A 3.2-L volume of neon gas (Ne)is at a pressure of 3.3 atm and a temperature of 330 K.The atomic mass of neon is 20.2 g/mol,Avogadro's number is 6.022 × 10²³ molecules/mol,and the ideal gas constant is R = 8.314 J/mol · K = 0.0821 L · atm/mol · K.The mass of the neon gas is closest to A)7.9 × 10^-3 kg. B)4.6 × 10^-3 kg. C)3.8 kg. D)7.8 kg. E)7.8 × 10² kg.

Question

Quizplus · Accepted Answer

The mass of the neon gas can be calculated using the ideal gas law:PV = nRTwhere P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.The number of moles can be calculated using the formula:n = m/Mwhere m is the mass and M is the molar mass.Substituting the given values into the ideal gas law, we get:3.3 atm * 3.2 L = n * 0.0821 L · atm/mol · K * 330 KSolving for n, we get:n = 0.4 molesSubstituting the number of moles into the formula for mass, we get:m = n * M = 0.4 moles * 20.2 g/mol = 7.9 × 10^-3 kgTherefore, the mass of the neon gas is closest to 7.9 × 10^-3 kg.

A 32-L Volume of Neon Gas (Ne)is at a Pressure of of 3.3