At what temperature would the root-mean-square speed (thermal speed) of oxygen molecules be 13.0 m/s? Assume that oxygen approximates an ideal gas. The mass of one O₂molecule is 5.312 x 10^-26 kg. The Boltzmann constant is 1.38 × 10^-23 J/K. A) 0.217 K B) 1800 K C) 5410 K D) 0.0666 K

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Quizplus · Accepted Answer

The correct answer is A because the root-mean-square speed of an ideal gas is given by the equation vrms = sqrt(3RT/M), where R is the ideal gas constant, T is the temperature in Kelvin, and M is the molar mass of the gas. Plugging in the given values, we get vrms = sqrt(3 * 8.314 J/mol*K * T / (5.312 x 10^-26 kg/mol)) = 13.0 m/s. Solving for T, we get T = 0.217 K.

At What Temperature Would the Root-Mean-Square Speed (Thermal Speed) of Oxygen