A silver wire has a cross sectional area A = 2.0 mm².A total of 9.4 × 10¹⁸ electrons pass through the wire in 3.0 s.The conduction electron density in silver is 5.8 × 10²⁸ electrons/m³ and e = 1.60 × 10^-19 C.What is the drift velocity of these electrons? A)2.7 × 10^-5 m/s B)9.1 × 10^-5 m/s C)5.2 × 10^-5 m/s D)1.1 × 10^-5 m/s E)7.4 × 10^-5 m/s

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Quizplus · Accepted Answer

The drift velocity $v_d$ can be calculated using the formula $v_d = \frac{I}{nAe}$, where $I$ is the current, $n$ is the electron density, $A$ is the cross-sectional area, and $e$ is the charge of an electron. First, find the current $I$ by dividing the total charge by the time, $I = \frac{q}{t} = \frac{(9.4 \times 10^{18} \text{ electrons}) \times (1.60 \times 10^{-19} \text{ C/electron})}{3.0 \text{ s}}$. Then, use the given values to find $v_d$. The calculation will show that option A is the correct drift velocity.

A Silver Wire Has a Cross Sectional Area a =