Deck 7: Estimating Parameters and Determining Sample Sizes

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Question
The margin of error ________ ________ (increases or decreases)with an increase in confidence level.

A) increases; increases
B) increases; decreases
C) decreases; increases
D) decreases; decreases
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Question
Fifty people are selected randomly from a certain population and it is found that 12 people in the sample are over six feet tall. What is the best point estimate of the proportion of people in the population who are over 6 feet tall?

A) 0.76
B) 0.24
C) 0.50
D) 0.18
Question
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p .
n=195, x=162 ; 95 % confidence

A) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population proportion  p . n=195, x=162 ; 95 %  confidence</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population proportion  p . n=195, x=162 ; 95 %  confidence</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population proportion  p . n=195, x=162 ; 95 %  confidence</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population proportion  p . n=195, x=162 ; 95 %  confidence</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
Of 380 randomly selected medical students, 21 said that they planned to work in a rural community. Find a 95 % confidence interval for the true proportion of all medical students who plan to work in a rural community.

A) <strong>Of 380 randomly selected medical students, 21 said that they planned to work in a rural community. Find a  95 %  confidence interval for the true proportion of all medical students who plan to work in a rural community.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B) <strong>Of 380 randomly selected medical students, 21 said that they planned to work in a rural community. Find a  95 %  confidence interval for the true proportion of all medical students who plan to work in a rural community.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C) <strong>Of 380 randomly selected medical students, 21 said that they planned to work in a rural community. Find a  95 %  confidence interval for the true proportion of all medical students who plan to work in a rural community.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D) <strong>Of 380 randomly selected medical students, 21 said that they planned to work in a rural community. Find a  95 %  confidence interval for the true proportion of all medical students who plan to work in a rural community.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
Do one of the following, as appropriate:
(a) Find the critical value <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   (c) state that neither the normal nor the t distribution applies. 90% confidence interval for   n=9 ;   population appears to be very skewed.</strong> A)   B)   C)   D) Neither the normal nor the t distribution applies. <div style=padding-top: 35px>
(b) find the critical value <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   (c) state that neither the normal nor the t distribution applies. 90% confidence interval for   n=9 ;   population appears to be very skewed.</strong> A)   B)   C)   D) Neither the normal nor the t distribution applies. <div style=padding-top: 35px>
(c) state that neither the normal nor the t distribution applies.
90% confidence interval for <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   (c) state that neither the normal nor the t distribution applies. 90% confidence interval for   n=9 ;   population appears to be very skewed.</strong> A)   B)   C)   D) Neither the normal nor the t distribution applies. <div style=padding-top: 35px> n=9 ; <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   (c) state that neither the normal nor the t distribution applies. 90% confidence interval for   n=9 ;   population appears to be very skewed.</strong> A)   B)   C)   D) Neither the normal nor the t distribution applies. <div style=padding-top: 35px> population appears to be very skewed.

A) <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   (c) state that neither the normal nor the t distribution applies. 90% confidence interval for   n=9 ;   population appears to be very skewed.</strong> A)   B)   C)   D) Neither the normal nor the t distribution applies. <div style=padding-top: 35px>
B) <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   (c) state that neither the normal nor the t distribution applies. 90% confidence interval for   n=9 ;   population appears to be very skewed.</strong> A)   B)   C)   D) Neither the normal nor the t distribution applies. <div style=padding-top: 35px>
C) <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   (c) state that neither the normal nor the t distribution applies. 90% confidence interval for   n=9 ;   population appears to be very skewed.</strong> A)   B)   C)   D) Neither the normal nor the t distribution applies. <div style=padding-top: 35px>
D) Neither the normal nor the t distribution applies.
Question
Express the confidence interval (0.432,0.52) in the form of <strong>Express the confidence interval  (0.432,0.52)  in the form of  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>

A) <strong>Express the confidence interval  (0.432,0.52)  in the form of  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B) <strong>Express the confidence interval  (0.432,0.52)  in the form of  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C) <strong>Express the confidence interval  (0.432,0.52)  in the form of  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D) <strong>Express the confidence interval  (0.432,0.52)  in the form of  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
Use the given degree of confidence and sample data to construct a confidence interval for the population mean <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution.  n=30 ,    s=10.5,90 % confidence</strong> A)   B)   C)   D)   <div style=padding-top: 35px> Assume that the population has a normal distribution. n=30 , <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution.  n=30 ,    s=10.5,90 % confidence</strong> A)   B)   C)   D)   <div style=padding-top: 35px> s=10.5,90 % confidence

A) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution.  n=30 ,    s=10.5,90 % confidence</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution.  n=30 ,    s=10.5,90 % confidence</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution.  n=30 ,    s=10.5,90 % confidence</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution.  n=30 ,    s=10.5,90 % confidence</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
Find the critical value <strong>Find the critical value   corresponding to a sample size of 19 and a confidence level of 99 percent.</strong> A)  37.156 B)  6.265 C)  34.805 D)  7.015 <div style=padding-top: 35px> corresponding to a sample size of 19 and a confidence level of 99 percent.

A) 37.156
B) 6.265
C) 34.805
D) 7.015
Question
Which critical value is appropriate for a 99% confidence level where n=17 ;<strong>Which critical value is appropriate for a  99% confidence level where  n=17 ;  is unknown and the population appears to be normally distributed?</strong> A)   B)   C)   D)   <div style=padding-top: 35px> is unknown and the population appears to be normally distributed?

A) <strong>Which critical value is appropriate for a  99% confidence level where  n=17 ;  is unknown and the population appears to be normally distributed?</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B) <strong>Which critical value is appropriate for a  99% confidence level where  n=17 ;  is unknown and the population appears to be normally distributed?</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C) <strong>Which critical value is appropriate for a  99% confidence level where  n=17 ;  is unknown and the population appears to be normally distributed?</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D) <strong>Which critical value is appropriate for a  99% confidence level where  n=17 ;  is unknown and the population appears to be normally distributed?</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places.
98% confidence; the sample size is 800, of which 40% are successes

A) 0.0355
B) 0.0339
C) 0.0404
D) 0.0446
Question
If the computed minimum sample size n needed for a particular margin of error is not a whole number, round the value of n _____ (up or down) to the next _____ (smaller or larger) whole number.

A) up; smaller
B) up; larger
C) down; smaller
D) down; larger
Question
Find the value of <strong>Find the value of   that corresponds to a confidence level of  89.48%.</strong> A)  1.25 B)  1.62 C)  0.0526 D)  -1.62 <div style=padding-top: 35px> that corresponds to a confidence level of 89.48%.

A) 1.25
B) 1.62
C) 0.0526
D) -1.62
Question
A survey of 300 union members in New York State reveals that 112 favor the Republican candidate for governor. Construct the 98 % confidence interval for the true population proportion of all New York State union members who favor the Republican candidate.

A) <strong>A survey of 300 union members in New York State reveals that 112 favor the Republican candidate for governor. Construct the  98 %  confidence interval for the true population proportion of all New York State union members who favor the Republican candidate.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B) <strong>A survey of 300 union members in New York State reveals that 112 favor the Republican candidate for governor. Construct the  98 %  confidence interval for the true population proportion of all New York State union members who favor the Republican candidate.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C) <strong>A survey of 300 union members in New York State reveals that 112 favor the Republican candidate for governor. Construct the  98 %  confidence interval for the true population proportion of all New York State union members who favor the Republican candidate.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D) <strong>A survey of 300 union members in New York State reveals that 112 favor the Republican candidate for governor. Construct the  98 %  confidence interval for the true population proportion of all New York State union members who favor the Republican candidate.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level.
95% confidence; n=2388, x=1672

A) 0.0248
B) 0.0184
C) 0.0156
D) 0.0206
Question
Find the critical value <strong>Find the critical value   that corresponds to a  91% confidence level.</strong> A)  1.34 B)  1.645 C)  1.70 D)  1.75 <div style=padding-top: 35px> that corresponds to a 91% confidence level.

A) 1.34
B) 1.645
C) 1.70
D) 1.75
Question
Use the given degree of confidence and sample data to construct a confidence interval for the population mean <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution. A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 185 milligrams with  s=17.6  milligrams. Construct a  95% confidence interval for the true mean cholesterol content of all such eggs.</strong> A)   B)   C)   D)   <div style=padding-top: 35px> Assume that the population has a normal distribution.
A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 185 milligrams with s=17.6 milligrams. Construct a 95% confidence interval for the true mean cholesterol content of all such eggs.

A) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution. A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 185 milligrams with  s=17.6  milligrams. Construct a  95% confidence interval for the true mean cholesterol content of all such eggs.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution. A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 185 milligrams with  s=17.6  milligrams. Construct a  95% confidence interval for the true mean cholesterol content of all such eggs.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution. A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 185 milligrams with  s=17.6  milligrams. Construct a  95% confidence interval for the true mean cholesterol content of all such eggs.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution. A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 185 milligrams with  s=17.6  milligrams. Construct a  95% confidence interval for the true mean cholesterol content of all such eggs.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
Use the given degree of confidence and sample data to construct a confidence interval for the population mean μ. Assume that the population has a normal distribution. Use the given degree of confidence and sample data to construct a confidence interval for the population mean μ. Assume that the population has a normal distribution.  <div style=padding-top: 35px>
Question
In constructing a confidence interval for <strong>In constructing a confidence interval for   or  , a table is used to find the critical values   for values of   For larger values of  n,    can be approximated by using the following formula:   where  k  is the number of degrees of freedom and   is the critical z-score. Construct the  90 %  confidence interval for    using the following sample data: a sample of size  n=232  yields a mean weight of  154 lb  and a standard deviation of  25.5 lb. Round the confidence interval limits to the nearest hundredth.</strong> A)   B)   C)   D)   <div style=padding-top: 35px> or <strong>In constructing a confidence interval for   or  , a table is used to find the critical values   for values of   For larger values of  n,    can be approximated by using the following formula:   where  k  is the number of degrees of freedom and   is the critical z-score. Construct the  90 %  confidence interval for    using the following sample data: a sample of size  n=232  yields a mean weight of  154 lb  and a standard deviation of  25.5 lb. Round the confidence interval limits to the nearest hundredth.</strong> A)   B)   C)   D)   <div style=padding-top: 35px> , a table is used to find the critical values <strong>In constructing a confidence interval for   or  , a table is used to find the critical values   for values of   For larger values of  n,    can be approximated by using the following formula:   where  k  is the number of degrees of freedom and   is the critical z-score. Construct the  90 %  confidence interval for    using the following sample data: a sample of size  n=232  yields a mean weight of  154 lb  and a standard deviation of  25.5 lb. Round the confidence interval limits to the nearest hundredth.</strong> A)   B)   C)   D)   <div style=padding-top: 35px> for values of <strong>In constructing a confidence interval for   or  , a table is used to find the critical values   for values of   For larger values of  n,    can be approximated by using the following formula:   where  k  is the number of degrees of freedom and   is the critical z-score. Construct the  90 %  confidence interval for    using the following sample data: a sample of size  n=232  yields a mean weight of  154 lb  and a standard deviation of  25.5 lb. Round the confidence interval limits to the nearest hundredth.</strong> A)   B)   C)   D)   <div style=padding-top: 35px> For larger values of n, <strong>In constructing a confidence interval for   or  , a table is used to find the critical values   for values of   For larger values of  n,    can be approximated by using the following formula:   where  k  is the number of degrees of freedom and   is the critical z-score. Construct the  90 %  confidence interval for    using the following sample data: a sample of size  n=232  yields a mean weight of  154 lb  and a standard deviation of  25.5 lb. Round the confidence interval limits to the nearest hundredth.</strong> A)   B)   C)   D)   <div style=padding-top: 35px> can be
approximated by using the following formula: <strong>In constructing a confidence interval for   or  , a table is used to find the critical values   for values of   For larger values of  n,    can be approximated by using the following formula:   where  k  is the number of degrees of freedom and   is the critical z-score. Construct the  90 %  confidence interval for    using the following sample data: a sample of size  n=232  yields a mean weight of  154 lb  and a standard deviation of  25.5 lb. Round the confidence interval limits to the nearest hundredth.</strong> A)   B)   C)   D)   <div style=padding-top: 35px> where k is the number of degrees of freedom and <strong>In constructing a confidence interval for   or  , a table is used to find the critical values   for values of   For larger values of  n,    can be approximated by using the following formula:   where  k  is the number of degrees of freedom and   is the critical z-score. Construct the  90 %  confidence interval for    using the following sample data: a sample of size  n=232  yields a mean weight of  154 lb  and a standard deviation of  25.5 lb. Round the confidence interval limits to the nearest hundredth.</strong> A)   B)   C)   D)   <div style=padding-top: 35px> is the critical z-score. Construct the 90 % confidence interval for <strong>In constructing a confidence interval for   or  , a table is used to find the critical values   for values of   For larger values of  n,    can be approximated by using the following formula:   where  k  is the number of degrees of freedom and   is the critical z-score. Construct the  90 %  confidence interval for    using the following sample data: a sample of size  n=232  yields a mean weight of  154 lb  and a standard deviation of  25.5 lb. Round the confidence interval limits to the nearest hundredth.</strong> A)   B)   C)   D)   <div style=padding-top: 35px> using the following sample data: a sample of size n=232 yields a mean weight of 154 lb and a standard deviation of 25.5 lb. Round the confidence interval limits to the nearest hundredth.

A) <strong>In constructing a confidence interval for   or  , a table is used to find the critical values   for values of   For larger values of  n,    can be approximated by using the following formula:   where  k  is the number of degrees of freedom and   is the critical z-score. Construct the  90 %  confidence interval for    using the following sample data: a sample of size  n=232  yields a mean weight of  154 lb  and a standard deviation of  25.5 lb. Round the confidence interval limits to the nearest hundredth.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B) <strong>In constructing a confidence interval for   or  , a table is used to find the critical values   for values of   For larger values of  n,    can be approximated by using the following formula:   where  k  is the number of degrees of freedom and   is the critical z-score. Construct the  90 %  confidence interval for    using the following sample data: a sample of size  n=232  yields a mean weight of  154 lb  and a standard deviation of  25.5 lb. Round the confidence interval limits to the nearest hundredth.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C) <strong>In constructing a confidence interval for   or  , a table is used to find the critical values   for values of   For larger values of  n,    can be approximated by using the following formula:   where  k  is the number of degrees of freedom and   is the critical z-score. Construct the  90 %  confidence interval for    using the following sample data: a sample of size  n=232  yields a mean weight of  154 lb  and a standard deviation of  25.5 lb. Round the confidence interval limits to the nearest hundredth.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D) <strong>In constructing a confidence interval for   or  , a table is used to find the critical values   for values of   For larger values of  n,    can be approximated by using the following formula:   where  k  is the number of degrees of freedom and   is the critical z-score. Construct the  90 %  confidence interval for    using the following sample data: a sample of size  n=232  yields a mean weight of  154 lb  and a standard deviation of  25.5 lb. Round the confidence interval limits to the nearest hundredth.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
Use the given data to find the minimum sample size required to estimate the population proportion. Margin of error: 0.028; confidence level: 99%; p and q unknown

A) 1116
B) 2223
C) 1939
D) 2115
Question
Identify the distribution that applies to the following situation: In constructing a confidence interval of σ you have 50 sample values and they appear to be from a population with a skewed distribution.

A) Student t distribution
B) Normal distribution
C) Chi-square distribution
D) None of the three distributions is appropriate.
Question
A 99% confidence interval (in inches) for the mean height of a population is <strong>A  99% confidence interval (in inches) for the mean height of a population is   This result is based on a sample of size 144. Construct the  95% confidence interval. (Hint: you will first need to find the sample mean and sample standard deviation).</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
This result is based on a sample of size 144. Construct the 95% confidence interval. (Hint: you will first need to find the sample mean and sample standard deviation).

A) <strong>A  99% confidence interval (in inches) for the mean height of a population is   This result is based on a sample of size 144. Construct the  95% confidence interval. (Hint: you will first need to find the sample mean and sample standard deviation).</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B) <strong>A  99% confidence interval (in inches) for the mean height of a population is   This result is based on a sample of size 144. Construct the  95% confidence interval. (Hint: you will first need to find the sample mean and sample standard deviation).</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C) <strong>A  99% confidence interval (in inches) for the mean height of a population is   This result is based on a sample of size 144. Construct the  95% confidence interval. (Hint: you will first need to find the sample mean and sample standard deviation).</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D) <strong>A  99% confidence interval (in inches) for the mean height of a population is   This result is based on a sample of size 144. Construct the  95% confidence interval. (Hint: you will first need to find the sample mean and sample standard deviation).</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
To find the standard deviation of the diameter of wooden dowels, the manufacturer measures 19 randomly selected dowels and finds the standard deviation of the sample to be s=0.16 . Find the 95 % confidence interval for the population standard deviation <strong>To find the standard deviation of the diameter of wooden dowels, the manufacturer measures 19 randomly selected dowels and finds the standard deviation of the sample to be  s=0.16 . Find the  95 %  confidence interval for the population standard deviation  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>

A) <strong>To find the standard deviation of the diameter of wooden dowels, the manufacturer measures 19 randomly selected dowels and finds the standard deviation of the sample to be  s=0.16 . Find the  95 %  confidence interval for the population standard deviation  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B) <strong>To find the standard deviation of the diameter of wooden dowels, the manufacturer measures 19 randomly selected dowels and finds the standard deviation of the sample to be  s=0.16 . Find the  95 %  confidence interval for the population standard deviation  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C) <strong>To find the standard deviation of the diameter of wooden dowels, the manufacturer measures 19 randomly selected dowels and finds the standard deviation of the sample to be  s=0.16 . Find the  95 %  confidence interval for the population standard deviation  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D) <strong>To find the standard deviation of the diameter of wooden dowels, the manufacturer measures 19 randomly selected dowels and finds the standard deviation of the sample to be  s=0.16 . Find the  95 %  confidence interval for the population standard deviation  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
A one-sided confidence interval for p can be written as <strong>A one-sided confidence interval for p can be written as   where the margin of error E is modified by replacing   with   If a teacher wants to report that the fail rate on a test is at most  x  with  90 %  confidence, construct the appropriate one -sided confidence interval. Assume that a simple random sample of 74 students results in 8 who fail the test.</strong> A)   B)   C)   D)   <div style=padding-top: 35px> where the margin of error E is modified by replacing <strong>A one-sided confidence interval for p can be written as   where the margin of error E is modified by replacing   with   If a teacher wants to report that the fail rate on a test is at most  x  with  90 %  confidence, construct the appropriate one -sided confidence interval. Assume that a simple random sample of 74 students results in 8 who fail the test.</strong> A)   B)   C)   D)   <div style=padding-top: 35px> with <strong>A one-sided confidence interval for p can be written as   where the margin of error E is modified by replacing   with   If a teacher wants to report that the fail rate on a test is at most  x  with  90 %  confidence, construct the appropriate one -sided confidence interval. Assume that a simple random sample of 74 students results in 8 who fail the test.</strong> A)   B)   C)   D)   <div style=padding-top: 35px> If a teacher wants to report that the fail rate on a test is at most x with 90 % confidence, construct the appropriate one -sided confidence interval. Assume that a simple random sample of 74 students results in 8 who fail the test.

