 V C) +1.30 V D) +0.02 V E) +0.11 V <div style=padding-top: 35px> ] = 0.00300 M Zn(s) + <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 2.00 M and [   ] = 0.00300 M Zn(s) +   (aq) →   (aq) + Cr(s) E°(Zn<sup>2+</sup>/Zn) = -0.76 V and E°(Cr<sup>3+</sup>/Cr) = -0.73 V</strong> A) +0.06 V B) -0.19 V C) +1.30 V D) +0.02 V E) +0.11 V <div style=padding-top: 35px> (aq) → <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 2.00 M and [   ] = 0.00300 M Zn(s) +   (aq) →   (aq) + Cr(s) E°(Zn<sup>2+</sup>/Zn) = -0.76 V and E°(Cr<sup>3+</sup>/Cr) = -0.73 V</strong> A) +0.06 V B) -0.19 V C) +1.30 V D) +0.02 V E) +0.11 V <div style=padding-top: 35px> (aq) + Cr(s)
E°(Zn2+/Zn) = -0.76 V and E°(Cr3+/Cr) = -0.73 V

A) +0.06 V
B) -0.19 V
C) +1.30 V
D) +0.02 V
E) +0.11 V
Question
Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 3.20 M and [   ] = 0.000100 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) -2.24 V B) +2.24 V C) +1.24 V D) -1.24 V E) +2.14 V <div style=padding-top: 35px> ] = 3.20 M and [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 3.20 M and [   ] = 0.000100 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) -2.24 V B) +2.24 V C) +1.24 V D) -1.24 V E) +2.14 V <div style=padding-top: 35px> ] = 0.000100 M Mg(s) + <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 3.20 M and [   ] = 0.000100 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) -2.24 V B) +2.24 V C) +1.24 V D) -1.24 V E) +2.14 V <div style=padding-top: 35px> (aq) → <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 3.20 M and [   ] = 0.000100 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) -2.24 V B) +2.24 V C) +1.24 V D) -1.24 V E) +2.14 V <div style=padding-top: 35px> (aq) + Fe(s)
E°(Mg2+/Mg) = -2.37 V and E°(Fe3+/Fe) = -0.036 V

A) -2.24 V
B) +2.24 V
C) +1.24 V
D) -1.24 V
E) +2.14 V
Question
Use the tabulated half-cell potentials to calculate the equilibrium constant (K) for the following balanced redox reaction at 25 °C: 3I2(s) + 2Fe(s) → 2Fe3+(aq) + 6I⁻(aq)
E°(I2/I-) = + 0.54 V and E°(Fe3+/Fe) = -0.036 V

A) 3.5 × 10-59
B) 1.1 × 1017
C) 2.4 × 1058
D) 8.9 × 10-18
E) 1.7 × 1029
Question
Identify the characteristics of a spontaneous reaction.

A) ΔrG° > 0
B) ΔE°cell < 0
C) K < 0
D) ΔE°cell > 0
E) K = 0
Question
Which of the following metals will dissolve in nitric acid but not hydrochloric acid?

A) Fe; E°(Fe2+/Fe) = -0.45V
B) Pb; E°(Pb2+/Pb) = -0.13V
C) Cu; E°(Cu2+/Cu) = +0.34V
D) Sn; E°(Sn2+/Sn) = -0.14V
E) Ni; E°(Ni2+/Ni) = -0.23V
Question
Use the provided reduction potentials to calculate ΔrG° for the following balanced redox reaction: 3I2(s) + 2Fe(s) → 2Fe3+(aq) + 6I⁻(aq)
E°(I2/I-) = + 0.54 V and E°(Fe3+/Fe) = -0.036 V

A) -1.1 × 102 kJ mol-1
B) +4.9 × 101 kJ mol-1
C) -9.7 × 101 kJ mol-1
D) +2.3 × 102 kJ mol-1
E) -3.3 × 102 kJ mol-1
Question
Which of the following metals will dissolve in nitric acid but not hydrochloric acid?

A) Cd; E°(Cd2+/Cd) = -0.40V
B) Cr; E°(Cr3+/Cr) = -0.73V
C) Mn; E°(Mn2+/Mn) = -1.18V
D) Ag; E°(Ag+/Ag) = +0.80V
E) Al; E°(Al3+/Al) = -1.66V
Question
Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.500 M and [   ] = 2.00 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +2.09 V B) -3.18 V C) +2.35 V D) +0.36 V E) -1.51 V <div style=padding-top: 35px> ] = 0.500 M and [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.500 M and [   ] = 2.00 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +2.09 V B) -3.18 V C) +2.35 V D) +0.36 V E) -1.51 V <div style=padding-top: 35px> ] = 2.00 M Mg(s) + <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.500 M and [   ] = 2.00 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +2.09 V B) -3.18 V C) +2.35 V D) +0.36 V E) -1.51 V <div style=padding-top: 35px> (aq) → <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.500 M and [   ] = 2.00 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +2.09 V B) -3.18 V C) +2.35 V D) +0.36 V E) -1.51 V <div style=padding-top: 35px> (aq) + Fe(s)
E°(Mg2+/Mg) = -2.37 V and E°(Fe3+/Fe) = -0.036 V

A) +2.09 V
B) -3.18 V
C) +2.35 V
D) +0.36 V
E) -1.51 V
Question
Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.000612 M and [   ] = 1.29 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) -3.42 V B) +3.42 V C) -4.32 V D) +2.43 V E) +3.24 V <div style=padding-top: 35px> ] = 0.000612 M and [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.000612 M and [   ] = 1.29 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) -3.42 V B) +3.42 V C) -4.32 V D) +2.43 V E) +3.24 V <div style=padding-top: 35px> ] = 1.29 M Mg(s) + <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.000612 M and [   ] = 1.29 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) -3.42 V B) +3.42 V C) -4.32 V D) +2.43 V E) +3.24 V <div style=padding-top: 35px> (aq) → <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.000612 M and [   ] = 1.29 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) -3.42 V B) +3.42 V C) -4.32 V D) +2.43 V E) +3.24 V <div style=padding-top: 35px> (aq) + Fe(s)
E°(Mg2+/Mg) = -2.37 V and E°(Fe3+/Fe) = -0.036 V

A) -3.42 V
B) +3.42 V
C) -4.32 V
D) +2.43 V
E) +3.24 V
Question
Which of the following reactions would have the smallest value of K at 298 K?

A) A + B → C; E°cell = +1.22 V
B) A + 2 B → C; E°cell = +0.98 V
C) A + B → 2 C; E°cell = -0.030 V
D) A + B → 3 C; E°cell = +0.15 V
E) A + B → C; E°cell = -0.015 V
Question
Use the tabulated half-cell potentials to calculate the equilibrium constant (K) for the following balanced redox reaction at 25 °C: Pb2+(aq) + Cu(s) → Pb(s) + Cu2+(aq)
E°(Pb2+/Pb) = -0.13 V and E°(Cu2+/Cu) = +0.34 V

A) 7.9 × 10-8
B) 8.9 × 107
C) 7.9 × 1015
D) 1.3 × 10-16
E) 1.1 × 10-8
Question
Determine which of the following pairs of reactants will result in a spontaneous reaction at 25 °C.

A) I-(aq) + Zn2+(aq); if E°(I2/I-) = + 0.54V and E°(Zn2+/Zn) = -0.76V
B) Ca(s) + Mg2+(aq); if E°(Ca2+/Ca) = -2.76V and E°(Mg2+/Mg) = -2.37V
C) H2(g) + Cd2+(aq); if E°(Cd2+/Cd) = -0.40V
D) Ag(s) + Sn2+(aq); if E°(Ag+/Ag) = + 0.80V and E°(Sn2+/Sn) = -0.14V
E) Ag+(aq) + Mn2+(aq); if E°(Ag+/Ag) = + 0.80V and E°(MnO4-/Mn2+) = +1.51V
Question
Use the provided reduction potentials to calculate ΔrG° for the following balanced redox reaction: Pb2+(aq) + Cu(s) → Pb(s) + Cu2+(aq)
E°(Pb2+/Pb) = -0.13 V and E°(Cu2+/Cu) = +0.34 V

A) -41 kJ mol-1
B) -0.47 kJ mol-1
C) +46 kJ mol-1
D) +91 kJ mol-1
E) -21 kJ mol-1
Question
Predict the species that will be reduced first if a mixture of molten salts containing the following ions undergoes electrolysis: Zn2+, Fe3+, Mg2+, Br-, I-

A) Zn2+
B) Mg2+
C) Br-
D) Fe3+
E) I-
Question
Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °C: Sn(s) ∣ Sn2+(aq, 0.022 mol L-1) <strong>Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °C: Sn(s) ∣ Sn<sup>2+</sup>(aq, 0.022 mol L<sup>-1</sup>)   Ag<sup>+</sup>(aq, 2.7 mol L<sup>-1</sup>) ∣ Ag(s) E°(Sn<sup>2+</sup>/Sn) = -0.14 V and E°(Ag<sup>+</sup>/Ag) = +0.80 V</strong> A) +1.01 V B) -0.83 V C) +1.31 V D) +0.01 V E) -0.66 V <div style=padding-top: 35px> Ag+(aq, 2.7 mol L-1) ∣ Ag(s)
E°(Sn2+/Sn) = -0.14 V and E°(Ag+/Ag) = +0.80 V

A) +1.01 V
B) -0.83 V
C) +1.31 V
D) +0.01 V
E) -0.66 V
Question
Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °C: Mg(s) ∣ Mg2+(aq, 2.74 mol L-1) <strong>Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °C: Mg(s) ∣ Mg<sup>2+</sup>(aq, 2.74 mol L<sup>-1</sup>)   Cu<sup>2+</sup>(aq, 0.0033 mol L<sup>-1</sup>) ∣ Cu(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Cu<sup>2+</sup>/Cu) = +0.34 V</strong> A) -2.80 V B) +2.62 V C) +2.71 V D) +2.12 V E) -1.94 V <div style=padding-top: 35px> Cu2+(aq, 0.0033 mol L-1) ∣ Cu(s)
E°(Mg2+/Mg) = -2.37 V and E°(Cu2+/Cu) = +0.34 V

A) -2.80 V
B) +2.62 V
C) +2.71 V
D) +2.12 V
E) -1.94 V
Question
What is the reaction at the anode in a breathalyzer?

