Deck 8: Confidence Interval Estimation

Full screen (f)
exit full mode
Question
The following values have been calculated using the T DIST and T INV functions in Excel®. These values come from a t- distribution with 15 degrees of freedom.
These values represent the probability to the right of the given positive values. The following values have been calculated using the T DIST and T INV functions in Excel<sup>®</sup>. These values come from a t- distribution with 15 degrees of freedom. These values represent the probability to the right of the given positive values.   These values represent the positive t- value for a given probability in both tails (sum of both tails).   What is the probability of a t-value smaller than 1.00?<div style=padding-top: 35px> These values represent the positive t- value for a given probability in both tails (sum of both tails). The following values have been calculated using the T DIST and T INV functions in Excel<sup>®</sup>. These values come from a t- distribution with 15 degrees of freedom. These values represent the probability to the right of the given positive values.   These values represent the positive t- value for a given probability in both tails (sum of both tails).   What is the probability of a t-value smaller than 1.00?<div style=padding-top: 35px>
What is the probability of a t-value smaller than 1.00?
Use Space or
up arrow
down arrow
to flip the card.
Question
When we replace <strong>When we replace   with the sample standard deviation (s), we introduce a new source of variability and the sampling distribution becomes the:</strong> A) t -distribution B) F- distribution C) chi-square distribution D) normal distribution <div style=padding-top: 35px> with the sample standard deviation (s), we introduce a new source of variability and the sampling distribution becomes the:

A) t -distribution
B) F- distribution
C) chi-square distribution
D) normal distribution
Question
The following values have been calculated using the T DIST and T INV functions in Excel®. These values come from a t- distribution with 15 degrees of freedom.
These values represent the probability to the right of the given positive values. The following values have been calculated using the T DIST and T INV functions in Excel<sup>®</sup>. These values come from a t- distribution with 15 degrees of freedom. These values represent the probability to the right of the given positive values.   These values represent the positive t- value for a given probability in both tails (sum of both tails).   What would be the t-value where 0.05 of the values are in the upper tail?<div style=padding-top: 35px> These values represent the positive t- value for a given probability in both tails (sum of both tails). The following values have been calculated using the T DIST and T INV functions in Excel<sup>®</sup>. These values come from a t- distribution with 15 degrees of freedom. These values represent the probability to the right of the given positive values.   These values represent the positive t- value for a given probability in both tails (sum of both tails).   What would be the t-value where 0.05 of the values are in the upper tail?<div style=padding-top: 35px>
What would be the t-value where 0.05 of the values are in the upper tail?
Question
If you are constructing a confidence interval for a single mean, the confidence interval will _____ with an increase in the sample size.

A) decrease
B) increase
C) stay the same
D) increase or decrease, depending on the sample data,
Question
The general form of a confidence interval is:

A) Point Estimate = Multiple × Standard Error
B) Point Estimate = Multiple +Standard Error
C) Point Estimate = Multiple - Standard Error
D) Point Estimate = Multiple ± Standard Error
Question
A parameter such as <strong>A parameter such as   is sometimes referred to as a(n) ____ parameter, because many times, we need its value even though it is not the parameter of primary interest.</strong> A) special B) random C) nuisance D) independent E) dependent <div style=padding-top: 35px> is sometimes referred to as a(n) ____ parameter, because many times, we need its value even though it is not the parameter of primary interest.

A) special
B) random
C) nuisance
D) independent
E) dependent
Question
The following values have been calculated using the T DIST and T INV functions in Excel®. These values come from a t- distribution with 15 degrees of freedom.
These values represent the probability to the right of the given positive values. The following values have been calculated using the T DIST and T INV functions in Excel<sup>®</sup>. These values come from a t- distribution with 15 degrees of freedom. These values represent the probability to the right of the given positive values.   These values represent the positive t- value for a given probability in both tails (sum of both tails).   What would be the t-values where 0.10 of the values are in both tails (sum of both tails)?<div style=padding-top: 35px> These values represent the positive t- value for a given probability in both tails (sum of both tails). The following values have been calculated using the T DIST and T INV functions in Excel<sup>®</sup>. These values come from a t- distribution with 15 degrees of freedom. These values represent the probability to the right of the given positive values.   These values represent the positive t- value for a given probability in both tails (sum of both tails).   What would be the t-values where 0.10 of the values are in both tails (sum of both tails)?<div style=padding-top: 35px>
What would be the t-values where 0.10 of the values are in both tails (sum of both tails)?
Question
(A) Compute (A) Compute   has a t-distribution with 15 degrees of freedom. (B) Compute   has a t-distribution with 150 degrees of freedom. (C) How do you explain the difference between the results obtained in (A) and (B)? (D) Compute   where Z is a standard normal random variable. (E) Compare the results of (D) to the results obtained in (A) and (B). How do you explain the difference in these probabilities?<div style=padding-top: 35px> has a t-distribution with 15 degrees of freedom.
(B) Compute (A) Compute   has a t-distribution with 15 degrees of freedom. (B) Compute   has a t-distribution with 150 degrees of freedom. (C) How do you explain the difference between the results obtained in (A) and (B)? (D) Compute   where Z is a standard normal random variable. (E) Compare the results of (D) to the results obtained in (A) and (B). How do you explain the difference in these probabilities?<div style=padding-top: 35px> has a t-distribution with 150 degrees of freedom.
(C) How do you explain the difference between the results obtained in (A) and (B)?
(D) Compute (A) Compute   has a t-distribution with 15 degrees of freedom. (B) Compute   has a t-distribution with 150 degrees of freedom. (C) How do you explain the difference between the results obtained in (A) and (B)? (D) Compute   where Z is a standard normal random variable. (E) Compare the results of (D) to the results obtained in (A) and (B). How do you explain the difference in these probabilities?<div style=padding-top: 35px> where Z is a standard normal random variable.
(E) Compare the results of (D) to the results obtained in (A) and (B). How do you explain the difference in these probabilities?
Question
Two independent samples of sizes 50 and 50 are randomly selected from two populations to test the difference between the population means, <strong>Two independent samples of sizes 50 and 50 are randomly selected from two populations to test the difference between the population means,   . The sampling distribution of the sample mean difference   is:</strong> A) normally distributed B) approximately normal C) t - distributed with 98 degrees of freedom D) chi-squared distributed with 99 degrees of freedom <div style=padding-top: 35px> . The sampling distribution of the sample mean difference <strong>Two independent samples of sizes 50 and 50 are randomly selected from two populations to test the difference between the population means,   . The sampling distribution of the sample mean difference   is:</strong> A) normally distributed B) approximately normal C) t - distributed with 98 degrees of freedom D) chi-squared distributed with 99 degrees of freedom <div style=padding-top: 35px> is:

A) normally distributed
B) approximately normal
C) t - distributed with 98 degrees of freedom
D) chi-squared distributed with 99 degrees of freedom
Question
The t-distribution for developing a confidence interval for a mean has degrees of freedom equal to:

A) n + 2
B) n +1
C) n
D) n - 1
E) n - 2
Question
The following values have been calculated using the T DIST and T INV functions in Excel®. These values come from a t- distribution with 15 degrees of freedom.
These values represent the probability to the right of the given positive values. The following values have been calculated using the T DIST and T INV functions in Excel<sup>®</sup>. These values come from a t- distribution with 15 degrees of freedom. These values represent the probability to the right of the given positive values.   These values represent the positive t- value for a given probability in both tails (sum of both tails).   What is the probability of a t-value larger than 1.20?<div style=padding-top: 35px> These values represent the positive t- value for a given probability in both tails (sum of both tails). The following values have been calculated using the T DIST and T INV functions in Excel<sup>®</sup>. These values come from a t- distribution with 15 degrees of freedom. These values represent the probability to the right of the given positive values.   These values represent the positive t- value for a given probability in both tails (sum of both tails).   What is the probability of a t-value larger than 1.20?<div style=padding-top: 35px>
What is the probability of a t-value larger than 1.20?
Question
The chi-square and F-distributions are used primarily to make inferences about population ____.