A) <strong>A one-sided confidence interval for p can be written as   where the margin of error E is modified by replacing   with   If a teacher wants to report that the fail rate on a test is at most  x  with  90 %  confidence, construct the appropriate one -sided confidence interval. Assume that a simple random sample of 74 students results in 8 who fail the test.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B) <strong>A one-sided confidence interval for p can be written as   where the margin of error E is modified by replacing   with   If a teacher wants to report that the fail rate on a test is at most  x  with  90 %  confidence, construct the appropriate one -sided confidence interval. Assume that a simple random sample of 74 students results in 8 who fail the test.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C) <strong>A one-sided confidence interval for p can be written as   where the margin of error E is modified by replacing   with   If a teacher wants to report that the fail rate on a test is at most  x  with  90 %  confidence, construct the appropriate one -sided confidence interval. Assume that a simple random sample of 74 students results in 8 who fail the test.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D) <strong>A one-sided confidence interval for p can be written as   where the margin of error E is modified by replacing   with   If a teacher wants to report that the fail rate on a test is at most  x  with  90 %  confidence, construct the appropriate one -sided confidence interval. Assume that a simple random sample of 74 students results in 8 who fail the test.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
Do one of the following, as appropriate:
(a) Find the critical value <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   99 % ; n=17 ;   is unknown; population appears to be normally distributed.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
(b) find the critical value <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   99 % ; n=17 ;   is unknown; population appears to be normally distributed.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
99 % ; n=17 ; <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   99 % ; n=17 ;   is unknown; population appears to be normally distributed.</strong> A)   B)   C)   D)   <div style=padding-top: 35px> is unknown; population appears to be normally distributed.

A) <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   99 % ; n=17 ;   is unknown; population appears to be normally distributed.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B) <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   99 % ; n=17 ;   is unknown; population appears to be normally distributed.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C) <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   99 % ; n=17 ;   is unknown; population appears to be normally distributed.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D) <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   99 % ; n=17 ;   is unknown; population appears to be normally distributed.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p.
n=130, x=69 ; 90% confidence

A) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. n=130, x=69 ; 90% confidence</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. n=130, x=69 ; 90% confidence</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. n=130, x=69 ; 90% confidence</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. n=130, x=69 ; 90% confidence</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
Express the confidence interval <strong>Express the confidence interval   in the form of  </strong> A)   B)   C)   D)   <div style=padding-top: 35px> in the form of <strong>Express the confidence interval   in the form of  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>

A) <strong>Express the confidence interval   in the form of  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B) <strong>Express the confidence interval   in the form of  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C) <strong>Express the confidence interval   in the form of  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D) <strong>Express the confidence interval   in the form of  </strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
You want to be 95% confident that the sample variance is within 40% of the population variance. Find the appropriate minimum sample size.

A) 57
B) 224
C) 14
D) 11
Question
Find the degree of confidence used in constructing the confidence interval <strong>Find the degree of confidence used in constructing the confidence interval   - for the population proportion  p  using sample data with  n=109, x=65 .</strong> A)  88 % B)  90 % C)  95 % D)  99 % <div style=padding-top: 35px> - for the population proportion p using sample data with n=109, x=65 .

A) 88 %
B) 90 %
C) 95 %
D) 99 %
Question
Of 118 randomly selected adults, 34 were found to have high blood pressure. Construct a 95 % confidence interval for the true percentage of all adults that have high blood pressure.

A) <strong>Of 118 randomly selected adults, 34 were found to have high blood pressure. Construct a  95 %  confidence interval for the true percentage of all adults that have high blood pressure.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B) <strong>Of 118 randomly selected adults, 34 were found to have high blood pressure. Construct a  95 %  confidence interval for the true percentage of all adults that have high blood pressure.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C) <strong>Of 118 randomly selected adults, 34 were found to have high blood pressure. Construct a  95 %  confidence interval for the true percentage of all adults that have high blood pressure.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D) <strong>Of 118 randomly selected adults, 34 were found to have high blood pressure. Construct a  95 %  confidence interval for the true percentage of all adults that have high blood pressure.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
Identify the distribution that applies to the following situation:
In constructing a confidence interval of <strong>Identify the distribution that applies to the following situation: In constructing a confidence interval of  , you have 50 sample values and they appear to be from a population with a skewed distribution. The population standard deviation is not known.</strong> A) Student  t  distribution B) Normal distribution C) Chi-square distribution D) None of the three distributions is appropriate. <div style=padding-top: 35px> , you have 50 sample values and they appear to be from a population with a skewed distribution. The population standard deviation is not known.

A) Student t distribution
B) Normal distribution
C) Chi-square distribution
D) None of the three distributions is appropriate.
Question
Use the given data to find the minimum sample size required to estimate the population proportion. Margin of error: 0.008 ; confidence level: 98% ; <strong>Use the given data to find the minimum sample size required to estimate the population proportion. Margin of error:  0.008 ; confidence level:  98% ;   unknown</strong> A) 22,184 B) 10,384 C) 21,207 D) 20,308V <div style=padding-top: 35px> unknown

A) 22,184
B) 10,384
C) 21,207
D) 20,308V
Question
A group of 59 randomly selected students have a mean score of 29.5 with a standard deviation of 5.2 on a placement test. What is the 90 % confidence interval for the mean score, <strong>A group of 59 randomly selected students have a mean score of  29.5  with a standard deviation of  5.2  on a placement test. What is the  90 %  confidence interval for the mean score,   , of all students taking the test?</strong> A)   B)   C)   D)   <div style=padding-top: 35px> , of all students taking the test?

A) <strong>A group of 59 randomly selected students have a mean score of  29.5  with a standard deviation of  5.2  on a placement test. What is the  90 %  confidence interval for the mean score,   , of all students taking the test?</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B) <strong>A group of 59 randomly selected students have a mean score of  29.5  with a standard deviation of  5.2  on a placement test. What is the  90 %  confidence interval for the mean score,   , of all students taking the test?</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C) <strong>A group of 59 randomly selected students have a mean score of  29.5  with a standard deviation of  5.2  on a placement test. What is the  90 %  confidence interval for the mean score,   , of all students taking the test?</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D) <strong>A group of 59 randomly selected students have a mean score of  29.5  with a standard deviation of  5.2  on a placement test. What is the  90 %  confidence interval for the mean score,   , of all students taking the test?</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
Find the critical value <strong>Find the critical value   corresponding to a sample size of 19 and a confidence level of 99 percent.</strong> A)  37.156 B)  6.265 C)  34.805 D)  7.015 <div style=padding-top: 35px> corresponding to a sample size of 19 and a confidence level of 99 percent.

A) 37.156
B) 6.265
C) 34.805
D) 7.015
Question
Express a confidence interval defined as (0.432,0.52) in the form of the point estimate _____ <strong>Express a confidence interval defined as  (0.432,0.52)  in the form of the point estimate _____    the margin of error______ Express both in three decimal places.</strong> A)   B)   C)   D)   <div style=padding-top: 35px> the margin of error______
Express both in three decimal places.

A) <strong>Express a confidence interval defined as  (0.432,0.52)  in the form of the point estimate _____    the margin of error______ Express both in three decimal places.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B) <strong>Express a confidence interval defined as  (0.432,0.52)  in the form of the point estimate _____    the margin of error______ Express both in three decimal places.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C) <strong>Express a confidence interval defined as  (0.432,0.52)  in the form of the point estimate _____    the margin of error______ Express both in three decimal places.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D) <strong>Express a confidence interval defined as  (0.432,0.52)  in the form of the point estimate _____    the margin of error______ Express both in three decimal places.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
A laboratory tested 82 chicken eggs and found that the mean amount of cholesterol was 228 milligrams with <strong>A laboratory tested 82 chicken eggs and found that the mean amount of cholesterol was 228 milligrams with   Construct a  95% confidence interval for the true mean cholesterol content,   of all such eggs.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Construct a 95% confidence interval for the true mean cholesterol content, <strong>A laboratory tested 82 chicken eggs and found that the mean amount of cholesterol was 228 milligrams with   Construct a  95% confidence interval for the true mean cholesterol content,   of all such eggs.</strong> A)   B)   C)   D)   <div style=padding-top: 35px> of all such eggs.

