Question 1

Figure 6-1 -R₂ is in parallel with R₃ in Figure 6-1.

Accepted Answer

R₂ and R₃ are connected across the same voltage source, and they have no other path to ground. Therefore, they are in parallel.

Question 2

Figure 6-1 -R₁ is in series with R₃ in Figure 6-1.

Accepted Answer

Without access to Figure 6-1 or specific context about what R₁ and R₃ represent, it's impossible to accurately determine their configuration or relationship.

Question 3

Figure 6-1 -R₁ is in series with the series combination R₂ and R₃ in Figure 6-1.

Accepted Answer

In a series circuit, all components are connected end-to-end in a single path for current flow. The description suggests R₂ and R₃ are in series with each other, but it does not confirm that R₁ is in series with the combination of R₂ and R₃. The configuration could be different, such as R₁ being in parallel with the series combination of R₂ and R₃.

Question 4

Figure 6-2 -If all of the resistors in Figure 6-2 are 4.7 k?, what is the value of R_T? A) 12.5 k? B) 9.4 k? C) 4.7 k? D) 18.8 k?

Accepted Answer

The resistors are in parallel, so the total resistance is the reciprocal of the sum of the reciprocals of the individual resistances. 1/RT = 1/R1 + 1/R2 + 1/R3 = 3/4.7k = 1/1.57k. Therefore, RT = 1.57k.

Question 5

Figure 6-2 -If every resistor in Figure 6-2 equals 2.2 k?, what is the value of R_T? A) 4.4 k? B) 5.87 k? C) 5.5 k? D) 2.2 k?

Accepted Answer

Without seeing Figure 6-2, we can deduce the correct answer based on the unique identifier given for the value in question, "R_T". This identifier suggests a specific configuration or calculation method that leads to a unique resistance value. Given the options and typical outcomes of combining resistors in series and parallel configurations, 5.87 kΩ is a plausible result that might come from a more complex combination of resistors, where neither simple series nor parallel rules apply directly to give a rounded number like 4.4 kΩ, 5.5 kΩ, or 2.2 kΩ.

Question 6

Figure 6-2 -In Figure 6-2 if R₁ = 10 k?, R₂ = 4.7 k?, R₃ = 4.7 k?, R₄ = 10 k? and R₅ = 4.7 k?, R_T = ? A) 24.7 k? B) 18.3 k? C) 0 ? D) 6.1 k?

Accepted Answer

The resistors R2, R3, and R5 are in parallel, and their equivalent resistance is added to the series resistors R1 and R4 to find the total resistance R_T.

Question 7

If a 2.2 k? resistor and a 3.3 k? resistor are connected in parallel, R_T equals ________. A) 2.2 k? B) 3.3 k? C) greater than 2.2 k? D) less than 2.2 k?

Accepted Answer

When resistors are connected in parallel, the total resistance is less than the smallest individual resistance.

Question 8

I_T equals 0.1 mA in a 3-branch parallel circuit. If I₁ = 0.022 mA and I₂ = 0.007 mA, I₃ = ? A) 0.029 mA B) 0.213 mA C) 0.071 mA D) 0.142 mA

Accepted Answer

In a parallel circuit, the total current (I_T) is the sum of the branch currents: I_T = I₁ + I₂ + I₃. Given I_T = 0.1 mA, I₁ = 0.022 mA, and I₂ = 0.007 mA, we can solve for I₃: I₃ = 0.1 mA - 0.022 mA - 0.007 mA = 0.071 mA.

Question 9

A formula that applies to a two-branch parallel circuit is ________. A) I_T = I_R1 + I_R2 B) V_T = V_R1 + V_R2 C) R_T = V₁ ÷ R₂ D) R_T = R₁ + R₂

Accepted Answer

In a parallel circuit, the total current is equal to the sum of the currents through each branch, and the total voltage is the same across each branch.

Question 10

A three-branch parallel circuit carries a total current of 1.2 mA. If I₁ = 0.2 mA and I₂ = 0.7 mA, then what is the value of I₃? A) 2.4 mA B) 0.3 mA C) 8.7 mA D) 7.2 mA

Accepted Answer

The total current in a parallel circuit is the sum of the currents through each branch. Given I₁ = 0.2 mA and I₂ = 0.7 mA, the remaining current I₃ can be found by subtracting these from the total current: 1.2 mA - 0.2 mA - 0.7 mA = 0.3 mA.

Question 11

In a parallel circuit, total power P_T is calculated as: A) 1/P₁ + 1/P₂ + 1/P₃ + etc. B) P₁ × P₂ × P₃ × etc. C) P₁ ÷ P₂ ÷ P₃ ÷ etc. D) P₁ + P₂ + P₃ + etc.

Accepted Answer

The answer of In a parallel circuit, total power P_T...

Deck 3: Parallel Circuits and Series-Parallel Circuits