A) means
B) variances
C) medians
D) modes
E) proportions
Question
A confidence interval is an interval that, with a stated level of confidence, captures a population parameter.
Question
The approximate standard error of the point estimate of the population total is:

A) <strong>The approximate standard error of the point estimate of the population total is:</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B) <strong>The approximate standard error of the point estimate of the population total is:</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C) <strong>The approximate standard error of the point estimate of the population total is:</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D) <strong>The approximate standard error of the point estimate of the population total is:</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
The following values have been calculated using the T DIST and T INV functions in Excel®. These values come from a t- distribution with 15 degrees of freedom.
These values represent the probability to the right of the given positive values. The following values have been calculated using the T DIST and T INV functions in Excel<sup>®</sup>. These values come from a t- distribution with 15 degrees of freedom. These values represent the probability to the right of the given positive values.   These values represent the positive t- value for a given probability in both tails (sum of both tails).   What is the probability of a t-value between -1.40 and +1.40?<div style=padding-top: 35px> These values represent the positive t- value for a given probability in both tails (sum of both tails). The following values have been calculated using the T DIST and T INV functions in Excel<sup>®</sup>. These values come from a t- distribution with 15 degrees of freedom. These values represent the probability to the right of the given positive values.   These values represent the positive t- value for a given probability in both tails (sum of both tails).   What is the probability of a t-value between -1.40 and +1.40?<div style=padding-top: 35px>
What is the probability of a t-value between -1.40 and +1.40?
Question
If you increase the confidence level, the confidence interval .

A) decreases
B) increases
C) stays the same
D) may increase or decrease, depending on the sample data
Question
When samples of size n are drawn from a population, then the sampling distribution of the sample mean When samples of size n are drawn from a population, then the sampling distribution of the sample mean   is approximately normal, provided that n is reasonably large.<div style=padding-top: 35px> is approximately normal, provided that n is reasonably large.
Question
The t-distribution and the standard normal distribution are practically indistinguishable as the degrees of freedom increase.
Question
The following values have been calculated using the T DIST and T INV functions in Excel®. These values come from a t- distribution with 15 degrees of freedom.
These values represent the probability to the right of the given positive values. The following values have been calculated using the T DIST and T INV functions in Excel<sup>®</sup>. These values come from a t- distribution with 15 degrees of freedom. These values represent the probability to the right of the given positive values.   These values represent the positive t- value for a given probability in both tails (sum of both tails).   What would be the t-values where 0.95 of the values would fall within this interval?<div style=padding-top: 35px> These values represent the positive t- value for a given probability in both tails (sum of both tails). The following values have been calculated using the T DIST and T INV functions in Excel<sup>®</sup>. These values come from a t- distribution with 15 degrees of freedom. These values represent the probability to the right of the given positive values.   These values represent the positive t- value for a given probability in both tails (sum of both tails).   What would be the t-values where 0.95 of the values would fall within this interval?<div style=padding-top: 35px>
What would be the t-values where 0.95 of the values would fall within this interval?
Question
As the sample size increases, the t-distribution becomes more similar to the ____ distribution.

A) normal
B) exponential
C) multinominal
D) chi-square
E) binomial
Question
As a general rule, the normal distribution is used to approximate the sampling distribution of the sample proportion As a general rule, the normal distribution is used to approximate the sampling distribution of the sample proportion   only if the sample size n is greater than 30.<div style=padding-top: 35px> only if the sample size n is greater than 30.
Question
The average annual household income levels of citizens of selected U.S. cities are shown below. The average annual household income levels of citizens of selected U.S. cities are shown below.   (A) Use Excel<sup>®</sup> to obtain a simple random sample of size 10 from this frame. ​ (B) Using the sample generated in (A), construct a 95% confidence interval for the mean average annual household income level of citizens in the selected U.S. cities. Assume that the population consists of all average annual household income levels in the given frame. ​ (C) Interpret the 95% confidence interval constructed in (B). ​ (D) Does the 95% confidence interval contain the actual population mean? If not, explain why not. What proportion of many similarly constructed confidence intervals should include the true population mean value?<div style=padding-top: 35px>
(A) Use Excel® to obtain a simple random sample of size 10 from this frame.

(B) Using the sample generated in (A), construct a 95% confidence interval for the mean average annual household income level of citizens in the selected U.S. cities. Assume that the population consists of all average annual household income levels in the given frame.

(C) Interpret the 95% confidence interval constructed in (B).

(D) Does the 95% confidence interval contain the actual population mean? If not, explain why not. What proportion of many similarly constructed confidence intervals should include the true population mean value?
Question
The 95% confidence interval for the population mean The 95% confidence interval for the population mean   , given that the sample size n = 49 and the population standard deviation   = 7, is   .<div style=padding-top: 35px> , given that the sample size n = 49 and the population standard deviation The 95% confidence interval for the population mean   , given that the sample size n = 49 and the population standard deviation   = 7, is   .<div style=padding-top: 35px> = 7, is The 95% confidence interval for the population mean   , given that the sample size n = 49 and the population standard deviation   = 7, is   .<div style=padding-top: 35px> .
Question
(A) Construct a 90% confidence interval estimate of the mean family dental expenses for all employees of this corporation.
(B) What assumption about the population distribution must be made to answer (A)?
(C) Interpret the 90% confidence interval constructed in (A).
(D) Suppose you used a 95% confidence interval in (A). What would be your answer?
(E) Suppose the fourth value were 593 instead of 93. What would be your answer to (A)? What effect does this change have on the confidence interval?
(F) Construct a 90% confidence interval estimate for the standard deviation of family dental expenses for all employees of this corporation.
(G) Interpret the 90% confidence interval constructed in (E).
Question
The standard error of the sampling distribution of the sample proportion The standard error of the sampling distribution of the sample proportion   , when the sample size n = 50 and the population proportion p = 0.25, is 0.00375.<div style=padding-top: 35px> , when the sample size n = 50 and the population proportion p = 0.25, is 0.00375.
Question
If the standard error of the sampling distribution of the sample proportion If the standard error of the sampling distribution of the sample proportion   is 0.0324 for samples of size 200, then the population proportion must be 0.30.<div style=padding-top: 35px> is 0.0324 for samples of size 200, then the population proportion must be 0.30.
Question
In order to construct a confidence interval estimate of the population mean In order to construct a confidence interval estimate of the population mean   , the value of   must be given.<div style=padding-top: 35px> , the value of In order to construct a confidence interval estimate of the population mean   , the value of   must be given.<div style=padding-top: 35px> must be given.
Question
In general, increasing the confidence level will narrow the confidence interval, and decreasing the confidence level widens the interval.
Question
(A) Construct a 95% confidence interval for the average width of an elevator rail. Do we need to assume that the width of elevator rails follows a normal distribution?
(B) How large a sample of elevator rails would we have to measure to ensure that we could estimate, with 95% confidence, the average diameter of an elevator rail within 0.01 inch?
Question
Suppose there are 500 accounts in a population. You sample 50 of them and find a sample mean of $500. What would be your estimate for the population total?

A) $5,000
B) $50,000
C) $250,000
D) $500,000
E) none of these choices
Question
If a sample has 20 observations and a 95% confidence estimate for If a sample has 20 observations and a 95% confidence estimate for   is needed, the appropriate value of t-multiple is 2.093<div style=padding-top: 35px> is needed, the appropriate value of t-multiple is 2.093
Question
The interval estimate 18.5 The interval estimate 18.5   2.5 is developed for a population mean in which the sample standard deviation s is 7.5. Had s equaled 15 instead, the interval estimate would be 37   5.0.<div style=padding-top: 35px> 2.5 is developed for a population mean in which the sample standard deviation s is 7.5. Had s equaled 15 instead, the interval estimate would be 37 The interval estimate 18.5   2.5 is developed for a population mean in which the sample standard deviation s is 7.5. Had s equaled 15 instead, the interval estimate would be 37   5.0.<div style=padding-top: 35px> 5.0.
Question
If you are constructing a confidence interval for a single mean, the confidence interval will with a decrease in the sample size.

A) decrease
B) increase
C) stay the same
D) increase or decrease, depending on the sample data
Question
We can form a confidence interval for the population total T by finding a confidence interval for the population mean We can form a confidence interval for the population total T by finding a confidence interval for the population mean   in the usual way, and then multiplying the lower and upper limits the confidence interval by the population size N.<div style=padding-top: 35px> in the usual way, and then multiplying the lower and upper limits the confidence interval by the population size N.
Question
(A) Construct a 95% confidence interval for the mean of the average annual credit account balances.

(B) Interpret the 95% confidence interval constructed in (A).

