A series LRC ac circuit has a peak voltage of 111 V and a peak current of 2.00 A. If the current lags the voltage by 35.0^∘, what is the average power of the circuit? A) 91 W B) 182 W C) 78 W D) 156 W

Question

Quizplus · Accepted Answer

The average power in an AC circuit is given by P_avg = V_peak * I_peak * cos(φ) / 2, where φ is the phase angle. Here, V_peak = 111 V, I_peak = 2.00 A, and φ = 35°. So, P_avg = 111 * 2 * cos(35°) / 2 = 91 W.

A Series LRC Ac Circuit Has a Peak Voltage of 111