If pleural pressure changes from -3 cm H₂O to -7 cm H₂O as a subject breathes,and if the functional residual capacity (FRC)increases by 1 L,what is the compliance of the lung? A)0.1 L/cm H₂O B)4 cm H₂O/L C)0.25 L/cm H₂O D)10 cm H₂O/L

Question

Quizplus · Accepted Answer

Compliance is calculated as the change in volume (ΔV) divided by the change in pressure (ΔP). Here, ΔV = 1 L and ΔP = -7 - (-3) = -4 cm H2O. Thus, compliance = 1 L / 4 cm H2O = 0.25 L/cm H2O.

If Pleural Pressure Changes from -3 Cm H2O to -7

If Pleural Pressure Changes from -3 Cm H₂O to -7