A circular loop of diameter 10 cm,carrying a current of 0.20 A,is placed inside a magnetic field = 0.30 T .The normal to the loop is parallel to a unit vector = -0.60 - 0.80 .Calculate the magnitude of the torque on the loop due to the magnetic field. A)4.7 × 10^-4 N ∙ m B)2.8 × 10^-4 N ∙ m C)0.60 × 10^-4 N ∙ m D)1.2 × 10^-4 N ∙ m E)zero

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The Answer of A circular loop of diameter 10 cm,carrying a current of 0.20 A,is placed inside a magnetic field = 0.30 T .The normal to the loop is parallel to a unit vector = -0.60 - 0.80 .Calculate the magnitude of the torque on the loop due to the magnetic field. A)4.7 × 10^-4 N ∙ m B)2.8 × 10^-4 N ∙ m C)0.60 × 10^-4 N ∙ m D)1.2 × 10^-4 N ∙ m E)zero

A Circular Loop of Diameter 10 Cm,carrying a Current of 0.20