(C) Use the confidence interval constructed for (A) to help the store evaluate its criteria for whether or not the credit card program is worthwhile.
Question
The approximate standard error of the point estimate of the population total is The approximate standard error of the point estimate of the population total is   .<div style=padding-top: 35px> .
Question
(A) Construct a 95% confidence interval for the mean playing time of all Willie Nelson recordings.
(B) Interpret the confidence interval you constructed in (A).
Question
A 90% confidence interval estimate for a population mean A 90% confidence interval estimate for a population mean   is determined to be 72.8 to 79.6. If the confidence level is reduced to 80%, the confidence interval for   becomes narrower.<div style=padding-top: 35px> is determined to be 72.8 to 79.6. If the confidence level is reduced to 80%, the confidence interval for A 90% confidence interval estimate for a population mean   is determined to be 72.8 to 79.6. If the confidence level is reduced to 80%, the confidence interval for   becomes narrower.<div style=padding-top: 35px> becomes narrower.
Question
(A) Construct a 90% confidence interval for the total value of all savings account balances within this bank. Assume that the population consists of all savings account balances in the frame.
(B) Interpret the 90% confidence interval constructed in (A).
Question
If you decrease the confidence level, the confidence interval:

A) decreases
B) increases
C) stays the same
D) may increase or decrease, depending on the sample data
Question
The lower limit of the 95% confidence interval for the population proportion p, given that n = 300; and The lower limit of the 95% confidence interval for the population proportion p, given that n = 300; and   = 0.10 is 0.1339.<div style=padding-top: 35px> = 0.10 is 0.1339.
Question
The shape of a chi-square distribution:

A) is symmetric
B) is skewed to the left
C) is skewed to the right
D) depends on the sample data
Question
If two random samples of sizes 30 and 35 are selected independently from two populations whose means are 85 and 90, then the mean of the sampling distribution of the sample mean difference, If two random samples of sizes 30 and 35 are selected independently from two populations whose means are 85 and 90, then the mean of the sampling distribution of the sample mean difference,   , equals 5.<div style=padding-top: 35px> , equals 5.
Question
(A) Construct a 99% confidence interval for the proportion of company employees who prefer plan A. Assume that the population consists of the preferences of all employees in the frame.
(B) Interpret the 99% confidence interval constructed in (A).
Question
(A) Construct a 99% confidence interval for the standard deviation of the number of hours this firm's employees spend on work-related activities in a typical week.
(B) Interpret the 99% confidence interval constructed in (A).
(C) Given the target range of 40 to 60 hours of work per week, should senior management be concerned about the number of hours their employees are currently devoting to work? Explain why or why not.
Question
In general, the paired-sample procedure is appropriate when the samples are naturally paired in some way and there is a reasonably large positive correlation between the pairs. In this case, the paired-sample procedure makes more efficient use of the data and generally results in narrower confidence intervals.
Question
The upper limit of the 90% confidence interval for the population proportion p, given that n = 100; and The upper limit of the 90% confidence interval for the population proportion p, given that n = 100; and   = 0.20 is 0.2658.<div style=padding-top: 35px> = 0.20 is 0.2658.
Question
Two independent samples of sizes 20 and 25 are randomly selected from two normal populations with equal variances. In order to test the difference between the population means, the test statistic is:

A) a standard normal random variable
B) an approximately standard normal random variable
C) t-distributed with 45 degrees of freedom
D) t-distributed with 43 degrees of freedom
Question
The mean of the sampling distribution of the sample proportion The mean of the sampling distribution of the sample proportion   , when the sample size n = 100 and the population proportion p = 0.15, is 15.0.<div style=padding-top: 35px> , when the sample size n = 100 and the population proportion p = 0.15, is 15.0.
Question
In developing a confidence interval for the difference between two population means using two independent samples, we use the pooled estimate In developing a confidence interval for the difference between two population means using two independent samples, we use the pooled estimate   in estimating the standard error of the sampling distribution of the sample mean difference   if the populations are normal with equal variances.<div style=padding-top: 35px> in estimating the standard error of the sampling distribution of the sample mean difference In developing a confidence interval for the difference between two population means using two independent samples, we use the pooled estimate   in estimating the standard error of the sampling distribution of the sample mean difference   if the populations are normal with equal variances.<div style=padding-top: 35px> if the populations are normal with equal variances.
Question
If two random samples of size 40 each are selected independently from two populations whose variances are 35 and 45, then the standard error of the sampling distribution of the sample mean difference, If two random samples of size 40 each are selected independently from two populations whose variances are 35 and 45, then the standard error of the sampling distribution of the sample mean difference,   , equals 1.4142.<div style=padding-top: 35px> , equals 1.4142.
Question
You are told that a random sample of 150 people from Iowa has been given cholesterol tests, and 60 of these people had levels over the "safe" count of 200. Construct a 95% confidence interval for the population proportion of people in Iowa with cholesterol levels over 200.
Question
(A) Construct a 95% confidence interval estimate of the population proportion of all customers who still own the cars they purchased six years ago.

(B) How can the result in (A) be used by the automobile dealer to study satisfaction with cars purchased at the dealership?
Question
What is an example of a problem in which the sample data is likely to be paired?

A) the difference between the means of appraised and sales house prices
B) the difference between the proportion of defective items from two suppliers
C) the difference in the mean life of two major brands of batteries
D) the difference in the mean salaries for graduates in two different academic fields at a university
E) none of these choices
Question
The number of degrees of freedom needed to construct 90% confidence interval for the difference between means when the data are gathered from paired samples, with 15 observations in each sample, is:

A) 30
B) 15
C) 28
D) 14
Question
The degrees of freedom for the t and chi-square distributions is a numerical parameter of the distribution that defines the precise shape of the distribution.
Question
The confidence interval for the population standard deviation σ is centered at the point estimate, the sample standard deviation s.
Question
When the samples we want to compare pair in some natural way, such as a pretest/posttest for each person or husband/wife pairs, a more appropriate form of analysis is to not compare two separate variables, but instead to compare their ____.

A) difference
B) sum
C) ratio
D) total
E) product
Question
If a random sample of size 250 is taken from a population, where it is known that the population proportion p = 0.4, then the mean of the sampling distribution of the sample proportion If a random sample of size 250 is taken from a population, where it is known that the population proportion p = 0.4, then the mean of the sampling distribution of the sample proportion   is 0.60.<div style=padding-top: 35px> is 0.60.
Question
In developing a confidence interval for the population standard deviation In developing a confidence interval for the population standard deviation   , we make use of the fact that the sampling distribution of the sample standard deviation s is not the normal distribution or the t-distribution, but rather a right-skewed distribution called the chi-square distribution, which (for this procedure) has n - 1 degrees of freedom.<div style=padding-top: 35px> , we make use of the fact that the sampling distribution of the sample standard deviation s is not the normal distribution or the t-distribution, but rather a right-skewed distribution called the chi-square distribution, which (for this procedure) has n - 1 degrees of freedom.
Question
(A) Find a 95% confidence interval for the mean account balance on this store's credit card (the t-multiple with 39 degrees of freedom is 2.0227).
(B) What sample size would be needed to ensure that we could estimate the true mean account balance and have only 5 chances in 100 of being off by more than $100?
Question
Q-Mart is interested in comparing its male and female customers. Q-Mart would like to know if its female charge customers spend more money, on average, than its male charge customers. They have collected random samples of 25 female customers and 22 male customers. On average, women charge customers spend $102.23 and men charge customers spend $86.46. Some information are shown below. Q-Mart is interested in comparing its male and female customers. Q-Mart would like to know if its female charge customers spend more money, on average, than its male charge customers. They have collected random samples of 25 female customers and 22 male customers. On average, women charge customers spend $102.23 and men charge customers spend $86.46. Some information are shown below.   (A) Use a t - value of 2.014 to calculate a 95% confidence interval for the difference between the average female purchase and the average male purchase. Would you conclude that there is a significant difference between females and males in this case? Explain. (B) What are the degrees of freedom for the t-multiple in this calculation? Explain how you would calculate the degrees of freedom in this case. (C) What is the assumption in this case that allows you to use the pooled standard deviation for this confidence interval?<div style=padding-top: 35px>
(A) Use a t - value of 2.014 to calculate a 95% confidence interval for the difference between the average female purchase and the average male purchase. Would you conclude that there is a significant difference between females and males in this case? Explain.
(B) What are the degrees of freedom for the t-multiple in this calculation? Explain how you would calculate the degrees of freedom in this case.
(C) What is the assumption in this case that allows you to use the pooled standard deviation for this confidence interval?
Question
After calculating the sample size needed to estimate a population proportion to within 0.05, you have been told that the maximum allowable error (B) must be reduced to just 0.025. If the original calculation led to a sample size of 1000, the sample size will now have to be:

A) 2000
B) 4000
C) 1000
D) 8000
Question
You would like to estimate the average amount a family spends on food during a year. In the past, the standard deviation of the amount a family has spent on food during a year has been approximately $800. If you want to be 95% sure that you estimated average family food expenditures within $50, how many families do you need to survey?
Question
If we cannot make the strong assumption that the variances of two samples are equal, then we must use the pooled standard deviation in calculating the standard error of a difference between the means.
Question
Q-Mart is interested in comparing customers who use its own charge card with those who use other types of credit cards. Q-Mart would like to know if customers who use the Q-Mart card spend more money per visit, on average, than customers who use some other type of credit cards. They have collected information on a random sample of 38 charge customers as shown below. On average, the person using a Q-Mart card spends $192.81 per visit and customers using another type of card spend $104.47 per visit. Q-Mart is interested in comparing customers who use its own charge card with those who use other types of credit cards. Q-Mart would like to know if customers who use the Q-Mart card spend more money per visit, on average, than customers who use some other type of credit cards. They have collected information on a random sample of 38 charge customers as shown below. On average, the person using a Q-Mart card spends $192.81 per visit and customers using another type of card spend $104.47 per visit.   (A) Using a t - value of 2.0281, calculate a 95% confidence interval for the difference between the average Q-Mart charge and the average charge on another type of credit card. (B) What are the degrees of freedom for the t - multiple in this calculation? Explain how you would calculate the degrees of freedom in this case. (C) What is the assumption in this case that allows you to use the pooled standard deviation for this confidence interval? (D) Would you conclude that there is a significant difference between the two types of customers in this case? Explain.<div style=padding-top: 35px>
(A) Using a t - value of 2.0281, calculate a 95% confidence interval for the difference between the average Q-Mart charge and the average charge on another type of credit card.
(B) What are the degrees of freedom for the t - multiple in this calculation? Explain how you would calculate the degrees of freedom in this case.
(C) What is the assumption in this case that allows you to use the pooled standard deviation for this confidence interval?
(D) Would you conclude that there is a significant difference between the two types of customers in this case? Explain.
Question
In determining the sample size n for estimating the population proportion p, a conservative value of n can be obtained by using 0.50 as an estimate of p.
Question
In constructing a confidence interval estimate for the difference between the means of two populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows: In constructing a confidence interval estimate for the difference between the means of two populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   ,   ,   , and   . Construct a 90% confidence interval for   .<div style=padding-top: 35px> , In constructing a confidence interval estimate for the difference between the means of two populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   ,   ,   , and   . Construct a 90% confidence interval for   .<div style=padding-top: 35px> , In constructing a confidence interval estimate for the difference between the means of two populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   ,   ,   , and   . Construct a 90% confidence interval for   .<div style=padding-top: 35px> , In constructing a confidence interval estimate for the difference between the means of two populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   ,   ,   , and   . Construct a 90% confidence interval for   .<div style=padding-top: 35px> , In constructing a confidence interval estimate for the difference between the means of two populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   ,   ,   , and   . Construct a 90% confidence interval for   .<div style=padding-top: 35px> , and In constructing a confidence interval estimate for the difference between the means of two populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   ,   ,   , and   . Construct a 90% confidence interval for   .<div style=padding-top: 35px> . Construct a 90% confidence interval for In constructing a confidence interval estimate for the difference between the means of two populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   ,   ,   , and   . Construct a 90% confidence interval for   .<div style=padding-top: 35px> .
Question
A real estate agent has collected a random sample of 40 houses that were recently sold in Grand Rapids, Michigan. She is interested in comparing the appraised value and recent selling price (in thousands of dollars) of the houses in this particular market. The values of these two variables for each of the 40 randomly selected houses are shown below. A real estate agent has collected a random sample of 40 houses that were recently sold in Grand Rapids, Michigan. She is interested in comparing the appraised value and recent selling price (in thousands of dollars) of the houses in this particular market. The values of these two variables for each of the 40 randomly selected houses are shown below.   (A) Use the sample data to generate a 95% confidence interval for the mean difference between the appraised values and selling prices of the houses sold in Grand Rapids. (B) Interpret the constructed confidence interval fin (A) for the real estate agent.<div style=padding-top: 35px>
(A) Use the sample data to generate a 95% confidence interval for the mean difference between the appraised values and selling prices of the houses sold in Grand Rapids.
(B) Interpret the constructed confidence interval fin (A) for the real estate agent.
Question
(A) Construct a 95% confidence interval for the difference between the proportions of online and classroom customers who pass the final exam.
(B) Interpret the confidence interval obtained in (A).
Question
A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The average thickness and the standard deviation of thickness for shift 1, based on a random sample of 40 gaskets, are 10.85 mm and 0.16 mm, respectively. The similar figures for shift 2, based on a random sample of 30 gaskets, are 10.90 mm and 0.19 mm. Let A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The average thickness and the standard deviation of thickness for shift 1, based on a random sample of 40 gaskets, are 10.85 mm and 0.16 mm, respectively. The similar figures for shift 2, based on a random sample of 30 gaskets, are 10.90 mm and 0.19 mm. Let   be the difference in thickness between shifts 1 and 2, and assume that the population variances are equal. (A) Construct a 95% confidence interval for   . (B) Based on your answer to (A), are you convinced that the gaskets from shift 2 are, on average, wider than those from shift 1? Why or why not?<div style=padding-top: 35px> be the difference in thickness between shifts 1 and 2, and assume that the population variances are equal.
(A) Construct a 95% confidence interval for A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The average thickness and the standard deviation of thickness for shift 1, based on a random sample of 40 gaskets, are 10.85 mm and 0.16 mm, respectively. The similar figures for shift 2, based on a random sample of 30 gaskets, are 10.90 mm and 0.19 mm. Let   be the difference in thickness between shifts 1 and 2, and assume that the population variances are equal. (A) Construct a 95% confidence interval for   . (B) Based on your answer to (A), are you convinced that the gaskets from shift 2 are, on average, wider than those from shift 1? Why or why not?<div style=padding-top: 35px> .
(B) Based on your answer to (A), are you convinced that the gaskets from shift 2 are, on average, wider than those from shift 1? Why or why not?
Question
(A) Determine a 95% confidence interval for the proportion defective for the process today.
(B) Based on your answer to (A), is it still reasonable to think the overall proportion defective produced by today's process is actually the targeted 4%? Explain your reasoning.
(C) The confidence interval in (A) is based on the assumption of a large sample size. Is this sample size sufficiently large in this example? Explain how you arrived at your answer.
(D) How many units would have to be sampled to be 95% confident that you can estimate the fraction of defective parts within 2% (using the information from today's sample)?
Question
Confidence intervals are a function of the:

A) population, the sample, and the standard deviation
B) sample, the variable of interest, and the degrees of freedom
C) data in the sample, the confidence level, and the sample size
D) sampling distribution, the confidence level, and the degrees of freedom
E) mean, median, and mode
Question
Samples of exam scores for employees before and after a training class are examples of paired data.
Question
You are attempting to estimate the average amount a family spends on food during a year. In the past, the standard deviation of the amount a family has spent on food during a year has been approximately $1200. If you want to be 99% sure that you have estimated average family food expenditures within $60, how many families do you need to survey?
Question
When you calculate the sample size for a proportion, you use an estimate for the population proportion; namely <strong>When you calculate the sample size for a proportion, you use an estimate for the population proportion; namely   . A conservative value for n can be obtained by using   = :</strong> A) 0.01 B) 0.05 C) 0.10 D) 0.50 E) 1.00 <div style=padding-top: 35px> . A conservative value for n can be obtained by using <strong>When you calculate the sample size for a proportion, you use an estimate for the population proportion; namely   . A conservative value for n can be obtained by using   = :</strong> A) 0.01 B) 0.05 C) 0.10 D) 0.50 E) 1.00 <div style=padding-top: 35px> = :

A) 0.01
B) 0.05
C) 0.10
D) 0.50
E) 1.00
Question
(A) You can be 95% confident that the mean salary for all production managers with at least 15 years of experience is between what two numbers (the t-multiple with 8 degrees of freedom is 2.306). What assumption are you making about the distribution of salaries?

(B) What sample size would be needed to ensure that we could estimate the true mean salary of all production managers with more than 15 years of experience and have only 5 chances in 100 of being off by more than $4200?
Question
A market research consultant hired by Coke Classic Company is interested in estimating the difference between the proportions of female and male customers who favor Coke Classic over Pepsi Cola in Chicago. A random sample of 200 consumers from the market under investigation shows the following frequency distribution. A market research consultant hired by Coke Classic Company is interested in estimating the difference between the proportions of female and male customers who favor Coke Classic over Pepsi Cola in Chicago. A random sample of 200 consumers from the market under investigation shows the following frequency distribution.   ​ (A) Construct a 95% confidence interval for the difference between the proportions of male and female customers who prefer Coke Classic<sup>®</sup> over Pepsi Cola<sup>®</sup>. ​ (B) Interpret the constructed confidence interval.<div style=padding-top: 35px>
(A) Construct a 95% confidence interval for the difference between the proportions of male and female customers who prefer Coke Classic® over Pepsi Cola®.