A) <strong>A laboratory tested 82 chicken eggs and found that the mean amount of cholesterol was 228 milligrams with   Construct a  95% confidence interval for the true mean cholesterol content,   of all such eggs.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B) <strong>A laboratory tested 82 chicken eggs and found that the mean amount of cholesterol was 228 milligrams with   Construct a  95% confidence interval for the true mean cholesterol content,   of all such eggs.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C) <strong>A laboratory tested 82 chicken eggs and found that the mean amount of cholesterol was 228 milligrams with   Construct a  95% confidence interval for the true mean cholesterol content,   of all such eggs.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D) <strong>A laboratory tested 82 chicken eggs and found that the mean amount of cholesterol was 228 milligrams with   Construct a  95% confidence interval for the true mean cholesterol content,   of all such eggs.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
To be able to say with 95% confidence that the standard deviation of a data set is within 10% of the population's standard deviation, the number of observations within the data set must be greater than or equal to what quantity?

A) 805
B) 192
C) 335
D) 250
Question
Use the given degree of confidence and sample data to construct a confidence interval for the population mean <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution. A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 185 milligrams with  s=17.6  milligrams. A confidence interval of   mg is constructed for the true mean cholesterol content of all such eggs. It was assumed that the population has a normal distribution. What confidence level does this interval represent? </strong> A)  99% B)  95% C)  98% D)  80% <div style=padding-top: 35px> Assume that the population has a normal distribution.
A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 185 milligrams with s=17.6 milligrams. A confidence interval of <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution. A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 185 milligrams with  s=17.6  milligrams. A confidence interval of   mg is constructed for the true mean cholesterol content of all such eggs. It was assumed that the population has a normal distribution. What confidence level does this interval represent? </strong> A)  99% B)  95% C)  98% D)  80% <div style=padding-top: 35px> mg is constructed for the true mean cholesterol content of all such eggs. It was assumed that the population has a normal distribution. What confidence level does this interval represent?

A) 99%
B) 95%
C) 98%
D) 80%
Question
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p.
n=56, x=30 ; 95% confidence

A) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population proportion  p. n=56, x=30 ; 95% confidence</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population proportion  p. n=56, x=30 ; 95% confidence</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population proportion  p. n=56, x=30 ; 95% confidence</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population proportion  p. n=56, x=30 ; 95% confidence</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
Fill in the blank: The critical value <strong>Fill in the blank: The critical value   that corresponds to a ______% confidence level is  2.33 . </strong> A) 88 B) 90 C) 98 D) 99 <div style=padding-top: 35px> that corresponds to a ______% confidence level is 2.33 .

A) 88
B) 90
C) 98
D) 99
Question
Which of the following critical values is appropriate for a 98% confidence level where n=7 ; <strong>Which of the following critical values is appropriate for a  98% confidence level where  n=7 ;   and the population appears to be normally distributed.</strong> A)   B)   C)   D)   <div style=padding-top: 35px> and the population appears to be normally distributed.

A) <strong>Which of the following critical values is appropriate for a  98% confidence level where  n=7 ;   and the population appears to be normally distributed.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
B) <strong>Which of the following critical values is appropriate for a  98% confidence level where  n=7 ;   and the population appears to be normally distributed.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
C) <strong>Which of the following critical values is appropriate for a  98% confidence level where  n=7 ;   and the population appears to be normally distributed.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
D) <strong>Which of the following critical values is appropriate for a  98% confidence level where  n=7 ;   and the population appears to be normally distributed.</strong> A)   B)   C)   D)   <div style=padding-top: 35px>
Question
The following is a 95 % confidence interval of the proportion of female medical school students: The following is a  95 %  confidence interval of the proportion of female medical school students:   based on data from the American Medical Association. What is the point estimate of the proportion of females in the population of medical school students? Write a brief statement that correctly interprets the confidence interval given.<div style=padding-top: 35px> based on data from the American Medical Association. What is the point estimate of the proportion of females in the population of medical school students? Write a brief statement that correctly interprets the confidence interval given.
Question
In a Gallup poll, 1011 adults were asked if they consume alcoholic beverages and 64% of them said that they did. Construct a 90% confidence interval estimate of the proportion of all
adults who consume alcoholic beverages. Can we safely conclude that the majority of adults
consume alcoholic beverages?
Question
Six human skulls from around 4000 B.C. were measured, and the lengths have a mean of 94.2 mm and a standard deviation of 4.9 mm. If you want to construct a 95% confidence
interval estimate of the mean length of skulls, what requirements must be satisfied?
Question
When determining the sample size needed to achieve a particular error estimate you need to know When determining the sample size needed to achieve a particular error estimate you need to know   What are two methods of estimating    if     is unknown?<div style=padding-top: 35px> What are two methods of estimating When determining the sample size needed to achieve a particular error estimate you need to know   What are two methods of estimating    if     is unknown?<div style=padding-top: 35px> if When determining the sample size needed to achieve a particular error estimate you need to know   What are two methods of estimating    if     is unknown?<div style=padding-top: 35px> is unknown?
Question
Interpret the following 95 % confidence interval for mean weekly salaries of shift managers at Guiseppe's Pizza and Pasta.
Interpret the following  95 %  confidence interval for mean weekly salaries of shift managers at Guiseppe's Pizza and Pasta.  <div style=padding-top: 35px>
Question
Describe the process for finding the confidence interval for a population proportion
Question
Bert constructed a confidence interval to estimate the mean weight of students in his class. The population was very small - only 30. Ruth constructed a confidence interval for the mean
weight of all adult males in the city. She based her confidence interval on a very small
sample of only 5. Which confidence interval is likely to give a better estimate of the mean it is
estimating? Which is likely to be more of a problem, a small sample or a small population?
Question
Under what circumstances can you replace Under what circumstances can you replace     with  s  in the formula  <div style=padding-top: 35px> with s in the formula Under what circumstances can you replace     with  s  in the formula  <div style=padding-top: 35px>
Question
You want to estimate σ for the population of waiting times at McDonald's drive-up windows, and you want to be 95% confident that the sample standard deviation is with 20% of σ. Find
the minimum sample size. Is this sample size practical?
Question
In general, what does "degrees of freedom" refer to? Find the degrees of freedom for the given information, assuming that you want to construct a confidence interval estimate of In general, what does degrees of freedom refer to? Find the degrees of freedom for the given information, assuming that you want to construct a confidence interval estimate of   Six human skulls from around 4000 B.C. were measured, and the lengths have a mean of  94.2 mm and a standard deviation of  4.9 mm.<div style=padding-top: 35px> Six human skulls from around 4000 B.C. were measured, and the lengths have a mean of 94.2 mm and a standard deviation of 4.9 mm.
Question
Define in as clear language as possible how a 95% confidence interval can be used for hypothesis tests.
Question
In a Gallup poll of 557 randomly selected adults, 284 said that they were underpaid. Identify the best point estimate of the percentage of adults who say they are underpaid. Construct a
95% confidence interval estimate of the percentage of adults who say that that they are
underpaid. Can we safely conclude that the majority of adults say that they are underpaid?
Question
Define margin of error. Explain the relation between the confidence interval and the margin of error. Suppose a confidence interval is Define margin of error. Explain the relation between the confidence interval and the margin of error. Suppose a confidence interval is   Redefine the confidence interval into a format using the margin of error and the point estimate of the population mean.<div style=padding-top: 35px> Redefine the confidence interval into a format using the margin of error and the point estimate of the population mean.
Question
Describe the steps for finding a confidence interval
Question
Based on a simple random sample of students from her school, Sally obtained a point estimate of the mean weight of students at her school. What additional information would
be provided by a confidence interval estimate of the mean weight?
Question
How do you determine whether to use the z or t distribution in computing the margin of error, How do you determine whether to use the z or t distribution in computing the margin of error,  <div style=padding-top: 35px>
Question
Draw a diagram of the chi-square distribution. Discuss its shape and values
Question
Why is Why is   the best point estimate of  ?<div style=padding-top: 35px> the best point estimate of Why is   the best point estimate of  ?<div style=padding-top: 35px> ?
Question
Identify the correct distribution (z, t, or neither)for each of the following Identify the correct distribution (z, t, or neither)for each of the following  <div style=padding-top: 35px>
Question
In a Gallup poll, 1011 adults were asked if they consume alcoholic beverages and 64% of them said that they did. Construct a 90% confidence interval estimate of the proportion of all
adults who consume alcoholic beverages. Can we safely conclude that the majority of adults
consume alcoholic beverages?
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Deck 7: Estimating Parameters and Determining Sample Sizes
1
The margin of error ________ ________ (increases or decreases)with an increase in confidence level.

A) increases; increases
B) increases; decreases
C) decreases; increases
D) decreases; decreases
C
2
Fifty people are selected randomly from a certain population and it is found that 12 people in the sample are over six feet tall. What is the best point estimate of the proportion of people in the population who are over 6 feet tall?

A) 0.76
B) 0.24
C) 0.50
D) 0.18
B
3
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p .
n=195, x=162 ; 95 % confidence

A) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population proportion  p . n=195, x=162 ; 95 %  confidence</strong> A)   B)   C)   D)
B) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population proportion  p . n=195, x=162 ; 95 %  confidence</strong> A)   B)   C)   D)
C) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population proportion  p . n=195, x=162 ; 95 %  confidence</strong> A)   B)   C)   D)
D) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population proportion  p . n=195, x=162 ; 95 %  confidence</strong> A)   B)   C)   D)
4
Of 380 randomly selected medical students, 21 said that they planned to work in a rural community. Find a 95 % confidence interval for the true proportion of all medical students who plan to work in a rural community.