A) Ethanol is oxidized to acetic acid.
B) Acetic acid is reduced to ethanol.
C) Oxygen is reduced.
D) Hydrogen is oxidized.
E) Ethanol is oxidized to acetaldehyde.
Question
Predict the species that will be reduced first if a mixture of molten salts containing the following ions undergoes electrolysis: Zn2+, Mn2+, Na+, Al3+, Li+

A) Na+
B) Zn2+
C) Mn2+
D) Al3+
E) Li+
Question
Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °C: Sn(s) ∣ Sn2+(aq, 0.010 mol L-1) <strong>Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °C: Sn(s) ∣ Sn<sup>2+</sup>(aq, 0.010 mol L<sup>-1</sup>)   Ag<sup>+</sup>(aq, 1.00 mol L<sup>-</sup><sup>1</sup>) ∣ Ag(s) E°(Sn<sup>2+</sup>/Sn) = -0.14 V and E°(Ag<sup>+</sup>/Ag) = +0.80 V</strong> A) +1.18 V B) -1.18 V C) +1.00 V D) +0.94 V E) -0.94 V <div style=padding-top: 35px> Ag+(aq, 1.00 mol L-1) ∣ Ag(s)
E°(Sn2+/Sn) = -0.14 V and E°(Ag+/Ag) = +0.80 V

A) +1.18 V
B) -1.18 V
C) +1.00 V
D) +0.94 V
E) -0.94 V
Question
Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °C: Al(s) ∣ Al3+(aq, 0.115 mol L-1) <strong>Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °C: Al(s) ∣ Al<sup>3+</sup>(aq, 0.115 mol L<sup>-1</sup>)   Al<sup>3+</sup>(aq, 3.89 mol L<sup>-1</sup>) ∣ Al(s) E°(Al<sup>3+</sup>/Al) = -1.66 V</strong> A) +1.66 V B) +0.060 V C) 0.00 V D) +0.090 V E) +0.030 V <div style=padding-top: 35px> Al3+(aq, 3.89 mol L-1) ∣ Al(s)
E°(Al3+/Al) = -1.66 V

A) +1.66 V
B) +0.060 V
C) 0.00 V
D) +0.090 V
E) +0.030 V
Question
Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 1.10 M and [   ] = 1.10 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +2.33 V B) -3.23 V C) +1.48 V D) +2.22 V E) +0.68 V <div style=padding-top: 35px> ] = 1.10 M and [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 1.10 M and [   ] = 1.10 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +2.33 V B) -3.23 V C) +1.48 V D) +2.22 V E) +0.68 V <div style=padding-top: 35px> ] = 1.10 M Mg(s) + <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 1.10 M and [   ] = 1.10 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +2.33 V B) -3.23 V C) +1.48 V D) +2.22 V E) +0.68 V <div style=padding-top: 35px> (aq) → <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 1.10 M and [   ] = 1.10 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +2.33 V B) -3.23 V C) +1.48 V D) +2.22 V E) +0.68 V <div style=padding-top: 35px> (aq) + Fe(s)
E°(Mg2+/Mg) = -2.37 V and E°(Fe3+/Fe) = -0.036 V

A) +2.33 V
B) -3.23 V
C) +1.48 V
D) +2.22 V
E) +0.68 V
Question
Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °: Cu(s) ∣ Cu2+(aq, 0.0032 mol L-1) <strong>Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °: Cu(s) ∣ Cu<sup>2+</sup>(aq, 0.0032 mol L<sup>-1</sup>)   Cu<sup>2+</sup>(aq, 4.48 mol L<sup>-1</sup>) ∣ Cu(s) E°(Cu<sup>2+</sup>/Cu) = +0.34 V</strong> A) 0.00 V B) +0.093 V C) +0.34 V D) +0.186 V E) +0.052 V <div style=padding-top: 35px> Cu2+(aq, 4.48 mol L-1) ∣ Cu(s)
E°(Cu2+/Cu) = +0.34 V

A) 0.00 V
B) +0.093 V
C) +0.34 V
D) +0.186 V
E) +0.052 V
Question
Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °C: Sn(s) ∣ Sn2+(aq, 0.100 mol L-1) <strong>Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °C: Sn(s) ∣ Sn<sup>2+</sup>(aq, 0.100 mol L<sup>-1</sup>)   Ag<sup>+</sup>(aq, 0.200 mol L<sup>-1</sup>) ∣ Ag(s) E°(Sn<sup>2+</sup>/Sn) = -0.14 V and E°(Ag<sup>+</sup>/Ag) = +0.80 V</strong> A) -2.68 V B) -0.03 V C) +0.95 V D) +0.93 V E) +2.10 V <div style=padding-top: 35px> Ag+(aq, 0.200 mol L-1) ∣ Ag(s)
E°(Sn2+/Sn) = -0.14 V and E°(Ag+/Ag) = +0.80 V

A) -2.68 V
B) -0.03 V
C) +0.95 V
D) +0.93 V
E) +2.10 V
Question
Identify the battery that is used as a common flashlight battery.

A) dry-cell battery
B) lithium-ion battery
C) lead-acid storage battery
D) NiCad battery
E) fuel cell
Question
What is the reaction at the cathode in a breathalyzer?

A) Ethanol is oxidized to acetic acid.
B) Acetic acid is reduced to ethanol.
C) Oxygen is reduced.
D) Hydrogen is oxidized.
E) Ethanol is oxidized to acetaldehyde.
Question
Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °C: Sn(s) ∣ Sn2+(aq, 1.8 mol L-1) <strong>Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °C: Sn(s) ∣ Sn<sup>2+</sup>(aq, 1.8 mol L<sup>-1</sup>)   Ag<sup>+</sup>(aq, 0.055 mol L<sup>-1</sup>) ∣ Ag(s) E°(Sn<sup>2+</sup>/Sn) = -0.14 V and E°(Ag<sup>+</sup>/Ag) = +0.80 V</strong> A) -0.94 V B) -0.85 V C) +1.02 V D) +0.98 V E) +0.86 V <div style=padding-top: 35px> Ag+(aq, 0.055 mol L-1) ∣ Ag(s)
E°(Sn2+/Sn) = -0.14 V and E°(Ag+/Ag) = +0.80 V

A) -0.94 V
B) -0.85 V
C) +1.02 V
D) +0.98 V
E) +0.86 V
Question
Identify the battery type that has a high overcharge tolerance.

A) NiCad battery
B) lithium-ion battery
C) nickel-metal hydride battery
D) lead-acid storage battery
E) zinc-manganese battery
Question
Identify the battery that is in most automobiles.

A) dry-cell battery
B) lithium-ion battery
C) lead-acid storage battery
D) NiCad battery
E) fuel cell
Question
Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °: Fe(s) ∣ Fe3+(aq, 0.0011 mol L-1) <strong>Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °: Fe(s) ∣ Fe<sup>3+</sup>(aq, 0.0011 mol L<sup>-1</sup>)   Fe<sup>3+</sup>(aq, 2.33 mol L<sup>-1</sup>) ∣ Fe(s) E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +0.066 V B) -0.036 V C) 0.00 V D) -0.099 V E) +0.20 V <div style=padding-top: 35px> Fe3+(aq, 2.33 mol L-1) ∣ Fe(s)
E°(Fe3+/Fe) = -0.036 V

A) +0.066 V
B) -0.036 V
C) 0.00 V
D) -0.099 V
E) +0.20 V
Question
Predict the species that will be reduced first if a mixture of molten salts containing the following ions undergoes electrolysis: Cd2+, Ni2+, Sn2+, Al3+, Pb2+

A) Pb2+
B) Al3+
C) Sn2+
D) Ni2+
E) Cd2+
Question
Predict the species that will be reduced first if a mixture of molten salts containing the following ions undergoes electrolysis: Cu2+, Ag+, Sn4+, Fe3+, Au3+

A) Cu2+
B) Ag+
C) Sn4+
D) Fe3+
E) Au3+
Question
Identify the components of a fuel cell.

A) nickel-metal hydride
B) lithium-ion
C) hydrogen-oxygen
D) nickel-cadmium
E) zinc-manganese
Question
Predict the species that will be reduced first if a mixture of molten salts containing the following ions undergoes electrolysis: Na+, Ca2+, Cl⁻, Br⁻, F⁻

A) Na⁺
B) Cl⁻
C) Ca2+
D) Br⁻
E) F⁻
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Deck 18: Electrochemistry
1
What is undergoing oxidation in the redox reaction represented by the following cell notation? Fe(s) ∣ Fe3+(aq) <strong>What is undergoing oxidation in the redox reaction represented by the following cell notation? Fe(s) ∣ Fe<sup>3+</sup>(aq)   Cl<sub>2</sub>(g) ∣ Cl⁻(aq) ∣ Pt(s)</strong> A) Fe(s) B) Fe<sup>3+</sup>(aq) C) Cl<sub>2</sub>(g) D) Cl⁻(aq) E) Pt(s) Cl2(g) ∣ Cl⁻(aq) ∣ Pt(s)

A) Fe(s)
B) Fe3+(aq)
C) Cl2(g)
D) Cl⁻(aq)
E) Pt(s)
Fe(s)
2
Which of the following is the strongest reducing agent?

