In solution, glucose exists as ________.

Question

Quizplus · Accepted Answer

Glucose exists in equilibrium between its open-chain form and cyclic hemiacetal form, known as the Haworth projection. The cyclic hemiacetal form is more stable due to the formation of an intramolecular hydrogen bond between the carbonyl group and hydroxyl group on the same molecule which leads to ring formation. Therefore, option D, an equilibrium mixture of the open-chain form and cyclic hemiacetal forms is the correct choice.

In Solution, Glucose Exists as ________