(B) Interpret the constructed confidence interval.
Question
For a given confidence level, the procedure for controlling interval length usually begins with the specification of the:

A) point estimate
B) population standard deviation, s
C) sample standard deviation, s
D) interval half-length, B
Question
If two samples contain the same number of observations, then the data must be paired.
Unlock Deck
Sign up to unlock the cards in this deck!
Unlock Deck
Unlock Deck
1/84
auto play flashcards
Play
simple tutorial
Full screen (f)
exit full mode
Deck 8: Confidence Interval Estimation
1
The following values have been calculated using the T DIST and T INV functions in Excel®. These values come from a t- distribution with 15 degrees of freedom.
These values represent the probability to the right of the given positive values. The following values have been calculated using the T DIST and T INV functions in Excel<sup>®</sup>. These values come from a t- distribution with 15 degrees of freedom. These values represent the probability to the right of the given positive values.   These values represent the positive t- value for a given probability in both tails (sum of both tails).   What is the probability of a t-value smaller than 1.00? These values represent the positive t- value for a given probability in both tails (sum of both tails). The following values have been calculated using the T DIST and T INV functions in Excel<sup>®</sup>. These values come from a t- distribution with 15 degrees of freedom. These values represent the probability to the right of the given positive values.   These values represent the positive t- value for a given probability in both tails (sum of both tails).   What is the probability of a t-value smaller than 1.00?
What is the probability of a t-value smaller than 1.00?
0.8334
2
When we replace <strong>When we replace   with the sample standard deviation (s), we introduce a new source of variability and the sampling distribution becomes the:</strong> A) t -distribution B) F- distribution C) chi-square distribution D) normal distribution with the sample standard deviation (s), we introduce a new source of variability and the sampling distribution becomes the:

A) t -distribution
B) F- distribution
C) chi-square distribution
D) normal distribution
t -distribution
3
The following values have been calculated using the T DIST and T INV functions in Excel®. These values come from a t- distribution with 15 degrees of freedom.
These values represent the probability to the right of the given positive values. The following values have been calculated using the T DIST and T INV functions in Excel<sup>®</sup>. These values come from a t- distribution with 15 degrees of freedom. These values represent the probability to the right of the given positive values.   These values represent the positive t- value for a given probability in both tails (sum of both tails).   What would be the t-value where 0.05 of the values are in the upper tail? These values represent the positive t- value for a given probability in both tails (sum of both tails). The following values have been calculated using the T DIST and T INV functions in Excel<sup>®</sup>. These values come from a t- distribution with 15 degrees of freedom. These values represent the probability to the right of the given positive values.   These values represent the positive t- value for a given probability in both tails (sum of both tails).   What would be the t-value where 0.05 of the values are in the upper tail?
What would be the t-value where 0.05 of the values are in the upper tail?
+ 1.7531
4
If you are constructing a confidence interval for a single mean, the confidence interval will _____ with an increase in the sample size.

A) decrease
B) increase
C) stay the same
D) increase or decrease, depending on the sample data,
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
5
The general form of a confidence interval is:

A) Point Estimate = Multiple × Standard Error
B) Point Estimate = Multiple +Standard Error
C) Point Estimate = Multiple - Standard Error
D) Point Estimate = Multiple ± Standard Error
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
6
A parameter such as <strong>A parameter such as   is sometimes referred to as a(n) ____ parameter, because many times, we need its value even though it is not the parameter of primary interest.</strong> A) special B) random C) nuisance D) independent E) dependent is sometimes referred to as a(n) ____ parameter, because many times, we need its value even though it is not the parameter of primary interest.

A) special
B) random
C) nuisance
D) independent
E) dependent
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
7
The following values have been calculated using the T DIST and T INV functions in Excel®. These values come from a t- distribution with 15 degrees of freedom.
These values represent the probability to the right of the given positive values. The following values have been calculated using the T DIST and T INV functions in Excel<sup>®</sup>. These values come from a t- distribution with 15 degrees of freedom. These values represent the probability to the right of the given positive values.   These values represent the positive t- value for a given probability in both tails (sum of both tails).   What would be the t-values where 0.10 of the values are in both tails (sum of both tails)? These values represent the positive t- value for a given probability in both tails (sum of both tails). The following values have been calculated using the T DIST and T INV functions in Excel<sup>®</sup>. These values come from a t- distribution with 15 degrees of freedom. These values represent the probability to the right of the given positive values.   These values represent the positive t- value for a given probability in both tails (sum of both tails).   What would be the t-values where 0.10 of the values are in both tails (sum of both tails)?
What would be the t-values where 0.10 of the values are in both tails (sum of both tails)?
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
8
(A) Compute (A) Compute   has a t-distribution with 15 degrees of freedom. (B) Compute   has a t-distribution with 150 degrees of freedom. (C) How do you explain the difference between the results obtained in (A) and (B)? (D) Compute   where Z is a standard normal random variable. (E) Compare the results of (D) to the results obtained in (A) and (B). How do you explain the difference in these probabilities? has a t-distribution with 15 degrees of freedom.
(B) Compute (A) Compute   has a t-distribution with 15 degrees of freedom. (B) Compute   has a t-distribution with 150 degrees of freedom. (C) How do you explain the difference between the results obtained in (A) and (B)? (D) Compute   where Z is a standard normal random variable. (E) Compare the results of (D) to the results obtained in (A) and (B). How do you explain the difference in these probabilities? has a t-distribution with 150 degrees of freedom.
(C) How do you explain the difference between the results obtained in (A) and (B)?
(D) Compute (A) Compute   has a t-distribution with 15 degrees of freedom. (B) Compute   has a t-distribution with 150 degrees of freedom. (C) How do you explain the difference between the results obtained in (A) and (B)? (D) Compute   where Z is a standard normal random variable. (E) Compare the results of (D) to the results obtained in (A) and (B). How do you explain the difference in these probabilities? where Z is a standard normal random variable.
(E) Compare the results of (D) to the results obtained in (A) and (B). How do you explain the difference in these probabilities?
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
9
Two independent samples of sizes 50 and 50 are randomly selected from two populations to test the difference between the population means, <strong>Two independent samples of sizes 50 and 50 are randomly selected from two populations to test the difference between the population means,   . The sampling distribution of the sample mean difference   is:</strong> A) normally distributed B) approximately normal C) t - distributed with 98 degrees of freedom D) chi-squared distributed with 99 degrees of freedom . The sampling distribution of the sample mean difference <strong>Two independent samples of sizes 50 and 50 are randomly selected from two populations to test the difference between the population means,   . The sampling distribution of the sample mean difference   is:</strong> A) normally distributed B) approximately normal C) t - distributed with 98 degrees of freedom D) chi-squared distributed with 99 degrees of freedom is:

A) normally distributed
B) approximately normal
C) t - distributed with 98 degrees of freedom
D) chi-squared distributed with 99 degrees of freedom
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
10
The t-distribution for developing a confidence interval for a mean has degrees of freedom equal to:

A) n + 2
B) n +1
C) n
D) n - 1
E) n - 2
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
11
The following values have been calculated using the T DIST and T INV functions in Excel®. These values come from a t- distribution with 15 degrees of freedom.
These values represent the probability to the right of the given positive values. The following values have been calculated using the T DIST and T INV functions in Excel<sup>®</sup>. These values come from a t- distribution with 15 degrees of freedom. These values represent the probability to the right of the given positive values.   These values represent the positive t- value for a given probability in both tails (sum of both tails).   What is the probability of a t-value larger than 1.20? These values represent the positive t- value for a given probability in both tails (sum of both tails). The following values have been calculated using the T DIST and T INV functions in Excel<sup>®</sup>. These values come from a t- distribution with 15 degrees of freedom. These values represent the probability to the right of the given positive values.   These values represent the positive t- value for a given probability in both tails (sum of both tails).   What is the probability of a t-value larger than 1.20?
What is the probability of a t-value larger than 1.20?
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
12
The chi-square and F-distributions are used primarily to make inferences about population ____.