A) Al(s)
B) Zn(s)
C) Mg(s)
D) Al3+(aq)
E) Mg2+(aq)
Mg(s)
3
Describe how water can be made to be a good conductor of electrical current.

A) use pure water
B) heat the water
C) add salt
D) chill the water
E) vaporize the water
add salt
4
Determine the cell notation for the redox reaction given below: Sn(s) + 2Ag⁺(aq) → Sn2+(aq) + 2Ag(s)

A) Ag+(aq) ∣ Ag(s) <strong>Determine the cell notation for the redox reaction given below: Sn(s) + 2Ag⁺(aq) → Sn<sup>2+</sup>(aq) + 2Ag(s)</strong> A) Ag<sup>+</sup>(aq) ∣ Ag(s)   Sn(s) ∣ Sn<sup>2+</sup>(aq) B) Ag(s) ∣ Ag<sup>+</sup>(aq)   Sn<sup>2+</sup>(aq) ∣ Sn(s) C) Sn(s) ∣ Sn<sup>2+</sup>(aq)   Ag<sup>+</sup>(aq) ∣ Ag(s) D) Sn<sup>2+</sup>(aq) ∣ Sn(s)   Ag(s) ∣ Ag<sup>+</sup>(aq) E) Sn(s) ∣ Ag(s)   Sn<sup>2+</sup>(aq) ∣ Ag<sup>+</sup>(aq) Sn(s) ∣ Sn2+(aq)
B) Ag(s) ∣ Ag+(aq) <strong>Determine the cell notation for the redox reaction given below: Sn(s) + 2Ag⁺(aq) → Sn<sup>2+</sup>(aq) + 2Ag(s)</strong> A) Ag<sup>+</sup>(aq) ∣ Ag(s)   Sn(s) ∣ Sn<sup>2+</sup>(aq) B) Ag(s) ∣ Ag<sup>+</sup>(aq)   Sn<sup>2+</sup>(aq) ∣ Sn(s) C) Sn(s) ∣ Sn<sup>2+</sup>(aq)   Ag<sup>+</sup>(aq) ∣ Ag(s) D) Sn<sup>2+</sup>(aq) ∣ Sn(s)   Ag(s) ∣ Ag<sup>+</sup>(aq) E) Sn(s) ∣ Ag(s)   Sn<sup>2+</sup>(aq) ∣ Ag<sup>+</sup>(aq) Sn2+(aq) ∣ Sn(s)
C) Sn(s) ∣ Sn2+(aq) <strong>Determine the cell notation for the redox reaction given below: Sn(s) + 2Ag⁺(aq) → Sn<sup>2+</sup>(aq) + 2Ag(s)</strong> A) Ag<sup>+</sup>(aq) ∣ Ag(s)   Sn(s) ∣ Sn<sup>2+</sup>(aq) B) Ag(s) ∣ Ag<sup>+</sup>(aq)   Sn<sup>2+</sup>(aq) ∣ Sn(s) C) Sn(s) ∣ Sn<sup>2+</sup>(aq)   Ag<sup>+</sup>(aq) ∣ Ag(s) D) Sn<sup>2+</sup>(aq) ∣ Sn(s)   Ag(s) ∣ Ag<sup>+</sup>(aq) E) Sn(s) ∣ Ag(s)   Sn<sup>2+</sup>(aq) ∣ Ag<sup>+</sup>(aq) Ag+(aq) ∣ Ag(s)
D) Sn2+(aq) ∣ Sn(s) <strong>Determine the cell notation for the redox reaction given below: Sn(s) + 2Ag⁺(aq) → Sn<sup>2+</sup>(aq) + 2Ag(s)</strong> A) Ag<sup>+</sup>(aq) ∣ Ag(s)   Sn(s) ∣ Sn<sup>2+</sup>(aq) B) Ag(s) ∣ Ag<sup>+</sup>(aq)   Sn<sup>2+</sup>(aq) ∣ Sn(s) C) Sn(s) ∣ Sn<sup>2+</sup>(aq)   Ag<sup>+</sup>(aq) ∣ Ag(s) D) Sn<sup>2+</sup>(aq) ∣ Sn(s)   Ag(s) ∣ Ag<sup>+</sup>(aq) E) Sn(s) ∣ Ag(s)   Sn<sup>2+</sup>(aq) ∣ Ag<sup>+</sup>(aq) Ag(s) ∣ Ag+(aq)
E) Sn(s) ∣ Ag(s) <strong>Determine the cell notation for the redox reaction given below: Sn(s) + 2Ag⁺(aq) → Sn<sup>2+</sup>(aq) + 2Ag(s)</strong> A) Ag<sup>+</sup>(aq) ∣ Ag(s)   Sn(s) ∣ Sn<sup>2+</sup>(aq) B) Ag(s) ∣ Ag<sup>+</sup>(aq)   Sn<sup>2+</sup>(aq) ∣ Sn(s) C) Sn(s) ∣ Sn<sup>2+</sup>(aq)   Ag<sup>+</sup>(aq) ∣ Ag(s) D) Sn<sup>2+</sup>(aq) ∣ Sn(s)   Ag(s) ∣ Ag<sup>+</sup>(aq) E) Sn(s) ∣ Ag(s)   Sn<sup>2+</sup>(aq) ∣ Ag<sup>+</sup>(aq) Sn2+(aq) ∣ Ag+(aq)
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5
Which of the following is the strongest reducing agent?

A) Na(s)
B) Li+(aq)
C) Ca(s)
D) Ca2+(aq)
E) Li(s)
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6
Which of the following is the strongest reducing agent?

A) Sn2+(aq)
B) Cr3+(aq)
C) Sn4+(aq)
D) Cr(s)
E) Sn(s)
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7
Which of the following is TRUE about standard electrode potentials?

A) E°cell is negative for spontaneous reactions.
B) Electrons will flow from a more positive electrode to a more negative electrode.
C) The electrode potential of the standard hydrogen electrode is exactly zero.
D) E°cell is the sum between standard reduction potentials of the anode and the cathode.
E) The electrode in any half-cell with a greater tendency to undergo reduction is negatively charged relative to the standard hydrogen electrode and therefore has E° < 0.
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8
How many electrons are transferred in the following reaction? (The reaction is unbalanced.) I2(s) + Fe(s) → Fe3+(aq) + I⁻(aq)

A) 1
B) 2
C) 6
D) 3
E) 4
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9
What is the oxidizing agent in the redox reaction represented by the following cell notation? Ni(s) ∣ Ni2+(aq) <strong>What is the oxidizing agent in the redox reaction represented by the following cell notation? Ni(s) ∣ Ni<sup>2+</sup>(aq)   Ag<sup>+</sup>(aq) ∣ Ag(s)</strong> A) Ni(s) B) Ni<sup>2+</sup>(aq) C) Ag<sup>+</sup>(aq) D) Ag(s) E) Pt(s) Ag+(aq) ∣ Ag(s)

A) Ni(s)
B) Ni2+(aq)
C) Ag+(aq)
D) Ag(s)
E) Pt(s)
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10
Determine the redox reaction represented by the following cell notation: Mg(s) ∣ Mg2+(aq) <strong>Determine the redox reaction represented by the following cell notation: Mg(s) ∣ Mg<sup>2+</sup>(aq)   Cu<sup>2+</sup>(aq) ∣ Cu(s)</strong> A) Cu(s) + Mg<sup>2+</sup>(aq) → Mg(s) + Cu<sup>2+</sup>(aq) B) Mg(s) + Cu<sup>2+</sup>(aq) → Cu(s) + Mg<sup>2+</sup>(aq) C) 2Mg(s) + Cu<sup>2+</sup>(aq) → Cu(s) + 2Mg<sup>2+</sup>(aq) D) 2Cu(s) + Mg<sup>2+</sup>(aq) → Mg(s) + 2Cu<sup>2+</sup>(aq) E) 3Mg(s) + 2Cu<sup>2+</sup>(aq) → 2Cu(s) + 3Mg<sup>2+</sup>(aq) Cu2+(aq) ∣ Cu(s)

A) Cu(s) + Mg2+(aq) → Mg(s) + Cu2+(aq)
B) Mg(s) + Cu2+(aq) → Cu(s) + Mg2+(aq)
C) 2Mg(s) + Cu2+(aq) → Cu(s) + 2Mg2+(aq)
D) 2Cu(s) + Mg2+(aq) → Mg(s) + 2Cu2+(aq)
E) 3Mg(s) + 2Cu2+(aq) → 2Cu(s) + 3Mg2+(aq)
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11
Which of the following is the weakest oxidizing agent?

