As shown in the figure,a wire is bent into the shape of a tightly closed omega (Ω),with a circular loop of radius 4.0 cm and two long straight sections.The loop is in the xy-plane,with the center at the origin.The straight sections are parallel to the x-axis.The wire carries a 5.0-A current,as shown.What is the magnitude of the magnetic field at the center of the loop? (μ₀ = 4π × 10^-7 T ∙ m/A) A)25 µT B)40 µT C)54 µT D)80 µT E)104 µT

Question

Quizplus · Accepted Answer

We can use the formula for magnetic field at the center of a current loop:
B = μ0*I/(2*R)
where μ0 is the permeability of free space (μ0 = 4π×10^-7 T⋅m/A), I is the current, and R is the radius of the loop.
In this case, I = 5.0 A and R = 0.04 m, so:
B = (4π×10^-7 T⋅m/A)*(5.0 A)/(2*0.04 m) ≈ 54 µT
Therefore, the correct answer is choice C.

As Shown in the Figure,a Wire Is Bent into the Shape