A solid steel sphere with a radius of 2.0 m falls off a ship and sinks to a depth where the pressure is 15 MN/m².The bulk modulus for this steel is 1.6 × 10¹¹N/m².What is the change in the radius of the sphere? A)-0.021 mm B)-4.2 mm C)-0.42 mm D)-0.19 mm E)-0.062 mm

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Quizplus · Accepted Answer

The change in volume due to pressure can be calculated using the formula for bulk modulus: ΔV/V = -ΔP/B. For a sphere, ΔV = 4πr²Δr. Solving for Δr gives a change in radius of approximately -0.062 mm.

A Solid Steel Sphere with a Radius of 2