A) Sn2+(aq)
B) Cr3+(aq)
C) Sn4+(aq)
D) Cr(s)
E) Sn(s)
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12
What is undergoing reduction in the redox reaction represented by the following cell notation? Fe(s) ∣ Fe3+(aq) <strong>What is undergoing reduction in the redox reaction represented by the following cell notation? Fe(s) ∣ Fe<sup>3+</sup>(aq)   Cl<sub>2</sub>(g) ∣ Cl⁻(aq) ∣ Pt(s)</strong> A) Fe(s) B) Fe<sup>3+</sup>(aq) C) Cl<sub>2</sub>(g) D) Cl⁻(aq) E) Pt(s) Cl2(g) ∣ Cl⁻(aq) ∣ Pt(s)

A) Fe(s)
B) Fe3+(aq)
C) Cl2(g)
D) Cl⁻(aq)
E) Pt(s)
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13
What is the reducing agent in the redox reaction represented by the following cell notation? Ni(s) ∣ Ni2+(aq) <strong>What is the reducing agent in the redox reaction represented by the following cell notation? Ni(s) ∣ Ni<sup>2+</sup>(aq)   Ag<sup>+</sup>(aq) ∣ Ag(s)</strong> A) Ni(s) B) Ni<sup>2+</sup>(aq) C) Ag<sup>+</sup>(aq) D) Ag(s) E) Pt(s) Ag+(aq) ∣ Ag(s)

A) Ni(s)
B) Ni2+(aq)
C) Ag+(aq)
D) Ag(s)
E) Pt(s)
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14
What is undergoing oxidation in the redox reaction represented by the following cell notation? Pb(s) ∣ Pb2+(aq) <strong>What is undergoing oxidation in the redox reaction represented by the following cell notation? Pb(s) ∣ Pb<sup>2+</sup>(aq)   H<sup>+</sup>(aq) ∣ H<sub>2</sub>(g) ∣ Pt(s)</strong> A) H<sub>2</sub>(g) B) H<sup>+</sup>(aq) C) Pb<sup>2+</sup>(aq) D) Pb(s) E) Pt(s) H+(aq) ∣ H2(g) ∣ Pt(s)

A) H2(g)
B) H+(aq)
C) Pb2+(aq)
D) Pb(s)
E) Pt(s)
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15
Determine the cell notation for the redox reaction given below: Pb(s) + 2H⁺(aq) → Pb2+(aq) + H2(g)

A) H+(aq) ∣ H2(g) ∣ Pt(s) <strong>Determine the cell notation for the redox reaction given below: Pb(s) + 2H⁺(aq) → Pb<sup>2+</sup>(aq) + H<sub>2</sub>(g)</strong> A) H<sup>+</sup>(aq) ∣ H<sub>2</sub>(g) ∣ Pt(s)   Pb(s) ∣ Pb<sup>2+</sup>(aq) B) H<sub>2</sub>(g) ∣ H<sup>+</sup>(aq) ∣ Pt(s)   Pb<sup>2+</sup>(aq) ∣ Pb(s) C) Pb<sup>2+</sup>(aq) ∣ Pb(s)   H<sub>2</sub>(g) ∣ H<sup>+</sup>(aq) ∣ Pt(s) D) Pb(s) ∣ Pb<sup>2+</sup>(aq)   H<sup>+</sup>(aq) ∣ H<sub>2</sub>(g) ∣ Pt(s) E) Pb(s) ∣ H<sub>2</sub>(g)   Pb<sup>2+</sup>(aq) ∣ H<sup>+</sup>(aq) ∣ Pt(s) Pb(s) ∣ Pb2+(aq)
B) H2(g) ∣ H+(aq) ∣ Pt(s) <strong>Determine the cell notation for the redox reaction given below: Pb(s) + 2H⁺(aq) → Pb<sup>2+</sup>(aq) + H<sub>2</sub>(g)</strong> A) H<sup>+</sup>(aq) ∣ H<sub>2</sub>(g) ∣ Pt(s)   Pb(s) ∣ Pb<sup>2+</sup>(aq) B) H<sub>2</sub>(g) ∣ H<sup>+</sup>(aq) ∣ Pt(s)   Pb<sup>2+</sup>(aq) ∣ Pb(s) C) Pb<sup>2+</sup>(aq) ∣ Pb(s)   H<sub>2</sub>(g) ∣ H<sup>+</sup>(aq) ∣ Pt(s) D) Pb(s) ∣ Pb<sup>2+</sup>(aq)   H<sup>+</sup>(aq) ∣ H<sub>2</sub>(g) ∣ Pt(s) E) Pb(s) ∣ H<sub>2</sub>(g)   Pb<sup>2+</sup>(aq) ∣ H<sup>+</sup>(aq) ∣ Pt(s) Pb2+(aq) ∣ Pb(s)
C) Pb2+(aq) ∣ Pb(s) <strong>Determine the cell notation for the redox reaction given below: Pb(s) + 2H⁺(aq) → Pb<sup>2+</sup>(aq) + H<sub>2</sub>(g)</strong> A) H<sup>+</sup>(aq) ∣ H<sub>2</sub>(g) ∣ Pt(s)   Pb(s) ∣ Pb<sup>2+</sup>(aq) B) H<sub>2</sub>(g) ∣ H<sup>+</sup>(aq) ∣ Pt(s)   Pb<sup>2+</sup>(aq) ∣ Pb(s) C) Pb<sup>2+</sup>(aq) ∣ Pb(s)   H<sub>2</sub>(g) ∣ H<sup>+</sup>(aq) ∣ Pt(s) D) Pb(s) ∣ Pb<sup>2+</sup>(aq)   H<sup>+</sup>(aq) ∣ H<sub>2</sub>(g) ∣ Pt(s) E) Pb(s) ∣ H<sub>2</sub>(g)   Pb<sup>2+</sup>(aq) ∣ H<sup>+</sup>(aq) ∣ Pt(s) H2(g) ∣ H+(aq) ∣ Pt(s)
D) Pb(s) ∣ Pb2+(aq) <strong>Determine the cell notation for the redox reaction given below: Pb(s) + 2H⁺(aq) → Pb<sup>2+</sup>(aq) + H<sub>2</sub>(g)</strong> A) H<sup>+</sup>(aq) ∣ H<sub>2</sub>(g) ∣ Pt(s)   Pb(s) ∣ Pb<sup>2+</sup>(aq) B) H<sub>2</sub>(g) ∣ H<sup>+</sup>(aq) ∣ Pt(s)   Pb<sup>2+</sup>(aq) ∣ Pb(s) C) Pb<sup>2+</sup>(aq) ∣ Pb(s)   H<sub>2</sub>(g) ∣ H<sup>+</sup>(aq) ∣ Pt(s) D) Pb(s) ∣ Pb<sup>2+</sup>(aq)   H<sup>+</sup>(aq) ∣ H<sub>2</sub>(g) ∣ Pt(s) E) Pb(s) ∣ H<sub>2</sub>(g)   Pb<sup>2+</sup>(aq) ∣ H<sup>+</sup>(aq) ∣ Pt(s) H+(aq) ∣ H2(g) ∣ Pt(s)
E) Pb(s) ∣ H2(g) <strong>Determine the cell notation for the redox reaction given below: Pb(s) + 2H⁺(aq) → Pb<sup>2+</sup>(aq) + H<sub>2</sub>(g)</strong> A) H<sup>+</sup>(aq) ∣ H<sub>2</sub>(g) ∣ Pt(s)   Pb(s) ∣ Pb<sup>2+</sup>(aq) B) H<sub>2</sub>(g) ∣ H<sup>+</sup>(aq) ∣ Pt(s)   Pb<sup>2+</sup>(aq) ∣ Pb(s) C) Pb<sup>2+</sup>(aq) ∣ Pb(s)   H<sub>2</sub>(g) ∣ H<sup>+</sup>(aq) ∣ Pt(s) D) Pb(s) ∣ Pb<sup>2+</sup>(aq)   H<sup>+</sup>(aq) ∣ H<sub>2</sub>(g) ∣ Pt(s) E) Pb(s) ∣ H<sub>2</sub>(g)   Pb<sup>2+</sup>(aq) ∣ H<sup>+</sup>(aq) ∣ Pt(s) Pb2+(aq) ∣ H+(aq) ∣ Pt(s)
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16
Determine the cell notation for the redox reaction given below: 3Cl2(g) + 2Fe(s) → 6Cl⁻(aq) + 2Fe3+(aq)