A) means
B) variances
C) medians
D) modes
E) proportions
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
13
A confidence interval is an interval that, with a stated level of confidence, captures a population parameter.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
14
The approximate standard error of the point estimate of the population total is:

A) <strong>The approximate standard error of the point estimate of the population total is:</strong> A)   B)   C)   D)
B) <strong>The approximate standard error of the point estimate of the population total is:</strong> A)   B)   C)   D)
C) <strong>The approximate standard error of the point estimate of the population total is:</strong> A)   B)   C)   D)
D) <strong>The approximate standard error of the point estimate of the population total is:</strong> A)   B)   C)   D)
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
15
The following values have been calculated using the T DIST and T INV functions in Excel®. These values come from a t- distribution with 15 degrees of freedom.
These values represent the probability to the right of the given positive values. The following values have been calculated using the T DIST and T INV functions in Excel<sup>®</sup>. These values come from a t- distribution with 15 degrees of freedom. These values represent the probability to the right of the given positive values.   These values represent the positive t- value for a given probability in both tails (sum of both tails).   What is the probability of a t-value between -1.40 and +1.40? These values represent the positive t- value for a given probability in both tails (sum of both tails). The following values have been calculated using the T DIST and T INV functions in Excel<sup>®</sup>. These values come from a t- distribution with 15 degrees of freedom. These values represent the probability to the right of the given positive values.   These values represent the positive t- value for a given probability in both tails (sum of both tails).   What is the probability of a t-value between -1.40 and +1.40?
What is the probability of a t-value between -1.40 and +1.40?
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
16
If you increase the confidence level, the confidence interval .

A) decreases
B) increases
C) stays the same
D) may increase or decrease, depending on the sample data
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
17
When samples of size n are drawn from a population, then the sampling distribution of the sample mean When samples of size n are drawn from a population, then the sampling distribution of the sample mean   is approximately normal, provided that n is reasonably large. is approximately normal, provided that n is reasonably large.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
18
The t-distribution and the standard normal distribution are practically indistinguishable as the degrees of freedom increase.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
19
The following values have been calculated using the T DIST and T INV functions in Excel®. These values come from a t- distribution with 15 degrees of freedom.
These values represent the probability to the right of the given positive values. The following values have been calculated using the T DIST and T INV functions in Excel<sup>®</sup>. These values come from a t- distribution with 15 degrees of freedom. These values represent the probability to the right of the given positive values.   These values represent the positive t- value for a given probability in both tails (sum of both tails).   What would be the t-values where 0.95 of the values would fall within this interval? These values represent the positive t- value for a given probability in both tails (sum of both tails). The following values have been calculated using the T DIST and T INV functions in Excel<sup>®</sup>. These values come from a t- distribution with 15 degrees of freedom. These values represent the probability to the right of the given positive values.   These values represent the positive t- value for a given probability in both tails (sum of both tails).   What would be the t-values where 0.95 of the values would fall within this interval?
What would be the t-values where 0.95 of the values would fall within this interval?
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
20
As the sample size increases, the t-distribution becomes more similar to the ____ distribution.

A) normal
B) exponential
C) multinominal
D) chi-square
E) binomial
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
21
As a general rule, the normal distribution is used to approximate the sampling distribution of the sample proportion As a general rule, the normal distribution is used to approximate the sampling distribution of the sample proportion   only if the sample size n is greater than 30. only if the sample size n is greater than 30.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
22
The average annual household income levels of citizens of selected U.S. cities are shown below. The average annual household income levels of citizens of selected U.S. cities are shown below.   (A) Use Excel<sup>®</sup> to obtain a simple random sample of size 10 from this frame. ​ (B) Using the sample generated in (A), construct a 95% confidence interval for the mean average annual household income level of citizens in the selected U.S. cities. Assume that the population consists of all average annual household income levels in the given frame. ​ (C) Interpret the 95% confidence interval constructed in (B). ​ (D) Does the 95% confidence interval contain the actual population mean? If not, explain why not. What proportion of many similarly constructed confidence intervals should include the true population mean value?
(A) Use Excel® to obtain a simple random sample of size 10 from this frame.

(B) Using the sample generated in (A), construct a 95% confidence interval for the mean average annual household income level of citizens in the selected U.S. cities. Assume that the population consists of all average annual household income levels in the given frame.

(C) Interpret the 95% confidence interval constructed in (B).

(D) Does the 95% confidence interval contain the actual population mean? If not, explain why not. What proportion of many similarly constructed confidence intervals should include the true population mean value?
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
23
The 95% confidence interval for the population mean The 95% confidence interval for the population mean   , given that the sample size n = 49 and the population standard deviation   = 7, is   . , given that the sample size n = 49 and the population standard deviation The 95% confidence interval for the population mean   , given that the sample size n = 49 and the population standard deviation   = 7, is   . = 7, is The 95% confidence interval for the population mean   , given that the sample size n = 49 and the population standard deviation   = 7, is   . .
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
24
(A) Construct a 90% confidence interval estimate of the mean family dental expenses for all employees of this corporation.
(B) What assumption about the population distribution must be made to answer (A)?
(C) Interpret the 90% confidence interval constructed in (A).
(D) Suppose you used a 95% confidence interval in (A). What would be your answer?
(E) Suppose the fourth value were 593 instead of 93. What would be your answer to (A)? What effect does this change have on the confidence interval?
(F) Construct a 90% confidence interval estimate for the standard deviation of family dental expenses for all employees of this corporation.
(G) Interpret the 90% confidence interval constructed in (E).
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
25
The standard error of the sampling distribution of the sample proportion The standard error of the sampling distribution of the sample proportion   , when the sample size n = 50 and the population proportion p = 0.25, is 0.00375. , when the sample size n = 50 and the population proportion p = 0.25, is 0.00375.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
26
If the standard error of the sampling distribution of the sample proportion If the standard error of the sampling distribution of the sample proportion   is 0.0324 for samples of size 200, then the population proportion must be 0.30. is 0.0324 for samples of size 200, then the population proportion must be 0.30.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
27
In order to construct a confidence interval estimate of the population mean In order to construct a confidence interval estimate of the population mean   , the value of   must be given. , the value of In order to construct a confidence interval estimate of the population mean   , the value of   must be given. must be given.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
28
In general, increasing the confidence level will narrow the confidence interval, and decreasing the confidence level widens the interval.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
29
(A) Construct a 95% confidence interval for the average width of an elevator rail. Do we need to assume that the width of elevator rails follows a normal distribution?
(B) How large a sample of elevator rails would we have to measure to ensure that we could estimate, with 95% confidence, the average diameter of an elevator rail within 0.01 inch?
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
30
Suppose there are 500 accounts in a population. You sample 50 of them and find a sample mean of $500. What would be your estimate for the population total?

A) $5,000
B) $50,000
C) $250,000
D) $500,000
E) none of these choices
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
31
If a sample has 20 observations and a 95% confidence estimate for If a sample has 20 observations and a 95% confidence estimate for   is needed, the appropriate value of t-multiple is 2.093 is needed, the appropriate value of t-multiple is 2.093
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
32
The interval estimate 18.5 The interval estimate 18.5   2.5 is developed for a population mean in which the sample standard deviation s is 7.5. Had s equaled 15 instead, the interval estimate would be 37   5.0. 2.5 is developed for a population mean in which the sample standard deviation s is 7.5. Had s equaled 15 instead, the interval estimate would be 37 The interval estimate 18.5   2.5 is developed for a population mean in which the sample standard deviation s is 7.5. Had s equaled 15 instead, the interval estimate would be 37   5.0. 5.0.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
33
If you are constructing a confidence interval for a single mean, the confidence interval will with a decrease in the sample size.

A) decrease
B) increase
C) stay the same
D) increase or decrease, depending on the sample data
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
34
We can form a confidence interval for the population total T by finding a confidence interval for the population mean We can form a confidence interval for the population total T by finding a confidence interval for the population mean   in the usual way, and then multiplying the lower and upper limits the confidence interval by the population size N. in the usual way, and then multiplying the lower and upper limits the confidence interval by the population size N.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
35
(A) Construct a 95% confidence interval for the mean of the average annual credit account balances.

(B) Interpret the 95% confidence interval constructed in (A).