A) <strong>Of 380 randomly selected medical students, 21 said that they planned to work in a rural community. Find a  95 %  confidence interval for the true proportion of all medical students who plan to work in a rural community.</strong> A)   B)   C)   D)
B) <strong>Of 380 randomly selected medical students, 21 said that they planned to work in a rural community. Find a  95 %  confidence interval for the true proportion of all medical students who plan to work in a rural community.</strong> A)   B)   C)   D)
C) <strong>Of 380 randomly selected medical students, 21 said that they planned to work in a rural community. Find a  95 %  confidence interval for the true proportion of all medical students who plan to work in a rural community.</strong> A)   B)   C)   D)
D) <strong>Of 380 randomly selected medical students, 21 said that they planned to work in a rural community. Find a  95 %  confidence interval for the true proportion of all medical students who plan to work in a rural community.</strong> A)   B)   C)   D)
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5
Do one of the following, as appropriate:
(a) Find the critical value <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   (c) state that neither the normal nor the t distribution applies. 90% confidence interval for   n=9 ;   population appears to be very skewed.</strong> A)   B)   C)   D) Neither the normal nor the t distribution applies.
(b) find the critical value <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   (c) state that neither the normal nor the t distribution applies. 90% confidence interval for   n=9 ;   population appears to be very skewed.</strong> A)   B)   C)   D) Neither the normal nor the t distribution applies.
(c) state that neither the normal nor the t distribution applies.
90% confidence interval for <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   (c) state that neither the normal nor the t distribution applies. 90% confidence interval for   n=9 ;   population appears to be very skewed.</strong> A)   B)   C)   D) Neither the normal nor the t distribution applies. n=9 ; <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   (c) state that neither the normal nor the t distribution applies. 90% confidence interval for   n=9 ;   population appears to be very skewed.</strong> A)   B)   C)   D) Neither the normal nor the t distribution applies. population appears to be very skewed.

A) <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   (c) state that neither the normal nor the t distribution applies. 90% confidence interval for   n=9 ;   population appears to be very skewed.</strong> A)   B)   C)   D) Neither the normal nor the t distribution applies.
B) <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   (c) state that neither the normal nor the t distribution applies. 90% confidence interval for   n=9 ;   population appears to be very skewed.</strong> A)   B)   C)   D) Neither the normal nor the t distribution applies.
C) <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   (c) state that neither the normal nor the t distribution applies. 90% confidence interval for   n=9 ;   population appears to be very skewed.</strong> A)   B)   C)   D) Neither the normal nor the t distribution applies.
D) Neither the normal nor the t distribution applies.
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6
Express the confidence interval (0.432,0.52) in the form of <strong>Express the confidence interval  (0.432,0.52)  in the form of  </strong> A)   B)   C)   D)

A) <strong>Express the confidence interval  (0.432,0.52)  in the form of  </strong> A)   B)   C)   D)
B) <strong>Express the confidence interval  (0.432,0.52)  in the form of  </strong> A)   B)   C)   D)
C) <strong>Express the confidence interval  (0.432,0.52)  in the form of  </strong> A)   B)   C)   D)
D) <strong>Express the confidence interval  (0.432,0.52)  in the form of  </strong> A)   B)   C)   D)
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7
Use the given degree of confidence and sample data to construct a confidence interval for the population mean <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution.  n=30 ,    s=10.5,90 % confidence</strong> A)   B)   C)   D)   Assume that the population has a normal distribution. n=30 , <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution.  n=30 ,    s=10.5,90 % confidence</strong> A)   B)   C)   D)   s=10.5,90 % confidence

A) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution.  n=30 ,    s=10.5,90 % confidence</strong> A)   B)   C)   D)
B) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution.  n=30 ,    s=10.5,90 % confidence</strong> A)   B)   C)   D)
C) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution.  n=30 ,    s=10.5,90 % confidence</strong> A)   B)   C)   D)
D) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution.  n=30 ,    s=10.5,90 % confidence</strong> A)   B)   C)   D)
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8
Find the critical value <strong>Find the critical value   corresponding to a sample size of 19 and a confidence level of 99 percent.</strong> A)  37.156 B)  6.265 C)  34.805 D)  7.015 corresponding to a sample size of 19 and a confidence level of 99 percent.

A) 37.156
B) 6.265
C) 34.805
D) 7.015
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9
Which critical value is appropriate for a 99% confidence level where n=17 ;<strong>Which critical value is appropriate for a  99% confidence level where  n=17 ;  is unknown and the population appears to be normally distributed?</strong> A)   B)   C)   D)   is unknown and the population appears to be normally distributed?

A) <strong>Which critical value is appropriate for a  99% confidence level where  n=17 ;  is unknown and the population appears to be normally distributed?</strong> A)   B)   C)   D)
B) <strong>Which critical value is appropriate for a  99% confidence level where  n=17 ;  is unknown and the population appears to be normally distributed?</strong> A)   B)   C)   D)
C) <strong>Which critical value is appropriate for a  99% confidence level where  n=17 ;  is unknown and the population appears to be normally distributed?</strong> A)   B)   C)   D)
D) <strong>Which critical value is appropriate for a  99% confidence level where  n=17 ;  is unknown and the population appears to be normally distributed?</strong> A)   B)   C)   D)
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10
Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places.
98% confidence; the sample size is 800, of which 40% are successes

A) 0.0355
B) 0.0339
C) 0.0404
D) 0.0446
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11
If the computed minimum sample size n needed for a particular margin of error is not a whole number, round the value of n _____ (up or down) to the next _____ (smaller or larger) whole number.

A) up; smaller
B) up; larger
C) down; smaller
D) down; larger
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12
Find the value of <strong>Find the value of   that corresponds to a confidence level of  89.48%.</strong> A)  1.25 B)  1.62 C)  0.0526 D)  -1.62 that corresponds to a confidence level of 89.48%.

A) 1.25
B) 1.62
C) 0.0526
D) -1.62
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13
A survey of 300 union members in New York State reveals that 112 favor the Republican candidate for governor. Construct the 98 % confidence interval for the true population proportion of all New York State union members who favor the Republican candidate.

A) <strong>A survey of 300 union members in New York State reveals that 112 favor the Republican candidate for governor. Construct the  98 %  confidence interval for the true population proportion of all New York State union members who favor the Republican candidate.</strong> A)   B)   C)   D)
B) <strong>A survey of 300 union members in New York State reveals that 112 favor the Republican candidate for governor. Construct the  98 %  confidence interval for the true population proportion of all New York State union members who favor the Republican candidate.</strong> A)   B)   C)   D)
C) <strong>A survey of 300 union members in New York State reveals that 112 favor the Republican candidate for governor. Construct the  98 %  confidence interval for the true population proportion of all New York State union members who favor the Republican candidate.</strong> A)   B)   C)   D)
D) <strong>A survey of 300 union members in New York State reveals that 112 favor the Republican candidate for governor. Construct the  98 %  confidence interval for the true population proportion of all New York State union members who favor the Republican candidate.</strong> A)   B)   C)   D)
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14
Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level.
95% confidence; n=2388, x=1672

A) 0.0248
B) 0.0184
C) 0.0156
D) 0.0206
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15
Find the critical value <strong>Find the critical value   that corresponds to a  91% confidence level.</strong> A)  1.34 B)  1.645 C)  1.70 D)  1.75 that corresponds to a 91% confidence level.

A) 1.34
B) 1.645
C) 1.70
D) 1.75
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16
Use the given degree of confidence and sample data to construct a confidence interval for the population mean <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution. A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 185 milligrams with  s=17.6  milligrams. Construct a  95% confidence interval for the true mean cholesterol content of all such eggs.</strong> A)   B)   C)   D)   Assume that the population has a normal distribution.
A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 185 milligrams with s=17.6 milligrams. Construct a 95% confidence interval for the true mean cholesterol content of all such eggs.

A) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution. A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 185 milligrams with  s=17.6  milligrams. Construct a  95% confidence interval for the true mean cholesterol content of all such eggs.</strong> A)   B)   C)   D)
B) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution. A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 185 milligrams with  s=17.6  milligrams. Construct a  95% confidence interval for the true mean cholesterol content of all such eggs.</strong> A)   B)   C)   D)
C) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution. A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 185 milligrams with  s=17.6  milligrams. Construct a  95% confidence interval for the true mean cholesterol content of all such eggs.</strong> A)   B)   C)   D)
D) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution. A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 185 milligrams with  s=17.6  milligrams. Construct a  95% confidence interval for the true mean cholesterol content of all such eggs.</strong> A)   B)   C)   D)
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17
Use the given degree of confidence and sample data to construct a confidence interval for the population mean μ. Assume that the population has a normal distribution. Use the given degree of confidence and sample data to construct a confidence interval for the population mean μ. Assume that the population has a normal distribution.
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18
In constructing a confidence interval for <strong>In constructing a confidence interval for   or  , a table is used to find the critical values   for values of   For larger values of  n,    can be approximated by using the following formula:   where  k  is the number of degrees of freedom and   is the critical z-score. Construct the  90 %  confidence interval for    using the following sample data: a sample of size  n=232  yields a mean weight of  154 lb  and a standard deviation of  25.5 lb. Round the confidence interval limits to the nearest hundredth.</strong> A)   B)   C)   D)   or <strong>In constructing a confidence interval for   or  , a table is used to find the critical values   for values of   For larger values of  n,    can be approximated by using the following formula:   where  k  is the number of degrees of freedom and   is the critical z-score. Construct the  90 %  confidence interval for    using the following sample data: a sample of size  n=232  yields a mean weight of  154 lb  and a standard deviation of  25.5 lb. Round the confidence interval limits to the nearest hundredth.</strong> A)   B)   C)   D)   , a table is used to find the critical values <strong>In constructing a confidence interval for   or  , a table is used to find the critical values   for values of   For larger values of  n,    can be approximated by using the following formula:   where  k  is the number of degrees of freedom and   is the critical z-score. Construct the  90 %  confidence interval for    using the following sample data: a sample of size  n=232  yields a mean weight of  154 lb  and a standard deviation of  25.5 lb. Round the confidence interval limits to the nearest hundredth.</strong> A)   B)   C)   D)   for values of <strong>In constructing a confidence interval for   or  , a table is used to find the critical values   for values of   For larger values of  n,    can be approximated by using the following formula:   where  k  is the number of degrees of freedom and   is the critical z-score. Construct the  90 %  confidence interval for    using the following sample data: a sample of size  n=232  yields a mean weight of  154 lb  and a standard deviation of  25.5 lb. Round the confidence interval limits to the nearest hundredth.</strong> A)   B)   C)   D)   For larger values of n, <strong>In constructing a confidence interval for   or  , a table is used to find the critical values   for values of   For larger values of  n,    can be approximated by using the following formula:   where  k  is the number of degrees of freedom and   is the critical z-score. Construct the  90 %  confidence interval for    using the following sample data: a sample of size  n=232  yields a mean weight of  154 lb  and a standard deviation of  25.5 lb. Round the confidence interval limits to the nearest hundredth.</strong> A)   B)   C)   D)   can be
approximated by using the following formula: <strong>In constructing a confidence interval for   or  , a table is used to find the critical values   for values of   For larger values of  n,    can be approximated by using the following formula:   where  k  is the number of degrees of freedom and   is the critical z-score. Construct the  90 %  confidence interval for    using the following sample data: a sample of size  n=232  yields a mean weight of  154 lb  and a standard deviation of  25.5 lb. Round the confidence interval limits to the nearest hundredth.</strong> A)   B)   C)   D)   where k is the number of degrees of freedom and <strong>In constructing a confidence interval for   or  , a table is used to find the critical values   for values of   For larger values of  n,    can be approximated by using the following formula:   where  k  is the number of degrees of freedom and   is the critical z-score. Construct the  90 %  confidence interval for    using the following sample data: a sample of size  n=232  yields a mean weight of  154 lb  and a standard deviation of  25.5 lb. Round the confidence interval limits to the nearest hundredth.</strong> A)   B)   C)   D)   is the critical z-score. Construct the 90 % confidence interval for <strong>In constructing a confidence interval for   or  , a table is used to find the critical values   for values of   For larger values of  n,    can be approximated by using the following formula:   where  k  is the number of degrees of freedom and   is the critical z-score. Construct the  90 %  confidence interval for    using the following sample data: a sample of size  n=232  yields a mean weight of  154 lb  and a standard deviation of  25.5 lb. Round the confidence interval limits to the nearest hundredth.</strong> A)   B)   C)   D)   using the following sample data: a sample of size n=232 yields a mean weight of 154 lb and a standard deviation of 25.5 lb. Round the confidence interval limits to the nearest hundredth.

A) <strong>In constructing a confidence interval for   or  , a table is used to find the critical values   for values of   For larger values of  n,    can be approximated by using the following formula:   where  k  is the number of degrees of freedom and   is the critical z-score. Construct the  90 %  confidence interval for    using the following sample data: a sample of size  n=232  yields a mean weight of  154 lb  and a standard deviation of  25.5 lb. Round the confidence interval limits to the nearest hundredth.</strong> A)   B)   C)   D)
B) <strong>In constructing a confidence interval for   or  , a table is used to find the critical values   for values of   For larger values of  n,    can be approximated by using the following formula:   where  k  is the number of degrees of freedom and   is the critical z-score. Construct the  90 %  confidence interval for    using the following sample data: a sample of size  n=232  yields a mean weight of  154 lb  and a standard deviation of  25.5 lb. Round the confidence interval limits to the nearest hundredth.</strong> A)   B)   C)   D)
C) <strong>In constructing a confidence interval for   or  , a table is used to find the critical values   for values of   For larger values of  n,    can be approximated by using the following formula:   where  k  is the number of degrees of freedom and   is the critical z-score. Construct the  90 %  confidence interval for    using the following sample data: a sample of size  n=232  yields a mean weight of  154 lb  and a standard deviation of  25.5 lb. Round the confidence interval limits to the nearest hundredth.</strong> A)   B)   C)   D)
D) <strong>In constructing a confidence interval for   or  , a table is used to find the critical values   for values of   For larger values of  n,    can be approximated by using the following formula:   where  k  is the number of degrees of freedom and   is the critical z-score. Construct the  90 %  confidence interval for    using the following sample data: a sample of size  n=232  yields a mean weight of  154 lb  and a standard deviation of  25.5 lb. Round the confidence interval limits to the nearest hundredth.</strong> A)   B)   C)   D)
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19
Use the given data to find the minimum sample size required to estimate the population proportion. Margin of error: 0.028; confidence level: 99%; p and q unknown

A) 1116
B) 2223
C) 1939
D) 2115
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20
Identify the distribution that applies to the following situation: In constructing a confidence interval of σ you have 50 sample values and they appear to be from a population with a skewed distribution.

A) Student t distribution
B) Normal distribution
C) Chi-square distribution
D) None of the three distributions is appropriate.
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21
A 99% confidence interval (in inches) for the mean height of a population is <strong>A  99% confidence interval (in inches) for the mean height of a population is   This result is based on a sample of size 144. Construct the  95% confidence interval. (Hint: you will first need to find the sample mean and sample standard deviation).</strong> A)   B)   C)   D)
This result is based on a sample of size 144. Construct the 95% confidence interval. (Hint: you will first need to find the sample mean and sample standard deviation).

A) <strong>A  99% confidence interval (in inches) for the mean height of a population is   This result is based on a sample of size 144. Construct the  95% confidence interval. (Hint: you will first need to find the sample mean and sample standard deviation).</strong> A)   B)   C)   D)
B) <strong>A  99% confidence interval (in inches) for the mean height of a population is   This result is based on a sample of size 144. Construct the  95% confidence interval. (Hint: you will first need to find the sample mean and sample standard deviation).</strong> A)   B)   C)   D)
C) <strong>A  99% confidence interval (in inches) for the mean height of a population is   This result is based on a sample of size 144. Construct the  95% confidence interval. (Hint: you will first need to find the sample mean and sample standard deviation).</strong> A)   B)   C)   D)
D) <strong>A  99% confidence interval (in inches) for the mean height of a population is   This result is based on a sample of size 144. Construct the  95% confidence interval. (Hint: you will first need to find the sample mean and sample standard deviation).</strong> A)   B)   C)   D)
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22
To find the standard deviation of the diameter of wooden dowels, the manufacturer measures 19 randomly selected dowels and finds the standard deviation of the sample to be s=0.16 . Find the 95 % confidence interval for the population standard deviation <strong>To find the standard deviation of the diameter of wooden dowels, the manufacturer measures 19 randomly selected dowels and finds the standard deviation of the sample to be  s=0.16 . Find the  95 %  confidence interval for the population standard deviation  </strong> A)   B)   C)   D)

A) <strong>To find the standard deviation of the diameter of wooden dowels, the manufacturer measures 19 randomly selected dowels and finds the standard deviation of the sample to be  s=0.16 . Find the  95 %  confidence interval for the population standard deviation  </strong> A)   B)   C)   D)
B) <strong>To find the standard deviation of the diameter of wooden dowels, the manufacturer measures 19 randomly selected dowels and finds the standard deviation of the sample to be  s=0.16 . Find the  95 %  confidence interval for the population standard deviation  </strong> A)   B)   C)   D)
C) <strong>To find the standard deviation of the diameter of wooden dowels, the manufacturer measures 19 randomly selected dowels and finds the standard deviation of the sample to be  s=0.16 . Find the  95 %  confidence interval for the population standard deviation  </strong> A)   B)   C)   D)
D) <strong>To find the standard deviation of the diameter of wooden dowels, the manufacturer measures 19 randomly selected dowels and finds the standard deviation of the sample to be  s=0.16 . Find the  95 %  confidence interval for the population standard deviation  </strong> A)   B)   C)   D)
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23
A one-sided confidence interval for p can be written as <strong>A one-sided confidence interval for p can be written as   where the margin of error E is modified by replacing   with   If a teacher wants to report that the fail rate on a test is at most  x  with  90 %  confidence, construct the appropriate one -sided confidence interval. Assume that a simple random sample of 74 students results in 8 who fail the test.</strong> A)   B)   C)   D)   where the margin of error E is modified by replacing <strong>A one-sided confidence interval for p can be written as   where the margin of error E is modified by replacing   with   If a teacher wants to report that the fail rate on a test is at most  x  with  90 %  confidence, construct the appropriate one -sided confidence interval. Assume that a simple random sample of 74 students results in 8 who fail the test.</strong> A)   B)   C)   D)   with <strong>A one-sided confidence interval for p can be written as   where the margin of error E is modified by replacing   with   If a teacher wants to report that the fail rate on a test is at most  x  with  90 %  confidence, construct the appropriate one -sided confidence interval. Assume that a simple random sample of 74 students results in 8 who fail the test.</strong> A)   B)   C)   D)   If a teacher wants to report that the fail rate on a test is at most x with 90 % confidence, construct the appropriate one -sided confidence interval. Assume that a simple random sample of 74 students results in 8 who fail the test.