A) Cl2(g) ∣ Cl⁻(aq) ∣ Pt(s) <strong>Determine the cell notation for the redox reaction given below: 3Cl<sub>2</sub>(g) + 2Fe(s) → 6Cl⁻(aq) + 2Fe<sup>3+</sup>(aq)</strong> A) Cl<sub>2</sub>(g) ∣ Cl⁻(aq) ∣ Pt(s)   Fe(s) ∣ Fe<sup>3+</sup>(aq) B) Cl⁻(aq) ∣ Cl<sub>2</sub>(g) ∣ Pt(s)   Fe<sup>3+</sup>(aq)<sup> </sup>∣<sup> </sup>Fe(s) C) Fe<sup>3+</sup>(aq) ∣ Fe(s)   Cl⁻(aq) ∣ Cl<sub>2</sub>(g) ∣ Pt(s) D) Fe(s) ∣ Cl<sub>2</sub>(g)   Fe<sup>3+</sup>(aq) ∣ Cl⁻(aq) ∣ Pt(s) E) Fe(s) ∣ Fe<sup>3+</sup>(aq)   Cl<sub>2</sub>(g) ∣ Cl⁻(aq) ∣ Pt(s) Fe(s) ∣ Fe3+(aq)
B) Cl⁻(aq) ∣ Cl2(g) ∣ Pt(s) <strong>Determine the cell notation for the redox reaction given below: 3Cl<sub>2</sub>(g) + 2Fe(s) → 6Cl⁻(aq) + 2Fe<sup>3+</sup>(aq)</strong> A) Cl<sub>2</sub>(g) ∣ Cl⁻(aq) ∣ Pt(s)   Fe(s) ∣ Fe<sup>3+</sup>(aq) B) Cl⁻(aq) ∣ Cl<sub>2</sub>(g) ∣ Pt(s)   Fe<sup>3+</sup>(aq)<sup> </sup>∣<sup> </sup>Fe(s) C) Fe<sup>3+</sup>(aq) ∣ Fe(s)   Cl⁻(aq) ∣ Cl<sub>2</sub>(g) ∣ Pt(s) D) Fe(s) ∣ Cl<sub>2</sub>(g)   Fe<sup>3+</sup>(aq) ∣ Cl⁻(aq) ∣ Pt(s) E) Fe(s) ∣ Fe<sup>3+</sup>(aq)   Cl<sub>2</sub>(g) ∣ Cl⁻(aq) ∣ Pt(s) Fe3+(aq) Fe(s)
C) Fe3+(aq) ∣ Fe(s) <strong>Determine the cell notation for the redox reaction given below: 3Cl<sub>2</sub>(g) + 2Fe(s) → 6Cl⁻(aq) + 2Fe<sup>3+</sup>(aq)</strong> A) Cl<sub>2</sub>(g) ∣ Cl⁻(aq) ∣ Pt(s)   Fe(s) ∣ Fe<sup>3+</sup>(aq) B) Cl⁻(aq) ∣ Cl<sub>2</sub>(g) ∣ Pt(s)   Fe<sup>3+</sup>(aq)<sup> </sup>∣<sup> </sup>Fe(s) C) Fe<sup>3+</sup>(aq) ∣ Fe(s)   Cl⁻(aq) ∣ Cl<sub>2</sub>(g) ∣ Pt(s) D) Fe(s) ∣ Cl<sub>2</sub>(g)   Fe<sup>3+</sup>(aq) ∣ Cl⁻(aq) ∣ Pt(s) E) Fe(s) ∣ Fe<sup>3+</sup>(aq)   Cl<sub>2</sub>(g) ∣ Cl⁻(aq) ∣ Pt(s) Cl⁻(aq) ∣ Cl2(g) ∣ Pt(s)
D) Fe(s) ∣ Cl2(g) <strong>Determine the cell notation for the redox reaction given below: 3Cl<sub>2</sub>(g) + 2Fe(s) → 6Cl⁻(aq) + 2Fe<sup>3+</sup>(aq)</strong> A) Cl<sub>2</sub>(g) ∣ Cl⁻(aq) ∣ Pt(s)   Fe(s) ∣ Fe<sup>3+</sup>(aq) B) Cl⁻(aq) ∣ Cl<sub>2</sub>(g) ∣ Pt(s)   Fe<sup>3+</sup>(aq)<sup> </sup>∣<sup> </sup>Fe(s) C) Fe<sup>3+</sup>(aq) ∣ Fe(s)   Cl⁻(aq) ∣ Cl<sub>2</sub>(g) ∣ Pt(s) D) Fe(s) ∣ Cl<sub>2</sub>(g)   Fe<sup>3+</sup>(aq) ∣ Cl⁻(aq) ∣ Pt(s) E) Fe(s) ∣ Fe<sup>3+</sup>(aq)   Cl<sub>2</sub>(g) ∣ Cl⁻(aq) ∣ Pt(s) Fe3+(aq) ∣ Cl⁻(aq) ∣ Pt(s)
E) Fe(s) ∣ Fe3+(aq) <strong>Determine the cell notation for the redox reaction given below: 3Cl<sub>2</sub>(g) + 2Fe(s) → 6Cl⁻(aq) + 2Fe<sup>3+</sup>(aq)</strong> A) Cl<sub>2</sub>(g) ∣ Cl⁻(aq) ∣ Pt(s)   Fe(s) ∣ Fe<sup>3+</sup>(aq) B) Cl⁻(aq) ∣ Cl<sub>2</sub>(g) ∣ Pt(s)   Fe<sup>3+</sup>(aq)<sup> </sup>∣<sup> </sup>Fe(s) C) Fe<sup>3+</sup>(aq) ∣ Fe(s)   Cl⁻(aq) ∣ Cl<sub>2</sub>(g) ∣ Pt(s) D) Fe(s) ∣ Cl<sub>2</sub>(g)   Fe<sup>3+</sup>(aq) ∣ Cl⁻(aq) ∣ Pt(s) E) Fe(s) ∣ Fe<sup>3+</sup>(aq)   Cl<sub>2</sub>(g) ∣ Cl⁻(aq) ∣ Pt(s) Cl2(g) ∣ Cl⁻(aq) ∣ Pt(s)
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17
How many electrons are transferred in the following reaction? (The reaction is unbalanced.) Fe2+(aq) + K(s) → Fe(s) + K+(aq)

A) 1
B) 2
C) 3
D) 4
E) 6
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18
What is the oxidizing agent in the redox reaction represented by the following cell notation? Sn(s) ∣ Sn2+(aq) <strong>What is the oxidizing agent in the redox reaction represented by the following cell notation? Sn(s) ∣ Sn<sup>2+</sup>(aq)   Ag<sup>+</sup>(aq) ∣ Ag(s)</strong> A) Sn(s) B) Ag<sup>+</sup>(aq) C) Sn<sup>2+</sup>(aq) D) Ag(s) E) Pt(s) Ag+(aq) ∣ Ag(s)

A) Sn(s)
B) Ag+(aq)
C) Sn2+(aq)
D) Ag(s)
E) Pt(s)
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19
What is the reducing agent in the redox reaction represented by the following cell notation? Sn(s) ∣ Sn2+(aq) <strong>What is the reducing agent in the redox reaction represented by the following cell notation? Sn(s) ∣ Sn<sup>2+</sup>(aq)   Ag<sup>+</sup>(aq) ∣ Ag(s)</strong> A) Sn(s) B) Ag<sup>+</sup>(aq) C) Sn<sup>2+</sup>(aq) D) Ag(s) E) Pt(s) Ag+(aq) ∣ Ag(s)

A) Sn(s)
B) Ag+(aq)
C) Sn2+(aq)
D) Ag(s)
E) Pt(s)
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20
What is undergoing reduction in the redox reaction represented by the following cell notation? Pb(s) ∣ Pb2+(aq) <strong>What is undergoing reduction in the redox reaction represented by the following cell notation? Pb(s) ∣ Pb<sup>2+</sup>(aq)   H<sup>+</sup>(aq) ∣ H<sub>2</sub>(g) ∣ Pt(s)</strong> A) H<sub>2</sub>(g) B) H<sup>+</sup>(aq) C) Pb<sup>2+</sup>(aq) D) Pb(s) E) Pt(s) H+(aq) ∣ H2(g) ∣ Pt(s)

A) H2(g)
B) H+(aq)
C) Pb2+(aq)
D) Pb(s)
E) Pt(s)
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21
Which of the following is the weakest oxidizing agent?

A) Cl2(g)
B) Au+3(aq)
C) F2(g)
D) O2(g)
E) Br2(l)
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22
Which of the following is the weakest oxidizing agent?

A) H2O2(aq)
B) Fe3+(aq)
C) ClO2(g)
D) I2(s)
E) Fe(s)
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23
Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring in an electrochemical cell at 25 °C. (The equation is balanced.) 2K(s) + I2(s) → 2K⁺(aq) + 2I⁻(aq)
K+(aq) + e⁻ → K (s) E° = -2.93 V
I2(s) + 2 e⁻ → 2 I⁻(aq) E° = +0.54 V

A) +6.40 V
B) +1.85 V
C) -5.32 V
D) +3.47 V
E) +5.32 V
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24
Which of the following is the strongest oxidizing agent?

A) Cl2(g)
B) Au+3(aq)
C) F2(g)
D) O2(g)
E) Fe(s)
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25
Which of the following is the weakest reducing agent?

A) Br2(l)
B) Au3+(aq)
C) Ag(s)
D) Br⁻(aq)
E) Au(s)
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26
Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring in an electrochemical cell at 25 °C. (The equation is balanced.) 3Cl2(g) + 2Fe(s) → 6Cl⁻(aq) + 2Fe3+(aq)
Cl2(g) + 2 e⁻ → 2Cl⁻(aq) E° = +1.36 V
Fe3+(aq) + 3 e⁻ → Fe(s) E° = -0.04 V

A) +4.16 V
B) -1.40 V
C) -1.32 V
D) +1.32 V
E) +1.40 V
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27
Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring in an electrochemical cell at 25 °C. (The equation is balanced.) 2 Ag+(aq) + Pb(s) → 2Ag(s) + Pb2+(aq)
Ag+(aq) + e- → Ag(s) E°= 0.80 V
Pb2+(aq) + 2 e- → Pb(s) E°= -0.13 V

A) +0.93 V
B) +1.85 V
C) -5.32 V
D) +5.47 V
E) +0.67 V
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28
Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring in an electrochemical cell at 25°C. (The equation is balanced.) Br2(l) + 2Cl-(aq) → 2Br-(aq) + Cl2 (g)
Br2(l) + 2 e → 2Br-(aq) E°= 1.09 V
2Cl- (aq) → Cl2(g) + 2 e - E°= -1.36 V

A) +0.93 V
B) +2.24 V
C) +2.45 V
D) +5.47 V
E) +0.67 V
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29
Which of the following reactions would be the most spontaneous at 298 K?

A) A + 2 B → C; E°cell = +0.98 V
B) A + B → 2 C; E°cell = -0.030 V
C) A + B → 3 C; E°cell = +0.15 V
D) A + B → C; E°cell = +1.22 V
E) A + B → C; E°cell = -1.22 V
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30
Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring in an electrochemical cell at 2 5°C. (The equation is balanced.) Pb(s) + Br2(l) → Pb2+(aq) + 2 Br⁻(aq)
Pb2+(aq) + 2 e⁻ → Pb(s) E° = -0.13 V
Br2(l) + 2 e⁻ → 2 Br⁻(aq) E° = +1.07 V

A) +1.20 V
B) +0.94 V
C) -0.94 V
D) -1.20 V
E) -0.60 V
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31
Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring in an electrochemical cell at 25°C. (The equation is balanced.) Pb2+(aq) + Mg(s) → Pb(s) + Mg2+(aq)
Mg2+(aq) +2 e- →Mg(s) E°= -2.37 V
Pb2+(aq) + 2e- → Pb(s) E°= -0.13 V

A) +0.93 V
B) +2.24 V
C) -5.32 V
D) +5.47 V
E) +0.67 V
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32
Which of the following is the strongest oxidizing agent?

