Optically pure (S)-monosodium glutamate has a specific rotation of + 24$\degree$.What specific rotation would (R)-monosodium glutamate of 50% optical purity have?

Question

Quizplus · Accepted Answer

The specific rotation of a compound is directly proportional to its optical purity. For (R)-monosodium glutamate with 50% optical purity, its specific rotation would be half that of the optically pure (S)-form but in the opposite direction, hence -12°.

Optically Pure (S)-Monosodium Glutamate Has a Specific Rotation of °\degree° What Specific Rotation Would (R)-Monosodium Glutamate of 50% Optical Purity

Optically Pure (S)-Monosodium Glutamate Has a Specific Rotation of $\degree$ What Specific Rotation Would (R)-Monosodium Glutamate of 50% Optical Purity