A wire carrying a current is shaped in the form of a circular loop of radius 3.0 mm. If the magnetic field strength that this current produces at the center of the loop is 1.1 mT, what is the magnitude of the current that flows through the wire? (μ₀ = 4π × 10^-7 T ∙ m/A) A) 5.3 A B) 16 A C) 9.1 A D) 23 A

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Quizplus · Accepted Answer

The magnetic field strength at the center of a circular loop of wire is given by:B = (μ₀/4π) * (2πI/r)where:B is the magnetic field strengthμ₀ is the permeability of free space (4π × 10^-7 T ∙ m/A)I is the current flowing through the wirer is the radius of the loopSolving for I, we get:I = (Br)/2πμ₀Plugging in the given values, we get:I = (1.1 mT * 3.0 mm) / (2π * 4π × 10^-7 T ∙ m/A) = 5.3 ATherefore, the magnitude of the current that flows through the wire is 5.3 A.

A Wire Carrying a Current Is Shaped in the Form