A) H2O2(aq)
B) Fe3+(aq)
C) ClO2(g)
D) I2(s)
E) Fe(s)
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33
Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring in an electrochemical cell at 25 °C. (The equation is balanced.) Sn(s) + 2Ag⁺(aq) → Sn2+(aq) + 2Ag(s)
Sn2+(aq) + 2 e⁻ → Sn(s) E° = -0.14 V
Ag⁺(aq) + e⁻ → Ag(s) E° = +0.80 V

A) +1.74 V
B) +0.94 V
C) +1.08 V
D) -1.08 V
E) -1.74 V
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34
Determine which of the following pairs of reactants will result in a spontaneous reaction at 25 °C.

A) Pb2+(aq) + Cu(s); if E°(Pb2+/Pb) = -0.13V and E°(Cu2+/Cu) = +0.16V
B) Ag+(aq) + Br⁻(aq); if E°(Ag+/Ag) = 0.80V and E°(Br2/Br-) = +1.09V
C) Li+(aq) + Al(s); if E°(Li+/Li) = -3.04V and E°(Al3+/Al) = -1.66V
D) Fe3+(aq) + Ni(s); if E°(Fe3+/Fe) = -0.04V and E°(Ni2+/Ni) = -0.23V
E) Cd2+(aq) + I-(aq); if E°(Cd2+/Cd) = -0.40V and E°(I2/I-) = + 0.54V
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35
Which of the following is the strongest oxidizing agent?

A) MnO2(s)
B) Cl⁻(aq)
C) Cu⁺(aq)
D) SO42-(aq)
E) MnO4⁻(aq)
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36
Which of the following statements is true for the cell diagram below? Zn(s) ∣ Zn2+(aq) <strong>Which of the following statements is true for the cell diagram below? Zn(s) ∣ Zn<sup>2+</sup>(aq)   Cu<sup>2+</sup>(aq) ∣ Cu(s)</strong> A) Zn is oxidized, Cu is reduced; the single vertical lines represent phase boundaries while the two vertical lines represent a salt bridge. B) Zn<sup>2+</sup>is oxidized, Cu is reduced; the single vertical lines represent phase boundaries while the two vertical lines represent a salt bridge. C) Zn is oxidized, Cu<sup>2+</sup> is reduced; the single vertical lines represent phase boundaries while the two vertical lines represent a salt bridge. D) Zn is oxidized, Cu<sup>2+</sup> is reduced; the single vertical lines represent salt bridges while the two vertical lines represent a phase boundary. E) Zn is reduced, Cu<sup>2+</sup> is oxidized; the single vertical lines represent phase boundaries while the two vertical lines represent a salt bridge. Cu2+(aq) ∣ Cu(s)

A) Zn is oxidized, Cu is reduced; the single vertical lines represent phase boundaries while the two vertical lines represent a salt bridge.
B) Zn2+is oxidized, Cu is reduced; the single vertical lines represent phase boundaries while the two vertical lines represent a salt bridge.
C) Zn is oxidized, Cu2+ is reduced; the single vertical lines represent phase boundaries while the two vertical lines represent a salt bridge.
D) Zn is oxidized, Cu2+ is reduced; the single vertical lines represent salt bridges while the two vertical lines represent a phase boundary.
E) Zn is reduced, Cu2+ is oxidized; the single vertical lines represent phase boundaries while the two vertical lines represent a salt bridge.
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37
Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring in an electrochemical cell at 25 °C. (The equation is balanced.) Mg(s) + Cu2+(aq) → Cu(s) + Mg2+(aq)
Mg2+(aq) + 2 e⁻ → Mg(s) E° = -2.38 V
Cu2+(aq) + 2 e⁻ → Cu(s) E° = +0.34 V

A) +2.04 V
B) -2.04 V
C) +2.72 V
D) -1.36 V
E) +1.36 V
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38
Which of the following is the weakest reducing agent?

A) Cl2(g)
B) Au+3 (aq)
C) F2(g)
D) O2(g)
E) Fe(s)
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39
Which of the following is the strongest oxidizing agent?

A) Al(s)
B) Zn2+(aq)
C) Mg(s)
D) Al3+(aq)
E) Mg2+(aq)
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40
Which of the following is the strongest oxidizing agent?

A) Br2(l)
B) Au3+(aq)
C) Ag(s)
D) Br⁻(aq)
E) Au(s)
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41
Use the provided reduction potentials to calculate the equilibrium constant (K) for the following balanced redox reaction at 25 °C: 2Al(s) + 3Mg2+(aq) → 2Al3+(aq) + 3Mg(s)
E°(Al3+/Al) = -1.66 V and E°(Mg2+/Mg) = -2.37 V

A) 1.1 × 1072
B) 8.9 × 10-70
C) 9.7 × 10-73
D) 1.0 × 1024
E) 4.6 × 1031
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42
Use the provided reduction potentials to calculate ΔrG° for the following redox reaction: 2Al(s) + 3Mg2+(aq) → 2Al3+(aq) + 3Mg(s)
E°(Al3+/Al) = -1.66 V and E°(Mg2+/Mg) = -2.37 V

A) +4.1 × 102 kJ mol-1
B) +1.4 × 102 kJ mol-1
C) -2.3 × 102 kJ mol-1
D) -7.8 × 102 kJ mol-1
E) +6.8 × 102 kJ mol-1
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43
Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.945 M and [   ] = 1.37 M Zn(s) +   (aq) →   (aq) + Cr(s) E°(Zn<sup>2+</sup>/Zn) = -0.76 V and E°(Cr<sup>3</sup><sup>+</sup>/Cr) = -0.73 V</strong> A) +0.03 V B) -0.03 V C) -1.18 V D) +1.18 V E) +0.49 V ] = 0.945 M and [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.945 M and [   ] = 1.37 M Zn(s) +   (aq) →   (aq) + Cr(s) E°(Zn<sup>2+</sup>/Zn) = -0.76 V and E°(Cr<sup>3</sup><sup>+</sup>/Cr) = -0.73 V</strong> A) +0.03 V B) -0.03 V C) -1.18 V D) +1.18 V E) +0.49 V ] = 1.37 M Zn(s) + <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.945 M and [   ] = 1.37 M Zn(s) +   (aq) →   (aq) + Cr(s) E°(Zn<sup>2+</sup>/Zn) = -0.76 V and E°(Cr<sup>3</sup><sup>+</sup>/Cr) = -0.73 V</strong> A) +0.03 V B) -0.03 V C) -1.18 V D) +1.18 V E) +0.49 V (aq) → <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.945 M and [   ] = 1.37 M Zn(s) +   (aq) →   (aq) + Cr(s) E°(Zn<sup>2+</sup>/Zn) = -0.76 V and E°(Cr<sup>3</sup><sup>+</sup>/Cr) = -0.73 V</strong> A) +0.03 V B) -0.03 V C) -1.18 V D) +1.18 V E) +0.49 V (aq) + Cr(s)
E°(Zn2+/Zn) = -0.76 V and E°(Cr3+/Cr) = -0.73 V

A) +0.03 V
B) -0.03 V
C) -1.18 V
D) +1.18 V
E) +0.49 V
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44
Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.914 M and [   ] = 0.0230 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +2.32 V B) +2.30 V C) -2.32 V D) -2.30 V E) +1.23 V ] = 0.914 M and [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.914 M and [   ] = 0.0230 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +2.32 V B) +2.30 V C) -2.32 V D) -2.30 V E) +1.23 V ] = 0.0230 M Mg(s) + <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.914 M and [   ] = 0.0230 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +2.32 V B) +2.30 V C) -2.32 V D) -2.30 V E) +1.23 V (aq) → <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.914 M and [   ] = 0.0230 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +2.32 V B) +2.30 V C) -2.32 V D) -2.30 V E) +1.23 V (aq) + Fe(s)
E°(Mg2+/Mg) = -2.37 V and E°(Fe3+/Fe) = -0.036 V

A) +2.32 V
B) +2.30 V
C) -2.32 V
D) -2.30 V
E) +1.23 V
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45
Which of the following metals will dissolve in HCl?

A) Au; E°(Au3+/Au) = +1.50V
B) Ag; E°(Ag+/Ag) = +0.80V
C) Cu; E°(Cu2+/Cu) = +0.34V
D) Al; E°(Al3+/Al) = -1.66V
E) Pt; E°(Pt2+/Pt) = +1.19V
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46
Determine which of the following pairs of reactants will result in a spontaneous reaction at 25 °C.

A) Sn4+(aq) + Mg(s); if E°(Sn4+/Sn2+) = +0.15V and E°(Mg2+/Mg) = -2.37V
B) Cr3+(aq) + Ni(s); if E°(Cr3+/Cr) = -0.73V and E°(Ni2+/Ni) = -0.23V
C) Zn(s) + Na+(aq); if E°(Zn2+/Zn) = -0.76V and E°(Na+/Na) = -2.71V
D) Fe(s) + Ba2+(aq); if E°(Fe3+/Fe) = -0.04V and E°(Ba2+/Ba) = -2.90V
E) Ni2+(aq) + NO(g); if E°(Ni2+/Ni) = -0.23V and E°(NO3-/NO) = +0.96V
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47
If the standard reduction potential of Zn is -0.76 V, which of the following statements about a cell whose half-cells are Zn2+/Zn and SHE is correct?

