A wire has a cross-sectional area of 0.10 mm².If there are 4.0 × 10²⁸ atoms per cubic meter in this wire,and if each atom contributes 2 free electrons,what is the drift velocity of the electrons when the current in the wire is 6.0 A? (e = 1.60 × 10^-19 C) A)0.0047 m/s B)0.0092 m/s C)0.94 m/s D)0.019 m/s

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Quizplus · Accepted Answer

The drift velocity is given by:$$v_d = \frac{I}{neA}$$where:* I is the current in the wire* n is the number of free electrons per unit volume* e is the charge of an electron* A is the cross-sectional area of the wireSubstituting the given values into the equation, we get:$$v_d = \frac{6.0 	ext{ A}}{(4.0 	imes 10^{28} 	ext{ m}^{-3})(1.60 	imes 10^{-19} 	ext{ C})(0.10 	imes 10^{-6} 	ext{ m}^2)} = 0.0047 	ext{ m/s}$$Therefore, the correct answer is A.

A Wire Has a Cross-Sectional Area of 0