A hydrogen atom is excited to the n = 10 stated.It then decays to the n = 4 state by emitting a photon which is detected in a photographic plate.What is the frequency of the detected photon? The lowest level energy state of hydrogen is -13.6 eV.(h = 6.626 × 10-34 J ∙ s, 1 eV = 1.60 × 10-19 J)
A) 3.46 × 1014 Hz
B) 0.865 × 1014 Hz
C) 1.27 × 1014 Hz
D) 4.05 × 1014 Hz
E) 1.73 × 1014 Hz
Correct Answer:
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