A) SHE will be the cell's cathode, Zn(s) will be the cell's anode, and the measured cell potential will be 0.76 V.
B) SHE will be the cell's anode, Zn(s) will be the cell's cathode, and the measured cell potential will be 0.76 V.
C) SHE will be the cell's cathode, Zn(s) will be the cell's anode, and the measured cell potential will be -0.76 V.
D) SHE will be the cell's cathode, Zn2+(aq) will be the cell's anode, and the measured cell potential will be 0.76 V.
E) H+(aq) will be the cell's cathode, Zn2+(aq) will be the cell's anode, and the measured cell potential will be 0.76 V.
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48
Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 2.00 M and [   ] = 0.00300 M Zn(s) +   (aq) →   (aq) + Cr(s) E°(Zn<sup>2+</sup>/Zn) = -0.76 V and E°(Cr<sup>3+</sup>/Cr) = -0.73 V</strong> A) +0.06 V B) -0.19 V C) +1.30 V D) +0.02 V E) +0.11 V ] = 2.00 M and [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 2.00 M and [   ] = 0.00300 M Zn(s) +   (aq) →   (aq) + Cr(s) E°(Zn<sup>2+</sup>/Zn) = -0.76 V and E°(Cr<sup>3+</sup>/Cr) = -0.73 V</strong> A) +0.06 V B) -0.19 V C) +1.30 V D) +0.02 V E) +0.11 V ] = 0.00300 M Zn(s) + <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 2.00 M and [   ] = 0.00300 M Zn(s) +   (aq) →   (aq) + Cr(s) E°(Zn<sup>2+</sup>/Zn) = -0.76 V and E°(Cr<sup>3+</sup>/Cr) = -0.73 V</strong> A) +0.06 V B) -0.19 V C) +1.30 V D) +0.02 V E) +0.11 V (aq) → <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 2.00 M and [   ] = 0.00300 M Zn(s) +   (aq) →   (aq) + Cr(s) E°(Zn<sup>2+</sup>/Zn) = -0.76 V and E°(Cr<sup>3+</sup>/Cr) = -0.73 V</strong> A) +0.06 V B) -0.19 V C) +1.30 V D) +0.02 V E) +0.11 V (aq) + Cr(s)
E°(Zn2+/Zn) = -0.76 V and E°(Cr3+/Cr) = -0.73 V

A) +0.06 V
B) -0.19 V
C) +1.30 V
D) +0.02 V
E) +0.11 V
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49
Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 3.20 M and [   ] = 0.000100 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) -2.24 V B) +2.24 V C) +1.24 V D) -1.24 V E) +2.14 V ] = 3.20 M and [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 3.20 M and [   ] = 0.000100 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) -2.24 V B) +2.24 V C) +1.24 V D) -1.24 V E) +2.14 V ] = 0.000100 M Mg(s) + <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 3.20 M and [   ] = 0.000100 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) -2.24 V B) +2.24 V C) +1.24 V D) -1.24 V E) +2.14 V (aq) → <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 3.20 M and [   ] = 0.000100 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) -2.24 V B) +2.24 V C) +1.24 V D) -1.24 V E) +2.14 V (aq) + Fe(s)
E°(Mg2+/Mg) = -2.37 V and E°(Fe3+/Fe) = -0.036 V

A) -2.24 V
B) +2.24 V
C) +1.24 V
D) -1.24 V
E) +2.14 V
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50
Use the tabulated half-cell potentials to calculate the equilibrium constant (K) for the following balanced redox reaction at 25 °C: 3I2(s) + 2Fe(s) → 2Fe3+(aq) + 6I⁻(aq)
E°(I2/I-) = + 0.54 V and E°(Fe3+/Fe) = -0.036 V

A) 3.5 × 10-59
B) 1.1 × 1017
C) 2.4 × 1058
D) 8.9 × 10-18
E) 1.7 × 1029
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51
Identify the characteristics of a spontaneous reaction.

A) ΔrG° > 0
B) ΔE°cell < 0
C) K < 0
D) ΔE°cell > 0
E) K = 0
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52
Which of the following metals will dissolve in nitric acid but not hydrochloric acid?

A) Fe; E°(Fe2+/Fe) = -0.45V
B) Pb; E°(Pb2+/Pb) = -0.13V
C) Cu; E°(Cu2+/Cu) = +0.34V
D) Sn; E°(Sn2+/Sn) = -0.14V
E) Ni; E°(Ni2+/Ni) = -0.23V
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53
Use the provided reduction potentials to calculate ΔrG° for the following balanced redox reaction: 3I2(s) + 2Fe(s) → 2Fe3+(aq) + 6I⁻(aq)
E°(I2/I-) = + 0.54 V and E°(Fe3+/Fe) = -0.036 V

A) -1.1 × 102 kJ mol-1
B) +4.9 × 101 kJ mol-1
C) -9.7 × 101 kJ mol-1
D) +2.3 × 102 kJ mol-1
E) -3.3 × 102 kJ mol-1
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54
Which of the following metals will dissolve in nitric acid but not hydrochloric acid?

A) Cd; E°(Cd2+/Cd) = -0.40V
B) Cr; E°(Cr3+/Cr) = -0.73V
C) Mn; E°(Mn2+/Mn) = -1.18V
D) Ag; E°(Ag+/Ag) = +0.80V
E) Al; E°(Al3+/Al) = -1.66V
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55
Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.500 M and [   ] = 2.00 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +2.09 V B) -3.18 V C) +2.35 V D) +0.36 V E) -1.51 V ] = 0.500 M and [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.500 M and [   ] = 2.00 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +2.09 V B) -3.18 V C) +2.35 V D) +0.36 V E) -1.51 V ] = 2.00 M Mg(s) + <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.500 M and [   ] = 2.00 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +2.09 V B) -3.18 V C) +2.35 V D) +0.36 V E) -1.51 V (aq) → <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.500 M and [   ] = 2.00 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +2.09 V B) -3.18 V C) +2.35 V D) +0.36 V E) -1.51 V (aq) + Fe(s)
E°(Mg2+/Mg) = -2.37 V and E°(Fe3+/Fe) = -0.036 V

A) +2.09 V
B) -3.18 V
C) +2.35 V
D) +0.36 V
E) -1.51 V
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56
Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.000612 M and [   ] = 1.29 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) -3.42 V B) +3.42 V C) -4.32 V D) +2.43 V E) +3.24 V ] = 0.000612 M and [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.000612 M and [   ] = 1.29 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) -3.42 V B) +3.42 V C) -4.32 V D) +2.43 V E) +3.24 V ] = 1.29 M Mg(s) + <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.000612 M and [   ] = 1.29 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) -3.42 V B) +3.42 V C) -4.32 V D) +2.43 V E) +3.24 V (aq) → <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 0.000612 M and [   ] = 1.29 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) -3.42 V B) +3.42 V C) -4.32 V D) +2.43 V E) +3.24 V (aq) + Fe(s)
E°(Mg2+/Mg) = -2.37 V and E°(Fe3+/Fe) = -0.036 V

A) -3.42 V
B) +3.42 V
C) -4.32 V
D) +2.43 V
E) +3.24 V
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57
Which of the following reactions would have the smallest value of K at 298 K?

A) A + B → C; E°cell = +1.22 V
B) A + 2 B → C; E°cell = +0.98 V
C) A + B → 2 C; E°cell = -0.030 V
D) A + B → 3 C; E°cell = +0.15 V
E) A + B → C; E°cell = -0.015 V
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58
Use the tabulated half-cell potentials to calculate the equilibrium constant (K) for the following balanced redox reaction at 25 °C: Pb2+(aq) + Cu(s) → Pb(s) + Cu2+(aq)
E°(Pb2+/Pb) = -0.13 V and E°(Cu2+/Cu) = +0.34 V

A) 7.9 × 10-8
B) 8.9 × 107
C) 7.9 × 1015
D) 1.3 × 10-16
E) 1.1 × 10-8
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59
Determine which of the following pairs of reactants will result in a spontaneous reaction at 25 °C.

A) I-(aq) + Zn2+(aq); if E°(I2/I-) = + 0.54V and E°(Zn2+/Zn) = -0.76V
B) Ca(s) + Mg2+(aq); if E°(Ca2+/Ca) = -2.76V and E°(Mg2+/Mg) = -2.37V
C) H2(g) + Cd2+(aq); if E°(Cd2+/Cd) = -0.40V
D) Ag(s) + Sn2+(aq); if E°(Ag+/Ag) = + 0.80V and E°(Sn2+/Sn) = -0.14V
E) Ag+(aq) + Mn2+(aq); if E°(Ag+/Ag) = + 0.80V and E°(MnO4-/Mn2+) = +1.51V
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60
Use the provided reduction potentials to calculate ΔrG° for the following balanced redox reaction: Pb2+(aq) + Cu(s) → Pb(s) + Cu2+(aq)
E°(Pb2+/Pb) = -0.13 V and E°(Cu2+/Cu) = +0.34 V

A) -41 kJ mol-1
B) -0.47 kJ mol-1
C) +46 kJ mol-1
D) +91 kJ mol-1
E) -21 kJ mol-1
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61
Predict the species that will be reduced first if a mixture of molten salts containing the following ions undergoes electrolysis: Zn2+, Fe3+, Mg2+, Br-, I-

A) Zn2+
B) Mg2+
C) Br-
D) Fe3+
E) I-
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62
Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °C: Sn(s) ∣ Sn2+(aq, 0.022 mol L-1) <strong>Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °C: Sn(s) ∣ Sn<sup>2+</sup>(aq, 0.022 mol L<sup>-1</sup>)   Ag<sup>+</sup>(aq, 2.7 mol L<sup>-1</sup>) ∣ Ag(s) E°(Sn<sup>2+</sup>/Sn) = -0.14 V and E°(Ag<sup>+</sup>/Ag) = +0.80 V</strong> A) +1.01 V B) -0.83 V C) +1.31 V D) +0.01 V E) -0.66 V Ag+(aq, 2.7 mol L-1) ∣ Ag(s)
E°(Sn2+/Sn) = -0.14 V and E°(Ag+/Ag) = +0.80 V

A) +1.01 V
B) -0.83 V
C) +1.31 V
D) +0.01 V
E) -0.66 V
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63
Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °C: Mg(s) ∣ Mg2+(aq, 2.74 mol L-1) <strong>Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °C: Mg(s) ∣ Mg<sup>2+</sup>(aq, 2.74 mol L<sup>-1</sup>)   Cu<sup>2+</sup>(aq, 0.0033 mol L<sup>-1</sup>) ∣ Cu(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Cu<sup>2+</sup>/Cu) = +0.34 V</strong> A) -2.80 V B) +2.62 V C) +2.71 V D) +2.12 V E) -1.94 V Cu2+(aq, 0.0033 mol L-1) ∣ Cu(s)
E°(Mg2+/Mg) = -2.37 V and E°(Cu2+/Cu) = +0.34 V

A) -2.80 V
B) +2.62 V
C) +2.71 V
D) +2.12 V
E) -1.94 V
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64
What is the reaction at the anode in a breathalyzer?

