A compound with molecular formula C₆H₁₂O₂ exhibits two singlet in its ¹HNMR spectrum,at $\delta$1.4 (I=9)and $\delta$2.0 (I=3).Its IR spectrum shows a strong absorption band near 1740 cm^-1.What is the structure for this compound?

Question

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The presence of a strong absorption band near 1740 cm-1 in the IR spectrum indicates the presence of a carbonyl group. The singlets in the ¹HNMR spectrum suggest isolated methyl groups. Combining these two pieces of information, we can conclude that the compound has a carbonyl group and two isolated methyl groups. The molecular formula and the number of atoms of each element suggest a tetrasubstituted cyclobutene ring as the core structure, with the carbonyl group and the two methyl groups attached to different carbons in the ring. The two singlets in the NMR spectrum are consistent with this structure, as the two methyl groups are nonequivalent. Among the choices given, only IV has this structure.

A Compound with Molecular Formula C6H12O2 Exhibits Two Singlet in Its

A Compound with Molecular Formula C₆H₁₂O₂ Exhibits Two Singlet in Its