A 25 kg object is undergoing lightly damped harmonic oscillations.If the maximum displacement of the object from its equilibrium point drops to 1/3 its original value in 1.8 s,what is the value of the damping constant b?
A) 31 kg/s
B) 34 kg/s
C) 37 kg/s
D) 40 kg/s

Question

Quizplus · Accepted Answer

The damping constant b can be found using the formula for the decay of amplitude in a damped harmonic oscillator: A(t) = A_0 * e^(-bt/2m). Given that A(t)/A_0 = 1/3 and t = 1.8 s, m = 25 kg, we solve for b: 1/3 = e^(-b*1.8/50), leading to b ≈ 31 kg/s.

A 25 Kg Object Is Undergoing Lightly Damped Harmonic Oscillations