Deck 7: Locus and Concurrence
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Deck 7: Locus and Concurrence
1

Supply missing reasons for the following proof.
Given:
bisects
;
and
Prove:
S1.
bisects
; R1.
and
S2.
R2.S3.
and
are rt.
R3.S4.
R4.S5.
R5.S6.
R6.S7.
R7.R1. Given
R2. Definition of angle-bisector
R3. Perpendicular lines form right angles.
R4. All right angles are congruent.
R5. Identity
R6. AAS
R7. CPCTC
R2. Definition of angle-bisector
R3. Perpendicular lines form right angles.
R4. All right angles are congruent.
R5. Identity
R6. AAS
R7. CPCTC
2

Use the drawing provided to explain the following.
Given:
,
, and
are the medians of
Prove: 
If
,
, and
are the medians of
, then their point of concurrence is
Q, the centroid of
. It follows that
. By the Segment-Addition
Postulate, we have
. By substitution,
. By subtraction,
. In turn,
or 2. Multiplying the equation
by
, we have
.
,
, and
are the medians of
, then their point of concurrence isQ, the centroid of
. It follows that
. By the Segment-AdditionPostulate, we have
. By substitution,
. By subtraction,
. In turn,
or 2. Multiplying the equation
by
, we have
. 3

Supply missing statements and missing reasons for the following proof.
Given: Point X not on
so that
Prove: X lies on the perpendicular-bisector of
S1. R1.S2.
R2.S3. With M the midpoint of
, R3.draw
S4. Then
R4.S5. Also,
R5.S6. R6. SSS
S7.
R7.S8. R8. Definition of perpendicular-bisector of a line segment
S1. Point X not on
so that
R1. Given
R2. Definition of congruent line segments
R3. Through 2 points, there is exactly one line.
R4. Definition of midpoint of line segment
R5. Identity
S6.
R7. CPCTC
S8. X lies on the perpendicular-bisector of
so that
R1. GivenR2. Definition of congruent line segments
R3. Through 2 points, there is exactly one line.
R4. Definition of midpoint of line segment
R5. Identity
S6.
R7. CPCTCS8. X lies on the perpendicular-bisector of

4

Use the drawing provided to explain the following theorem.
"The three angle bisectors of the angles of a triangle are concurrent."
Given:
,
, and
are the angle bisectors of the angles of
Prove:
,
, and
are concurrent at point Z Unlock Deck
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