What is the output of the following code fragment?
Int v1=2, v2=-1, *p1, *p2;
P1 = & v1;
P2= & v2;
P2=p1;
Cout

Name: What is the output of the following code fragment? Int v1=2, v2=-1, *p1, *p2; P1 = & v1; P2= & v2; P2=p1; Cout << *p2 << endl; A) 2 B) -1 C) -2 D) 1
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Question

What is the output of the following code fragment?
Int v1=2, v2=-1, *p1, *p2;
P1 = & v1;
P2= & v2;
P2=p1;
Cout << *p2 << endl;
A) 2
B) -1
C) -2
D) 1

Quizplus · Accepted Answer

The pointer p2 is assigned the address of v1 by the statement `P2=p1;`, so dereferencing p2 with `*p2` outputs the value of v1, which is 2.

What Is the Output of the Following Code Fragment