Given the following rate law,what will happen to the rate if the concentration of both reactants is doubled?
Rate = k[Me₃N][MeI]

Name: Given the following rate law,what will happen to the rate if the concentration of both reactants is doubled? Rate = k[Me 3 N][MeI]
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Question

Given the following rate law,what will happen to the rate if the concentration of both reactants is doubled? Rate = k[Me₃N][MeI]

Quizplus · Accepted Answer

Since the rate law is dependent on the concentration of both reactants, doubling the concentration of both reactants would result in a 2 x 2 = 4-fold increase in the rate. Therefore, the correct answer is D.

Given the Following Rate Law,what Will Happen to the Rate