(C) Use the confidence interval constructed for (A) to help the store evaluate its criteria for whether or not the credit card program is worthwhile.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
36
The approximate standard error of the point estimate of the population total is The approximate standard error of the point estimate of the population total is   . .
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
37
(A) Construct a 95% confidence interval for the mean playing time of all Willie Nelson recordings.
(B) Interpret the confidence interval you constructed in (A).
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
38
A 90% confidence interval estimate for a population mean A 90% confidence interval estimate for a population mean   is determined to be 72.8 to 79.6. If the confidence level is reduced to 80%, the confidence interval for   becomes narrower. is determined to be 72.8 to 79.6. If the confidence level is reduced to 80%, the confidence interval for A 90% confidence interval estimate for a population mean   is determined to be 72.8 to 79.6. If the confidence level is reduced to 80%, the confidence interval for   becomes narrower. becomes narrower.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
39
(A) Construct a 90% confidence interval for the total value of all savings account balances within this bank. Assume that the population consists of all savings account balances in the frame.
(B) Interpret the 90% confidence interval constructed in (A).
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
40
If you decrease the confidence level, the confidence interval:

A) decreases
B) increases
C) stays the same
D) may increase or decrease, depending on the sample data
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
41
The lower limit of the 95% confidence interval for the population proportion p, given that n = 300; and The lower limit of the 95% confidence interval for the population proportion p, given that n = 300; and   = 0.10 is 0.1339. = 0.10 is 0.1339.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
42
The shape of a chi-square distribution:

A) is symmetric
B) is skewed to the left
C) is skewed to the right
D) depends on the sample data
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
43
If two random samples of sizes 30 and 35 are selected independently from two populations whose means are 85 and 90, then the mean of the sampling distribution of the sample mean difference, If two random samples of sizes 30 and 35 are selected independently from two populations whose means are 85 and 90, then the mean of the sampling distribution of the sample mean difference,   , equals 5. , equals 5.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
44
(A) Construct a 99% confidence interval for the proportion of company employees who prefer plan A. Assume that the population consists of the preferences of all employees in the frame.
(B) Interpret the 99% confidence interval constructed in (A).
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
45
(A) Construct a 99% confidence interval for the standard deviation of the number of hours this firm's employees spend on work-related activities in a typical week.
(B) Interpret the 99% confidence interval constructed in (A).
(C) Given the target range of 40 to 60 hours of work per week, should senior management be concerned about the number of hours their employees are currently devoting to work? Explain why or why not.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
46
In general, the paired-sample procedure is appropriate when the samples are naturally paired in some way and there is a reasonably large positive correlation between the pairs. In this case, the paired-sample procedure makes more efficient use of the data and generally results in narrower confidence intervals.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
47
The upper limit of the 90% confidence interval for the population proportion p, given that n = 100; and The upper limit of the 90% confidence interval for the population proportion p, given that n = 100; and   = 0.20 is 0.2658. = 0.20 is 0.2658.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
48
Two independent samples of sizes 20 and 25 are randomly selected from two normal populations with equal variances. In order to test the difference between the population means, the test statistic is:

A) a standard normal random variable
B) an approximately standard normal random variable
C) t-distributed with 45 degrees of freedom
D) t-distributed with 43 degrees of freedom
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
49
The mean of the sampling distribution of the sample proportion The mean of the sampling distribution of the sample proportion   , when the sample size n = 100 and the population proportion p = 0.15, is 15.0. , when the sample size n = 100 and the population proportion p = 0.15, is 15.0.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
50
In developing a confidence interval for the difference between two population means using two independent samples, we use the pooled estimate In developing a confidence interval for the difference between two population means using two independent samples, we use the pooled estimate   in estimating the standard error of the sampling distribution of the sample mean difference   if the populations are normal with equal variances. in estimating the standard error of the sampling distribution of the sample mean difference In developing a confidence interval for the difference between two population means using two independent samples, we use the pooled estimate   in estimating the standard error of the sampling distribution of the sample mean difference   if the populations are normal with equal variances. if the populations are normal with equal variances.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
51
If two random samples of size 40 each are selected independently from two populations whose variances are 35 and 45, then the standard error of the sampling distribution of the sample mean difference, If two random samples of size 40 each are selected independently from two populations whose variances are 35 and 45, then the standard error of the sampling distribution of the sample mean difference,   , equals 1.4142. , equals 1.4142.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
52
You are told that a random sample of 150 people from Iowa has been given cholesterol tests, and 60 of these people had levels over the "safe" count of 200. Construct a 95% confidence interval for the population proportion of people in Iowa with cholesterol levels over 200.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
53
(A) Construct a 95% confidence interval estimate of the population proportion of all customers who still own the cars they purchased six years ago.

(B) How can the result in (A) be used by the automobile dealer to study satisfaction with cars purchased at the dealership?
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
54
What is an example of a problem in which the sample data is likely to be paired?

A) the difference between the means of appraised and sales house prices
B) the difference between the proportion of defective items from two suppliers
C) the difference in the mean life of two major brands of batteries
D) the difference in the mean salaries for graduates in two different academic fields at a university
E) none of these choices
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
55
The number of degrees of freedom needed to construct 90% confidence interval for the difference between means when the data are gathered from paired samples, with 15 observations in each sample, is:

A) 30
B) 15
C) 28
D) 14
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
56
The degrees of freedom for the t and chi-square distributions is a numerical parameter of the distribution that defines the precise shape of the distribution.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
57
The confidence interval for the population standard deviation σ is centered at the point estimate, the sample standard deviation s.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
58
When the samples we want to compare pair in some natural way, such as a pretest/posttest for each person or husband/wife pairs, a more appropriate form of analysis is to not compare two separate variables, but instead to compare their ____.

A) difference
B) sum
C) ratio
D) total
E) product
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
59
If a random sample of size 250 is taken from a population, where it is known that the population proportion p = 0.4, then the mean of the sampling distribution of the sample proportion If a random sample of size 250 is taken from a population, where it is known that the population proportion p = 0.4, then the mean of the sampling distribution of the sample proportion   is 0.60. is 0.60.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
60
In developing a confidence interval for the population standard deviation In developing a confidence interval for the population standard deviation   , we make use of the fact that the sampling distribution of the sample standard deviation s is not the normal distribution or the t-distribution, but rather a right-skewed distribution called the chi-square distribution, which (for this procedure) has n - 1 degrees of freedom. , we make use of the fact that the sampling distribution of the sample standard deviation s is not the normal distribution or the t-distribution, but rather a right-skewed distribution called the chi-square distribution, which (for this procedure) has n - 1 degrees of freedom.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
61
(A) Find a 95% confidence interval for the mean account balance on this store's credit card (the t-multiple with 39 degrees of freedom is 2.0227).
(B) What sample size would be needed to ensure that we could estimate the true mean account balance and have only 5 chances in 100 of being off by more than $100?
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
62
Q-Mart is interested in comparing its male and female customers. Q-Mart would like to know if its female charge customers spend more money, on average, than its male charge customers. They have collected random samples of 25 female customers and 22 male customers. On average, women charge customers spend $102.23 and men charge customers spend $86.46. Some information are shown below. Q-Mart is interested in comparing its male and female customers. Q-Mart would like to know if its female charge customers spend more money, on average, than its male charge customers. They have collected random samples of 25 female customers and 22 male customers. On average, women charge customers spend $102.23 and men charge customers spend $86.46. Some information are shown below.   (A) Use a t - value of 2.014 to calculate a 95% confidence interval for the difference between the average female purchase and the average male purchase. Would you conclude that there is a significant difference between females and males in this case? Explain. (B) What are the degrees of freedom for the t-multiple in this calculation? Explain how you would calculate the degrees of freedom in this case. (C) What is the assumption in this case that allows you to use the pooled standard deviation for this confidence interval?
(A) Use a t - value of 2.014 to calculate a 95% confidence interval for the difference between the average female purchase and the average male purchase. Would you conclude that there is a significant difference between females and males in this case? Explain.
(B) What are the degrees of freedom for the t-multiple in this calculation? Explain how you would calculate the degrees of freedom in this case.
(C) What is the assumption in this case that allows you to use the pooled standard deviation for this confidence interval?
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
63
After calculating the sample size needed to estimate a population proportion to within 0.05, you have been told that the maximum allowable error (B) must be reduced to just 0.025. If the original calculation led to a sample size of 1000, the sample size will now have to be:

