A metal having a work function of 2.8 eV is illuminated with monochromatic light whose photon energy is 3.9 eV.What is the threshold frequency for photoelectron production? (h = 6.626 × 10^-34 J ∙ s,1 eV = 1.60 × 10^-19 J) A)6.8 × 10¹⁴ Hz B)2.7 × 10¹⁴ Hz C)7.6 × 10¹⁴ Hz D)8.5 × 10¹⁴ Hz E)9.4 × 10¹⁴ Hz

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Quizplus · Accepted Answer

The threshold frequency (f₀) is calculated using the work function (Φ) and Planck's constant (h): f₀ = Φ/h. Convert the work function from eV to joules: 2.8 eV = 2.8 × 1.60 × 10⁻¹⁹ J = 4.48 × 10⁻¹⁹ J. Then, f₀ = 4.48 × 10⁻¹⁹ J / 6.626 × 10⁻³⁴ J∙s = 6.8 × 10¹⁴ Hz.

A Metal Having a Work Function of 2