An object starts from rest at time t = 0.00 s and moves in the +x direction with constant acceleration.The object travels 12.0 m from time t = 1.00 s to time t = 2.00 s.What is the acceleration of the object?

Question

Quizplus · Accepted Answer

The displacement from t = 1.00 s to t = 2.00 s is given by the equation: s = ut + 0.5at^2. Since the object starts from rest, u = 0. Therefore, 12.0 m = 0.5a(1^2), solving for a gives a = 8.00 m/s².

An Object Starts from Rest at Time T = 0