A) 2000
B) 4000
C) 1000
D) 8000
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
64
You would like to estimate the average amount a family spends on food during a year. In the past, the standard deviation of the amount a family has spent on food during a year has been approximately $800. If you want to be 95% sure that you estimated average family food expenditures within $50, how many families do you need to survey?
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
65
If we cannot make the strong assumption that the variances of two samples are equal, then we must use the pooled standard deviation in calculating the standard error of a difference between the means.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
66
Q-Mart is interested in comparing customers who use its own charge card with those who use other types of credit cards. Q-Mart would like to know if customers who use the Q-Mart card spend more money per visit, on average, than customers who use some other type of credit cards. They have collected information on a random sample of 38 charge customers as shown below. On average, the person using a Q-Mart card spends $192.81 per visit and customers using another type of card spend $104.47 per visit. Q-Mart is interested in comparing customers who use its own charge card with those who use other types of credit cards. Q-Mart would like to know if customers who use the Q-Mart card spend more money per visit, on average, than customers who use some other type of credit cards. They have collected information on a random sample of 38 charge customers as shown below. On average, the person using a Q-Mart card spends $192.81 per visit and customers using another type of card spend $104.47 per visit.   (A) Using a t - value of 2.0281, calculate a 95% confidence interval for the difference between the average Q-Mart charge and the average charge on another type of credit card. (B) What are the degrees of freedom for the t - multiple in this calculation? Explain how you would calculate the degrees of freedom in this case. (C) What is the assumption in this case that allows you to use the pooled standard deviation for this confidence interval? (D) Would you conclude that there is a significant difference between the two types of customers in this case? Explain.
(A) Using a t - value of 2.0281, calculate a 95% confidence interval for the difference between the average Q-Mart charge and the average charge on another type of credit card.
(B) What are the degrees of freedom for the t - multiple in this calculation? Explain how you would calculate the degrees of freedom in this case.
(C) What is the assumption in this case that allows you to use the pooled standard deviation for this confidence interval?
(D) Would you conclude that there is a significant difference between the two types of customers in this case? Explain.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
67
In determining the sample size n for estimating the population proportion p, a conservative value of n can be obtained by using 0.50 as an estimate of p.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
68
In constructing a confidence interval estimate for the difference between the means of two populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows: In constructing a confidence interval estimate for the difference between the means of two populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   ,   ,   , and   . Construct a 90% confidence interval for   . , In constructing a confidence interval estimate for the difference between the means of two populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   ,   ,   , and   . Construct a 90% confidence interval for   . , In constructing a confidence interval estimate for the difference between the means of two populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   ,   ,   , and   . Construct a 90% confidence interval for   . , In constructing a confidence interval estimate for the difference between the means of two populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   ,   ,   , and   . Construct a 90% confidence interval for   . , In constructing a confidence interval estimate for the difference between the means of two populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   ,   ,   , and   . Construct a 90% confidence interval for   . , and In constructing a confidence interval estimate for the difference between the means of two populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   ,   ,   , and   . Construct a 90% confidence interval for   . . Construct a 90% confidence interval for In constructing a confidence interval estimate for the difference between the means of two populations, where the unknown population variances are assumed not to be equal, summary statistics computed from two independent samples are as follows:   ,   ,   ,   ,   , and   . Construct a 90% confidence interval for   . .
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
69
A real estate agent has collected a random sample of 40 houses that were recently sold in Grand Rapids, Michigan. She is interested in comparing the appraised value and recent selling price (in thousands of dollars) of the houses in this particular market. The values of these two variables for each of the 40 randomly selected houses are shown below. A real estate agent has collected a random sample of 40 houses that were recently sold in Grand Rapids, Michigan. She is interested in comparing the appraised value and recent selling price (in thousands of dollars) of the houses in this particular market. The values of these two variables for each of the 40 randomly selected houses are shown below.   (A) Use the sample data to generate a 95% confidence interval for the mean difference between the appraised values and selling prices of the houses sold in Grand Rapids. (B) Interpret the constructed confidence interval fin (A) for the real estate agent.
(A) Use the sample data to generate a 95% confidence interval for the mean difference between the appraised values and selling prices of the houses sold in Grand Rapids.
(B) Interpret the constructed confidence interval fin (A) for the real estate agent.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
70
(A) Construct a 95% confidence interval for the difference between the proportions of online and classroom customers who pass the final exam.
(B) Interpret the confidence interval obtained in (A).
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
71
A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The average thickness and the standard deviation of thickness for shift 1, based on a random sample of 40 gaskets, are 10.85 mm and 0.16 mm, respectively. The similar figures for shift 2, based on a random sample of 30 gaskets, are 10.90 mm and 0.19 mm. Let A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The average thickness and the standard deviation of thickness for shift 1, based on a random sample of 40 gaskets, are 10.85 mm and 0.16 mm, respectively. The similar figures for shift 2, based on a random sample of 30 gaskets, are 10.90 mm and 0.19 mm. Let   be the difference in thickness between shifts 1 and 2, and assume that the population variances are equal. (A) Construct a 95% confidence interval for   . (B) Based on your answer to (A), are you convinced that the gaskets from shift 2 are, on average, wider than those from shift 1? Why or why not? be the difference in thickness between shifts 1 and 2, and assume that the population variances are equal.
(A) Construct a 95% confidence interval for A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The average thickness and the standard deviation of thickness for shift 1, based on a random sample of 40 gaskets, are 10.85 mm and 0.16 mm, respectively. The similar figures for shift 2, based on a random sample of 30 gaskets, are 10.90 mm and 0.19 mm. Let   be the difference in thickness between shifts 1 and 2, and assume that the population variances are equal. (A) Construct a 95% confidence interval for   . (B) Based on your answer to (A), are you convinced that the gaskets from shift 2 are, on average, wider than those from shift 1? Why or why not? .
(B) Based on your answer to (A), are you convinced that the gaskets from shift 2 are, on average, wider than those from shift 1? Why or why not?
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
72
(A) Determine a 95% confidence interval for the proportion defective for the process today.
(B) Based on your answer to (A), is it still reasonable to think the overall proportion defective produced by today's process is actually the targeted 4%? Explain your reasoning.
(C) The confidence interval in (A) is based on the assumption of a large sample size. Is this sample size sufficiently large in this example? Explain how you arrived at your answer.
(D) How many units would have to be sampled to be 95% confident that you can estimate the fraction of defective parts within 2% (using the information from today's sample)?
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
73
Confidence intervals are a function of the:

A) population, the sample, and the standard deviation
B) sample, the variable of interest, and the degrees of freedom
C) data in the sample, the confidence level, and the sample size
D) sampling distribution, the confidence level, and the degrees of freedom
E) mean, median, and mode
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
74
Samples of exam scores for employees before and after a training class are examples of paired data.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
75
You are attempting to estimate the average amount a family spends on food during a year. In the past, the standard deviation of the amount a family has spent on food during a year has been approximately $1200. If you want to be 99% sure that you have estimated average family food expenditures within $60, how many families do you need to survey?
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
76
When you calculate the sample size for a proportion, you use an estimate for the population proportion; namely <strong>When you calculate the sample size for a proportion, you use an estimate for the population proportion; namely   . A conservative value for n can be obtained by using   = :</strong> A) 0.01 B) 0.05 C) 0.10 D) 0.50 E) 1.00 . A conservative value for n can be obtained by using <strong>When you calculate the sample size for a proportion, you use an estimate for the population proportion; namely   . A conservative value for n can be obtained by using   = :</strong> A) 0.01 B) 0.05 C) 0.10 D) 0.50 E) 1.00 = :

A) 0.01
B) 0.05
C) 0.10
D) 0.50
E) 1.00
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
77
(A) You can be 95% confident that the mean salary for all production managers with at least 15 years of experience is between what two numbers (the t-multiple with 8 degrees of freedom is 2.306). What assumption are you making about the distribution of salaries?

(B) What sample size would be needed to ensure that we could estimate the true mean salary of all production managers with more than 15 years of experience and have only 5 chances in 100 of being off by more than $4200?
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
78
A market research consultant hired by Coke Classic Company is interested in estimating the difference between the proportions of female and male customers who favor Coke Classic over Pepsi Cola in Chicago. A random sample of 200 consumers from the market under investigation shows the following frequency distribution. A market research consultant hired by Coke Classic Company is interested in estimating the difference between the proportions of female and male customers who favor Coke Classic over Pepsi Cola in Chicago. A random sample of 200 consumers from the market under investigation shows the following frequency distribution.   ​ (A) Construct a 95% confidence interval for the difference between the proportions of male and female customers who prefer Coke Classic<sup>®</sup> over Pepsi Cola<sup>®</sup>. ​ (B) Interpret the constructed confidence interval.
(A) Construct a 95% confidence interval for the difference between the proportions of male and female customers who prefer Coke Classic® over Pepsi Cola®.

(B) Interpret the constructed confidence interval.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
79
For a given confidence level, the procedure for controlling interval length usually begins with the specification of the:

A) point estimate
B) population standard deviation, s
C) sample standard deviation, s
D) interval half-length, B
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
80
If two samples contain the same number of observations, then the data must be paired.
Unlock Deck
Unlock for access to all 84 flashcards in this deck.
Unlock Deck
k this deck
locked card icon
Unlock Deck
Unlock for access to all 84 flashcards in this deck.