A) Ethanol is oxidized to acetic acid.
B) Acetic acid is reduced to ethanol.
C) Oxygen is reduced.
D) Hydrogen is oxidized.
E) Ethanol is oxidized to acetaldehyde.
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65
Predict the species that will be reduced first if a mixture of molten salts containing the following ions undergoes electrolysis: Zn2+, Mn2+, Na+, Al3+, Li+

A) Na+
B) Zn2+
C) Mn2+
D) Al3+
E) Li+
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66
Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °C: Sn(s) ∣ Sn2+(aq, 0.010 mol L-1) <strong>Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °C: Sn(s) ∣ Sn<sup>2+</sup>(aq, 0.010 mol L<sup>-1</sup>)   Ag<sup>+</sup>(aq, 1.00 mol L<sup>-</sup><sup>1</sup>) ∣ Ag(s) E°(Sn<sup>2+</sup>/Sn) = -0.14 V and E°(Ag<sup>+</sup>/Ag) = +0.80 V</strong> A) +1.18 V B) -1.18 V C) +1.00 V D) +0.94 V E) -0.94 V Ag+(aq, 1.00 mol L-1) ∣ Ag(s)
E°(Sn2+/Sn) = -0.14 V and E°(Ag+/Ag) = +0.80 V

A) +1.18 V
B) -1.18 V
C) +1.00 V
D) +0.94 V
E) -0.94 V
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67
Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °C: Al(s) ∣ Al3+(aq, 0.115 mol L-1) <strong>Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °C: Al(s) ∣ Al<sup>3+</sup>(aq, 0.115 mol L<sup>-1</sup>)   Al<sup>3+</sup>(aq, 3.89 mol L<sup>-1</sup>) ∣ Al(s) E°(Al<sup>3+</sup>/Al) = -1.66 V</strong> A) +1.66 V B) +0.060 V C) 0.00 V D) +0.090 V E) +0.030 V Al3+(aq, 3.89 mol L-1) ∣ Al(s)
E°(Al3+/Al) = -1.66 V

A) +1.66 V
B) +0.060 V
C) 0.00 V
D) +0.090 V
E) +0.030 V
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68
Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 1.10 M and [   ] = 1.10 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +2.33 V B) -3.23 V C) +1.48 V D) +2.22 V E) +0.68 V ] = 1.10 M and [ <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 1.10 M and [   ] = 1.10 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +2.33 V B) -3.23 V C) +1.48 V D) +2.22 V E) +0.68 V ] = 1.10 M Mg(s) + <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 1.10 M and [   ] = 1.10 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +2.33 V B) -3.23 V C) +1.48 V D) +2.22 V E) +0.68 V (aq) → <strong>Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [   ] = 1.10 M and [   ] = 1.10 M Mg(s) +   (aq) →   (aq) + Fe(s) E°(Mg<sup>2+</sup>/Mg) = -2.37 V and E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +2.33 V B) -3.23 V C) +1.48 V D) +2.22 V E) +0.68 V (aq) + Fe(s)
E°(Mg2+/Mg) = -2.37 V and E°(Fe3+/Fe) = -0.036 V

A) +2.33 V
B) -3.23 V
C) +1.48 V
D) +2.22 V
E) +0.68 V
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69
Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °: Cu(s) ∣ Cu2+(aq, 0.0032 mol L-1) <strong>Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °: Cu(s) ∣ Cu<sup>2+</sup>(aq, 0.0032 mol L<sup>-1</sup>)   Cu<sup>2+</sup>(aq, 4.48 mol L<sup>-1</sup>) ∣ Cu(s) E°(Cu<sup>2+</sup>/Cu) = +0.34 V</strong> A) 0.00 V B) +0.093 V C) +0.34 V D) +0.186 V E) +0.052 V Cu2+(aq, 4.48 mol L-1) ∣ Cu(s)
E°(Cu2+/Cu) = +0.34 V

A) 0.00 V
B) +0.093 V
C) +0.34 V
D) +0.186 V
E) +0.052 V
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70
Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °C: Sn(s) ∣ Sn2+(aq, 0.100 mol L-1) <strong>Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °C: Sn(s) ∣ Sn<sup>2+</sup>(aq, 0.100 mol L<sup>-1</sup>)   Ag<sup>+</sup>(aq, 0.200 mol L<sup>-1</sup>) ∣ Ag(s) E°(Sn<sup>2+</sup>/Sn) = -0.14 V and E°(Ag<sup>+</sup>/Ag) = +0.80 V</strong> A) -2.68 V B) -0.03 V C) +0.95 V D) +0.93 V E) +2.10 V Ag+(aq, 0.200 mol L-1) ∣ Ag(s)
E°(Sn2+/Sn) = -0.14 V and E°(Ag+/Ag) = +0.80 V

A) -2.68 V
B) -0.03 V
C) +0.95 V
D) +0.93 V
E) +2.10 V
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71
Identify the battery that is used as a common flashlight battery.

A) dry-cell battery
B) lithium-ion battery
C) lead-acid storage battery
D) NiCad battery
E) fuel cell
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72
What is the reaction at the cathode in a breathalyzer?

A) Ethanol is oxidized to acetic acid.
B) Acetic acid is reduced to ethanol.
C) Oxygen is reduced.
D) Hydrogen is oxidized.
E) Ethanol is oxidized to acetaldehyde.
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73
Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °C: Sn(s) ∣ Sn2+(aq, 1.8 mol L-1) <strong>Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °C: Sn(s) ∣ Sn<sup>2+</sup>(aq, 1.8 mol L<sup>-1</sup>)   Ag<sup>+</sup>(aq, 0.055 mol L<sup>-1</sup>) ∣ Ag(s) E°(Sn<sup>2+</sup>/Sn) = -0.14 V and E°(Ag<sup>+</sup>/Ag) = +0.80 V</strong> A) -0.94 V B) -0.85 V C) +1.02 V D) +0.98 V E) +0.86 V Ag+(aq, 0.055 mol L-1) ∣ Ag(s)
E°(Sn2+/Sn) = -0.14 V and E°(Ag+/Ag) = +0.80 V

A) -0.94 V
B) -0.85 V
C) +1.02 V
D) +0.98 V
E) +0.86 V
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74
Identify the battery type that has a high overcharge tolerance.

A) NiCad battery
B) lithium-ion battery
C) nickel-metal hydride battery
D) lead-acid storage battery
E) zinc-manganese battery
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75
Identify the battery that is in most automobiles.

A) dry-cell battery
B) lithium-ion battery
C) lead-acid storage battery
D) NiCad battery
E) fuel cell
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76
Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °: Fe(s) ∣ Fe3+(aq, 0.0011 mol L-1) <strong>Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25 °: Fe(s) ∣ Fe<sup>3+</sup>(aq, 0.0011 mol L<sup>-1</sup>)   Fe<sup>3+</sup>(aq, 2.33 mol L<sup>-1</sup>) ∣ Fe(s) E°(Fe<sup>3+</sup>/Fe) = -0.036 V</strong> A) +0.066 V B) -0.036 V C) 0.00 V D) -0.099 V E) +0.20 V Fe3+(aq, 2.33 mol L-1) ∣ Fe(s)
E°(Fe3+/Fe) = -0.036 V

A) +0.066 V
B) -0.036 V
C) 0.00 V
D) -0.099 V
E) +0.20 V
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77
Predict the species that will be reduced first if a mixture of molten salts containing the following ions undergoes electrolysis: Cd2+, Ni2+, Sn2+, Al3+, Pb2+

A) Pb2+
B) Al3+
C) Sn2+
D) Ni2+
E) Cd2+
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78
Predict the species that will be reduced first if a mixture of molten salts containing the following ions undergoes electrolysis: Cu2+, Ag+, Sn4+, Fe3+, Au3+

A) Cu2+
B) Ag+
C) Sn4+
D) Fe3+
E) Au3+
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79
Identify the components of a fuel cell.

A) nickel-metal hydride
B) lithium-ion
C) hydrogen-oxygen
D) nickel-cadmium
E) zinc-manganese
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80
Predict the species that will be reduced first if a mixture of molten salts containing the following ions undergoes electrolysis: Na+, Ca2+, Cl⁻, Br⁻, F⁻

A) Na⁺
B) Cl⁻
C) Ca2+
D) Br⁻
E) F⁻
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