A) <strong>A one-sided confidence interval for p can be written as   where the margin of error E is modified by replacing   with   If a teacher wants to report that the fail rate on a test is at most  x  with  90 %  confidence, construct the appropriate one -sided confidence interval. Assume that a simple random sample of 74 students results in 8 who fail the test.</strong> A)   B)   C)   D)
B) <strong>A one-sided confidence interval for p can be written as   where the margin of error E is modified by replacing   with   If a teacher wants to report that the fail rate on a test is at most  x  with  90 %  confidence, construct the appropriate one -sided confidence interval. Assume that a simple random sample of 74 students results in 8 who fail the test.</strong> A)   B)   C)   D)
C) <strong>A one-sided confidence interval for p can be written as   where the margin of error E is modified by replacing   with   If a teacher wants to report that the fail rate on a test is at most  x  with  90 %  confidence, construct the appropriate one -sided confidence interval. Assume that a simple random sample of 74 students results in 8 who fail the test.</strong> A)   B)   C)   D)
D) <strong>A one-sided confidence interval for p can be written as   where the margin of error E is modified by replacing   with   If a teacher wants to report that the fail rate on a test is at most  x  with  90 %  confidence, construct the appropriate one -sided confidence interval. Assume that a simple random sample of 74 students results in 8 who fail the test.</strong> A)   B)   C)   D)
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24
Do one of the following, as appropriate:
(a) Find the critical value <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   99 % ; n=17 ;   is unknown; population appears to be normally distributed.</strong> A)   B)   C)   D)
(b) find the critical value <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   99 % ; n=17 ;   is unknown; population appears to be normally distributed.</strong> A)   B)   C)   D)
99 % ; n=17 ; <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   99 % ; n=17 ;   is unknown; population appears to be normally distributed.</strong> A)   B)   C)   D)   is unknown; population appears to be normally distributed.

A) <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   99 % ; n=17 ;   is unknown; population appears to be normally distributed.</strong> A)   B)   C)   D)
B) <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   99 % ; n=17 ;   is unknown; population appears to be normally distributed.</strong> A)   B)   C)   D)
C) <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   99 % ; n=17 ;   is unknown; population appears to be normally distributed.</strong> A)   B)   C)   D)
D) <strong>Do one of the following, as appropriate: (a) Find the critical value   (b) find the critical value   99 % ; n=17 ;   is unknown; population appears to be normally distributed.</strong> A)   B)   C)   D)
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25
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p.
n=130, x=69 ; 90% confidence

A) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. n=130, x=69 ; 90% confidence</strong> A)   B)   C)   D)
B) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. n=130, x=69 ; 90% confidence</strong> A)   B)   C)   D)
C) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. n=130, x=69 ; 90% confidence</strong> A)   B)   C)   D)
D) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. n=130, x=69 ; 90% confidence</strong> A)   B)   C)   D)
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26
Express the confidence interval <strong>Express the confidence interval   in the form of  </strong> A)   B)   C)   D)   in the form of <strong>Express the confidence interval   in the form of  </strong> A)   B)   C)   D)

A) <strong>Express the confidence interval   in the form of  </strong> A)   B)   C)   D)
B) <strong>Express the confidence interval   in the form of  </strong> A)   B)   C)   D)
C) <strong>Express the confidence interval   in the form of  </strong> A)   B)   C)   D)
D) <strong>Express the confidence interval   in the form of  </strong> A)   B)   C)   D)
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27
You want to be 95% confident that the sample variance is within 40% of the population variance. Find the appropriate minimum sample size.

A) 57
B) 224
C) 14
D) 11
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28
Find the degree of confidence used in constructing the confidence interval <strong>Find the degree of confidence used in constructing the confidence interval   - for the population proportion  p  using sample data with  n=109, x=65 .</strong> A)  88 % B)  90 % C)  95 % D)  99 % - for the population proportion p using sample data with n=109, x=65 .

A) 88 %
B) 90 %
C) 95 %
D) 99 %
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29
Of 118 randomly selected adults, 34 were found to have high blood pressure. Construct a 95 % confidence interval for the true percentage of all adults that have high blood pressure.

A) <strong>Of 118 randomly selected adults, 34 were found to have high blood pressure. Construct a  95 %  confidence interval for the true percentage of all adults that have high blood pressure.</strong> A)   B)   C)   D)
B) <strong>Of 118 randomly selected adults, 34 were found to have high blood pressure. Construct a  95 %  confidence interval for the true percentage of all adults that have high blood pressure.</strong> A)   B)   C)   D)
C) <strong>Of 118 randomly selected adults, 34 were found to have high blood pressure. Construct a  95 %  confidence interval for the true percentage of all adults that have high blood pressure.</strong> A)   B)   C)   D)
D) <strong>Of 118 randomly selected adults, 34 were found to have high blood pressure. Construct a  95 %  confidence interval for the true percentage of all adults that have high blood pressure.</strong> A)   B)   C)   D)
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30
Identify the distribution that applies to the following situation:
In constructing a confidence interval of <strong>Identify the distribution that applies to the following situation: In constructing a confidence interval of  , you have 50 sample values and they appear to be from a population with a skewed distribution. The population standard deviation is not known.</strong> A) Student  t  distribution B) Normal distribution C) Chi-square distribution D) None of the three distributions is appropriate. , you have 50 sample values and they appear to be from a population with a skewed distribution. The population standard deviation is not known.

A) Student t distribution
B) Normal distribution
C) Chi-square distribution
D) None of the three distributions is appropriate.
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31
Use the given data to find the minimum sample size required to estimate the population proportion. Margin of error: 0.008 ; confidence level: 98% ; <strong>Use the given data to find the minimum sample size required to estimate the population proportion. Margin of error:  0.008 ; confidence level:  98% ;   unknown</strong> A) 22,184 B) 10,384 C) 21,207 D) 20,308V unknown

A) 22,184
B) 10,384
C) 21,207
D) 20,308V
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32
A group of 59 randomly selected students have a mean score of 29.5 with a standard deviation of 5.2 on a placement test. What is the 90 % confidence interval for the mean score, <strong>A group of 59 randomly selected students have a mean score of  29.5  with a standard deviation of  5.2  on a placement test. What is the  90 %  confidence interval for the mean score,   , of all students taking the test?</strong> A)   B)   C)   D)   , of all students taking the test?

A) <strong>A group of 59 randomly selected students have a mean score of  29.5  with a standard deviation of  5.2  on a placement test. What is the  90 %  confidence interval for the mean score,   , of all students taking the test?</strong> A)   B)   C)   D)
B) <strong>A group of 59 randomly selected students have a mean score of  29.5  with a standard deviation of  5.2  on a placement test. What is the  90 %  confidence interval for the mean score,   , of all students taking the test?</strong> A)   B)   C)   D)
C) <strong>A group of 59 randomly selected students have a mean score of  29.5  with a standard deviation of  5.2  on a placement test. What is the  90 %  confidence interval for the mean score,   , of all students taking the test?</strong> A)   B)   C)   D)
D) <strong>A group of 59 randomly selected students have a mean score of  29.5  with a standard deviation of  5.2  on a placement test. What is the  90 %  confidence interval for the mean score,   , of all students taking the test?</strong> A)   B)   C)   D)
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33
Find the critical value <strong>Find the critical value   corresponding to a sample size of 19 and a confidence level of 99 percent.</strong> A)  37.156 B)  6.265 C)  34.805 D)  7.015 corresponding to a sample size of 19 and a confidence level of 99 percent.

A) 37.156
B) 6.265
C) 34.805
D) 7.015
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34
Express a confidence interval defined as (0.432,0.52) in the form of the point estimate _____ <strong>Express a confidence interval defined as  (0.432,0.52)  in the form of the point estimate _____    the margin of error______ Express both in three decimal places.</strong> A)   B)   C)   D)   the margin of error______
Express both in three decimal places.

