A doubly charged ion (charge 2e) with velocity 6.9 × 10⁶ m/s moves in a circular path of diameter 60.0 cm in a magnetic field of 0.80 T in a mass spectrometer. What is the mass of this ion? (e = 1.60 × 10^-19C) A) 11 × 10^-27 kg B) 6.7 × 10^-27 kg C) 4.5 × 10^-27 kg D) 3.3 × 10^-27 kg

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The correct answer is A because the mass of the ion can be calculated using the formula: m = (2e * B * r) / v, where m is the mass of the ion, e is the charge of the ion, B is the magnetic field strength, r is the radius of the circular path, and v is the velocity of the ion. Plugging in the given values, we get: m = (2 * 1.60 * 10^-19 C * 0.80 T * 0.30 m) / (6.9 * 10^6 m/s) = 11 * 10^-27 kg.

A Doubly Charged Ion (Charge 2e) with Velocity 6