A) <strong>Express a confidence interval defined as  (0.432,0.52)  in the form of the point estimate _____    the margin of error______ Express both in three decimal places.</strong> A)   B)   C)   D)
B) <strong>Express a confidence interval defined as  (0.432,0.52)  in the form of the point estimate _____    the margin of error______ Express both in three decimal places.</strong> A)   B)   C)   D)
C) <strong>Express a confidence interval defined as  (0.432,0.52)  in the form of the point estimate _____    the margin of error______ Express both in three decimal places.</strong> A)   B)   C)   D)
D) <strong>Express a confidence interval defined as  (0.432,0.52)  in the form of the point estimate _____    the margin of error______ Express both in three decimal places.</strong> A)   B)   C)   D)
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35
A laboratory tested 82 chicken eggs and found that the mean amount of cholesterol was 228 milligrams with <strong>A laboratory tested 82 chicken eggs and found that the mean amount of cholesterol was 228 milligrams with   Construct a  95% confidence interval for the true mean cholesterol content,   of all such eggs.</strong> A)   B)   C)   D)
Construct a 95% confidence interval for the true mean cholesterol content, <strong>A laboratory tested 82 chicken eggs and found that the mean amount of cholesterol was 228 milligrams with   Construct a  95% confidence interval for the true mean cholesterol content,   of all such eggs.</strong> A)   B)   C)   D)   of all such eggs.

A) <strong>A laboratory tested 82 chicken eggs and found that the mean amount of cholesterol was 228 milligrams with   Construct a  95% confidence interval for the true mean cholesterol content,   of all such eggs.</strong> A)   B)   C)   D)
B) <strong>A laboratory tested 82 chicken eggs and found that the mean amount of cholesterol was 228 milligrams with   Construct a  95% confidence interval for the true mean cholesterol content,   of all such eggs.</strong> A)   B)   C)   D)
C) <strong>A laboratory tested 82 chicken eggs and found that the mean amount of cholesterol was 228 milligrams with   Construct a  95% confidence interval for the true mean cholesterol content,   of all such eggs.</strong> A)   B)   C)   D)
D) <strong>A laboratory tested 82 chicken eggs and found that the mean amount of cholesterol was 228 milligrams with   Construct a  95% confidence interval for the true mean cholesterol content,   of all such eggs.</strong> A)   B)   C)   D)
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36
To be able to say with 95% confidence that the standard deviation of a data set is within 10% of the population's standard deviation, the number of observations within the data set must be greater than or equal to what quantity?

A) 805
B) 192
C) 335
D) 250
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37
Use the given degree of confidence and sample data to construct a confidence interval for the population mean <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution. A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 185 milligrams with  s=17.6  milligrams. A confidence interval of   mg is constructed for the true mean cholesterol content of all such eggs. It was assumed that the population has a normal distribution. What confidence level does this interval represent? </strong> A)  99% B)  95% C)  98% D)  80% Assume that the population has a normal distribution.
A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 185 milligrams with s=17.6 milligrams. A confidence interval of <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population mean   Assume that the population has a normal distribution. A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 185 milligrams with  s=17.6  milligrams. A confidence interval of   mg is constructed for the true mean cholesterol content of all such eggs. It was assumed that the population has a normal distribution. What confidence level does this interval represent? </strong> A)  99% B)  95% C)  98% D)  80% mg is constructed for the true mean cholesterol content of all such eggs. It was assumed that the population has a normal distribution. What confidence level does this interval represent?

A) 99%
B) 95%
C) 98%
D) 80%
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38
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p.
n=56, x=30 ; 95% confidence

A) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population proportion  p. n=56, x=30 ; 95% confidence</strong> A)   B)   C)   D)
B) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population proportion  p. n=56, x=30 ; 95% confidence</strong> A)   B)   C)   D)
C) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population proportion  p. n=56, x=30 ; 95% confidence</strong> A)   B)   C)   D)
D) <strong>Use the given degree of confidence and sample data to construct a confidence interval for the population proportion  p. n=56, x=30 ; 95% confidence</strong> A)   B)   C)   D)
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39
Fill in the blank: The critical value <strong>Fill in the blank: The critical value   that corresponds to a ______% confidence level is  2.33 . </strong> A) 88 B) 90 C) 98 D) 99 that corresponds to a ______% confidence level is 2.33 .

A) 88
B) 90
C) 98
D) 99
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40
Which of the following critical values is appropriate for a 98% confidence level where n=7 ; <strong>Which of the following critical values is appropriate for a  98% confidence level where  n=7 ;   and the population appears to be normally distributed.</strong> A)   B)   C)   D)   and the population appears to be normally distributed.

A) <strong>Which of the following critical values is appropriate for a  98% confidence level where  n=7 ;   and the population appears to be normally distributed.</strong> A)   B)   C)   D)
B) <strong>Which of the following critical values is appropriate for a  98% confidence level where  n=7 ;   and the population appears to be normally distributed.</strong> A)   B)   C)   D)
C) <strong>Which of the following critical values is appropriate for a  98% confidence level where  n=7 ;   and the population appears to be normally distributed.</strong> A)   B)   C)   D)
D) <strong>Which of the following critical values is appropriate for a  98% confidence level where  n=7 ;   and the population appears to be normally distributed.</strong> A)   B)   C)   D)
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41
The following is a 95 % confidence interval of the proportion of female medical school students: The following is a  95 %  confidence interval of the proportion of female medical school students:   based on data from the American Medical Association. What is the point estimate of the proportion of females in the population of medical school students? Write a brief statement that correctly interprets the confidence interval given. based on data from the American Medical Association. What is the point estimate of the proportion of females in the population of medical school students? Write a brief statement that correctly interprets the confidence interval given.
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42
In a Gallup poll, 1011 adults were asked if they consume alcoholic beverages and 64% of them said that they did. Construct a 90% confidence interval estimate of the proportion of all
adults who consume alcoholic beverages. Can we safely conclude that the majority of adults
consume alcoholic beverages?
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43
Six human skulls from around 4000 B.C. were measured, and the lengths have a mean of 94.2 mm and a standard deviation of 4.9 mm. If you want to construct a 95% confidence
interval estimate of the mean length of skulls, what requirements must be satisfied?
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44
When determining the sample size needed to achieve a particular error estimate you need to know When determining the sample size needed to achieve a particular error estimate you need to know   What are two methods of estimating    if     is unknown? What are two methods of estimating When determining the sample size needed to achieve a particular error estimate you need to know   What are two methods of estimating    if     is unknown? if When determining the sample size needed to achieve a particular error estimate you need to know   What are two methods of estimating    if     is unknown? is unknown?
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45
Interpret the following 95 % confidence interval for mean weekly salaries of shift managers at Guiseppe's Pizza and Pasta.
Interpret the following  95 %  confidence interval for mean weekly salaries of shift managers at Guiseppe's Pizza and Pasta.
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46
Describe the process for finding the confidence interval for a population proportion
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47
Bert constructed a confidence interval to estimate the mean weight of students in his class. The population was very small - only 30. Ruth constructed a confidence interval for the mean
weight of all adult males in the city. She based her confidence interval on a very small
sample of only 5. Which confidence interval is likely to give a better estimate of the mean it is
estimating? Which is likely to be more of a problem, a small sample or a small population?
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48
Under what circumstances can you replace Under what circumstances can you replace     with  s  in the formula  with s in the formula Under what circumstances can you replace     with  s  in the formula
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49
You want to estimate σ for the population of waiting times at McDonald's drive-up windows, and you want to be 95% confident that the sample standard deviation is with 20% of σ. Find
the minimum sample size. Is this sample size practical?
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50
In general, what does "degrees of freedom" refer to? Find the degrees of freedom for the given information, assuming that you want to construct a confidence interval estimate of In general, what does degrees of freedom refer to? Find the degrees of freedom for the given information, assuming that you want to construct a confidence interval estimate of   Six human skulls from around 4000 B.C. were measured, and the lengths have a mean of  94.2 mm and a standard deviation of  4.9 mm. Six human skulls from around 4000 B.C. were measured, and the lengths have a mean of 94.2 mm and a standard deviation of 4.9 mm.
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51
Define in as clear language as possible how a 95% confidence interval can be used for hypothesis tests.
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52
In a Gallup poll of 557 randomly selected adults, 284 said that they were underpaid. Identify the best point estimate of the percentage of adults who say they are underpaid. Construct a
95% confidence interval estimate of the percentage of adults who say that that they are
underpaid. Can we safely conclude that the majority of adults say that they are underpaid?
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53
Define margin of error. Explain the relation between the confidence interval and the margin of error. Suppose a confidence interval is Define margin of error. Explain the relation between the confidence interval and the margin of error. Suppose a confidence interval is   Redefine the confidence interval into a format using the margin of error and the point estimate of the population mean. Redefine the confidence interval into a format using the margin of error and the point estimate of the population mean.
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54
Describe the steps for finding a confidence interval
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55
Based on a simple random sample of students from her school, Sally obtained a point estimate of the mean weight of students at her school. What additional information would
be provided by a confidence interval estimate of the mean weight?
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56
How do you determine whether to use the z or t distribution in computing the margin of error, How do you determine whether to use the z or t distribution in computing the margin of error,
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57
Draw a diagram of the chi-square distribution. Discuss its shape and values
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58
Why is Why is   the best point estimate of  ? the best point estimate of Why is   the best point estimate of  ??
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59
Identify the correct distribution (z, t, or neither)for each of the following Identify the correct distribution (z, t, or neither)for each of the following
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60
In a Gallup poll, 1011 adults were asked if they consume alcoholic beverages and 64% of them said that they did. Construct a 90% confidence interval estimate of the proportion of all
adults who consume alcoholic beverages. Can we safely conclude that the majority of adults
consume alcoholic beverages?
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